what is the process by which we can control what parts of a program can acccess the members of class

Answers

Answer 1

Answer:

Encapsulation.

Explanation:

Information hiding involves using private fields within classes and it's a feature found in all object-oriented languages such as Java, Python, C#, Ruby etc.

In object-oriented programming language, a process known as encapsulation is used for the restrictions of the internal data of a software program from the outside code, therefore preventing an unauthorized direct access to the codes. This is achieved through the use of classes.

In Computer programming, class members can be defined as the members of a class that typically represents or indicates the behavior and data contained in a class.

Basically, the members of a class are declared in a class, as well as all classes in its inheritance hierarchy except for destructors and constructors.

In a class, member variables are mainly known as its attributes while its member function are seldomly referred to as its methods or behaviors.

One of the main benefits and importance of using classes is that classes helps to protect and safely guard their member variables and methods by controlling access from other objects.

Therefore, the class members which should be declared as public are methods and occasionally final attributes because a public access modifier can be accessed from anywhere such as within the current or external assembly, as there are no restrictions on its access.


Related Questions

The menu bar display information about your connection process, notifies you when you connect to another website, and identifies the percentage information transferred from the Website server to your browser true or false

Answers

Answer:

false

Explanation:

My teacher quized me on this

Give one example of where augmented reality is used​

Answers

Augmented reality is used during Construction and Maintenance

Service manuals with interactive 3D animations and other instructions can be displayed in the physical environment via augmented reality technology.
Augmented reality can help provide remote assistance to customers as they repair or complete maintenance procedures on products.

Answer

Medical Training

From operating MRI equipment to performing complex surgeries, AR tech holds the potential to boost the depth and effectiveness of medical training in many areas. Students at the Cleveland Clinic at Case Western Reserve University, for example, will now learn anatomy utilizing an AR headset allowing them to delve into the human body in an interactive 3D format.

it is also use in retail ,. Repair & Maintenance,Design & Modeling,Business Logistics etc

Create a function, return type: char parameters: int *, int * Inside the function, ask for two integers. Set the user responses to the int * parameters. Prompt the user for a character. Get their response as a single character and return that from the function. In main Define three variables and call your function. Print values of your variables

Answers

Answer and Explanation:

In C programming language:

char fun(int*a, int*b){

printf("enter two integers: ");

scanf("%d%d",a,b);

int e;

printf("please enter a character: ");

e=getchar();

return e;

}

int main(int argc, char *argv[]) {

int d;

int f;

int g;

fun();

printf("%d%d%d", d, f, g);

}

We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.

Consider a DataFrame named df with columns named P2010, P2011, P2012, P2013, 2014 and P2015 containing float values. We want to use the apply method to get a new DataFrame named result_df with a new column AVG. The AVG column should average the float values across P2010 to P2015. The apply method should also remove the 6 original columns (P2010 to P2015). For that, what should be the value of x and y in the given code?

Answers

Answer:

x = 1

y = 1

Explanation:

The apply method has the axis argument which enables it to use the applied function either across the rows or columns, by passing the value 1 to the axis argument, the mean of at each index is calculated, (across the column) such that the length of the AVG column is equal to the lengtb of the original dataframe.

The drop method is used in pandas to remove row or column entry from a dataframe. To remove columns from a data table, the value 1 is passed to the axis argument of the drop method. Hence, passing 1 to the axis argument removes all 6 columns leaving only the AVG column in result_df.

2. A computer that is easy to operate is called
I
10 POINTSSSS PLEASEEE HELPPP

DIT QUESTION

Answers

Answer:

Explanation:

A computer that is easy to operate is called User Friendly

Components of micro computer with diagram

Answers

Answer:

CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator.

Explanation:

There are six basic components of a microcomputer which includes CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator. CPU is the central processing unit which is considered as the brain of the computer. It is the part of a computer that executes instructions. Data memory is the place where data is stored that is present in the CPU.

During the testing phase of an ERP system, the system implementation assurers should review: Group of answer choices Program change requests Vendor contracts Error reports Configuration design specifications

Answers

Answer:

Error reports

Explanation:

ERP is a multimodal software system that integrates all business processes and the function's of the entire organizations into  single software system using a one database.

We canconnect  two or more computer together using cables true or false​

Answers

This is true for most modern computers

Develop a program that will maintain an ordered linked list of positive whole numbers. Your program will provide for the following options: a. Add a number b. Delete a number c. Search for a number d. Display the whole list of numbers At all times, the program will keep the list ordered (the smallest number first and the largest number last).

Answers

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

Discuss the OSI Layer protocols application in Mobile Computing

Answers

Answer:

The OSI Model (Open Systems Interconnection Model) is a conceptual framework used to describe the functions of a networking system. The OSI model characterizes computing functions into a universal set of rules and requirements in order to support interoperability between different products and software.

In database a record is also called a

Answers

Explanation:

hope it helps you

pls mark this ans brainlist ans

you get a call from a customer who says she can't access your site with her username and password. both are case-sensitive and you have verified she is entering what she remembers to be her user and password correctly. what should you do to resolve this problem?

a. have the customer clear her browser history and retry

b. look up her username and password, and inform her of the correct information over the phone

c. have the user reboot her system and attempt to enter her password again

d. reset the password and have her check her email account to verify she has the information

Answers

Answer:

answer would be D. I do customer service and would never give information over the phone always give a solution

In order to resolve this problem correctly, you should: D. reset the password and have her check her email account to verify she has the information.

Cybersecurity can be defined as a group of preventive practice that are adopted for the protection of computers, software applications (programs), servers, networks, and data from unauthorized access, attack, potential theft, or damage, through the use of the following;

Processes.A body of technology.Policies.Network engineers.Frameworks.

For web assistance, the security standard and policy which must be adopted to enhance data integrity, secure (protect) data and mitigate any unauthorized access or usage of a user's sensitive information such as username and password, by a hacker, is to ensure the information is shared discreetly with the user but not over the phone (call).

In this context, the most appropriate thing to do would be resetting the password and have the customer check her email account to verify she has the information.

Read more: https://brainly.com/question/24112967

Discuss the DMA process​

Answers

Answer:

Direct memory access (DMA) is a process that allows an input/output (I/O) device to send or receive data directly to or from the main memory, bypassing the CPU to speed up memory operations and this process is managed by a chip known as a DMA controller (DMAC).

Explanation:

A defined portion of memory is used to send data directly from a peripheral to the motherboard without involving the microprocessor, so that the process does not interfere with overall computer operation.

In older computers, four DMA channels were numbered 0, 1, 2 and 3. When the 16-bit industry standard architecture (ISA) expansion bus was introduced, channels 5, 6 and 7 were added.

ISA was a computer bus standard for IBM-compatible computers, allowing a device to initiate transactions (bus mastering) at a quicker speed. The ISA DMA controller has 8 DMA channels, each one of which associated with a 16-bit address and count registers.

ISA has since been replaced by accelerated graphics port (AGP) and peripheral component interconnect (PCI) expansion cards, which are much faster. Each DMA transfers approximately 2 MB of data per second.

A computer's system resource tools are used for communication between hardware and software. The four types of system resources are:

   I/O addresses    Memory addresses.    Interrupt request numbers (IRQ).    Direct memory access (DMA) channels.

DMA channels are used to communicate data between the peripheral device and the system memory. All four system resources rely on certain lines on a bus. Some lines on the bus are used for IRQs, some for addresses (the I/O addresses and the memory address) and some for DMA channels.

A DMA channel enables a device to transfer data without exposing the CPU to a work overload. Without the DMA channels, the CPU copies every piece of data using a peripheral bus from the I/O device. Using a peripheral bus occupies the CPU during the read/write process and does not allow other work to be performed until the operation is completed.

With DMA, the CPU can process other tasks while data transfer is being performed. The transfer of data is first initiated by the CPU. The data block can be transferred to and from memory by the DMAC in three ways.

In burst mode, the system bus is released only after the data transfer is completed. In cycle stealing mode, during the transfer of data between the DMA channel and I/O device, the system bus is relinquished for a few clock cycles so that the CPU can perform other tasks. When the data transfer is complete, the CPU receives an interrupt request from the DMA controller. In transparent mode, the DMAC can take charge of the system bus only when it is not required by the processor.

However, using a DMA controller might cause cache coherency problems. The data stored in RAM accessed by the DMA controller may not be updated with the correct cache data if the CPU is using external memory.

Solutions include flushing cache lines before starting outgoing DMA transfers, or performing a cache invalidation on incoming DMA transfers when external writes are signaled to the cache controller.

Answer:

See explanation

Explanation:

DMA [tex]\to[/tex] Direct Memory Access.

The peripherals of a computer system are always in need to communicate with the main memory; it is the duty of the DMA to allow these peripherals to transfer data to and from the memory.

The first step is that the processor starts the DMA controller, then the peripheral is prepared to send or receive the data; lastly, the DMA sends signal when the peripheral is ready to carry out its operation.

Create a python program that display this
Factorial Calculator
Enter a positive integer: 5
5! = 1 x 2 x 3 x 4 x 5
The factorial of 5 is: 120
Enter a positive integer: 4
4! = 1 x 2 x 5 x 4
.
The factorial of 4 is: 24
Enter a positive integer: -5
Invalid input! Program stopped!​

Answers

Answer:

vxxgxfufjdfhgffghgfghgffh

As the first step, load the dataset from airline-safety.csv by defining the load_data function below. Have this function return the following (in order):
1. The entire data frame
2. Total number of rows
3. Total number of columns
def load_data():
# YOUR CODE HERE
df, num_rows, num_cols

Answers

Answer:

import pandas as pd

def load_data():

df = pd.read_csv("airline-safety.csv')

num_rows = df.shape[0]

num_cols = df.shape[1]

return df, num_rows, num_cols

Explanation:

Using the pandas python package.

We import the package using the import keyword as pd and we call the pandas methods using the dot(.) notation

pd.read_csv reads the csv data into df variable.

To access the shape of the data which is returned as an array in the format[number of rows, number of columns]

That is ; a data frame with a shape value of [10, 10] has 10 rows and 10 columns.

To access the value of arrays we use square brackets. With values starting with an index of 0 and so on.

The row value is assigned to the variable num_rows and column value assigned to num_cols

a. Download the attached �Greetings.java� file.
b. Implement the �getGreetings� method, so that the code prompts the user to enter the first name, the last name, and year of birth, then it returns a greetings message in proper format (see the example below). The �main� method will then print it out. Here is an example dialogue with the user:
Please enter your first name: tom
Please enter your last name: cruise
Please enter your year of birth: 1962
Greetings, T. Cruise! You are about 50 years old.
Note that the greetings message need to be in the exact format as shown above (for example, use the initial of the first name and the first letter of the last name with capitalization).
c. Submit the final �Greetings.java� file (DO NOT change the file name) online.

Answers

Answer:

Code:

import java.util.*;  

public class Greetings  

{  

   public static void main(String[] args)  

   {        

       Scanner s = new Scanner(System.in);  

       System.out.println(getGreetings(s));  

   }  

   private static String getGreetings(Scanner console)  

   {          

   System.out.print("Please enter your first name: ");  

   String firstName=console.next();    

   char firstChar=firstName.toUpperCase().charAt(0);  

   System.out.print("Please enter your last name: ");  

   String lastName=console.next();    

   lastName=lastName.toUpperCase().charAt(0)+lastName.substring(1, lastName.length());  

   System.out.print("Please enter your year of birth: ");  

   int year=console.nextInt();  

   int age=getCurrentYear()-year;  

   return "Greetings, "+firstChar+". "+lastName+"! You are about "+age+" years old.";  

   }  

   private static int getCurrentYear()  

   {  

       return Calendar.getInstance().get(Calendar.YEAR);  

   }  

}

Output:-

Dr. Watson has been kidnaped! Sherlock Holmes was contacted by the kidnapper for ransom. Moments later he received a message from Dr. Watson's phone. The message contained three random strings. Sherlock being Sherlock, was able to deduce immediately that Dr. Watson was trying to give a hint about his location. He figured out that the longest common subsequence between the 3 words is the location. But since it was too easy for him, he got bored and asked you to find out what the actual location is. Your task is to find the longest common subsequence from the 3 given strings before it is too late. A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements. For instance, given a sequence "drew"; "d", "w", "de", "drw", "drew" are all examples of valid subsequences (there are also others), while "er", "wdre" are not. Design a dynamic programming algorithm which takes three input sequences X, Y, and Z, of lengths m, n, and p, respectively, and returns their longest common subsequence. For full marks your algorithm should run in (mnp) time. Note that W is a common subsequence of X, Y, and Z if and only if W is a subsequence of X, W is a subsequence of Y, and W is a subsequence of Z.

Required:
Describe the set of subproblems that your dynamic programming algorithm will consider.

Answers

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

 

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

 

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837

What will be the pseudo code for this

Answers

Answer:

Now, it has been a while since I have written any sort of pseudocode. So please take this answer with a grain of salt. Essentially pseudocode is a methodology used by programmers to represent the implementation of an algorithm.

create a variable(userInput) that stores the input value.

create a variable(celsius) that takes userInput and applies the Fahrenheit to Celsius formula to it

Fahrenheit to Celsius algorithm is (userInput - 32) * (5/9)

Actual python code:

def main():

   userInput = int(input("Fahrenheit to Celsius: "))

   celsius = (userInput - 32) * (5/9)

   print(str(celsius))

main()

Explanation:

I hope this helped :) If it didn't tell me what went wrong so I can make sure not to make that mistake again on any question.    

Identify the class of the address, the number of octets in the network part of the address, the number of octets in the host part of the address, the network number, and the network broadcast address g

Answers

Answer:

1.

190.190.190.190

Class B

Number of octets in the network part of the address: 2

Number of octets in the host part of the address: 2

Network number: 190.190.0.0/16

Network broadcast address: 190.190.255.255

2.

200.1.1.1

Class C

Number of octets in the network part of the address: 3

Number of octets in the host part of the address: 1

Network number: 200.1.1.0/24

Network broadcast address: 200.1.1.255

Explanation:

What is true about the pivot in Quicksort? Group of answer choices After partitioning, the pivot will always be in the center of the list. After partitioning, the pivot will never move again. Before partitioning, it is always the smallest element in the list. A random choice of pivot is always the optimal choice, regardless of input.

Answers

Answer:

The pivot is selected randomly in quick sort.

Write a Racket two-way selection structure that will produce a list '(1 2 3) when the first element of a list named a_lst is identical to the atom 'a and an empty list otherwise. Note that you are NOT required to write a function definition!

Answers

Answer:

A

Explanation:

Write a pseudocode For loop that displays all the numbers from 0 to 5, one at a time. We have the following pseudocode so far. Declare Integer number Write this statement Display number End For Type the exact text for the line of pseudocode that should replace Write this statement shown above.

Answers

Answer:

The statement is:

For number = 0 to 5

Explanation:

Given

The incomplete pseudocode

Required

The loop statement to complete the pseudocode

To loop from 0 to 5, we make use of:

For number = 0 to 5

Where:

number is the integer variable declared on line 1

So, the complete pseudocode is:

Declare Integer number

For number = 0 to 5

Display number

End For

How does Accenture view automation?

Answers

Answer:

The description of the given question is summarized below.

Explanation:

These organizations retrained, retooled, and empowered our employees amongst all organization's internal management operating areas throughout order to create an increased automation attitude.Accenture's Innovative Software department was indeed adopting a concept called Human Plus technology, which includes this type of training.

Fasilitas untuk pengaturan batas kertas pada Microsoft Word adalah….

a. Margin
b. View
c. LayOut
d. Paragraph

Office 92 sering disebut juga dengan….

a. Office 3.0
b. Office 7.0
c. Office Xp
d. Office 2.0


Answers

Fasilitas untuk pengaturan batas kertas pada Microsoft Word adalah

B.View

Office 92 sering disebut juga dengan

A.Office 3.0

Type the correct answer in the box. Spell all words correctly.
As a project team member, Mike needs to create a requirements document. What is one of the most important aspects Mike should take care of while creating a requirements document?
Maintaining ( blank)
is one of the most important aspects of creating a requirements document.

Answers

Answer:

Gantt charts

Explanation:

Gantt charts control all aspects of your project plan from scheduling to assigning tasks and even monitoring progress. A Gantt chart shows your tasks across a timeline and puts them in phases for better organization.

what is computer with figure​

Answers

Answer:

A computer is an electronic device that accept raw data and instructions and process it to give meaningful results.

explain the working principle of computer? can anyone tell​

Answers

Answer:

input process and output hehe


Calculator is an example of
computer
A. analogue
B. hybrid
C. manual
D. digital
E. public​

Answers

D. digital

Explanation:

I hope it helps you

You have n warehouses and n shops. At each warehouse, a truck is loaded with enough goods to supply one shop. There are m roads, each going from a warehouse to a shop, and driving along the ith road takes d i hours, where d i is an integer. Design a polynomial time algorithm to send the trucks to the shops, minimising the time until all shops are supplied.

Answers

Following are the steps of the polynomial-time algorithm:

Split the routes according to their categorizationAssuming that mid = di of the middle road, low = road with the least di, and high = road with the highest di, we may do a binary search on the sorted list.All shops must be approachable only using these roads for every road, from low to mid.Check if all shops can be reached from[tex]\bold{ low \ to\ mid+1}[/tex] using only these roads.There is a solution if every shop can be reached by road only up to [tex]\bold{mid+1}[/tex], but not up to mid.You can [tex]\bold{set \ low = mid+1}[/tex] if all businesses aren't accessible using both [tex]\bold{mid\ and\ mid+1}[/tex] roads.If every shop could be reached using both mid and mid+1, then set high to mid-1.With these layouts of businesses and roads, no response can be given because [tex]\bold{ low > high}[/tex]You can do this by [tex]\bold{set\ mid = \frac{(low + high)}{2}}[/tex]The new low, mid, and high numbers are used in step (a).

In a minimum amount of time, this algorithm will determine the best strategy to supply all shops.

Learn more:

polynomial-time algorithm: brainly.com/question/20261998

Clarissa needs to modify a runtime environment variable that will be set for all users on the system for both new logins as well as new instances of the BASH shell being launched. Which of the following files should she modify?

a. /root/.profile
b. /etc/profile
c. /root/.bashrc
d. /etc/bashrc

Answers

Clarissa should modify the file /root/.profile.

Runtime environment variables

The Runtime environment variables are defined as the key pairs that are deployed along the function. The variables are mainly scoped to a function in the project.

Therefore, in the context, Clarissa wishes to modify the run time environment variable which can be used for all the new logins and also for the new instances for the BASH shell. So for this, Clarissa should modify the /root/.profile file command.

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The environmental variable is a dynamic-name value, that might alter how the way a computer works. These constitute part of nature where a process is carried.In the Container Management, every value of Environment Variables might be changed or the code that whilst also might be executed during runtime: Throughout the Property of each Environment modifications introduced in the Container Management got saved.

Following are the description of the wrong choice:

In option b and option d, both are wrong because it's file directory.In option c,  it is a software file directory which install in the main disk, that's why it is wrong.

Therefore, the "/root/.profile" file should be changed by Clarissa.

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