What will you use if you are looking for the space bounded by a rectangle A. 2(I + w) B. S² C. B × h ________ 2 D. I × w

Answer:

16.67% of your day is spent in math class.

Step-by-step explanation:

The total would be 100% and then since you have 6 periods we divide 100 by 6 to get 16.67%. So 16.67% of your day is spent in math class.

Answer:

16.3

Step-by-step explanation:

i just took the quiz

Answer:

16.3 units

Step-by-step explanation:

Helloo, I just took the quiz too and the answer is 16.3

Answer:

x=-3 and y=-2

Step-by-step explanation:

let the numbers be x and y

x+y=-5

x-y=-1

therefore x=-5-y

-5-y-y=-1

-2y=-1+5

-2y=4

y=-2

×=-5-(-2)

x=-5+2

x=-3

Answer: -2 and -3

Step-by-step explanation:

x + y = -5

x - y = -1 -> x = y - 1

(y - 1) + y = -5

y - 1 + y = -5

2y = 1 - 5

2y = -4

y = -2

x = y - 1 = -2 - 1 = -3

Answer:

90

Step-by-step explanation:

From the given drawing, we have;

ΔRST is circumscribed about circle A

The center of the circle A = The point A

The line RT = A tangent to the circle A

The radius to the circle A = The line AP

According to circle theory, a line which is tangent to a circle is perpendicular to the radius of the circle drawn from the point of tangency

Where two lines are perpendicular to each other, then the angle formed between them = 90°

The angle formed between a tangent and the radius of the circle = m∠APT

Therefore;

m∠APT = 90°

Answer:

20 Lines

Step-by-step explanation:

According to the Question,

Now,  the total pairs of points which can be formed is 9

And, the line passing through 2 such points 9c2 = 9! / (2! x 7!) = 9x4 ⇒ 36

Here, We have overcounted all of the lines which pass through three points.

And, each line that passes through three points will have been counted 3c2 = 3! / 2! ⇒ 3 times

Now, the sides of the square consist of 3 points. We have counted each side thrice, so 4*2 are repeated.

Answers:

==================================================

Explanation:

To get the mean, we add up the scores and divide by 10 (because there are 10 scores at first)

28+13+4+12+32+22+13+22+26+32 = 204

204/10 = 20.4

The mean is 20.4

------------

For part b), we redo those steps shown above, but tack 16 onto the list. So we'll add up all the values (including that 16 at the end) and divide by 11 this time.

28+13+4+12+32+22+13+22+26+32+16 = 220

220/11 = 20

The new mean is 20.

The new mean is slightly smaller than the old mean. Notice how 16 is smaller than 20.4, so this new score pulls down the mean just a little bit.

Answer:

Zach chose C as the correct answer

Answer:

10

Step-by-step explanation:

last year he planted 12.

1/3 of that is 12/3 = 4.

6 more than that is 4 + 6 = 10.

Answer: C.)  10

Step-by-step explanation:

Answer:

because internal staggal angles are equal

Step-by-step explanation:

The first reason is wrong.

Angle EGH and DEG are internal staggal angles:

the two angles are on both sides of the cut line EG, and the two angles are between the two divided lines.

{the definition of internal staggal angle}

Answer:

32

Step-by-step explanation:

Number 1 =x

Number 2 =(3x-10)

number 1 + number 2 =46

x+(3x-10)=46

4x=56

x=14

Number 1 =x=14

Number 2=3x-10

                 3(14)-10

                   32

Number 1 (14)+Number 2 (32)=46

Answer:

no solutions

Step-by-step explanation:

Hi there!

We're given this system of equations:

x+y=3

4y=-4x-4

and we need to solve it (find the point where the lines intersect, as these are linear equations)

let's solve this system by substitution, where we will set one variable equal to an expression containing the other variable, substitute that expression to solve for the variable the expression contains, and then use the value of the solved variable to find the value of the first variable

we'll use the second equation (4y=-4x-4), as there is already only one variable on one side of the equation. Every number is multiplied by 4, so we'll divide both sides by 4

y=-x-1

now we have y set as an expression containing x

substitute -x-1 as y in x+y=3 to solve for x

x+-x-1=3

combine like terms

-1=3

This statement is untrue, meaning that the lines x+y=3 and 4y=-4x-4 won't intersect.

Therefore the answer is no solutions

Hope this helps! :)

The graph below shows the two equations graphed; they are parallel, which means they will never intersect. If they don't intersect, there's no common solution

Answer:

247.18

Step-by-step explanation:

please watch the diagram carefully to see marked areas

According to given situation cosine law in trigonometry identities used

[tex]c^{2}=b^{2} +a^{2} -2abcosx[/tex] to find the bearing angle of P from R is 67 degree.

If the identities or equations are applicable for all the triangles and not just for right triangles, then they are the triangle identities. These identities will include:

Sine law

Cosine law

Tangent law

According to question,

The angle between RP & RQ.

Using the cosine law

[tex]PQ^{2} = RP^{2} + QR^{2} - 2PR*RQ*cosx\\12^{2}=8^2+10^2-2*8*10cosx\\cosx = \frac{164-144}{160} \\cosx = \frac{20}{160} \\cosx =\frac{1}{8}[/tex]

[tex]x=83[/tex] degree

[tex]150-83=67[/tex]

Hence, the bearing of P from R​ is 67 degree

To know more about cosine law here

https://brainly.com/question/17289163

#SPJ2

Answer:

28

Step-by-step explanation:

Answer: 68

Step-by-step explanation: Complementary angles are angles that add up to 90. So, you need to do 90-22=68.

Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]

Answer:4 and 8?

Step-by-step explanation:

Answer:

9.32m is the height of. the tree from the ground.

Answer:

H

Step-by-step explanation:

When h=0,t=45.

so we can exclude F.

When h=10,t=15.

only H satisfiy the condition.

Answer:

H

The line shows an inverse proportionality between temperature and time:

[tex]{ \tt{t \: \alpha \: \frac{1}{h} }} \\ \\ { \tt{t = \frac{k}{h} }}[/tex]

Slope or change:

[tex] = \frac{45 - 30}{0 - 5} \\ = - 3[/tex]

y-intercept:

[tex]c = 45[/tex]

General equation:

[tex]y = - 3x + 45[/tex]

Answer:

option d is correct answer

Answer:

1234567891011121314151617181920

Step-by-step explanation:

you just count

Answer:

44

Step-by-step explanation:

5+8/4*3

5+24/4

20+24

44

Answer:

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].

Step-by-step explanation:

Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:

[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].

Multiply both sides by [tex](-1)[/tex] to obtain:

[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].

[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].

If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:

[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].

However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].

Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].

Determinant of this quadratic equation about [tex]y[/tex]:

[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].

Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:

[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].

[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].

Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].

The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:

[tex]-2 \le -m^{2} \le 0[/tex].

[tex]0 \le m^{2} \le 2[/tex].

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

In other words,  solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].

Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

Answer:

The question is very not detailed but I assume that because the path will finish does not mean that the whole thing/project will finish.

Step-by-step explanation:

Answer:

option 3. (4, -2)

Step-by-step explanation:

For a relation to be a function there should be exactly one output value for a given input.

In the given relation :-

4 has 2 outputs, -2 and 2, so if we remove the pair (4, -2) 4 will have only one output value ,i. e., 2. And hence the relation will be a function.

So the answer is option 3. (4, -2)

Answer:

∠3 = 142°

Step-by-step explanation:

L // M

∠2 = 38°    {Corresponding angles are congruent}

∠2 + ∠3 = 180   {Linear pair}

38 + ∠3 = 180

       ∠3 = 180 - 38

∠3 = 142°

the answer is 142 degrees, get 180 degrees from a straight lines and subtract the acute angle from 180 to get the answer, 180-38

Step-by-step explanation:

40+24+11+8+17= 100

100 - 700

24 - ?

24×700/100

= 168 visitors ordered apple juice

100-700

11-?

11×700/100

=77 people ordered grape juice

Answer:

[tex]\frac{2(x-6)(x-10)}{(x-4)(x-5)}[/tex]

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

[tex]\frac{()}{(x-4)(x-5)}[/tex]

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ([tex](x - 6)(x-10)[/tex]). Now one has this much of the function assembled

[tex]\frac{(x-6)(x-10)}{(x-4)(x-5)}[/tex]

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

[tex]\frac{2(x-6)(x-10)}{(x-4)(x-5)}[/tex]