Which expression is equivalent to 2^-3/2^-5

Answer:

d

Step-by-step explanation:

on edge

Answer:

D!!

Step-by-step explanation:

Got it right

Answer: 700

Step-by-step explanation: 3 x 200 + 100

Answer:

c.$700

Step-by-step explanation:

3x+100 3 per chair=3x plus the additional 100 dollar fee

3(200)+100

600+100

700

Answer:

Our two numbers are:

[tex]2+4\sqrt{2} \text{ and } 4\sqrt{2}-2[/tex]

Or, approximately 7.66 and 3.66.

Step-by-step explanation:

Let the two numbers be a and b.

One positive real number is four less than another. So, we can write that:

[tex]b=a-4[/tex]

The sum of the squares of the two numbers is 72. Therefore:

[tex]a^2+b^2=72[/tex]

Substitute:

[tex]a^2+(a-4)^2=72[/tex]

Solve for a. Expand:

[tex]a^2+(a^2-8a+16)=72[/tex]

Simplify:

[tex]2a^2-8a+16=72[/tex]

Divide both sides by two:

[tex]a^2-4a+8=36[/tex]

Subtract 36 from both sides:

[tex]a^2-4a-28=0[/tex]

The equation isn't factorable. So, we can use the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 1, b = -4, and c = -28. Substitute:

[tex]\displaystyle x=\frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-28)}}{2(1)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{4\pm\sqrt{128}}{2}=\frac{4\pm8\sqrt{2}}{2}=2\pm4\sqrt{2}[/tex]

So, our two solutions are:

[tex]\displaystyle x_1=2+4\sqrt{2}\approx 7.66\text{ or } x_2=2-4\sqrt{2}\approx-3.66[/tex]

Since the two numbers are positive, we can ignore the second solution.

So, our first number is:

[tex]a=2+4\sqrt{2}[/tex]

And since the second number is four less, our second number is:

[tex]b=(2+4\sqrt{2})-4=4\sqrt{2}-2\approx 3.66[/tex]

Answer:

[tex]2+4\sqrt{2}\text{ and }4\sqrt{2}-2[/tex]

Step-by-step explanation:

Let the large number be [tex]x[/tex]. We can represent the smaller number with [tex]x-4[/tex]. Since their squares add up to 72, we have the following equation:

[tex]x^2+(x-4)^2=72[/tex]

Expand [tex](x-4)^2[/tex] using the property [tex](a-b)^2=a^2-2ab+b^2[/tex]:

[tex]x^2+x^2-2(4)(x)+16=72[/tex]

Combine like terms:

[tex]2x^2-8x+16=72[/tex]

Subtract 72 from both sides:

[tex]2x^2-8x-56=0[/tex]

Use the quadratic formula to find solutions for [tex]x[/tex]:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex] for [tex]ax^2+bx+c[/tex]

In [tex]2x^2-8x-56[/tex], assign:

Solving, we get:

[tex]x=\frac{-(-8)\pm \sqrt{(-8)^2-4(2)(-56)}}{2(2)},\\x=\frac{8\pm 16\sqrt{2}}{4},\\\begin{cases}x=\frac{8+16\sqrt{2}}{4}, x=\boxed{2+4\sqrt{2}} \\x=\frac{8-16\sqrt{2}}{4}, x=\boxed{2-4\sqrt{2}}\end{cases}[/tex]

Since the question stipulates that [tex]x[/tex] is positive, we have [tex]x=\boxed{2+4\sqrt{2}}[/tex]. Therefore, the two numbers are [tex]2+4\sqrt{2}[/tex] and [tex]4\sqrt{2}-2[/tex].

Verify:

[tex](2+4\sqrt{2})^2+(4\sqrt{2}-2)^2=72\:\checkmark[/tex]

Answer:

D

Step-by-step explanation:

D on edg

Answer:

last term is 1536

Value of the geometric series is 3,069

Step-by-step explanation:

took one for the team

There are 10 terms in the geometric series.

And, The first term of the series is, 3

We know that;

An sequence has the ratio of every two successive terms is a constant, is called a Geometric sequence.

Given that;

The geometric series is,

⇒ S₁₀ = ∑ 3 (2)ⁿ⁻¹

Where, n is from 1 to 10.

Thus, We get;

There are 10 terms in the geometric series.

And, For first term;

Put n = 1;

⇒ S₁₀ = ∑ 3 (2)ⁿ⁻¹

⇒ S₁₀ = ∑ 3 (2)¹⁻¹

⇒ S₁₀ = ∑ 3 (2)⁰

⇒ S₁₀ = ∑ 3 × 1

⇒ S₁₀ = 3

Thus, The first term of the series is, 3

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Answer:

Step-by-step explanation:

If you look at the diagram, you notice there are two triangular bases and three rectangular faces.

Therefore, the surface area, or the total area of all the bases and faces, would be the area of one triangular base multiplied by 2 and the area of each rectangular face

area of triangle = (1/2)*height*base

area of triangular base = (1/2)*15*28 = 210 cm^2

area of rectangle = base*height

area of rectangular face #1 = 25*30 = 750 cm^2

area of rectangular face #2 = 17*30 = 510 cm^2

area of rectangular face #3 = 28*30 = 840 cm^2

total surface area = 2*210 + 750 + 510 + 840 = 2520 cm^2

Answer:

???????????????????????

Step-by-step explanation:

sorry di ko po alam yung sagot pasensiya na po

Given :

Parallel lines are

x – 2y = 3 and 2x – 4y = 12

Step-by-step explanation:

Lets write the given lines in slope intercept form y=mx+b

[tex]x -2y = 3 \\-2y=-x+3\\Divide \; both \; sides \; by -2\\y=\frac{x}{2} -\frac{3}{2}[/tex]

From the above equation , y intercept of first line is [tex]\frac{-3}{2}[/tex]

Solve the second equation for y and find out y intercept

[tex]2x-4y=12\\-4y=-2x+12\\Divide \; by \; -4\\y=\frac{1}{2} x-3[/tex]

y intercept of second line is -3

To find the distance between parallel lines, we subtract the y intercepts

[tex]\frac{-3}{2} -(-3)=\frac{-3}{2} +\frac{6}{2} =\frac{3}{2} =1.5[/tex]

Answer:

The distance between the parallel lines = 1.5

Reference:

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Answer:

Ben = $ 41

Kaden = $ 31

Step-by-step explanation:

Let initially Ben has $ p and then Kaden has $ (p  - 10).

After that

Ben has= $ (p + 4)

Kaden has = $ (p- 10 + 4) = $ ( p - 6)

According to the question,

[tex]p- 6 = \frac{7}{9}\times (p+4)\\\\9 p- 54 = 7 p + 28 \\\\2 p = 82\\\\p =41[/tex]

Initially Ben has $ 41 and Kaden has $ 31.  

Answer: a = 7.5h + bn

Step-by-step explanation:

Since Ava works at a florist shop and earns $7.50 an hour plus a fixed bonus for each bouquet she arranges.

where,

a = total amount earned,

h= hours worked in one week,

n = number of bouquets she arranged

b= bonus amount for bouquets

Then, the formula that will help her determine how much she will make in a week will be:

a = (7.5 × h) + (b × n)

a = 7.5h + bn

The formula is a = 7.5h + bn.

Answer:

Does this seem right to you?

Step-by-step explanation:

there Are 120 possibilities for the top three positions

We will see that there are 120 different possibilities for the top 3 positions.

Here we need to count the number of options for each of the positions.

The total number of different combinations is given by the product between the numbers of options, we will get:

C = 6*5*4 = 120

There are 120 different possibilities for the 3 positions.

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Answer:

The power is 1.68 W.

Step-by-step explanation:

Voltage, V = 3 V

charge, q = 0.56 C

time, t = 1 s

The power is given by

P = V q/t

P = 3 x 0.56 / 1

P = 1.68 W

Answer:, Joey will pay $117.18 for sneakers.

Step-by-step explanation:

Given: original price = $155

Discount rate = 30%

Tax rate = 8%

Price after discount = Original price - (Discount) x (original price)

[tex]= 155-0.30\times 155\\\\=155-46.5\\\\=\$\ 108.5[/tex]

Tax = Tax rate x (Price after discount)

[tex]= 0.08 \times 108.5[/tex]

= $ 8.68

Final price for sneakers = Price after discount + Tax

= $ (108.5+8.68)

= $ 117.18

Hence

Answer:

The fourth angles is 105

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360

3*85 = 225

Let the fourth angle be x

225 +x = 360

x = 360 -225

x =105

Answer:

perpendicular

Given:

Rahul and Swapnil brought an equal amount of money for shopping.

Rahul spend rupees 95 and Swapnil spend rupees 350.

After that Swapnil had [tex]\dfrac{4}{7}[/tex] of what Rahul had left.

To find:

How much money did Rahul have left after shopping.

Solution:

Let x be the amount brought by both Rahul and Swapnil.

Rahul spend rupees 95 and Swapnil spend rupees 350. So, the remaining amounts are:

Rahul's remaining amount = [tex]x-95[/tex]

Swapnil's remaining amount = [tex]x-350[/tex]

After that Swapnil had [tex]\dfrac{4}{7}[/tex] of what Rahul had left.

[tex](x-350)=\dfrac{4}{7}\times (x-95)[/tex]

[tex]7(x-350)=4(x-95)[/tex]

[tex]7x-2450=4x-380[/tex]

Isolate the variable terms.

[tex]7x-4x=2450-380[/tex]

[tex]3x=2070[/tex]

[tex]x=\dfrac{2070}{3}[/tex]

[tex]x=690[/tex]

Now, the remaining amount of Rahul is:

[tex]x-95=690-95[/tex]

[tex]x-95=595[/tex]

Therefore, the correct option is B.

Answer:

I think its No Solution

Step-by-step explanation:

Hope it helps

Given:

[tex]PQRS\sim TUVW[/tex]

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

[tex]PQRS\sim TUVW[/tex]

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

[tex]k=\dfrac{VW}{RS}[/tex]

[tex]k=\dfrac{25}{35}[/tex]

[tex]k=\dfrac{5}{7}[/tex]

Therefore, the scale factor from PQRS to TUVW is [tex]k=\dfrac{5}{7}[/tex].

Answer:

7/5 is the scale factor

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

⏩ 107° angle will be an obtuse angle because its measurement is more than 90° but less than 180°.

⁺˚*･༓☾✧.* ☽༓･*˚⁺‧

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

An obtuse angle

Step-by-step explanation:

Angles are classified by how large their degree measure is. Here is a list of the basic classifications of an angle,

acute: degree measure between (0) and (90) degrees

right: exactly (90) degrees,

obtuse: degree measure between (90) and (180) degrees

reflex: degree measure between (180) and (360) degrees

Answer:

[tex]x = \frac{7 + \sqrt{65}}{2} \ , \ x = \frac{7 - \sqrt{65}}{2}[/tex]

Step-by-step explanation:

[tex]x^2 = 7x + 4 \\\\x^2 - 7x - 4 = 0\\\\ a = 1 \ , \ b = - 7 , \ c \ = \ - 4 \\\\x = \frac{-b \pm \sqt{b^2 - 4ac }}{2a}\\\\Substitute \ the \ values : \\\\x = \frac{7 \pm \sqrt{7^2 - (4 \times 1 \times -4)}}{2 \times 1}\\\\x = \frac{7 \pm \sqrt{49 + 16}}{2 }\\\\x = \frac{7 \pm \sqrt{65}}{2 }\\\\x = \frac{7 + \sqrt{65}}{2}\ , \ x = \frac{7 - \sqrt{65}}{2}[/tex]

Complete Question

A truck is being filled with cube-shaped packages that have side lengths 1/4 ​ foot. The part of the truck that is being filled is in the shape of a rectangular prism with dimensions 8ft × 6 1/4 ft × 7 1/2 ft. Find the number of cubes that can fill that part of the truck

Answer:

1500 cubes

Step-by-step explanation:

Step 1

Find the volume of the cube

V = side length ³

V = (1/4 ft)³

V = 1/64

Step 2

Find the volume of the rectangular prism

= Length × Width × Height

= 8ft × 6 1/4 ft × 7 1/2 ft

= 8 × 25/4 × 15/2

= 375 ft³

Step 3

Number of cubes in the truck

Volume of the Rectangular Prism ÷ Volume of the cube

= 375ft³ ÷ 1/4ft³

= 375 × 4

= 1500 cubes

Therefore, the number of cubes that can fill that part of the truck(Rectangular prism) = 1500 cubes

Answer:

4/8 = 1/2

Step-by-step explanation:

hope it thepled u

[tex]804.2\:ft^{2}[/tex]

Step-by-step explanation:

[tex]A=4 \pi r^{2}[/tex]

We are given D = 16 ft, which means that r = (1/2)D = 8 ft. Therefore, the surface area of the sphere is

[tex]A=4 \pi (8 ft)^{2} = 804.2\:ft^{2}[/tex]

The surface area of the sphere is approximately 804.2 square feet.

It is a three-dimensional figure where the volume is given as:

The volume of a sphere = 4/3 πr³

We have,

The surface area of a sphere with diameter d is given by the formula:

SA = 4πr²

where r is the radius of the sphere, which is half the diameter. In this case, the diameter is 16 feet, so the radius is 8 feet.

Plugging in the value of r, we get:

SA = 4π(8²)

SA = 4π(64)

SA = 256π

Rounding to the nearest tenth gives:

SA ≈ 804.2 square feet

Therefore,

The surface area of the sphere is approximately 804.2 square feet.

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Answer:

x=0;y=2

Step-by-step explanation:

4(-x+2)=2x+8 -4x+8=2x+8 -4x-2x=8-8 -6x=0 x=0 y=-x+2 y=0+2 y=2

Answer:

y=5, y=[tex]\frac{38}{11}[/tex]

Step-by-step explanation:

Hi there!

We are given the equation

[tex]\frac{y+2}{y-3}[/tex]+[tex]\frac{y-1}{y-4}[/tex]=[tex]\frac{15}{2}[/tex] and we need to solve for y

first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0

which means that y-3≠0, or y≠3, and y-4≠0, or y≠4

[tex]\frac{y+2}{y-3}[/tex] and [tex]\frac{y-1}{y-4}[/tex] are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions

Nonetheless, they are still fractions, and we need to add them.

To add fractions, we need to find a common denominator

One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together

Let's do that here;

on [tex]\frac{y+2}{y-3}[/tex], multiply the numerator and denominator by y-4

[tex]\frac{(y+2)(y-4)}{(y-3)(y-4)}[/tex]; simplify by multiplying the binomials together using FOIL to get:

[tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex]

Now on [tex]\frac{y-1}{y-4}[/tex], multiply the numerator and denominator by y-3

[tex]\frac{(y-1)(y-3)}{(y-4)(y-3)}[/tex]; simplify by multiplying the binomials together using FOIL to get:

[tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex]

now add [tex]\frac{y^{2}-2y-8}{y^{2}-7y+12}[/tex] and [tex]\frac{y^{2}-4y+3}{y^{2}-7y+12}[/tex] together

Remember: since they have the same denominator, we add the numerators together

[tex]\frac{y^{2}-2y-8+y^{2}-4y+3}{y^{2}-7y+12}[/tex]

simplify by combining like terms

the result is:

[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]

remember, that's set equal to [tex]\frac{15}{2}[/tex]

here is our equation now:

[tex]\frac{2y^{2}-6y-5}{y^{2}-7y+12}[/tex]=[tex]\frac{15}{2}[/tex]

it is a proportion, so you may cross multiply

2(2y²-6y-5)=15(y²-7y+12)

do the distributive property

4y²-12y-10=15y²-105y+180

subtract 4y² from both sides

-12y-10=11y²-105y+180

add 12 y to both sides

-10=11y²-93y+180

add 10 to both sides

11y²-93y+190=0

now we have a quadratic equation

Let's solve this using the quadratic formula

Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation

in this case,

a=11

b=-93

c=190

substitute into the formula

y=(93±√(8649-4(11*190))/2*11

simplify the part under the radical

y=(93±√289)/22

take the square root of 289

y=(93±17)/22

split into 2 separate equations:

y=[tex]\frac{93+17}{22}[/tex]

y=[tex]\frac{110}{22}[/tex]

y=5

and:

y=[tex]\frac{93-17}{22}[/tex]

y=[tex]\frac{76}{22}[/tex]

y=[tex]\frac{38}{11}[/tex]

Both numbers work in this case (remember: the domain is y≠3, y≠4)

So the answer is:

y=5, y=[tex]\frac{38}{11}[/tex]

Hope this helps! :)

Answer: C

Step-by-step explanation:

Answer:

[tex]V_w =1100[/tex] ---- velocity of wind

[tex]V_a = 150[/tex] --- velocity of airplane

Step-by-step explanation:

Given

[tex]V_a \to[/tex] velocity of airplane

[tex]V_w \to[/tex] velocity of wind

Flying with the wind, the distance (d) is:

[tex]d = (V_w + V_a) * t[/tex]

Where d and t are distance travel and time spent with the wind

So:

[tex]3750 = (V_w + V_a) * 3[/tex]

Divide by 3

[tex]1250 = (V_w + V_a)[/tex]

Flying against the wind, the distance (d) is:

[tex]d = (V_w - V_a) * t[/tex]

Where d and t are distance travel and time against with the wind

So:

[tex]3800 = (V_w - V_a) * 4[/tex]

Divide by 4

[tex]950 = (V_w - V_a)[/tex]

Make [tex]V_w[/tex] the subject

[tex]V_w= 950 + V_a[/tex]

Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]

[tex]1250 = 950 + V_a + V_a[/tex]

[tex]1250 = 950 + 2V_a[/tex]

Collect like terms

[tex]2V_a = 1250 -950[/tex]

[tex]2V_a = 300[/tex]

Divide by 2

[tex]V_a = 150[/tex]

Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]

[tex]V_w =950 +150[/tex]

[tex]V_w =1100[/tex]

Answer:

3c + 9

Step-by-step explanation:

Remember to multiply everything in the brackets by the number outside the brackets.