What is the mass of 8.83 x 10^23 formula units of Iron (III) oxide, Fe2O3?

Answer:

Avogadro's Law; 15.1L

Explanation:

Boyle's Law- Pressure and volume are inversely related, so an increase in pressure= decrease in volume. We see this in the equation P1V1=P2V2.

Charle's Law- Gas expands/increases in volume when temperature increases, so they are proportional. We see this in the formula [tex]\frac{V1}{T1} = \frac{V2}{T2}[/tex].

Guy-Lussac's Law-  As temperature increases, pressure increases, so they are proportional. We see this in the formula [tex]\frac{P1}{T1} = \frac{P2}{T2}[/tex].

Avogadro's Law- There are equal amount of volume have an equal amount of moles, so they are proportional. We see this in the formula [tex]\frac{V1}{n1} = \frac{V2}{n2}[/tex].

Plugging in the values based on Avogadro's Law, we'll have:

[tex]\frac{36.5}{2.9} = \frac{V2}{1.2}[/tex]

12.6 = [tex]\frac{V2}{1.2}[/tex]

12.6 x 1.2 = V2

15.1L =V2

Answer:

41.8 g of water.

Explanation:

To solve this, we introduce the concept of mol.

1 mol of anything contains 6.02×10²³ particles.

In this case, we talk about molecules of water.

Molecular weigh is 18 g/mol which indicates that 1 mol of water weighs 18 g.

So let's do the conversion

(18 g of water / 6.02×10²³ 1 mol of molecules) . 1.4×10²⁴ molecules = 41.8 g

Answer:

I think b

Explanation:

50 moles of ammonia gas are produced in the following reaction if 25 moles of nitrogen gas reacts with hydrogen. Therefore, the correct option is option C.

In the National System of Units, the mole represents the unit of substance amount. However many elementary units of a particular substance are present inside an object as well as sample is determined by the quantity of that material. There are precisely  6.022×10²³ elementary entities in a mole.

An elementary object may include an atom, any molecule, and ion, an ion pair, or perhaps a subatomic particle like an electron depending upon what the substance is. 

N[tex]_2[/tex](g) + 3H[tex]_2[/tex](g). → 2NH[tex]_3[/tex](g)

moles of nitrogen = 25 moles

the  mole ratio between nitrogen and ammonia is 1:2

moles of nitrogen = 25×2=50 moles

Therefore, the correct option is option C.

To know more about moles, here:

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Answer:

2260 J

Explanation:

For water at its boiling point of 100 ºC, the heat of vaporization is 2260 J g-1. This means that to convert 1 g of water at 100 ºC to 1 g of steam at 100 ºC, 2260 J of heat must be absorbed by the water.

Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we're finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

We have

[tex]P_2 = \frac{6.4 \times 0.87}{20.5} = \frac{5.568}{20.5} \\ = 0.2716.... \\ \\ = 0.27 \: \: \: atm[/tex]

But

1 atm = 14.7 psi

Then 0.27 atm =

[tex] \frac{14.7 \times 0.27}{1} = 3.969 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

3.97 psi

Explanation:

Answer:

Liquid water is held together by hydrogen bonds. (Liquid water has fewer hydrogen bonds than ice.) Oils and fats not have any polar part and so for them to dissolve in water they would have to break some of water's hydrogen bonds. Water will not do this so the oil is forced to stay separate from the water.

Answer:

mi no speak espanol

Explanation:

Answer: The pressure is 2.14 atm if the gas was heated to 373 K and the volume decreased to 1.90 L.

Explanation:

Given: [tex]V_{1} = 2.50 L[/tex],      [tex]P_{1} = 1.34 atm[/tex],       [tex]T_{1} = 308 K[/tex]

[tex]P_{2} = ?[/tex] ,            [tex]V_{2} = 1.90 L[/tex],          [tex]T_{1} = 373 K[/tex]

Formula used to calculate the final pressure is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.34 atm \times 2.50 L}{308 K} = \frac{P_{2} \times 1.90 L}{373 K}\\P_{2} = \frac{1.34 atm \times 2.50 L \times 373}{308 K \times 1.90 L}\\= 2.14 atm[/tex]

Thus, we can conclude that the pressure is 2.14 atm if the gas was heated to 373 K and the volume decreased to 1.90 L.

Answer:

Explanation:

The mass of the sun is about 1.98 x 10^30 kilograms. The mass of the earth is 5.97x 10^24 kilograms.

1.98 x 10^30 / 5.97x 10^24 = 331658 times greater

Answer:

Explanation:

The mass of the sun / the mass of the earth

= 1.98 x 10^30 / 5.97x 10^24

= 3.32 x 10^5 times greater

Answer:

Average atomic mass = f1M1 + f2M2 +… + fnMn where f is the fraction representing the natural abundance of the isotope and M is the mass number (weight) of the isotope. The average atomic mass of an element can be found on the periodic table, typically under the elemental symbol.

Answer: An amount of [tex]40980.48 J/g^{o}C[/tex] heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Explanation:

Given: mass of lead = 4.64 kg

Convert kg into grams as follows.

[tex]1 kg = 1000 g\\4.64 kg = 4.64 kg \times \frac{1000 g}{1 kg}\\= 4640 g[/tex]

[tex]T_{1} = 150^{o}C[/tex]

[tex]T_{2} = 219^{o}C[/tex]

The standard value of specific heat of lead is [tex]0.128 J/g^{o}C[/tex].

Formula used to calculate heat is as follows.

[tex]q = m \times C \times \Delta T[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat of substance

[tex]\Delta T[/tex] = change in temperature

Substitute the value into above formula as follows.

[tex]q = m \times C \times \Delta T\\= 4640 g \times 0.128 J/g^{o}C \times (219 - 150)^{o}C\\= 40980.48 J/g^{o}C[/tex]

Thus, we can conclude that [tex]40980.48 J/g^{o}C[/tex] heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Answer:

V=d/t

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Answer:

The interior of the Earth, like that of the other terrestrial planets, is chemically divided into layers. The Earth has an outer silicate solid crust, a highly viscous mantle, a liquid outer core that is much less viscous than the mantle, and a solid inner core.

Answer:

True; Water is stored in reservoirs.

What happen if your Adrenal Glands become overprotective of underproductive?

Answer: if your adrenals becomes overproductive it will lead to a health issue known as CUSHING'S SYNDROME while when they become underproductive it will lead to a health condition known as ADDISON'S DISEASE.

Explanation:

The adrenal glands are divided into two embryologically and functionally distinct parts: the adrenal cortex and adrenal medulla.

The adrenal cortex is part of the hypothalamic - pituitary - adrenal endocrine system. Morphologically, the adult adrenal cortex consists of three layers which include:

--> The outer thin layer: this is also called zona glomerulosa. It secrets only aldosterone.

--> The inner two layers: these comprises of the zona fasciculata and zona reticularis. They both form a functional unit and secrete most of the adrenocortical hormones.

The adrenal medulla is the inner part of the adrenal gland which secrets the adrenaline and noradrenaline hormones.thry take part in sympathetic nervous system.

When the adrenal glands become a OVERPRODUCTIVE, the adrenal cortex is highly affected. This may occur due to hyperstimulation of the adrenal gland by adrenocorticotrophic hormone,either from the pituitary gland or from an ectopic source or due to largely autonomous secretion by an adrenal tumor such as an adenoma or carcinoma. The increased endogenous cortisol production leads to a disorder known as CUSHING'S SYNDROME. The clinical and metabolic features include obesity, hyperglycaemia and hypertension.

Also when the adrenal glands become UNDERPRODUCTIVE, a health condition known as ADDISON'S DISEASE may occur. This is cause any the bilateral destruction of all zones of the adrenal cortex, usually as the result of an autoimmune process or mycotic infections. The resulting decrease in cortisol production may lead to clinical features such as hypotension, hypoglycemia, nausea and vomiting.

Answer:

La cantidad de energía disponible de una fuente de energía determinada se denomina recurso energético. La escasez de recursos energéticos (petróleo, carbón y madera) en algunas de las fuentes de energía más utilizadas plantear necesidad de usar otras fuentes investigar el modo más rentable de emplearlas

Explanation:

Answer:

false

Explanation:

its the amount of high-quality energy available from a given quantity of an energy resource minus the high-quality energy needed to make the energy available.

Answer:

The answer is "As [tex]Q=336[/tex], at high-temperature [tex]\Delta G_{rxn}>0[/tex] and When[tex]K>1,[/tex][tex]\Delta G^{\circ}_{rxn}>0[/tex]."

Explanation:

The equation for the reaction is:

[tex]A(g) \leftrightharpoons B(g)[/tex]  

[tex]K=5.8\\\\Q=336[/tex]

At equilibrium,

[tex]\Delta G^{\circ}_{rxn}>0[/tex][tex]=-RT \ln \ K[/tex]

When k=5.8(>1), the value of [tex]\ln k[/tex] would be positive

So, [tex]\Delta G^{\circ}_{rxn}[/tex] is negative (< 0)

So if K > l, [tex]\Delta G^{\circ}_{rxn}<0[/tex]

If the reaction is not in equilibrium so the equation is :

[tex]\Delta G_{rxn}>0[/tex]=[tex]\Delta G^{\circ}_{rxn}[/tex][tex]+RT \ln Q[/tex]

Substituting the expression:

[tex]\Delta G_{rxn}>0[/tex][tex]= (-RT \ln K) + RT \ln Q[/tex]

                 [tex]= RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)[/tex]

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature [tex]\Delta G_{rxn}>0[/tex].

Answer:

But there is nothing above

Answer:

The pressure of the gas at 323 degrees Celsius is 2 atm.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

[tex]\frac{P}{T} =k[/tex]

Where P = pressure, T = temperature, K = Constant

Having two different states, an initial state 1 and a final state 2, it is satisfied:

[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]

In this case:

Replacing:

[tex]\frac{1 atm}{298 K} =\frac{P2}{596 K}[/tex]

Solving:

[tex]P2=\frac{1 atm}{298 K}*596 K[/tex]

P2= 2 atm

The pressure of the gas at 323 degrees Celsius is 2 atm.

Answer: 18

Explanation:hope this help

When water is boiled, the heat energy is transferred to the molecules of water, which begin to move more quickly. Eventually, the molecules have too much energy to stay connected as a liquid. When this occurs, they form gaseous molecules of water vapor, which float to the surface as bubbles and travel into the air.

Answer:

Explanation:

The answer is 202

Answer:

Decreased change in temperature

Explanation:

Delta T signifies the temperature is changing, but by adding a negative, it specifies that it changes by decreasing.

Answer: There is 0.8 liters (L) of water required to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.5 M        

[tex]V_{1}[/tex] = 4800 mL

Convert mL into L as follows.

[tex]1 mL = 0.001 L\\4800 mL = 4800 mL \times \frac{0.001 L}{1 mL}\\= 4.8 L[/tex]

[tex]M_{2}[/tex] = 3 M

Formula used to calculate the volume of water required as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 4.8 L = 3 M \times V_{2}\\V_{2} = \frac{0.5 M \times 4.8 L}{3 M}\\= 0.8 L[/tex]

Thus, we can conclude that 0.8 liters (L) of water need to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

salt is not because it gets u dehydrated

Answer:

option d) is the correct answer

Answer:

The heat contained is 1236 Joules

Explanation:

As we know

[tex]Q = mc\Delta[/tex]T

Where

[tex]\Delta[/tex]T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

[tex]Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236[/tex]Joules