What is the common ratio for this geometric sequence?
27, 9, 3, 1, ...

14. largest 9510

15. smallest 1000000

16. n+6=22 —> n=22-6 —>n = 16

17. Add : 204 + 38429= 38633

Answer:

Step-by-step explanation:

The first jar holds 45 marbles and 5 of them are black.

The second jar holds 100 marbles and 10 of them are black.

Required probability:

Now we have to find,

The probability that a black marble will be drawn from both jars.

The given information is,

→ 1st jar contains/holds 45 marbles.

→ 5 of the marbles are black.

→ 2nd jar contains/holds 100 marbles.

→ 10 of the marbles are are black.

Then the probability will be,

→ P(b,b)

→ (5/45) × (10/100)

→ (1/9) × (1/10)

→ 1/90

Thus, required probability is 1/90.

Answer:

19 m

Step-by-step explanation:

Perimeter = 2(length + width) ; P = 2(l+w) - - (1)

Area = Length * width ; A = l*w - - - (2)

76 = 2(l+w)

76/2 = l+w

l+w = 38

l = 38 - w

Put l = 38 - w in (1)

A = (38-w)*w

A = 38w - w²

At maximum point:

dA/dw = 0

dA/dw = 38 - 2w

38 - 2w = 0

38 = 2w

w = 38/2

w = 19

Answer:

1  ≤  y  <  ∞

Step-by-step explanation:

very true

Answer:

H0 : μ = 91000

H1 : μ ≠ 91000

Test statistic = - 2.594

Pvalue = 0.016

|Tcritical | = 2.064

Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.

Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.

Step-by-step explanation:

The hypothesis :

H0 : μ = 91000

H1 : μ ≠ 91000

From the data given :

77600 76000 90700 97200 90700

101800 78700 81300 84200 97600

77500 75700 89400 84300 78700

84600 87700 103400 83800 101300

94700 69200 95400 61500 68800

Using calculator :

Sample mean, xbar = 85272

Sample standard deviation, s = 11039.23

Sample size, n = 25

The test statistic :

(xbar - μ) ÷ (s/√(n))

(85272 - 91000) / (11039.23/√(25)

Test statistic = - 5728 / 2207.846

Test statistic = - 2.594

The Pvalue : df = n - 1 = 25 - 1 = 24

Pvalue(-2.594, 24) = 0.0159

Decision region :

Reject H0 ; If Pvalue < α ;

α = 0.05

Using the critical value :

Decision region :

Reject H0 ; If Test statistic > |Tcritical;

Tcritical value at df = 24 ; α = 0.05 ;

|Tcritical | = 2.064

Hence,

We Reject H0 ; Since, |Test statistic| > |Tcritical|and conclude that mean salary depends differs

Answer:

5x3 y(5xy-4)

5x3y ×1xy

5x4y2

Answer:

[tex]5 {x}^{3} y[/tex]

step by step

[tex]5 {x}^{3} y(2x + 3y - 4) \\ = 10 {x}^{3}y + 15 {x}^{3} y + 20 {x}^{3} y \\ = 5 {x}^{3} y[/tex]

Answer:

x=1

Step-by-step explanation:

5x+37=-6(1-8x)

Distribute

5x+37 = -6 +48x

Subtract 5x from each side

5x+37 -5x = -6+48x-5x

37 = -6+43x

Add 6 to each side

37+6 = -6+43x+6

43 = 43x

Divide by 43

43/43 = 43x/43

1 =x

Answer:

x=1

Step-by-step explanation:

5x+37=-6(1-8×)

5x+37=-6(-7)

5x+37=6 x 7

5x+37= 42

5x+37-37=42-37

5x=5

5x/5 = 5/5

x = 1

Hope it Helps !!

Answer:

Y = (x + 1)^2 - 4

where is

look the Diagram when the line arrow cross to x line got -4 it's mean left side is Negative and reach to y diagram within 1 on positive to below

so the right answer is = Y = (x+1)^2 - 4

Carlene's employer's contribution to the 401(k) was of $3,200., using proportions.

A proportion is a fraction of a total amount, and this fraction is combined with basic arithmetic operations, especially multiplication and division, to find the desired measures in the context of a problem.

The proportion of her salary that she contributed to the 401(k) plan is of:

4000/40000 = 0.1.

The first 6% of her salary is:

0.06 x 40000 = $2,400.

Hence her employee contributed $2,400 relative to the first 6% of her salary.

For the 4% between 6% and 10%, the employee contributed 50% of her contributions, hence:

0.5 x (4000 - 2400) = 0.5 x 1600 = $800.

Hence the total contribution by the employee is of:

2400 + 800 = $3,200.

More can be learned about proportions at https://brainly.com/question/24372153

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Answer:

100

Step-by-step explanation:

if every 1/100 is 1 tuna can you need to multiply the amount of tuna to make a tuna can so it will be 1 so times 100

Answer: 64000000

Explanation: Why are you named as my ALT-

Answer:

The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 70 - 1 = 69

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 69 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.649

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.649\frac{8.4}{\sqrt{70}} = 2.66[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 52 - 2.66 = 49.34

The lower bound of the 99% confidence interval for the gift basket's average shipping weight is of 49.34 ounces.

Answer:

2+6=8

Step-by-step explanation:

Start at 2

Then since we are adding 6 move 6 units to the right

Answer:

w =-4

Step-by-step explanation:

4w = 2w - 8

Subtract 2w from each side

4w-2w = 2w-2w - 8

2w = -8

Divide by 2

2w/2 = -8/2

w = -4

Answer:

35

Step-by-step explanation:

7-7(-4)

Using PEMDAS

Multiply first

7 +28

Then add

35

Answer:

option b

Step-by-step explanation:

both are rectangles and similar measures  

Yes, because both figures are rectangles and all rectangles are similar

The rectangle EFGH is a result of the dilation of rectangle ABCD

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the first rectangle be represented as ABCD

Now , the rectangle is dilated by a scale factor k

And , the transformed rectangle is given by EFGH

where the center of origin is the scale factor of dilation

Now , the ratios of the sides of the rectangles will be similar

So , the rectangles ABCD and EFGH are similar

Hence , the dilated rectangle is EFGH

To learn more about dilation click :

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Answer:

27405

Step-by-step explanation:

There are 6 different variants available for each croissant. There are 26 croissants in all out of which 1 is plain. We use combination and permutation technique to identify different ways to choose croissant.

[5 + 26 - 1 ] 26 = 30C26 = 27405.

Answer:

arithmetic

hyj

bhhm

bm.hg

hgjm

hgjgshmih

mhh

jhuu

Let X(s) and Y(s) denote the Laplace transforms of x(t) and y(t), respectively. Then taking the transform of both sides of both equations gives

LT[dx/dt + 5x + dy/dt] = LT[1]

==>   s X(s) - x (0) + 5 X(s) + s Y(s) - y (0) = 1/s

==>   s X(s) + 5 X(s) + s Y(s) = 1/s

==>   (s + 5) X(s) + s Y(s) = 1/s

LT[dx/dt - x + dy/dt - y] = LT[exp(t )]

==>   s X(s) - x (0) - X(s) + s Y(s) - y (0) - Y(s) = 1/(s - 1)

==>   s X(s) - X(s) + s Y(s) - Y(s) = 1/(s - 1)

==>   (s - 1) X(s) + (s - 1) Y(s) = 1/(s - 1)

Solve for X(s) and Y(s). Using elimination, you would get

X(s) = (1 - 2s) / (5s (s - 1)²)

Y(s) = (7s - 1) / (5s (s - 1)²)

Now take the inverse transforms of each. Start by getting the partial fraction decompositions:

(1 - 2s) / (5s (s - 1)²) = 1/5 (a/s + b/(s - 1) + c/(s - 1)²)

-2s + 1 = a (s - 1)² + bs (s - 1) + cs

-2s + 1 = (a + b) s ² + (-2a - b + c) s + a

==>   a + b = 0, -2a - b + c = -10, a = 5

==>   a = 1, b = -1, c = -1

==>   X(s) = 1/5 (1/s - 1/(s - 1) - 1/(s - 1)²)

Similarly, you would find

Y(s) = -1/5 (1/s - 1/(s - 1) - 6/(s - 1)²)

Now for the inverse transforms:

LT⁻¹ [1/s] = 1

LT⁻¹ [1/(s - 1)] = exp(t )

LT⁻¹ [1/(s - 1)²] = t exp(t )

Putting everything together, we have

LT⁻¹ [X(s)] = x(t) = 1/5 - 1/5 exp(t ) - 1/5 t exp(t )

and

LT⁻¹ [Y(s)] = y(t) = -1/5 + 1/5 exp(t ) + 6/5 t exp(t )

Answer:

yes

Step-by-step explanation:

3/9  Divide the top and bottom by 3

1/3

5/15 Divide the top and bottom by 5

1/3

They are equal

Answer:

[tex]269 \frac{1}{4} [/tex]

Step-by-step explanation:

the solution is found above in the diagram.

////////////////////////

Answer:

Step-by-step explana

540

Answer:

x = -3  or x = 3  or x = 6

Step-by-step explanation:

x3 – 6x2 – 9x + 54 = 0

There is no common factor to factor out. There are 4 terms. We try factoring by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.

x^2(x - 6) - 9(x - 6) = 0

x - 6 is a common factor, so we factor it out.

(x^2 - 9)(x - 6) = 0

x^2 - 9 is the difference of 2 squares, so we factor it.

(x + 3)(x - 3)(x - 6) = 0

x + 3 = 0  or  x - 3 = 0  or x - 6 = 0

x = -3  or x = 3  or x = 6

Answer:

x=6     x=3   x=-3

Step-by-step explanation:

x^3 – 6x^2 – 9x + 54 = 0

Factor by grouping

x^3 – 6x^2     – 9x + 54 = 0

x^2(x-6)    -9(x-6 ) =0

Factor out x-6

(x-6)(x^2 -9) =0

Notice x^2 -9 is the difference of squares

(x-6)(x-3)(x+3) = 0

Using the zero product property

x-6 =0    x-3 =0   x+3 =0

x=6     x=3   x=-3

Answer:

I have to go get my car from the doctor office today

9514 1404 393

Answer:

  13

Step-by-step explanation:

152AB1 is not a square in hexadecimal, so we assume A and B are supposed to represent single digits in decimal.

If A=B=0, √152001 ≈ 389.9

If A=B=9, √152991 ≈ 391.1

The least significant digit of 152AB1 being non-zero, we know it is not the square of 390. Hence, it must be the square of 391.

For 152AB1 to be a perfect square, we must have ...

  152AB1 = 391² = 152881

The sum of the digits of the square root is 3+9+1 = 13.

Answer:

[tex]d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} } \\\\=\sqrt{(4-(-1))^{2}+(7-9)^{2} } \\\\=\sqrt{(5)^{2}+(-2)^{2}} \\\\=\sqrt{25+4} \\\\=\sqrt{29}[/tex]

Answer:

A (1 + i)^n = 1490    time for amount to reach 1490

(1 + i)^n = 1.49    since A = $1000

n log (1 + .06/4) = log 1.49       take log of both sides at 1.5% per quarter

n = log (1.49) / log 1.015  = 26.78 periods or 6.695 years

(compare to 6.843 years compounded annually)

[tex]t = ln(A/P) / n[ln(1 + r/n)]\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.06/4)] )\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.015)] )\\t = 6.7 years[/tex]

It would take around 6 years 8 months to get $1,490 from $1,000 at 6%.

I hope I've helped! :)

Answer:

mean ≈ 25.45

Step-by-step explanation:

mean is calculated as

mean = [tex]\frac{sum}{count}[/tex]

We require the sum for both classes

class A

mean = [tex]\frac{sum}{9}[/tex] = 40 ( multiply both sides by 9 )

sum = 9 × 40 = 360

class B

mean = [tex]\frac{sum}{24}[/tex] = 20 ( multiply both sides by 24

sum = 24 × 20 = 480

Total sum for both classes = 360 + 480 = 840 , then mean for both classes is

mean = [tex]\frac{840}{33}[/tex] ≈ 25.45 ( to 2 dec. places )