Which equation represents a circle with a center point of (-2,3) that passes through the point (4, -3)?

PLEASE HELP ASAP IM GIVING BRAINLIEST

Answer:

[tex]A) (x+2)^{2} +(y-3)^{2} =72[/tex]

Step-by-step explanation:

[tex]Radius=\sqrt{(4+2)^{2}+(-3-3)^{2} }[/tex]

[tex]=\sqrt{6^{2} +6^{2} } =6\sqrt{2 }[/tex]

[tex]equation:[/tex]

[tex](x+2)^{2}+(y-3)^{2} =(6\sqrt{2}^{2})\\[/tex]

[tex](x+2)^{2}+(y-3)^{2} =72[/tex]

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have a great day!!

The equation represents a circle is option (A) (x+2)^2 +(y-3)^2 = 72 is the correct answer.

A circle is a collection of all points in a plane which are at a constant distance from a fixed point. A circle is a round-shaped figure that has no corners or edges.

For the given situation,

The center of the circle, (h,k) = (-2,3)

The point on the circle, (x,y) = (4,-3)

The radius of the circle is

[tex]r=\sqrt{(h-x)^{2} +(k-y)^{2} }[/tex]

⇒ [tex]r=\sqrt{(-2-4)^{2} +(3-(-3))^{2} }[/tex]

⇒ [tex]r=\sqrt{6^{2}+6^{2} }[/tex]

⇒ [tex]r=\sqrt{72}[/tex]

The formula of equation of circle is

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

The circle has the center (h,k) = (-2,3) and radius is √72,

⇒ [tex](x-(-2))^{2}+(y-3)^{2}=(\sqrt{72} )^{2}[/tex]

⇒ [tex](x+2)^{2}+(y-3)^{2}=72[/tex]

Hence we can conclude that the equation represents a circle is option (A) [tex](x+2)^{2}+(y-3)^{2}=72[/tex] is the correct answer.

Learn more about circles here

https://brainly.com/question/27421661

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