Using the following image, solve for x

Answer:

i^−3 = i

i^−2 = −1

i^−1 = −i

i^0 = 1

i^1 = i

i^2 = −1

i^3 = −i

i^4 = 1

i^5 = i

i^ 6 = −1

See the pattern

Answer:

the answer is d

Step-by-step explanation:

because when we put-1 from x the equation hasn't any value

[tex]\frac{13}{28}[/tex]

Given:

Blue marbles: 3

Reb marbles: 5

Total marbles: 8

Two marbles are selected at random, one after the other with replacement.

Getting the same colour of marbles from the selection means the two marbles are both red or both blue.

(a) Probability of getting 2 marbles being red in colour

i. Probability of picking a red at the first selection:

Number of red marbles ÷ Total number of marbles

=> 5 ÷ 8 = [tex]\frac{5}{8}[/tex]

ii. Probability of picking a red at the second selection:

Number of remaining red marbles ÷ Total number of remaining marbles

Since after the first pick, the marble is not replaced, the remaining red marbles is 4 while the total number of remaining marbles is 7

=> 4 ÷ 7 = [tex]\frac{4}{7}[/tex]

iii. The probability of getting both marbles being red is the product of i and ii above. i.e

[tex]\frac{5}{8}[/tex] x [tex]\frac{4}{7}[/tex] = [tex]\frac{5}{14}[/tex]

(b) Probability of getting 2 marbles being blue in colour

i. Probability of picking a blue at the first selection:

Number of blue marbles ÷ Total number of marbles

=> 3 ÷ 8 = [tex]\frac{3}{8}[/tex]

ii. Probability of picking a blue at the second selection:

Number of remaining blue marbles ÷ Total number of remaining marbles

Since after the first pick, the marble is not replaced, the remaining blue marbles is 2 while the total number of remaining marbles is 7

=> 2 ÷ 7 = [tex]\frac{2}{7}[/tex]

iii. The probability of getting both marbles being blue is the product of i and ii above. i.e

[tex]\frac{3}{8}[/tex] x [tex]\frac{2}{7}[/tex] = [tex]\frac{3}{28}[/tex]

(c) Probability of getting 2 marbles of the same colour.

The probability of getting 2 marbles of same colour is the sum of the probability of getting both marbles of red colour and the probability of getting both marbles as blue colour. i.e The sum of a(iii) and b(iii)

[tex]\frac{5}{14}[/tex] + [tex]\frac{3}{28}[/tex] = [tex]\frac{13}{28}[/tex]

The probability of getting 2 of the same colour is [tex]\frac{13}{28}[/tex]

Answer:

Attached images

It was just easier for me this way.

Let me know in comments if you have questions.

Step-by-step explanation:

Answer:

A. No, because the arcs do not have the same measure.

Step-by-step explanation:

Two arcs can be said to be congruent when the length measure of the two arcs are the same and not necessarily the degree measure. This implies that two arcs can have the same degree measure measure but their length may not be the same.

If two arcs have the same measure in one circle, therefore we can say they are congruent or if they have the same measure in congruent circles respectively, they are congruent.

In the two circles given above, although we are not told if both circles are congruent, however, since both arcs have different degree measure, both arcs cannot be congruent.

Answer:

[tex]X=6.67ft/s[/tex]

Step-by-step explanation:

From the question we are told that:

Height of pole [tex]H_p=15[/tex]

Height  of man [tex]h_m=6ft[/tex]

Speed of Man [tex]\triangle a =4ft/s[/tex]

Distance from pole [tex]d=35ft[/tex]

Let

Distance from pole to man=a

Distance from man to shadow =b

Therefore

 [tex]\frac{a+b}{15}=\frac{b}{6}[/tex]

 [tex]6a+6b=15y[/tex]

 [tex]2a=3b[/tex]

Generally the equation for change in velocity is mathematically given by

 [tex]2(\triangle a)=3(\triangle b )[/tex]

 [tex]2*4=3(\triangle b)[/tex]

 [tex]\triangle a=\frac{8}{3}[/tex]

Since

The speed of the shadow is given as

 [tex]X=\triangle b+\triangle a[/tex]

 [tex]X=4+8/3[/tex]

 [tex]X=6.67ft/s[/tex]

Answer:

C

Step-by-step explanation:

Answer: B

Step-by-step explanation:

can you put the whole question here

Answer:

z> -2

Step-by-step explanation:

STEP 1) Any expression divided by itself equals 1

-3z-1<5

STEP 2) Move the constant to the right-hand side and change its sign

-3z<5+1

STEP 3) Add the numbers

5+1= 6

-3z<6

STEP 4) Divide both sides of the inequality by -3 and flip the inequality sign

z>-2

9514 1404 393

Answer:

  1/3; geometric

Step-by-step explanation:

Apparently, your sequence is ...

  81, 27, 9, 3, 1, ...

The differences between these numbers vary, but the ratio of each to the one before is a constant:

  27/81 = 9/27 = 3/9 = 1/3

The sequence is geometric with a common ratio of 1/3. The next number in the sequence is (1)(1/3) = 1/3.

Answer:

The probability that you get an even card or a spade is P = 0.596

Step-by-step explanation:

In a deck of 52 cards, all the cards have the exact same probability of being drawn.

So, the probability of drawing an even card of a spade, will be equal to the quotient between the number of even cards and spades, and the total number of cards (52).

First, let's found the number of even cards and spades.

There are 13 spades.

For each set, the even cards are:

{2. 4, 6, 8, 10}

(not counting the queen as a "12")

Then for each set, there are 6 even cards.

(there are four sets but we already counted the 6 even cards from the spade set, so we ignore that set)

Then there are 3 sets with 6 even cards each, there are:

3*6 = 18 even cards

So we have:

13 spades + 18 even cards = 31 cards that meet the condition.

The probability is then:

P = 31/52 = 0.596

The probability that you get an even card or a spade is P = 0.596

Answer:

916.67 (corrected to 2 decimal places)

Hope I'm right, fingers crossed

Step-by-step explanation:

[tex]55 \times 50 = 2750 \div \frac{3}{4 } = 916.6666667[/tex]

Answer:

[tex]2 \times \frac{22}{7} \times 10 = 62.87 [/tex]

Answer:

11 hours is right answer i hope it will help you

Answer:

54 cm is the perimeter I think

Answer:

0 = 0

1 = 4

2 = 8

Step-by-step explanation:

So you multiply x by 4 to get y. Your first column is x. So you multiply those numbers by 4 to get y.

Answer:

0

4

8

Step-by-step explanation:

y = 4x

Substitute each x into equation to get y

y = 4(0)

y = 0

Answer:

The expected number of winning balls that Heather draws is 0.3.

Step-by-step explanation:

The balls are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Expected value of the hypergeometric distribution:

The expected value is given by:

[tex]E(X) = \frac{nk}{N}[/tex]

Expected number of blue and green balls:

40 balls, which means that [tex]N = 40[/tex]

2 are chosen, which means that [tex]n = 2[/tex]

25 are blue, which means that [tex]k = 25[/tex]

So

[tex]E(X) = \frac{nk}{N} = \frac{25(2)}{40} = 1.25[/tex]

1.25 balls are expected to be blue and 2 - 1.25 = 0.75 green.

Of the blue balls, 12% are winning.

Of the green balls, 20% are winning.

Calculate the expected number of winning balls that Heather draws.

[tex]E_w = 1.25*0.12 + 0.75*0.2 = 0.3[/tex]

The expected number of winning balls that Heather draws is 0.3.

Answer:

I think you have a type.. "the seventh number must be a 1"

there are no 1's in the original set of numbers

Step-by-step explanation:

Answer:

[tex]\bar x = 107.11[/tex]

[tex]\sigma_x = 31.07[/tex]

Step-by-step explanation:

See comment for complete question

Given

[tex]x: 97\ 178\ 129\ 90\ 75\ 94\ 116\ 100\ 85[/tex]

Solving (a): The sample mean

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{97+ 178+ 129+ 90+ 75+ 94+ 116+ 100+ 85}{9}[/tex]

[tex]\bar x = \frac{964}{9}[/tex]

[tex]\bar x = 107.11[/tex]

Solving (b): The sample standard deviation

This is calculated as:

[tex]\sigma_x = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

So, we have:

[tex]\sigma_x = \sqrt{\frac{(97 - 107.11)^2 +.............+ (85- 107.11)^2 }{9-1}}[/tex]

[tex]\sigma_x = \sqrt{\frac{7720.8889}{8}}[/tex]

[tex]\sigma_x = \sqrt{965.1111125}[/tex]

[tex]\sigma_x = 31.07[/tex]

Answer:

At 4:00 PM the distance between the two ships is 104.40 kilometers.

Step-by-step explanation:

Given that at noon, ship A is 150 km west of ship B, and ship A is sailing east at 30 km / h and ship B is sailing north at 25 km / h, to determine how fast is the distance between the ships changing at 4:00 PM the following calculation must be performed:

150 - (30 x 4) = 150 - 120 = 30

0 + (25 x 4) = 0 + 100 = 100

30 ^ 2 + 100 ^ 2 = X ^ 2

√ (900 + 10,000) = X

√10,900 = X

104.40 = X

Therefore, at 4:00 PM the distance between the two ships is 104.40 kilometers.

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

Answer:

AB = 5.6 cm

Step-by-step explanation:

Reference angle (θ) = 62°

Hypotenuse = 12 cm

Adjacent = AB

Apply the trigonometric ratio formula, CAH, which is:

Cos θ = Adj/Hyp

Plug in the values

Cos 62° = AB/12

12*Cos 62° = AB

5.63365876 = AB

AB = 5.6 cm (1 decimal place)

i)50

Steps

30+20=50

ii)7

Steps

75-(30+20)-18

=75-(50)-18

=7

iii)20

Steps

From the available data from the question

iv)30

Steps

From the available data from the questionl

v)From the attcged image file

Answer:

in a square all sides are equal so x has to equal

128

Hope This Helps!!!

Answer:

x=−40

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x4−3x8=5

14x+−38x=5

(14x+−38x)=5(Combine Like Terms)

−18x=5

−18x=5

Step 2: Multiply both sides by 8/(-1).

(8−1)*(−18x)=(8−1)*(5)

x=−40

Answer:

x=−40

Hello!

x/4 - 3x/8 = 5

2x - 3x = 40

-x = 40

x = -40

Good luck! :)

Answer:

$0.60

Step-by-step explanation:

To find the cost of 1 orange, divide the $6 by 10:

6/10 = 0.6

Hope it helps (●'◡'●)

Answer:

t = 1

Step-by-step explanation:

16 - 2t = 5t + 9

7 = 7t

t = 1

Answer:

a) 0.46 = 46% probability that a person who walks by the store will enter the store.

b) 0.36 = 36% probability that a person who walks into the store will buy something.

c) 0.17 = 17% probability that a person who walks by the store will come in and buy something.

d) 0.64 = 64% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

(a) Estimate the probability that a person who walks by the store will enter the store.

58 out of 125. So

[tex]p = \frac{58}{125} = 0.46[/tex]

0.46 = 46% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

58 walked, 21 bought. So

[tex]p = \frac{21}{58} = 0.36[/tex]

0.36 = 36% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

21 came in and bought out of 125 that walked by. So

[tex]p = \frac{21}{125} = 0.17[/tex]

0.17 = 17% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

0.36 probability that a person buys something, so 1 - 0.36 = 0.64 = 64% probability that a person who comes into the store will buy nothing.

(not a or not b) implies c   <==>   not (not a or not b) or c

so negating gives

not [(not a or not b) implies c]   <==>   not[ not (not a or not b) or c]

which we can simplify somewhat to

not (not (not a or not b)) and not c

(not a or not b) and not c

(not a and not c) or (not b and not c)

not (a or c) or not (b or c)

not ((a or c) and (b or c))

not ((a and b) or c)