What is the lateral area of the square pyramid, to the nearest whole number?
A. 165 m2
B. 176 m2
C. 330 m2
D. 351 m2

Answer:

4

Step-by-step explanation:

2 · 4 = 8

8 + 4 = 12

the value of x is 4

Answer:

I = $ 6.00

Step-by-step explanation:

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 60 × 0.1 × 1 = 6

I = $ 6.00

The simple interest accumulated

on a principal of $ 60.00

at a rate of 10% per year

for 1 years is $ 6.00.

Answer:

1230

Step-by-step explanation:

i multipled to see what i was gone get

Answer:

9.61cm

Step-by-step explanation:

Let height be x thus length will also be x

since the base is a square the width and length are also equal.

volume of pyramid=length×width×height

3

296cm³=x×x×x

3

296×3=x³

888=x³

x= cube root of 888

x=9.61cm

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer.....

= 90 - 18

= 72

--> 72° is the complement angle of 18°

Hope it helps!

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Answer:

B. 2(11A + 7)

Step-by-step explanation:

The common factor of 22 and 14 is 2

Answer:

D. Parallelogram

Step-by-step explanation:

Answer:

The answer is Parallelgram(D)

two pairs of parallel sides in a quadrilateral

hope it helps...

The answer is  4.25 miles

Answer:

yb

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Since they have the same denominator, it would be:

[tex]\frac{4}{3}-\frac{1}{3}=\frac{4-1}{3} =\frac{3}{3}=1[/tex]

Let X be a random variable denoting pulse rates of females as described, with mean µ = 74.0 bpm and standard deviation σ = 12.5 bpm. Then

P(70 < X < 78) = P((70 - µ)/σ < (X - µ)/σ < (78 - µ)/σ)

… = P(-0.32 < Z < 0.32)

… = P(Z < 0.32) - P(Z < -0.32)

… ≈ 0.6255 - 0.3745

… ≈ 0.2510

where Z is normally distributed with mean 0 and s.d. 1.

• • •

Next, you sample 25 females from the population and want to find the probability that their average falls between 70 and 78 bpm. Let [tex]X_i[/tex] denote the pulse rate of the i-th woman from the sample, and let Y be the random variable for the sample mean; that is,

[tex]Y=\displaystyle\sum_{i=1}^{25}\frac{X_i}{25}[/tex]

Recall that a sample of size n taken from a normal distribution with mean µ and s.d. σ has a mean that is also normally distributed with mean µ and s.d. σ/√n.

The mean stays the same, µ = 74.0, but now the s.d. is σ/√n = σ/5 = 2.5. So we have

P(70 < Y < 78) = P((70 - µ)/(σ/5) < (Y - µ)/(σ/5) < (78 - µ)/(σ/5))

… = P(-1.6 < Z < 1.6)

… = P(Z < 1.6) - P(Z < -1.6)

… ≈ 0.9452 - 0.0548

… ≈ 0.8904

Answer:

9

Step-by-step explanation:

9

9x9 = 81

Therefore, 81 ÷ 9 is 9

Answer:

x is vertical *laying down* y in upward also (x,y) so ifthe first on would be anywhere on the y axis

Answer:

x =30/19 and y =2/19

Step-by-step explanation:

5x + y = 8

x + 4y = 2

then

5x + y = 8

-5(x +4y =2)

5x + y = 8

-5x - 20y = - 10

0 +y - 20y = -2

- 19y = -2

y = 2/19 then

5x + 2/19 = 8

5x = 152-2/19

5x/5 =150/19 *1/5

x =30/19

Answer:

No solution

Step-by-step explanation:

The given equations are :

9x-3y=-6

3x-y=2.....(1)

5y=15x+10

5y-15x=10

or

y-3x=2 .....(2)

Equations (1) and (2) shows that the lines are parallel. We know that for parallel lines, there is no solution.

Answer:

The correct answer is "$5000".

Step-by-step explanation:

The given values are:

Two investments totaling,

= $47,500

Annual income,

= $3000

One investment yields per year,

= 9%

Other yield,

= 6%

Let,

Now,

⇒  [tex]0.09x+0.06(47,500-x)=3000[/tex]

⇒        [tex]0.09x+2850-0.06x=3000[/tex]

⇒                     [tex]0.03x+2850=3000[/tex]

⇒                                [tex]0.03x=150[/tex]

⇒                                       [tex]x=\frac{150}{0.03}[/tex]

⇒                                       [tex]x=5000[/tex]

9514 1404 393

Answer:

  (x, y) = ((√2)/2, (√2)/2))

Step-by-step explanation:

See the attached chart. The 45° angle can be found in the upper-right portion of the chart (1st quadrant).

Answer:

C

Step-by-step explanation:

The surface area can be found through the formula

SA=2A+(a+b+c)h

in this case, A is the area of the base, a and b are the legs, c is the base of the triangle, and h is the height. By substituting the values 25 and 25 for the legs and 14 for the base and 48 for the height, you will get 3408 sq cm.

9514 1404 393

Answer:

  5 ft

Step-by-step explanation:

You are given the area and base lengths of a trapezoid and asked for its height. The formula for the area of a trapezoid is useful.

  A = (1/2)(b1 +b2)h

Filling in the given information, you have ...

  30 ft² = (1/2)(4 ft +8 ft)h

  30 ft² = (6 ft)h . . . . . . . . . . . simplify

  h = (30 ft²)/(6 ft) = 5 ft . . . . divide by the coefficient of h

The height of the trapezoid is 5 feet.

Answer:

your answer will be 699.78 km

Step-by-step explanation:

Answer:

The correct answers 252 calories

Step-by-step explanation:

How I figured it out was by dividing 180 by 5, which gave me 36. Then 36(7) which equaled out to be 252.

Answer:

A) 12.24

Step-by-step explanation:

Mean absolute deviation: 65, 90, 85, 70, 70, 95, 55 = 12.244897959184

Answer:

75.7

Step-by-step explanation:

Answer:

There were 200 passengers on the plane.

Step-by-step explanation:

1. 3/10  of the passengers were children -> 30% of the passengers were children

2. 60 children on the flight 30% of passengers = 60 people

divide by 3 -> 10% of passengers = 20 people

multiply by 10 -> 100% of passengers = 200 people.

Answer:

[tex]y = 56.6208[/tex]

Step-by-step explanation:

Given

The attached triangle

Required

Find y

To find y, we make use of the relationship between sides lengths 44 & y and angle 39

The relationship is:

[tex]cos(39) = \frac{44}{y}[/tex]

i.e.

[tex]cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]

Make y the subject

[tex]y = \frac{44}{cos(39)}[/tex]

[tex]y = \frac{44}{0.7771}[/tex]

[tex]y = 56.6208[/tex] -- approximated

Given:

The matrix equation is:

[tex]\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}[/tex]

To find:

The value of matrix C.

Solution:

Let [tex]A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}[/tex]. Then the given equation can be rewritten as

[tex]A-C=B[/tex]

[tex]-C=B-A[/tex]

[tex]C=-(B-A)[/tex]

[tex]C=A-B[/tex]

On substituting the values of the matrices, we get

[tex]C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}[/tex]

[tex]C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}[/tex]

[tex]C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}[/tex]

[tex]C=\begin{bmatrix}-4&2&-7\end{bmatrix}[/tex]

Therefore, the correct option is C.

Answer: C

Step-by-step explanation: [ 4 2 -7 ]

Answer:

14

Step-by-step explanation:

hope it helps!

Answer:

857

Step-by-step explanation:

70th term = a + d(n-1)

d= 29-17=12

a=29

n-1 = 69

70th term = 29 + 12×69

= 29 + 828

= 857