What is the probability that a point would be in the blue region? Triangle area=bh/2

Answer:

it is not clear .... please add the question and send the link of the question

Answer:

$712.79

Step-by-step explanation:

Answer:

+

Step-by-step explanation:

b/c

18+2×4

18+8

26

hope it's helpful ❤❤❤

THANK YOU.

Answer:

b

Step-by-step explanation:

Answer:

[tex]\dfrac{w}{z}=\dfrac{2}{7}[/tex]

Step-by-step explanation:

Given that,

[tex]w=\dfrac{6}{7}[/tex]

z = 3

We need to find [tex]\dfrac{w}{z}[/tex].

Put w = 6/7 and z = 3 in the w/z

[tex]\dfrac{w}{z}=\dfrac{\dfrac{6}{7}}{3}\\\\=\dfrac{6}{7}\cdot\dfrac{1}{3}\\\\=\dfrac{2}{7}[/tex]

So, [tex]\dfrac{w}{z}=\dfrac{2}{7}[/tex]. Hence, the correct answer is 2/7.

Answer:

b.

Step-by-step explanation:

1. You have the following parent function given in the problem above:

f(x)=x³ (This is the simplest form. We need to translate it 3 units left and 2 units down)

2. If you take the parent function and make y=f(x+3), then you have:

(The function is shifted 3 units left on the x-axis).

3. Then you if you make y=f(x+3)-2, as following, you obtain:

(The function is shifted 2 units down on the y-axis).

4. Therefore, that is how you obtain the final function.

The answer is the graph shown in .b

[tex]16 - 3 \times 5 {}^{2} \div 5[/tex]

[tex]16 - 3 \times 5 {}^{2} \div 5 {}^{1} [/tex]

[tex]16 - 3 \times 5 {}^{2} \div 5 {}^{ - 1} [/tex]

[tex]16 - 3 \times 5 {}^{2 - 1} [/tex]

[tex]16 - 3 \times 5 {}^{1} [/tex]

[tex]16 - 3 \times 5[/tex]

[tex]16 - 15[/tex]

[tex]1[/tex]

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Answer:

3) 21/60= 0.35

4) 5/4= 1.25

5) 9/15= 0.6 or 2/3

6) 378/15= 25.2 or 25 and 1/5

7) 1 1/2/ 2/3= 2.5

8) 28 1/3 / 3 1/3= 8.5

Step-by-step explanation:

hope this helps!

mark me brainliest please!

Step-by-step explanation:

[tex]x ^{1} = - 5 \\ y ^{1} = - 2 \\ x {}^{2} = - 2 \\ y {}^{2} = 1 \\ then \: you \: solve \: with \: that \: formula \: you \: know[/tex]

Answer:

70-25=45

45+25=70

Step-by-step explanation:

Answer:

a)  f(5) = 24

b) The inverse of given function

              f⁻¹ ( x ) = √x+1

c)    f⁻¹ ( 8 ) = √9 =3

Step-by-step explanation:

Explanation:-

Given  f(x) = x² - 1

a)

      f(5) = 5² -1 = 25-1 =24

b)      

put y =  f(x) = x² - 1

   ⇒   y =  x² - 1

 ⇒     x² = y + 1

⇒     x = √y+1

⇒ f⁻¹ ( y ) = √y+1      ( ∵ f⁻¹ ( y) =x)

The inverse of given function

              f⁻¹ ( x ) = √x+1

c)   put x=8

             f⁻¹ ( 8 ) = √8+1 = √9 =3

Answer:

-1.25, -1.5, 0.5, 0.66

hope it helps you

Answer:

29.8÷3=9.93333333333

Step-by-step explanation:

*note* the 3 is a repeating number

Answer:

Step-by-step explanation:

1/6 x 1/5 + 1/30

= 1/30 + 1/30

= 2/30

=1/15

Answer:

17 units

Step-by-step explanation:

Use distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], to find the distance between (-9, 5) and (8, 5):

Let,

[tex] (x_1, y_1) = (-9, 5) [/tex]

[tex] (x_2, y_2) = (8, 5) [/tex]

Plug in the values into the distance formula:

[tex] d = \sqrt{(8 - (-9))^2 + (5 - 5)^2} [/tex]

[tex] d = \sqrt{(17)^2 + (0)^2} [/tex]

[tex] d = \sqrt{(289 + 0)} [/tex]

[tex] d = \sqrt{289} [/tex]

[tex] d = 17 [/tex]

Answer:

-3/4

Step-by-step explanation:

-1 1/4 = -5/4

1/2 = 2/4

-5 + 2 = -3

-3/4

Answer: The answer is -3/4

Step-by-step explanation: covert the mixed numbers to improper fractions, then find the LCD and combine.

Let the two number is a and b

so,

product =ab=20

sum of square=[tex]\bold{a^2+b^2=41 }[/tex]

Then,

[tex]\bold{(a+b)^2=a^2+b^2+2ab }[/tex]

[tex]\bold{ (a+b)^2=41+2×40 }[/tex]

[tex]\bold{ (a+b)^2=81 }[/tex]

[tex]\bold{a+b=\sqrt{81} }[/tex]

[tex]\bold{a+b=9 }[/tex]•••••••••(equation I)

Now,

[tex]\bold{(a-b)^2=a^2+b^2-4ab }[/tex]

[tex]\bold{ (a-b)^2=41-4×20 }[/tex]

[tex]\bold{(a-b)^2=41-40 }[/tex]

[tex]\bold{a-b=\sqrt{1} }[/tex]

[tex]\bold{a-b=1 }[/tex]••••••••(equation II)

Now,combine the equation I and equation II

we,get

[tex]\bold{a+b+a-b=9+1 }[/tex]

[tex]\bold{a+\cancel{b}+a\cancel{-b}=10 }[/tex]

[tex]\bold{ 2a=10 }[/tex]

[tex]\bold{a=\dfrac{10}{2} }[/tex]

[tex]\blue{\boxed{ a=5 }}[/tex]

Then,

put the value of a in equation II.

we get that,

[tex]\bold{5-b=1 }[/tex]

[tex]\bold{b+1=5 }[/tex]

[tex]\bold{b=5-1 }[/tex]

[tex]\bold{\boxed{\blue{b=4}} }[/tex]

so,

The two number is 5 and 4.

Answer:

i believe the answer is C

Step-by-step explanation:

Answer:

p=5x+3y

solve for x, number of cupcakes. isolate x

5x=p-3y

divide by 5

x=(p-3y)/5

Step-by-step explanation:

D. x<15

Answer: 22

Step-by-step explanation:

Solve for x

   1/2x + 7 = 18

Combine 1/2 and x.

  x/2+ 7 = 18

Move all terms not containing x to the right side of the equation.

Subtract 7 from both sides of the equation.

  x/2= 18 − 7

  x/2 = 11

Multiply both sides of the equation by 2.

  2 ⋅ x/2 = 2 ⋅ 11

Simplify both sides of the equation.

Cancel the common factor of 2.

  x = 2 ⋅ 11

Multiply 2 by 11.

  x = 22

Answer:

4/1

Step-by-step explanation:

g is 4

Answer:

Graph ii and iii

Step-by-step explanation:

In graph ii and iii, every input has one and only output. Another way to check is by doing the vertical line test.

Answer:

0.1402

Step-by-step explanation:

For each baby elk, there are only two possible outcomes. Either they survive adulthood, or they do not survive. The probability of an elk surviving adulthood is independent of other elks. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Biologists estimate that a randomly selected baby elk has a 44% chance of surviving to adulthood.

This means that [tex]p = 0.44[/tex]

Suppose researchers choose 7 baby elk at random to monitor.

This means that [tex]n = 7[/tex]

What is the probability that more than 4 elk in the sample to survive to adulthood?

This is:

[tex]P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 5) = C_{7,5}.(0.44)^{5}.(0.56)^{2} = 0.1086[/tex]

[tex]P(X = 6) = C_{7,6}.(0.44)^{6}.(0.56)^{1} = 0.0284[/tex]

[tex]P(X = 7) = C_{7,7}.(0.44)^{7}.(0.56)^{0} = 0.0032[/tex]

[tex]P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) = 0.1086 + 0.0284 + 0.0032 = 0.1402[/tex]

0.1402 probability that more than 4 elk in the sample to survive to adulthood.

Using the concept of binomial probability, the probability that more than 4 survive is 0.1402

Using the binomial probability formula :

The probability that more than 4 survive can be defined thus :

Using a binomial probability calculator :

[tex] P(x > 4) = 0.1086 + 0.0284 + 0.0032 [/tex]

[tex] P(x > 4) = 0.1402 [/tex]

Hence, the probability that more than 4 survive is 0.1402

Learn more : https://brainly.com/question/15929089

Answer:

angle JKL is 21

Step-by-step explanation:

the angle of the two triangles are the same, so (2x + 1) = (3x - 9)

You would then find the x, which equals to 10.

Then replace x with ten with the equation.

Answer:

yeah I would say deal #1 is better

Answer:  30

Step-by-step explanation:

Answer: 829 3/4 or 829 75/100

Step-by-step explanation:

Answer:

304

Step-by-step explanation:

The area of the square is 12 x 8 = 96.

There are two triangles with area (11x8)/2=44. 44x2=88.

There are two triangles with area (10x12)/2=60. 60x2=120.

96+88+120=304

Hope I helped!

Answer:

34

Step-by-step explanation:

Answer:

Area of rectangle =LXB

L=7m

B=3m

so 7m multiply by 3m gives 21 so the area is 21

Answer:

Proved all parts below.

Step-by-step explanation:

As given ,

|x| = [tex]\left \{ {{x , x\geq 0} \atop {-x, x< 0}} \right.[/tex]

To prove- a) For any real number x , | x | ≥ 0 . Moreover, | x | = 0 ⇒ x = 0

                 b) For any two real numbers x and y , | x | ⋅ | y | = | x y | .

                 c) For any two real numbers x and y , | x + y | ≤ | x | + | y | .

Proof -

a)

As given x is a real number

Also , by definition of absolute value of x , we get

| x | ≥ 0

Now,

if |x| = 0

⇒ x = 0 and -x = 0

⇒ x = 0 and x = 0

⇒ x = 0

∴ we get

| x | = 0 ⇒  x = 0

Hence proved.

b)

To prove - | x | ⋅ | y | = | x y |

As we have,

|x| = [tex]\left \{ {{x , x\geq 0} \atop {-x, x< 0}} \right.[/tex]

|y| = [tex]\left \{ {{y , y\geq 0} \atop {-y, y< 0}} \right.[/tex]

|xy| = [tex]\left \{ {{xy , x,y > 0 and x,y < 0} \atop {-xy, x > 0, y< 0 and x <0 , y > 0}} \right.[/tex]

We have 4 cases : i)  when x > 0 , y > 0

                              ii) when x > 0 , y < 0

                              iii) when x < 0, y > 0

                              iv) when x < 0, y < 0

For Case I - when x > 0 , y > 0

⇒ |x| = x, |y| = y

⇒|x|.|y| = xy

For Case Ii - when x > 0 , y < 0

⇒ |x| = x, |y| = -y

⇒|x|.|y| = -xy

For Case Iii - when x < 0 , y > 0

⇒ |x| = -x, |y| = y

⇒|x|.|y| = -xy

For Case IV - when x < 0 , y < 0

⇒ |x| = -x, |y| = -y

⇒|x|.|y| = (-x)(-y) = xy

∴ we get , from all 4 cases

| x | ⋅ | y | = | x y |

Hence Proved.

c)

To prove - | x + y | ≤ | x | + | y |

Let

|x| = |x + y - y|

    ≥ |x + y| - |y|     ( Triangle inequality)

⇒ |x| + |y| ≥ |x + y|

Hence Proved.