Answer:
Explanation:
First off, let's call the -15 degree water solution1, and the 32 degree water solution2. The formula for this is
[tex]t_f=\frac{(m_1*spheat_1*temp_1)+(m_*spheat_2*temp_2)}{(m_1*spheat_1)+(m_2*spheat_2)}[/tex]
where spheat is specific heat of water that I found to be 4182 J/(kgC). This means that we need our masses in kg and they are currently in g.
100 g = .100 kg and
220 g = .220 kg. Now we're ready to plug everything in:
[tex]t_f=\frac{(.100*4182*-15)+(.220*4182*32)}{(.100*4182)+(.220*4182)}[/tex] and
[tex]t_f=\frac{-6273+29441.28}{418.2+920.04}[/tex] and
[tex]t_f=\frac{23168.28}{1338.24}[/tex] so
[tex]t_f=17.3[/tex] °C
Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357° C?
Answer:
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
Explanation:
Por definición de entropía ([tex]S[/tex]), medida en joules por Kelvin, tenemos la siguiente expresión:
[tex]dS = \frac{\delta Q}{T}[/tex] (1)
Donde:
[tex]Q[/tex] - Ganancia de calor, en joules.
[tex]T[/tex] - Temperatura del sistema, en Kelvin.
Ampliamos (1) por la definición de calor latente:
[tex]dS = \frac{L_{v}}{T}\cdot dm[/tex] (1b)
Donde:
[tex]m[/tex] - Masa del sistema, en kilogramos.
[tex]L_{v}[/tex] - Calor latente de vaporización, en joules
Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:
[tex]\Delta S = \frac{\Delta m \cdot L_{v}}{T}[/tex]
Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que [tex]m = 0.50\,kg[/tex],[tex]L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}[/tex] and [tex]T = 630.15\,K[/tex], entonces el cambio de entropía es:
[tex]\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}[/tex]
[tex]\Delta S = 214.235 \,\frac{J}{K}[/tex]
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a radius of 0.25 m. The other end of the rope is attached to a massless suspended platform, upon which 0.5 kg weights may be placed. While the system is initially in equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling the rope. What is the torque on the pulley when the system is motionless?
Answer:
The torque on the pulley, when the system is motionless is approximately 9.81 N·m
Explanation:
The given parameters are;
The mass of the object = 2 kg
The friction between the rope and the pulley = 0
The mass of the rope, [tex]m_r[/tex] = 0.5 kg
The mass of the pulley, [tex]m_p[/tex] = 0.01 kg
The radius of the pulley, r = 0.25 m
The torque on the pulley, τ = I·α = F × D
The torque on the pulley, when the system is motionless, τ = F × D
Where;
F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N
D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m
Therefore;
τ = 19.62 N × 0.5 m = 9.81 N·m
The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.
1 Diagram 1 shows an experiment to prove the existence
of electric fields. The two electrodes are connected to a
very high voltage
(a) Why is cooking oil used?
elect
11 mark]
23
Answer:
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An overworked computer software engineer works on the computer the whole day. He gets very tired after work. Somebody advised him to eat more carbohydrates and fats to get more energy. Do you think this will help him? Why?
Answer:
Following are the solution to the given question:
Explanation:
The answer is "Yes," as it will provide more fuel than a source of vitamins and minerals for him as carbohydrates. Whereas after carbohydrates supply energy, lipids were applied to long-term electricity. Obesity is caused by over intakes of carbohydrates and fats. They must therefore be given in the amount recommended. For its activity, the brain uses glucose. Nevertheless, he does not require sufficient fat since fat is difficult to absorb & fat may make him sound more tired. To recover rapidly, one should consume carbohydrates and meals rich in vitamins. Selection for fat in the form of nuts should be mainly.
Who was Sir Isaac Newton? Be sure to explain in your own words.
Answer:
the person who invented gravity
Explanation:
newton was a mathmaticians when one day an apple fell on him. he had the idea to name the force gravity. While he "made" gravity he made other important laws the 3 newton laws of physics
Answer:
Issac Newton was around in the 1600s and early 1700s and is a very important mathematician and invented calculus.
Explanation:
A 0.1 kg popper is placed on a table. When it pops
up, it reaches a height of 2.0 meters. What was the
initial velocity of the popper off the table?
Answer:
The initial velocity of the pooper off the table is approximately 9.264 m/s
Explanation:
The mass of the popper, m = 0.1 kg
The height the popper reaches, h = 2.0 meters
The initial velocity of the popper, 'u', is given by the following kinematic relation;
v² = u² - 2·g·h
Where;
h = The height the popper reaches = 2.0 m
v = The final velocity of the popper at the height it reached = 0 m/s
u = The initial velocity of the pooper off the table
g = The acceleration du to gravity, g ≈ 9.81 m/s²
Plugging in the values gives;
0² = u² - 2 × 9.81 × 2.0
∴ u - √(2 × 9.81 × 2.0) ≈ 9.264
The initial velocity of the pooper off the table, u ≈ 9.264 m/s.
What are the advantages and disadvantages of renewable and non-renewable energy?
Renewable energy
Advantages :-
1. Easily regenerate
2. Boost economic growth
3. Easily available
4. Support environment
5. Low maintenance cost
Disadvantages :-
1. Weather dependency
2. High installation cost
3. Noise caused by wind energy
4. Fluctuation problem (solar)
5. Intermittency issue (wind)
Non-renewable energy
Advantages :-
1. Concentrated energy source
2. Reliable energy source
3. Can be built anywhere
4. No radioactive waste
Disadvantages :-
1. Produces greenhouse gases
2. Contributes to global warming
3. Produces acid rain
4. Harmful to environment when they are burnt
I hope this helps.....
A person notices water waves on the surface of the pond. 18 waves pass by a person in 12 seconds. Calculate the frequency of these water waves. Give the unit.
Answer:
f = 1.5 Hz
Explanation:
Given that,
18 waves pass by a person in 12 seconds.
We need to find the frequency of these water waves.
We know that,
Frequency = no. of waves per second
So,
[tex]f=\dfrac{18}{12}\\\\f=1.5\ Hz[/tex]
So, the frequency of these water waves is equal to 1.5 Hz.
In a right angled triangle, length of hypotenuse is 8 cm and its
perpendicular is 3 cm. Find Sin θ
Explanation:
Sin θ = P/H = 3/8
Answer 0.375
Explanation
sin theta= opp /hyp
= 3/8
=0.375
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en los 13 segundos
Answer:
Acceleration = 5.77 m/s²
Distance cover in 13 seconds = 487.56 meter
Explanation:
Given:
Final velocity of mobile device = 75 m/s
initial velocity of mobile device = 0 m/s
Time taken = 13 seconds
Find:
Acceleration
Distance cover in 13 seconds
Computation:
v = u + at
75 = 0 + (a)(13)
13a = 75
a = 5.77
Acceleration = 5.77 m/s²
s = ut + (1/2)(a)(t²)
s = (0)(t) + (1/2)(5.77)(13²)
Distance cover in 13 seconds = 487.56 meter
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
m ahead. The ranger, who is driving at 11.4 m/s, immediately applies the brakes and
slows down with an acceleration of 3.80 m/s2. How much distance is required for the
ranger's vehicle to come to rest? Only enter the number, not the units.
Answer:
17.1
Explanation:
The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m
The initial speed with which the ranger was driving, u = 11.4 m/s
The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)
The distance required for the ranger to come to rest, s = Required
The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;
v² = u² + 2·a·s
∴ s = (v² - u²)/(2·a)
Where;
v = The final velocity = 0 m/s (the vehicle comes to rest (stops))
Plugging in the values for 'v', 'u', and 'a', gives;
s = (0² - 11.4²)/(2 × -3.8) = 17.1
The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).
What is latent heat?
A.
energy released or absorbed to change the kinetic energy of a substance
B.
energy released or absorbed to change the pressure of a substance
C.
energy released or absorbed to change the temperature of a substance
D.
energy released or absorbed to change the phase of a substance
calculate the charge flow when the vurrent is 0.50A in the wites for 17s
Answer:
Quantity of charge = 8.5 Coulombs
Explanation:
Given the following data;
Current = 0.5 A
Time = 17 seconds
To find the charge flowing through the wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 0.5 * 17
Quantity of charge = 8.5 Coulombs
a wire is stretched to double its length .what happened to its resistance and resistivity?
A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is moving at a velocity of –7 m/s. After colliding, the 35-gram ball moves at a velocity of –15 m/s. Assume there is no net force on the system.
What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth.
Explanation:
the answer is in the above image
Given:
mass of first ball, m1 = 35g
mass of second ball, m2 = 75g
velocity of first ball before collision, u1 = 9m/s
velocity of second ball before collision, u2 = -7m/s
velocity of first ball after collision, v1 = -15m/s
velocity of second ball after collision, v2 = ? (To Find)
Now it is given that there is no net force on the system of two balls
according to the Law of Conservation of Momentum so, here momentum is constant before and after collision:
P1 = P2
m1u1 + m2u2 = m1v1 + m2v2
35g*9m/s + 75g*(-7m/s) = 35g*(-15m/s) + 75g*v2
v2 = (35g*9m/s + 75g*(-7m/s) - 35g*(-15m/s))/75g
v2 = 4.2m/s
therefore, the velocity of second ball after collision is 4.2m/s
What is the formula of conservation of momentum?
As a result, the equation of the law of conservation of momentum is as follows: m1 u1 + m2 u2 represents the total momentum of particles A and B before the collision, and m1 v1 + m2 v2 represents the total momentum of particles A and B after the collision.
What is momentum unit?Momentum. If the mass of an object is m and it has a velocity v, then the momentum of the object is defined to be its mass multiplied by its velocity. momentum = mv. Momentum has both magnitude and direction and thus is a vector quantity. The units of momentum are kg m s−1 or newton seconds, N s.
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Un automóvil de carreras da una vuelta a una pista circular de 500 m de radio en 50 s. A) La velocidad media del carro es 1) cero, 2) 100 m/s, 3) 200 m/s o 4) ninguna de las anteriores. ¿Por qué? B) Calcule la rapidez media del carro Solución: Datos r=500m ∆ = 50
Answer:
La velocidad media del carro no es ninguna de las ofrecidas como respuesta.
La velocidad es
v = 62.8 m/s
Explanation:
La longitud de una circunferencia de 500 metros de radio es:
L = 2*π*r por sustitución L = 2* 3.14* 500
L = 3140 m esta es la distancia recorrida por el carro de carreras en 50 segundos.
la velocidad media es v v = L / t por definición luego
v = 3140 m/ 50 s v = 62.8 m/s
in the compound CaCO3 at the end of the compound represents the number of
Answer:
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).
Solution —
Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g
No. of moles of CaCO3
= No. of molecules/Avogadro constant
= 6.022 × 1023/ 6.022 × 1023
= 1 mole
Mass of CaCO3
= No. of moles × molar mass
= 1 × 100 g = 100 g.
a. An object takes 5 s to reach the
ground from a height of 5 m on a
planet. What is the value of g on the
planet?
Ans: 0.4 m/s2
Answer:
g = 0.4 m/s²
Explanation:
Given the following data;
Height = 5 meters
Time = 5 seconds
To find the acceleration due to gravity (g) on the planet;
Mathematically, the maximum height of an object is given by the formula;
H = ½gt²
Where;
H is the height measured in meters.
g is the acceleration due to gravity.
t is time measured in seconds.
Substituting into the formula, we have;
5 = ½ * g * 5²
5 = 0.5 * g * 25
5 = 12.5 * g
g = 5/12.5
g = 0.4 m/s²
How to solve the equation of power ?
Answer:
OK HERE
Explanation:
When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. For example, in the following expression, x to the power of 3 is being raised to the power of 6, and so you would multiply 3 and 6 to find the new power.
A satellite orbits the earth with a kinetic energy of 2.0 x 10^10 J. Its gravitational potential energy
in this orbit is -4.0 x 10^10 J. What is the total energy of the satellite (relative to infinity)?
0 -6.0 x 10^10 J
O 6.0 x 10^10 J
0-2.0 x 10^10 J
O 2.0 x 10^10 J
Answer:
the total energy of the satellite is -2.0 x 10¹⁰ J
Explanation:
Given;
kinetic energy of the satellite, K.E = 2.0 x 10¹⁰ J
gravitational potential energy, P.E = -4 x 10¹⁰ J
The total mechanical energy of the satellite is calculated as follows;
M.E = K.E + P.E
M.E = 2.0 x 10¹⁰ J - 4 x 10¹⁰ J
M.E = -2.0 x 10¹⁰ J
Therefore, the total energy of the satellite is -2.0 x 10¹⁰ J
why must geostationary satellite rotate in the same direction as Earth's rotation?
Answer:
Its happen because the satellite orbits at the same speed as the Earth is rotating, so it appears that the satellite is located at the same longitude, although it may drift from north to south. This particular, high Earth orbit is called geosynchronous. It is always directly in the same place on the surface of the earth.
Explanation:
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A man stands 80m in front of a cliff face.
He makes aloud bang and listens for the
echo. He makes a loud bong once every second
He hears an echo exactly half way between
the bang that caused it and the next hang
A 40mis
B. 20m/s
C 160mis
D 320m/s
Answer:
v = 40 m/s
Explanation:
Given that,
A man stands 80m in front of a cliff face. He makes aloud bang and listens for the echo. He makes a loud bong once every second.
He hears an echo exactly half way between the bang that caused it and the next hang.
Distance = 40 m, t = 1 s
The speed of sound is given by :
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{40\ m}{1\ s}\\\\v=40\ m/s[/tex]
Hence, the speed of sound is equal to 40 m/s.
Which is not true of friction? A. Causes wear and tear of the surfaces B. Helps us to fall easily on roads C. Produces heat D. Produces light E. Stops bodies when they move over each other.
Answer:
B.
Hope this helps
Which one of the following is NOT an example of
force?
A Magnetism
B. Mass
C Weight
D. Effort
What is electric potential
Answer:
The amount of work need to move a unit charge from a reference point to a specific point against an electric field.
12 Write a difference between FPS
and CGS unit system of unit.
Answer:
CGS means Centimeter Gram Second while FPS means Foot Pounds Second
Explanation:
FPS is the standard used to measurement of length, mass and time. The unit of length is foot.
The time is calculated as the unit of seconds. CGS is the measurement of length, mass and time in units of centimeter, gram and second respectively
Which types of forces exist between the two protons in a helium nucleus?
1.
a repulsive electrostatic force and a repulsive gravitational force
2.
a repulsive electrostatic force and an attractive strong nuclear force
3.
an attractive electrostatic force and an attractive gravitational force
4.
an attractive electrostatic force and an attractive strong nuclear force
Answer:
Option (2) is correct.
Explanation:
When two charges have equal charges they repel each other. On the other hand, if they have unequal charges they attract each other.
The force between the two protons in a helium nucleus is electrostatic charges and the force is repulsive in nature.
Also, there exists a strong nuclear force between charges.
So, a repulsive electrostatic force and an attractive strong nuclear force is the correct answer.
Consider the case in which the clay is launched along Path Y. The sphere of clay is launched with an initial velocity of v0 and collides with the rod at a distance of l from the pivot. The length of the rod is L. The rotational inertia of the rod about the joint is IR, and the mass of the clay is mc. The clay is considered a point mass. What is the angular speed f of the clay-rod system immediately after the collision
Answer:
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = [tex]\frac{m}{I_{total} }[/tex] v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
The angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
What is angular speed?Angular speed is defined as the rate of change of angular displacement,Angular Speed (ω) is the scalar measure of rotation rate. In one complete rotation, angular distance travelled is 2π and time is time period (T)
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
[tex]L_o=mvl[/tex]
Final moment. After the collision with the clay stuck to the rod
[tex]L_o = L_f m v l = I_{total} w[/tex]
[tex]w=\dfrac{m}{I_{total}} Vl[/tex]
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
[tex]I_rod = I R^2 I_{total} = m l^2 + IR^2[/tex]
we substitute
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
Hence the angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
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PLEASE HELP WITH THIS QUESTION
The reason you should always wear your seatbelt in a moving car
A. Newton's 1st law
B. Newton's 2nd law
C. Newton's 3rd law
Calculate the change in the gravitational potential energy store of the following objects.
A cat with a mass of 3 kg climbs a tree, reaching a final height of 4.5 m (g = 9.8 N/kg).
Silver
Change in gravitational potential energy store =
Explanation:
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. ... Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. PE = kg x 9.8 m/s2 x m = joules.
So, the PE is
3 x 9.8 x 4.5 = 132.3 J
