what’s the answer to this problem please and thank you

Answer:

a

Step-by-step explanation:

Answer:

P

Step-by-step explanation:

It's where the altitudes meet

Answer:

Let's solve for k.

x2−y2=k

Step 1: Flip the equation.

k=x2−y2

Answer:

k=x2−y2

Step-by-step explanation:

Answer:

"x" cantidad de personas, que será igual a

f(x) = $10x   Si   x < 30

f(x) = $9.5x si x ≥ 30

Si tenemos que son 29 personas entonces el costo es de:

f(x) = $10*29 = $290

Si incluye un miembro adicional

f(x) = $9.5*30 = $285

Ahorra un total de: $290 - $285 = $5

Answer:

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean per capita consumption of milk per year is 131 liters with a variance of 841.

This means that [tex]\mu = 131, \sigma = \sqrt{841} = 29[/tex]

Sample of 132 people

This means that [tex]n = 132, s = \frac{29}{\sqrt{132}}[/tex]

What is the probability that the sample mean would be less than 133.5 liters?

This is the p-value of Z when X = 133.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{133.5 - 131}{\frac{29}{\sqrt{132}}}[/tex]

[tex]Z = 0.99[/tex]

[tex]Z = 0.99[/tex] has a p-value of 0.8389

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

Answer:

[tex]d_2=-8.32ft[/tex]

Step-by-step explanation:

From the question we are told that:

Height of first draw down [tex]h=30[/tex]

Pump Discharge [tex]Q=250gallons/day[/tex]

Well 1 depth [tex]d_1=10ft[/tex]

Transmissivity[tex]\=T 10.0 ft2/day[/tex]

Radius[tex]r=0.5[/tex]

Well 2 depth [tex]d_2=50ft[/tex]

Generally the Thiem's equation for Discharge is mathematically given by

 [tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]

 [tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]

 [tex]1151.293=2*\pi 10 (10-d_2)[/tex]

 [tex]d_2=-8.32ft[/tex]

Answer:

$637.50

Step-by-step explanation:

According to the Question,

Thus, the first months interest is

$200,000 list price x 0.90 = $180,000 contract sales price.

Since lender always uses the less of the appraised value or the contract sales price, use $180,00 for the remainder of the calculations.

Answer:

$637.50

Step-by-step explanation:

The appraised value is irrelevant. The lender will consider the lower of the appraised value or the agreed purchase price.

The term of the loan is also irrelevant. It is not an amortization problem.

The first month’s interest is $637.50.

Answer:

Step-by-step explanation:

Given,

Total no. of cards = 52

No. of 2 of spades cards = 1

Therefore,

Probability of getting 2 of spades

[tex] = \frac{no. \: of \: required \: outcomes}{total \: outcomes} [/tex]

[tex] = \frac{1}{52} (ans)[/tex]

Answer:

200 test tubes will fill the container

Step-by-step explanation:

Hi there!

We need to find out how many 5 milliliter tubes will fill a 1 liter container

First, let's convert everything to the same unit, as the tubes and the container are in different units.

Let's do milliliters, as those are smaller than liters and we will avoid having decimals.

there are 1,000 milliliters in a liter (the unit prefix "milli-" means "thousand")

Let's say the number of test tubes needed to fill the container is x

As each tube has 5 milliliters of water, 5x milliliters will equal 1,000 milliliters (1 liter)

as an equation, that's

5x=1,000

divide both sides by 5

x=200

So that means 200 test tubes will fill the container

Hope this helps! :)

Answer:

Here is how to start

Step-by-step explanation:    7  2  13  42

1 milliliter is one one thousands of a liter      1 milliliter  = 0.001 liter

1000 milliliter is equal to 1 liter

How many 5 milliliter test tubes are in 1 liter?

1000 milliliter / 5 milliliter per test tube   =  ________  test tubes

Answer:

option (B) is the answer

Answer:

-28

Step-by-step explanation:

if c = 3 and x = -5 than,

-c + 5x = -3 + 5 * (-5) = -3 + (-25) = - 28

Answer:

A is the equation in standard form

Step-by-step explanation:

Answer:

1/4 *1/4*1/2 =0.03125

which as a fraction is 1/32

so the minimuim number of passes that will get him a goal is 1 since he could get it on the first try

Hope This Helps!!!

Answer:

(2k, k)

Step-by-step explanation:

x + y = 3k

x - y = k

Add the equations.

2x = 4k

x = 2k

2k + y = 3k

y = k

Answer: (2k, k)

Answer:

Option A, 7b

Step-by-step explanation:

a/b=7/2

or, 2a=7b

Answered by GAUTHMATH

Answer:

A)7b

its yr ans.

hope it helps.

Answer:

251.33

Step-by-step explanation:

C=3.14(d)

C=3.14(80)

Answer:

[tex]A"B" = \frac{AB}{2}[/tex]

Step-by-step explanation:

Given

[tex]k = \frac{1}{2}[/tex] --- scale factor

Required

Relationship between AB and A"B"

[tex]k = \frac{1}{2}[/tex] implies that the sides of A"B"C" are smaller than ABC

i.e.

[tex]A"B" = k * AB[/tex]

[tex]A"B" = \frac{1}{2} * AB[/tex]

This gives:

[tex]A"B" = \frac{AB}{2}[/tex]

Answer:

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points

This means that [tex]\mu = 167, \sigma = 20[/tex]

Sample of 76:

This means that [tex]n = 76, s = \frac{20}{\sqrt{76}}[/tex]

What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points?

P-value of Z when X = 167 + 3.8 = 170.8 subtracted by the p-value of Z when X = 167 - 3.8 = 163.2. So

X = 170.8

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{170.8 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = 1.66[/tex]

[tex]Z = 1.66[/tex] has a p-value of 0.9515

X = 163.2

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{163.2 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = -1.66[/tex]

[tex]Z = -1.66[/tex] has a p-value of 0.0485

0.9514 - 0.0485 = 0.9029

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

can you show a picture of the symbols

Answer:

108 square metres

Step-by-step explanation:

A=√d square - l square

here

A = area

d= diagonal

l= length

Answer:

B

Step-by-step explanation:

B is the only one that doesnt share x-values

Answer:  1/ 233856 chance changed to 233856  x 2 = 467712

= 1 / 467712 chance as there are 2 drawings

Workings;

1 and 65 = 64

1 and 65 - 1 ball drawn = 63

1 and 60 -1 = 58

1/64 x 1/63 x 1/58 = 233856

1/4032 x 1/58 and to make these the same we 4038/58 =  69.62

then convert properly = 1/4032  x 69.62/4032 4032 x 4032 = 69.62/16257024 then 16257024/69.62 =233510.83

= 233511 chance if rounding before

1/ (233511 x 2) = 1/467022

Then one part is our actual probability

P) = 1/233856

But as they specified a special drawing

you need to repeat this as 64 x 63 x 58 x 2 as the last one cannot be in 1 drawing it has to be in 2nd drawing

233856  x 2 = 467712

= 1 / 467712 chance not rounding down before hand.

Answer:

f(6)=-42

f(0)=0

f(-1)=7

Step-by-step explanation:

since f(x) =-7x

it implies that f(6),f(0) and f(-1) are all equal to f(x)

which is equal to -7x .

so wherever you find x you out it in the

function

Answer:

D. The y-intercept of the new graph would shift down 2 units.

Step-by-step explanation:

y = -9x + 3 has a y-intercept of 3 (0, 3).

y = -9x + 1 has a y-intercept of 1 (0, 1).

3 - 1 = 2

So, down two units.

Answer:

x=5

y=3/2

Step-by-step explanation:

Take it or leave it, that's what the computer said.

Answer:

D. <S, <R, <T

Step-by-step explanation:

Recall: On a triangle, the bigger an angle measure the longer the side opposite it and vice versa.

In ∆RST,

The longest side, SR = 22, is opposite to <T

Therefore, <T is the biggest angle.

Medium side, ST = 21, is opposite to <R, therefore,

<R is the medium angle measure

The smallest angle measure <S is opposite to the shortest side, RT.

Angels I'm order form the smallest to largest will be:

<S, <R, <T

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

Answer:

Step-by-step explanation:

A.

[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]

which equation has the steepest graph ?

[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]

[tex]y = mx + c[/tex]

[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]

[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex] \blue{A.T.Q}[/tex]

PART A:-

[tex]y = mx + c \sim y= -14x+1 [/tex]

[tex] \orange{SO}[/tex]

m= (-14)

which is equal to the slope of the equation .

PART B:-

[tex]y = mx + c \sim y= ¾x-9 [/tex]

[tex] \orange{SO}[/tex]

m= (¾)

PART C:-

[tex]y = mx + c \sim y= 10x-5[/tex]

[tex] \orange{SO}[/tex]

m= (10)

PART D:-

[tex]y = mx + c \sim y= 2x+8[/tex]

[tex] \orange{SO}[/tex]

m= (2)

Negative shows Slope is in negative direction.

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

Answer:

Step-by-step explanation:

-2