Which of the following situations are equal to 30%? Select all that apply.
A) 27 out of 90
B) 12 out of 36
C) 50 out of 80
D) 9 out of 30
E) 6 out of 24


Will give brainlest

Answers

Answer 1
The answer is A and D

Related Questions

In the diagram, Find the value of w

Answers

Answer:

-13

Step-by-step explanation:

the angle of ACD is 180-72 = 108 degrees.

simply because every side of a line represents 180 degrees of turning potential (to flip something around on a flat ground is a 180 degree turn). and we know 72 degrees are already "taken" at the other side of the angle.

BC bisects the angle. that means it divided the angle into 2 equal parts.

so the angle between BC and k is 108/2 = 54 degrees.

because j is parallel to k, this angle is the same as the angle between BC and j.

so,

54 = 2w + 80

-26 = 2w

w = -13

Solve the following system.
x2 + y2 = 20
y= x2

Answers

Answer:

x=2±√6. Explanation: Since we are given y in terms of x, we can substitute directly into the other equation...

3. Find the value of:
a) 9²
b) 15²
c) (0.2)²
d) (0.7)​

Answers

Answer:

Step-by-step explanation:

9^2

=9*9

=81

15^2

=15*15

=225

(0.2)^2

=0.2 * 0.2

=0.04

(0.7)

=0.7

2. How many degrees has PRQ been rotated to make PRQ

Answers

Answer:

180 degree

Step-by-step explanation:

180 degee

......

......

.......

Which angle is an obtuse angle?
A. 310°
B. 80°
O c. 260°
O D. 170°

Answers

Step-by-step explanation:

obtuse angle is an angle whose measure is more than 90 degree but less than 180 degree..

So,

170°

Russell deposited $200 to open a new bank account before he paid $250 for his portion of the rent. His bank charged him a $50 overdraft fee. Then he deposited his paycheck of $400. How much money is in Russell’s account now?

Answers

300 dollars I think is it multiple choice

The answers isssssssss

$300

:)


cosa \div tana = 1 - sin ^{2} a \div \sqrt{1 - cos ^{2} } acosa÷tana=1−sin
2

1−cos
2


a

Answers

Step-by-step explanation:

Hey there!

LHS

[tex] = \frac{ \cos(a) }{ \tan(a) } [/tex]

Use tan A = sin A/cosA

[tex] = \cos(a) \times \frac{ \cos(a) }{ \sin(a) } [/tex]

[tex] = \frac{ { \cos(a) }^{2} }{ \sin(a) } [/tex]

Then, Use formula cos²A = 1-sin²A and sinA = √(1-cos²A)

[tex] = \frac{1 - { \sin(a) }^{2} }{ \sqrt{ - { \cos(a) }^{2} } } [/tex]

Proved!

Hope it helps!

Question 6. * The number of likes a social media post has generated has been tracked as a function of the number of min since it was posted. The data is shown in the table below, where t is the number of minutes and I is the number of likes. If an exponential model was used to fit this data, which of the following would be closest to its prediction for the number of likes after one hour

Answers

Answer:

Step-by-step explanation:

yes

what is the derivative of y=(x^2√(1+x))/((1+x^2)^3/2))

Answers

Step-by-step explanation:

Maple calculator used.........................

Answer:

Step-by-step explanation:

[tex]f(x)={x^2\sqrt{1+x}\over{(1+x^2)^{3\over{2}}}}\\\\f^\prime (x)=\frac{{{(x^2\sqrt{1+x})^\prime (1+x^2)^{\frac{3}{2}}+ (x^2\sqrt{1+x})}((1+x^2)^{\frac{3}{2}}})^\prime}{((1+x^2)^\frac{3}{2})^2}}}[/tex]

[tex](x^2 \sqrt{1+x})^\prime=2x\sqrt{1+x}+ \frac{x^2}{2\sqrt{1+x}}[/tex]

[tex]((1+x^2)^{\frac{3}{2}})^\prime=\frac{3}{2}(1+x^2)^{\frac{1}{2}} (2x)=3x(1+x^2)^{\frac{1}{2}}[/tex]

[tex]f^\prime(x)=\frac{\{(1+x^2)^{\frac{3}{2}}\}(2x\sqrt{1+x}+\frac{x^2}{2\sqrt{1+x}})+(x^2 \sqrt{1+x})(3x\sqrt{1+x^2})}{(1+x^2)^{3}}}[/tex]

[tex]\sqrt{1+x^2}=\sqrt{(1+x)(1-x)}[/tex]

[tex]f^\prime (x)=x\sqrt{1+x}~\frac{(1+x^2)^{\frac{3}{2}}(2+\frac{x^2}{2(1+x)})+3x^2\sqrt{1-x}}{(1+x^2)^3}[/tex]

Do they take your phones and watch you take the cumulative test on edginuity?

Answers

Answer:

I don't know what your school is doing but what happened to me was that I just waited for the test to be unlocked and I was working from home so I was able to keep my phone and I didn't need to be in a meeting

Los principales accionistas de la empresa global zafiro S.A. están interesado en una empresa que representa una importante competencia. Entre los datos de la empresa tiene los siguientes: la planta opera a nivel que oscila entre 80 y 100% de su capacidad. Cuando su nivel de actividad es de 80% los costos variables de fabricación totalizan $180,000,000. A su nivel normal de 90% de la empresa utiliza 40,500 horas de mano de obra directa y tiene costos de fabricación totales de $371,500,000. Determina los costos de fabricación finos y variables al 80 y 100% de su capacidad

Answers

Answer:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Explicación:

 

Los costos totales de fabricación (CT) vienen dados por la suma de los costos fijos (CF) y los costos variables (CV), recordando que los costos fijos son aquellos en los que se incurre independientemente de que se esté operando o no; mientras que los costos variables son aquellos que dependen del nivel de actividad pues corresponden a consumibles en el proceso productivo.

En el caso estudio, se sabe que los costos variables de fabricación totalizan $180,000,000.00 al nivel de actividad de 80%. Ya que estos costos incrementan o disminuyen en relación con el nivel de actividad, planteamos una regla de tres simple para calcular los costos variables en los niveles de actividad 90% y 100%

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    90%    de actividad        ----------------    los CV serán    x

x  =  [(90)(180,000,000.00)]/(80)  =  202,500,000.00

Los costos variables de fabricación al nivel de actividad de 90% son  $202,500,000.00

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    100%    de actividad       ----------------    los CV serán    x

x  =  [(100)(180,000,000.00)]/(80)  =  225,000,000.00

Los costos variables de fabricación al nivel de actividad de 100% son  $225,000,000.00

Para conocer los costos fijos basta recordar que al nivel de actividad de 90% lo costos de fabricación totales son $371,500,000.00. Este monto es la suma de los costos fijos y los costos variables; así que:

CT  =  CV  +  CF             ⇒                CV  =  CT  -  CF          ⇒    

CV  =  371,500,000.00  -  202,500,000.00  =  169,000,000.00

Los costos fijos de fabricación son de $169,000,000.00

Conclusión:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Graph the image of rectangle BCDE after a translation 8 units left and 5 units up.​

Answers

E (-4,8) D(2,8) B(-4,1) C(2,1)

calculate 5/10÷9 please​

Answers

Answer:

1/2 times 1/9

which equals 1/18

Step-by-step explanation:

5/10 equals 1/2 and /9 equals *1/9

Answer: i think its 1/9

Which of the following represents the ratio of the given side to the
hypotenuse?

HELP if you’re good at GEOMETRY!!

Answers

C that’s the answer

the product of -3 and m increased by 7 is -20. what is the value of m?

Answers

Answer:

The value of m is 9.

Step-by-step explanation:

We need to set up an algebraic equation, then solve.

(-3 * m) + 7 = -20

-3m + 7 = -20

Subtract 7 from both sides so we can get -3m by itself. We are isolating it.

-3m + 7 - 7 = -20 - 7

-3m = -27

Divide by -3 on both sides.

m = 9

The value of m is 9.

Please help solve this using L.C.M and explain the steps plz ty.

Answers

9514 1404 393

Answer:

  (x, y) = (2, 3)

Step-by-step explanation:

The first step is to find the least common multiple of the denominators of each of the equations. If the denominators have no common factors, a reasonable choice is their product. Here, it works to start with the fractions that must be added, then compare the LCM found to the denominator on the right to see if any further factors must be included.

First equation:

  LCM = 3×4 = 12

  12(2x/3 -y/4) = 12(7/12) . . . . . multiply the equation by 12

 8x -3y = 7 . . . . . . . . . simplify

Second equation:

  LCM = 4×5 =20

  20(3x/4 -2y/5) = 20(3/10) . . . . multiply equation by 20

  15x -8y = 6 . . . . . . simplify

Solve by elimination

We can eliminate the y-variable by subtracting 3 times the second equation from 8 times the first:

  8(8x -3y) -3(15x -8y) = 8(7) -3(6)

  19x = 38 . . . . . simplify

  x = 2 . . . . . . . divide by 19

Substituting into the first equation gives ...

  8(2) -3y = 7

  3y = 9 . . . . . . add 3y-7

  y = 3 . . . . . divide by 3

The solution is ...

  (x, y) = (2, 3)

_____

There are many ways to solve such a system of equations. Using the LCM to eliminate fractions is one way to start. You can also do the arithmetic with the fractions intact, though most folks don't care to. In addition to the elimination method used here, you can use matrix or graphical methods, substitution, or any of the variations of Cramer's Rule.

Find the Value of X (in this picture)​

Answers

9514 1404 393

Answer:

  x = 64

Step-by-step explanation:

The two base angles in the isosceles obtuse triangle are equal, so are both 29°. The sum of these angles is 58°, which is the measure of the external acute angle at the upper left of the acute triangle.

The two base angles of the acute isosceles triangle are equal, so are both 58°. The angle marked x° has a measure that makes the sum of angles in that triangle be 180°.

  x° = 180° -2(58°)

  x° = 64°

Please awnser
Please help

Answers

Answer:

I believe the answer would be 11/30 longer but you might want to simplify it

Mark Brainliest please

Answer is 11/30

The orange fish is foot longer than blue fish.
Step-by-step explanation:

Solution :
The blue fish length is 2/15 foot.
The orange fish length is 5/10 foot.

Now, we have to find how much longer is orange fish that means there is a comparison with blue fish.

So, the length of orange fish than blue is

5/10 - 2/15

= 55/150

= 11/30





Therefore, The orange fish is 11/30 foot longer than blue fish.

A puppy named Dusty started out at 2 pounds and gained 1 pound every month. At
how many months did Dusty weigh 6 pounds?

Answers

Answer:

4 months

Step-by-step explanation:

Let x be the number of months

Dusty started at 2 lbs, and gains 1 lb every month

So we can make the equation

2+x=6

x=4

At 4 months, Dusty was 6 lbs

Anyone know this? Please help

Answers

Answer:
C
Explanation
Because i said so

NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math.No guessing please.

Keisha's teacher gives her the following information:

• m,n,p,and q are all integers and p= 0 and q=0

•A= m/q and B= n/p

What conclusion can Keisha make?

A: A +B = mp+nq/PQ,so the sum of a rational number and an irrational number is an irrational number.

B: A•B= mp+nq/PQ,so the product of two irrational numbers is an irrational number.

C: A+B= mp + nq/PQ,so the sum of two rational numbers is a rational number.

D: A•B= mp + nq/PQ,so the product of two rational numbers is a rational number.​

Answers

Answer:

C.

Step-by-step explanation:

Integers are rational numbers.

A + B = m/q + n/p = (mp + nq)/pq

Please help don't get it.

Answers

Answer:

Part A: B is the answer since if you move the triangle they would be differently rotated

Part B: the answer is C since if you translate both over the y-axis and then the x-axis you will get the other pair

2×(4×2-10)³ How do you simplify powers in this? ​

Answers

Answer:

Step-by-step explanation:

first work what's in the brackets { 4 x 2 -10}^3

{4 x 2-1000}

4 x -998

Answer = -16

Explication:

FYI: Use P.E.M.D.A.S
(Parentheses, exponent, multiply or divide, add or subtract)

2(4x2-10)^3
4x2=8
(8 - 10)
2(8-10)^3
8-10=-2
(-2)
2(-2)^3
-2^3=-8
2 (-8)
-16

khjdfasagggggggg
chikcen

Answers

Answer:

Hahaha I love u

Step-by-step explanation:

Hihi kilig kanooo

If 8 x - 4 = 6 - 3 x then x =

Answers

Answer:

x = 10/11

Step-by-step explanation:

Your welcome! :)

The answer is equals to 10/11 which is also the same as 0.9090 approximately it is 1

Mathematical Literacy Assignment no 2021​

Answers

what’s the question ??

Find the simple interest on a loan of ₱65,000.00 if the loan is given at a rate of 2% and is

due in 5 years and 3 months?​

Answers

Answer:

6,825

Step-by-step explanation:

The principlal is #65,000

Rate, = 2%

= 2/100

= 0.02

Time= 5+0.25

= 5.25

Simple interest= 65,000×0.02×5.25

= 6,825

Solve for x.
-15x + 60 ≤ 105 AND 14x + 11 ≤ -31
Choose 1 answer:
A. x ≤ -3
B. x ≥ -3
C. x = -3
D. There are no solutions
E. All values of x are solutions

Answers

Answer:

C. x = -3

Step-by-step explanation:

-15x + 60 <= 105

-15x <= 45

-x <= 3

x >= -3

14x + 11 <= -31

14x <= -42

x <= -3

the only solution that is in both solution areas is x = -3.

for all other values of x we violate one of the 2 conditions.

Find the value of the polynomial 3x
3 – 4x
2+ 7x + 5, when x = 3 and also when
x = –3.

Answers

Answer:

71

-133

Step-by-step explanation:

Given the polynomial :

3x³– 4x² + 7x + 5, when x = 3 and also when

x = –3.

Put x = 3

3(3)³– 4(3)² + 7(3) + 5

3(27) - 4(9) + 21 + 5

81 - 36 + 21 + 5

= 71

Put x = - 3

3(-3)³– 4(-3)² + 7(-3) + 5

3(-27) - 4(9) - 21 + 5

-81 - 36 - 21 + 5

= - 133

Solve this equation 2n-9<25

Answers

Answer:

n < 17

Step-by-step explanation:

2n-9<25

Add 9 to each side

2n-9+9<25+9

2n < 34

Divide each side by 2

2n/2 < 34/2

n < 17

Answer:

n < 17

Step-by-step explanation:

Move the constant to the right -hand side and change its sign

2n<25+9

Then add the numbers

2n < 34

Divide both sides of the inequality by 2

so that would be n<17

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