What percent of 0.2 gram of 32 mg

Answer:

162 minutes

Step-by-step explanation:

Since she takes 6.2 minutes a mile, you multiply it by 26.2 for every mile. 6.2x26.2= 162.44, then round it to 162

Answer:

The center is ( -2, 7) and the radius is 6

Step-by-step explanation:

A circle is written in the form

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x+2)^2+(y-7)^2=36

(x -  -2)^2+(y-7)^2=6^2

The center is ( -2, 7) and the radius is 6

9514 1404 393

Answer:

  60 gallons

Step-by-step explanation:

The area of the trapezoid-shaped wall is given by ...

  A = 1/2(b1 +b2)h

where b1 and b2 are the lengths of the parallel sides, and h is the perpendicular distance between them.

The area of the wall is ...

  A = (1/2)(5 ft + 15 ft)(6 ft) = 60 ft²

If it takes 1 gallon to cover 1 square foot, then it will take 60 gallons to cover 60 square feet.

Isha needs 60 gallons of paint.

Answer:

Isha needs 60 gallons of paints to the wall.

Step-by-step explanation:

The area of trapezoid shaped like wall is given by :-

Area of trapezoid = 1/2 × ( Base ¹ + Base ² ) × H

Where,

B ¹ and B ² are the length of bases and H is the perpendicular distance between them.

Area of wall = 1/2 × ( Base¹ + Base²) × Height

Where, according to question we have

substitute the values

Area = 1/2 × ( 5 ft + 15 ft ) × 6 ft

add the values of Base¹ and Base ²

Area = 1/2 × 20 ft × 6 ft

multiply

Area = 1 / 2 × 120 ft ²

divide

Area = 120 ft ² / 2 = 60 ft ²

It takes 1 gallon to cover 1 ft ². ... ( given)

So, For covering 60 ft ² it takes 60 gallons .

check

( 1 × 60 ) gallon = 60 ft ²

60 gallon = 60 ft²

Answer:

the answer is 125. if you cut them slice to slice you'll get 25 because of there five slices of 25 all you got to do is 25 x 5 and you'll get 125.

Hope this help

Have a nice day :)

Answer:

D (The square root property should have been applied to both complete sides of the equation instead of to select variables)

Step-by-step explanation:

On edge 2021

Answer:

d. static

Step-by-step explanation:

This is a question about Java programming.

A class contains information about it's members(objects). Private, public or inline variables must be related to an object, that is, an object has to be created before the variable is acessed.

Static variables, otherwise, may pertain to the class, and not to the object, that is, and thus, the correct answer is given by option d.

Answer:

[tex]\displaystyle y = 2sin\:1\frac{1}{3}\pi{x} + 3[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{3}{8}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although the exercise told you to write the sine equation based on the speculations it gave you, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:1\frac{1}{3}\pi{x} + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{3}{8}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{3}{8}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{3}{8}} = \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have the exercise to wourk with, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]It displays the formula on how to define each wavelength of the graph. You just need to remember that the B-term has [tex]\displaystyle \pi[/tex]in it as well, meaning both of them strike each other out, leaving you with just a fraction. Now, the amplitude is obvious to figure out because it is the A-term, so this is self-explanatory. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter what the vertical shift is, that will ALWAYS be the equation of the midline, and if viewed from a graph, no matter how far it shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Step-by-step explanation:

This is called a nested function. Remember, math is a language.

We define a function where x is whatever we want it to be, f(x) = g(x) +10

but we have yet another function inside and itvs defined as g(x) = 3x - 18

if we were to write it out, it woukd be

f(x) = (3x - 18) + 10

Answer:

-1 =s

Step-by-step explanation:

7 = -10s - 3

Add 3 to each side

7+3 = -10s - 3+3

10 = -10s

Divide by -10

10/-10 = -10s/-10

-1 =s

Answer: My teacher told me to use 180 and divide something.

Step-by-step explanation:

Answer:

isnt itjust 15?

Step-by-step explanation:

1 +1+1+1 = 4  5+3+3 = 11 then 11+4 = 15 if this is incorrect im sorry

Answer:

pls complete your question. what exactly are we supposed to calculate?

Answer:

A is the closest

Answer:

4t - 3y

Step-by-step explanation:

8t - 3y - 4t

8t - 4t - 3y

4t - 3y

7t +(-3t) - 3y

7t - 3t - 3y

4t - 3y

Answer:

These expressions are equivalent, as both of them simplify down to (4t - 3y).

Step-by-step explanation:

In order to determine if (8t - 3y - 4t) is equivalent to (7t + (-3t) - 3y) one must simplify each equation. Combine like terms by performing the operations between the coefficients of the variables.

8t - 3y - 4t

= 4t - 3y

7t + (-3t) - 3y

= 7t - 3t - 3y

= 4t - 3y

Answer:

The answer is "[tex](32.8318736, 29.1681264)[/tex]"

Step-by-step explanation:

When the [tex]95\%[/tex] of the confidence interval are true population means of the dog weight then:

[tex]=\bar{x} \pm \frac{\sigma }{\sqrt{n}} \times z_{0.05}\\\\=31 \pm \frac{6.1}{\sqrt{30}}\times 1.64485\\\\=31 \pm 1.83187361\\\\=(32.8318736, 29.1681264)[/tex]

Answer:

I am pretty sure its 30 students

Answer:

a. Photographer A by $10

b. Photographer B by $25

Answer:

h(-8) = -40

Step-by-step explanation:

Find h(-8) by plugging in -8 as x:

h(x) = 1/4x² + 7x

h(-8) = 1/4(-8)² + 7(-8)

Simplify:

h(-8) = 1/4(64) - 56

h(-8) = 16 - 56

h(-8) = -40

So, the answer is h(-8) = -40

The value of h(-8) is -40.

Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.

Given:

h(x)=1/4x²+7x

h(-8)= 1/4* 64+7*(-8)

      = 16-56

      = -40

Hence, h(-8)=-40.

Learn more about quadratic equation here:

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9514 1404 393

Answer:

  9 +7i

Step-by-step explanation:

i^2 = -1, so i^8 = (-1)^4 = 1, and i^5 = (-1)^2×i = i

Then ...

  7i^5 +9i^8 = 7i +9 = 9 +7i

Answer:

x is 13°.take the triangle to find the measure of x.180° -(85°+82°)=x

180°-167°=13°

For the given triangle the measure of the angle x is = 3 degrees.

Labeling the given figure,

since angle C and angle B are alternate angles

Therefore,

For the triangle ABE

The interior angle for A = x

The interior angle for B = 180 -98

                                       = 92 degree

Since we know that,

The sum of the two interior angles of a triangle is equal to the exterior angle of the opposite side.

Therefore,

⇒ x  + 92 = 180 - 85

⇒ x  = 3 degrees.

Hence,

The measure of the angle x is = 3 degrees.

Learn more about the triangle visit;

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Answer:   876

Step-by-step explanation:so all you need to do is go into  

Answer:

Step-by-step explanation:

Answer:

-28 1/3

Step-by-step explanation:

-8 1/3= -25/3

3 2/5= 17/5

-25/3*17/5= -28 1/3

Answer:

27.4 feet down deep

Step-by-step explanation:

28 feet down, swins up for 0.3 feet times 6 or 1.8 feet up

leaving a total of 26.2 under the sea and he swims back down at 0.3 feet times 4 or 1.2 feet down. and the new total is 26.2 + 1.2 which equals 27.4 feet down in the deep sea

Answer:

27.4 feet

Step-by-step explanation:

.3 ft per sec for 6 sec = 1.8 feet

.3 ft per sec for 4 sec = 1.2 feet

28 - 1.8 + 1.2 = 27.4

Answer:

Step-by-step explanation:

Distance : [tex]\sqrt{(x2-x1)^2 + (y2 - y1)^2} = \sqrt{(9-2)^2 + (-9+14)^2}= \sqrt{49 + 25} = \sqrt{74}[/tex]

Midpoint :

x (m) = (2+9)/2 = 11/2

y (m) = (-14-9)/2 = -23/2

M (11/2, -23/2)

Answer:

6 cm

Step-by-step explanation:

Volume of a prism= Length X Width x height

750 = 25 x 5 x h

750= 125h

750/125 = 125h/125

h= 6

Answered by Gauthmath