Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
For a charity event, raffle tickets are printed such that they have a vowel (excluding ») as the first character and a
prime number less than 10 as the second digit. (Note that 1 is not a prime number.)
The probability that the winning ticket has the vowel contained in the word event and the digit is the number of
letters in the word event is 1/20 .
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Answer:

yes 1/20 is correct

Step-by-step explanation:

The probability that the winning ticket will have the letter e on it would be P=5%.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

For the probability of two independent events:

P(A and B) = P(A) P(B)

so we have to find the probability for each event to happen.

For a charity event, raffle tickets are printed such that they have a vowel (excluding ») as the first character and a prime number less than 10 as the second digit.

(Note that 1 is not a prime number.)

There are 5 vowels in the alphabet (a, e, i, o, and u).

Therefore the probability for the first letter to be e

P(A) = 1/5

We also know there are 4 prime numbers between 0 and 10 (2, 3, 5, 7)

so the probability for the number to be a 5 is:

P(B) = 1/4

Now, the probability of getting a ticket that starts with an e and ends with a 5

P(A and B) = P(A) P(B)

= 1/4 x 1/5

= 1/20

Therefore, the probability is 5%.

Learn more about probability here;

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