What is the probability of landing on a number on the spinner that is less than 3?

1/4
3/8
5/8
1/2

Answer:

There are no like terms.

Step-by-step explanation:

Answer:

.............soooooooooooooooerrrrrrrrrrrrryyyyyyyyyyyyyyy.......... iiiiiiiii........ doooooooonnnnnnnnntttttttt......... kkkknnnnnooooowwww

Answer:

4cm

Step-by-step explanation:

first find the length of the side of one square

the length of the rectangle will be twice the width

let y represent the width

area of a rectangle=length x width

2cm²=2yxy

2cm²=2y²

2cm²/2=2y²/2

1cm²=y²

1√cm²=√y²

1cm=y

perimeter of a square=4xside

4x1cm

4cm

Answer:

I think you mean significant figures

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

-14+15 leaves a positive 1

-11+20 leaves a positve 9

add.

Answer:

28 km per hour

Step-by-step explanation:

First determine the amount of time that the trip took

17:55 - 17:40 = :15 or 15 minutes

We need the time in hours

15 minutes * 1 hour/ 60 minutes = 15/60 hours = 1/4 hours

To determine speed, take distance and divide by time

7 km ÷( 1/4 hours)

Copy dot flip

7 * 4/1

28 km per hour

Answer:gotta go sorry

Step-by-step explanation:

Answer:

Part A

The volume of the triangular prism is 500 cm³

Part B

The total surface area of the prism is approximately 441.42 cm²

Step-by-step explanation:

The given details are;

The dimensions of the side length of the cube, s = 10 cm

The shape the cube was cut across to obtain = A prism

Part A

Whereby the prism obtained is a triangular prism, we have;

The cube can be cut in half to form a triangular prism

The volume of each triangular prism obtained = (1/2) × The volume of the cube

∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³

Part B

The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism

The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50

The square cross sectional area, A₂  = 10 × 10 = 100

The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2

The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃

∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42

The total surface area of the prism, A ≈ 441.42 cm²

Answer:

32ft

Step-by-step explanation:

Tan = opp/adj

Tan(65) = n / 15

Tan(65) x 15 = n

n = 32.16 = 32ft

Answer:

32 feet

Step-by-step explanation:

Hi there!

We are given a right triangle and the angle of elevation (one of the acute angles in the triangle) as 65°, as well as one of the legs (sides that make up the right triangle) as 15

We need to find the height of the triangle.

Let's make the height of the triangle (the side we need to find) x

Since we need to find the height of the triangle, let's use tangent. As we have the angle of elevation given, we'll use that.

Recall that tangent is [tex]\frac{opposite}{adjacent}[/tex]

in reference to the angle of elevation, the opposite side is x, and the adjacent side is 15

that means that:

tan(65)=[tex]\frac{x}{15}[/tex]

plug tan(65) into your calculator (make sure it's on degree mode!)

tan(65)≈2.14

2.14=[tex]\frac{x}{15}[/tex]

multiply both sides by 15 to clear the fraction

32.1=x

The problem asks us to round to the nearest foot, so the height of the building is 32 feet

Hope this helps! :)

Answer:

[tex]\theta = \frac{\pi}{6}[/tex]

Step-by-step explanation:

[tex]tan^ 2 \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) tan \theta + 1 = 0\\\\tan \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) +\frac{1}{ tan \theta } = 0\\\\[/tex]          [tex][ \ divide \ by \ tan \theta \ on \ both \ sides \ ][/tex]

[tex]tan\theta + \frac{1}{ tan \theta }- ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{tan^2 \theta + 1}{ tan \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{sec ^2 \theta}{ \frac{sin \theta }{cos \theta}} - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0[/tex]              [tex][ \tan ^ 2\theta + 1 = sec ^2 \theta \ , \ tan \theta = \frac{sin \theta }{cos \theta } \ ][/tex]

[tex]\frac{sec^2 \theta }{sin \theta \times sec \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]                  [tex][\ \frac{sin \theta }{cos \theta } = sin \theta \times sec \theta \ ][/tex]

[tex]\frac{sec \theta }{sin \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]

[tex]sec \theta \ cosec \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]              [tex][ \ \frac{1}{sin \theta } = cosec \theta \ , \ \frac{ sec \theta }{sin \theta } = sec \theta cosec \theta \ ][/tex]

[tex]sec \theta \ cosec \theta - \sqrt 3 - \frac{1}{\sqrt3}} = 0\\\\\frac{\sqrt 3\ sec \theta \ cosec \theta - 3 - 1}{\sqrt3} = 0\\\\\sqrt 3 sec \theta cosec \theta - 4 = 0\\\\[/tex]              

[tex]\sqrt3 \frac{1}{cos \theta } \frac{1}{sin \theta } - 4 = 0\\\\\frac{\sqrt3 - 4sin \theta cos \theta} { sin \theta cos \theta } = 0[/tex]                      

[tex]\sqrt 3 - 2sin 2\theta = 0[/tex]                                  [tex][ \ sin 2 \theta = 2 sin \theta cos \theta \ ][/tex]

[tex]2sin 2 \theta = \sqrt3\\\\sin 2 \theta = \frac{\sqrt3 }{2} \\\\2 \theta = sin^{-1} (\frac{\sqrt3}{2})\\\\2 \theta = 60^{ \circ} = \frac{ \pi}{3}\\\\\theta = \frac{\pi} {6}[/tex]

Answer:

complete the square 2 x + 38 = 0

Step-by-step explanation:

Answer:

to do this lets first solve this so

5*5*5*5=625

5^-3=0.008

0.008^2=0.000064

0.000064*625=0.4

so all equations that are equal to 0.4 are right which is C

Answer: The answer is the diameter.

Step-by-step explanation:

Answer:

diameter

Step-by-step explanation:

the diameter goes straight through the center of the circle

Answer:

B) 376 units squared

Step-by-step explanation:

Imma put a picture that has a fully explanation. Hope this helps, good luck! ;)

Btw saw your other one got deleted •_• *sigh*

Answer:

A pair of linear functions

Step-by-step explanation:

Given

See comment for options

Required

Which has real numbers as its range and domain

The answer to this is, the linear functions

Take for instance

[tex]f(x) = mx + b[/tex]

The above function is real for all values of x

The inverse is calculated as thus:

[tex]f(x) = mx + b[/tex]

Replace f(x) with y

[tex]y = mx + b[/tex]

Swap y and x

[tex]x = my + b[/tex]

Make y the subject

[tex]my = x - b[/tex]

Divide by m

[tex]y = \frac{x - b}{m}[/tex]

Replace y with the inverse function

[tex]f^{-1}(x) = \frac{x - b}{m}[/tex]

The above function (i.e. the inverse function) is real for all values of x

This is not true for other options

Answer:

3.5

Step-by-step explanation:

It's technically 3.69 but 3.5 is the closest answer you can get

Answer:

Range: 0.07

Median: 0.145

Mode: none

Step-by-step explanation:

Range: largest #- smallest #

Median: middle number (when numbers are in order least to greatest) or when two are middle number you add them, and divide by two

Mode: most occurring number(s) (if there aren't any, no mode)—but if there are multiples such as 2 zeros and 2 ones then 0 and 1 would be the mode

Answer:

6 6 6 6 11

Step-by-step explanation:

The median is the middle number

the mode is the number of items, usually the number that are the same.

the mean is the average

the range is the number between the smallest and the largest.

So the information you have makes 4 of the 5 numbers the same.

The middle number is 6. This is an interesting fact because it means that 4 of the five numbers are 6

x 6 6 6 6  or  6 6 6 6 x  is what you know so far.

The range is a bit of a devil. And so is the mean. We need the mean to be related to  5*7 = 35. So the sum of the five numbers equals 35. The range would have to be 5, I think. (35 - 4*6) = 11

The difference between 11 and 6 = 5

So 11 works for everything but the range.

If the range must be ten, then x = 16 but then the mean = 8 and 7  is incorrect

So I can get 3 out of 4, but not them all.

Answer:

its either B or D.

Step-by-step explanation:

could you mark me brainliest pls or even hit the thanks button

Answer:

is there a pic to go along? i need more to this..

Answer:

45kg

Step-by-step explanation:

60.3/4=45

Answer:

it's called the horizontal line

Step-by-step explanation:

also known as y=0

Answer:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots.

Step-by-step explanation:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots. The true factorized form of the fourth grade polynomial is:

[tex]r(x) = (x^{2}+1)\cdot (x^{2}-9)[/tex]

[tex]r(x) = (x- i)\cdot (x+i)\cdot (x+3)\cdot (x-3)[/tex]