which
Which of the following lines is perpendicular to y = 3x + 2?
A.
1
y = 3x --
2
B.
-1
= — X+6
3
C.
1
y = -x +2
3
D.
1
y = 3x +-
2

Answers

Answer 1
the answer is B. -1/3x + 6

Related Questions

Find the value of x and y is (3x_6) (12,y-1)​

Answers

Answer:

x=4

y=7

Step-by-step explanation:

12=3x

x=4

6=y-1

y=6+1

y=7

Answer:

x=4

Step-by-step explanation:

The width of a rectangle is 9 less than twice its length. If the area of the rectangle is 129cm^2. What is the length of the diagonal? Give your answer to 2 decimal places.

Answers

Answer:  16.14  cm

==========================================================

Explanation:

L = x = length of the rectangleW = 2x-9 = width of the rectangle, since its 9 less than twice the length

area of rectangle = L*W = 129

L*W = 129

x*(2x-9) = 129

2x^2-9x = 129

2x^2-9x-129 = 0

Apply the quadratic formula. We'll use a = 2, b = -9, c = -129.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-9)\pm\sqrt{(-9)^2-4(2)(-129)}}{2(2)}\\\\x = \frac{9\pm\sqrt{1113}}{4}\\\\x \approx \frac{9\pm33.36165464}{4}\\\\x \approx \frac{9+33.36165464}{4}\ \text{ or } \ x \approx \frac{9-33.36165464}{4}\\\\x \approx \frac{42.36165464}{4}\ \text{ or } \ x \approx \frac{-24.36165462}{4}\\\\x \approx 10.59041366\ \text{ or } \ x \approx -6.09041364\\\\[/tex]

We ignore the negative solution because a negative length makes no sense.

The length is approximately L = 10.5904 cm.

The width is 2L-9 = 2*10.5904-9 = 12.1808 cm approximately.

As a quick check,

L*W = 10.5904*12.1808 = 128.99954432

which isn't too far off from 129. We have rounding error which is why we don't perfectly land on the target area value. If you wanted to get closer to the value 129, then use more decimal digits in the approximations of L and W.

----------------------------

If you draw a diagonal in the rectangle, then you form two identical or congruent right triangles.

Focusing on one of those triangles, we have

a = 10.5904b = 12.1808c = unknown hypotenuse = diagonal length

Apply the pythagorean theorem

a^2+b^2 = c^2

c = sqrt( a^2 + b^2 )

c = sqrt( (10.5904)^2 + (12.1808)^2 )

c = 16.1408940520653

c = 16.14

The diagonal is roughly 16.14 cm long.

so, sunny is 16 he is 132 pounds
the song my time lasts 3:33 and sunny is falling for an entire 3 minutes
the gravitational pull which is pulling sunny back down to the ground is about 10m/s²
we have the new height of the hospital, is 49312,674 meters, or 161.787 feet
upon theory, sunny died upon coming to contact with the ground if you fall head first from 100 feet you're bound to die
you can break just your legs from falling from atleast 16-18 feet so imagine that

??????

Answers

The answer would be 79 because the dog punched the alpaca

What are the first and third quartiles for the following data set?
12, 15, 18, 16, 14, 9, 12, 21
A 9 and 21
C 12 and 17
B 12 and 16
D 15 and 17

Answers

Answer:

A

Step-by-step explanation:

I guess that is it may be

solve for x : 2(x^2+9)-4=0

Answers

Answer:

no solution

Step-by-step explanation:

multiply 2 and get 2x^2+18-4=0

combine like terms

2x^2+14=0

subtract 14

2x^2=-14

there can't be a square root of a negative number so there's no solution

Answer:

x = ±i sqrt(7)

Step-by-step explanation:

2(x^2+9)-4=0

Add 4 to each side

2(x^2+9)-4+4=0+4

2(x^2+9)=4

Divide by 2

2(x^2+9)/2=4/2

(x^2+9)=2

Subtract 9 from each side

x^2 +9-9 = 2-9

x^2 = -7

Taking the square root of each side

sqrt(x^2) =sqrt(-7)

x = sqrt(-1 *7)

x = ±i sqrt(7)

Suppose (-13,2) is a point on the graph of y=f(x). What is a point that will be on the graph of y=9f(x)-5

Answers

9514 1404 393

Answer:

  (x, y') = (-13, 13)

Step-by-step explanation:

At the given value of x, f(x) = 2. Then 9f(x)-5 = 9(2) -5 = 13.

The point on the scaled, translated graph will be ...

  (x, y') = (-13, 13)

_____

The graph shows a function f(x) with a distinct feature (vertex) at (-13, 2). It also shows where that distinct feature moves to when the function is scaled and translated.

10x^3 - 25x^2 + 20
How to factor this

Answers

5(2x^2-x-2)(x-2)

Step-by-step

Answer:  [tex]5(\frac{10x^3}{5}+\frac{-25x^2}{5}+\frac{20}{5}) \\\\5(2x^3-5x^2+4)\\\\5(2x^2-x-2)(x-2)[/tex]

A school sports team contains 68 students. 33 do field events, 40 do track events, 23 do swimming, 14 do both field and track events, 8 do both swimming and field events. If 15 students do field events only and 10 do both swimming and track events, how many students do a. Swimming only b. Track events only c. All three events? ​

Answers

Answer:

a. 9 students

b. 20 students

c. 4 students

9 students20 students4 students

Polygon mnopq is dialated by scale factor of 0.8 with the origin as the center dilation resulting in the image MNOPQ the coordinates of point M are (2,4) and the coordinates of point N are (3,5). The slope of MN is?

Answers

9514 1404 393

Answer:

  1

Step-by-step explanation:

The slope is given by the formula ...

  slope = (y2 -y1)/(x2 -x1)

  slope = (5 -4)/(3 -2) = 1/1 = 1

The slope of MN is 1.

__

Dilation does not change the slope.

A^2 + 2AB +B^2



habsbsjabdhjsbfhjbsdjh

Answers

(A+b)(a+b)
I dont understand the writing. I’m doing this math using factoring

Find the fraction equivalent to 5/7 with: a) numerator 25 b) denominator 42​

Answers

Answer:

a) 25/35

b) 30/42

Step-by-step explanation:

a)

Variable x = denominator if numerator is 25

5/7 = 25/x

5 × x = 7 × 25

5x = 175

x = 35

b)

Variable y = numerator if denominator is 42

5/7 = y/42

5 × 42 = 7 × y

210 = 7y

30 = y

25/35

30/42

To get 25/35 multiply by 5

To get 30/42 multiply by 6

Given that the supply and demand function for the product type is Qd = [tex]\sqrt{260-p}[/tex],
Qs = [tex]\sqrt{p-14}[/tex]. consumer surplus ??.

Answers

Secs jrjrjsjrjsrjjjjjrjjjrjrjjjjjrjj try t
U
Ojim okay omjjmmimp oil my kkui mom m
Ok oulo
Lmk
Onjominml I’m o mmm I’m

WILL GIVE BRAINLIEST
Complete the equation describing how
x and y are related.
х
-3
-2
-1
0
1
2
3
y
12
8
4
0
-4
-8
-12
y = [? ]x

Answers

Answer:

[tex]y=4x[/tex]

Answer:

y = -4x

hope that helped.........

Solve the system of equations.
3x + 4y + 3z = 5
2x + 2y + 3z = 5
5x+ 6y+7z = 7
a. (x = 13, y=-6, z = -2)
b. (x = 15, y = -8, z = -4)
c. (x = 16, y = -9, z = -1)
d. (x = 14, y = -7, z = 3)

Answers

Answer:

x = 14

y = -7

z = -3

but this is none of the provided answer options !

Step-by-step explanation:

it's really easy by principle. it's just some work to do.

we try to find equations to express one variable in terms of the others.

but one thing there is : your teacher made a mistake.

the right solution is x = 14, y = -7, z = -3

your teacher made a typo at d.

but the right answer should be d.

just to give you an idea how this can be done (and also to prove that there is a mistake by the teacher):

we can directly try to transform one expression into one that describes x by y and z.

and then another to describe e.g. z by y. and then solve the third one just for y. and then we get the other 2 by these other expressions.

or we can e.g. add or subtract one equation to/from another. this is one of these cases, because we can find really simple expressions that way :

we do

5x + 6y + 7z = 7

- (3x + 4y + 3z = 5)

- (2x + 2y + 3z = 5)

---------------------------

0x + 0y + z = -3

=> z = -3

3x + 4y - 3×3 = 5

3x = -4y + 14

x = (-4y + 14)/3

2×(-4y + 14)/3 + 2y - 9 = 5

(-8y + 28)/3 + 2y = 14

-8y + 28 + 6y = 42

-2y = 14

y = -7

x = (-4×-7 + 14)/3 = (28+14)/3 = 42/3 = 14


Assume x and y are two odd numbers and x/y is an integer.
Which of the following statements are true?
I. x + y is odd
2. xy is odd.
3. x/y is odd
4. x-y is odd







Answers

Answer:

Let us check these out one at a time:

 

1. x + y is odd.  FALSE.  The sum of 2 odd numbers is even.

2. xy is odd.  TRUE.  The product of 2 odd numbers is odd.

3. x/y is odd.  TRUE.  The ratio of 2 odd numbers is odd, if the ratio is an integer.

4. x - y is odd.  FALSE.  The difference of 2 odd numbers is even.

 

Only statements 2 and 3 are TRUE, so that makes (C) the correct answer.

what is the scale of factor?

Answers

The length of CV is 5 units

The length of C’V’ is 7.5 units

The scale factor is 7.5 / 5 = 1.5

Answer: 1.5

Sandra ride her bike 5 times as many miles as Barbara. If b, the distance Barbara rode equals 3.4 miles what is the correct expression and the distance Sandra rode

Answers

Answer:

b + 5; when b = 3.4 the distance Sandra rode is 17 miles.

Step-by-step explanation:

A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line?

Answers

Answer:

y= 1/2x-3/2

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 1/2x+b

Using the point for x and y we can find b

-3 = 1/2(-3)+b

-3 = -3/2 +b

-6/2 = -3/2+b

Add 3/2 to each side

-6/2 +3/2 = b

-3/2 = b

y= 1/2x-3/2

Answer:

Step-by-step explanation:

y + 3 = 1/2(x + 3)

y + 3 = 1/2x + 3/2

y + 6/2 = 1/2x + 3/2

y = 1/2x - 3/2

If the slope of a wheelchair ramp is 1/11 then what is the angle of inclination to the nearest tenth of a degree?

Answers

Answer

4.8 degrees to the nearest tenth.

Step-by-step explanation:

The slope = rise / run = opposite side / adjacent side.

So the angle of inclination is the angle whose tangent is 1/12.

To the nearest tenth of a degree it is 4.8 degrees.

The answer is 4.8 degrees

7. Ten samples of 15 parts each were taken from an ongoing process to establish a p-chart for control. a. Develop a p-Chart for 95 percent confidence (1.96 standard deviation). b. Based on the plotted data points, what comments can you make

Answers

Answer: Hello the table related to your question is attached below

answer:

a) attached below

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Step-by-step explanation:

a) p-chart for 95% confidence

std = 1.96

Total defects = ∑ number of defective items in the sample = 10

number of samples = 10

sample size ( n ) = 15

The P value for the process is calculated as :

Total defects / ( number of sample * sample size )

= 10 / ( 15 * 10 ) = 10 / 150 = 0.067

standard deviation ( σ ) = [tex]\sqrt{\frac{p(1-p)}{n } } = \sqrt{\frac{0.067(1-0.067)}{15} }[/tex]  =  0.065

next we determine the limits ( i.e. upper and lower )

UCL = p + zSp = 0.067 + 1.96(0.065 ) = 0.194

LCL = p - zSp = 0.067 - 1.96(0.065) = -0.060 ≈ 0 ( because LCL ≠ negative)

attached below is the required p-chart

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Natalie's team needs to make a decision on how to handle a big product recall. People on the team have a lot of strong opinions. Management wants everyone to come to a consensus and to find a solution that everyone can support. What's the best way to get to a consensus? a) Everyone on the team talks until the entire team agrees on one decision. O b) Everyone on the team discusses options and then votes. O c) The team passes the decision-making responsibility to an outside person. O di The team leader makes a decision without input from the other members.

Answers

B) Everyone on the team discusses options and then and then votes.

PLEASE HELP ASAP!!! (answer in decimal)

Answers

Answer:

re send it

Step-by-step explanation:

ty

HELP PLEASEEEE!!!! ASAP

Answers

Answer:

6.22 sec

Step-by-step explanation:

h(t) = 105t-16t^2

For values of t for which height will be 34 feet can be obtained by substituting 34 in place of h(t) and solving for t

34=105t-16t^2, using quadratic formula we have t=1/32*(105±sqrt(8849)) which translates to - 0.34sec and 6.22sec but as time can't be negative, time is 6.22sec

(1+y²)dx + (1+x²)dy = 0

Answers

This differential equation is separable:

(1 + y²) dx + (1 + x²) dy = 0

(1 + y²) dx = - (1 + x²) dy

dy/(1 + y²) = -dx/(1 + x²)

Integrating both sides gives

arctan(y) = -arctan(x) + C

and solving for y gives (over an appropriate domain)

y = tan(C - arctan(x))

(the domain being -1 ≤ y ≤ 1).

A sample of 38 babies in the zinc group had a mean birth weight of 3328 grams. A sample of 31 babies in the placebo group had a mean birth weight of 3406 grams. Assume that the population standard deviation for the zinc group is 640 grams, while the population standard deviation for the placebo group is 851851 grams. Determine the 99% confidence interval for the true difference between the mean birth weights for "zinc" babies versus "placebo" babies.

Required:
Find the point estimate for the true difference between the population means.

Answers

Answer:

-78

Step-by-step explanation:

Zinc group :

Mean, x1 = 3328

σ1 = 640

Sample size, n1 = 28

Placebo group :

Mean, x2 = 3406

σ2 = 851

Sample size, n2 = 31

The point estimate for the true difference between the population means is obtained as :

Mean difference between population :

x1 - x2 = 3328 - 3406 = - 78

What is the length of BC in the right triangle below?
B
00
A
15
с
A. 17
B. 60
C. 17
D. 289

Answers

Perpendicular=P=8Base=B=15Hypotenuse=H

Using Pythagorean Theorem

[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]

[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]

[tex]\\ \sf\longmapsto H^2=64+225[/tex]

[tex]\\ \sf\longmapsto H^2=289[/tex]

[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]

[tex]\\ \sf\longmapsto H=17[/tex]

BC=17

PLZ HELPPPPPPPPPPPPPPPPPPP

Answers

We can see : KM = KL + LM
So : KM = 14 + 3 = 17
So KM = 17

Hope it helps! If it is, Brainliest please!

Assume a random variable representing the amount of time it takes for a customer service representative to pick up has a uniform distribution between 15 and 20 minutes. What is the probability that a randomly selected application from this distribution took less than 18 minutes

Answers

Answer:

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniform distribution between 15 and 20 minutes.

This means that [tex]a = 15, b = 20[/tex]

What is the probability that a randomly selected application from this distribution took less than 18 minutes?

[tex]P(X < 18) = \frac{18 - 15}{20 - 15} = 0.6[/tex]

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Fill in the blank with a number to make the expression a perfect square.
u^2- 18u +

Answers

Answer:

u^2- 18u +81 = (u-9)^2

Step-by-step explanation:

u^2- 18u +

Take the u coefficient

-18

Divide by 2

-18/2 = -9

Square it

(-9)^2 = 81

u^2- 18u +81 = (u-9)^2

Answer:

The blank should contain 81

Step-by-step explanation:

E = u^2 - 18u + (-18/2)^2

E = (u^2 - 18u + 9^2)

E = (u - 9)^2

To be perfectly correct what you have there is a perfect square, but you need to subtract out (9/2)^2 to make it a valid statement.

E = (u - 9)^2 - 81

divide 111001 by 1101​

Answers

Based on the fact that you asked this three times and got the same answer three times, I suspect the interpretation made by the users that posted those answers was incorrect, and that you meant to ask about dividing in base 2.

We have

111001₂ = 1×2⁵ + 1×2⁴ + 1×2³ + 1×2⁰ = 57

1101₂ = 1×2³ + 1×2² + 1×2⁰ = 13

and 57/13 = (4×13 + 5)/13 = 4 + 5/13.

4 = 2² is already a power of 2, so we have

111001₂/1101₂ = 1×2² + 5/13

we just need to convert 5/13. To do this, we look for consecutive negative powers of 2 that 5/13 falls between, then expand 5/13 as the sum of the smaller power of 2 and some remainder term. For instance,

• 1/4 < 5/13 < 1/2, and

5/13 - 1/4 = (20 - 13)/52= 7/52

so that

5/13 = 1/4 + 7/52

or

5/13 = 1×2 ⁻² + 7/52

Then a partial conversion into base 2 gives us

111001₂/1101₂ = 1×2² + 1×2 ⁻² + 7/52

111001₂/1101₂ = 100.01₂ + 7/52

Continuing in this fashion, we find

• 1/8 < 7/52 < 1/4, and

7/52 = 1/8 + 1/104

==>   111001₂/1101₂ = 100.011₂ + 1/104

• 1/128 < 1/104 < 1/64, and

1/104 = 1/128 + 3/1664

==>   111001₂/1101₂ = 100.0110001₂ + 3/1664

• 1/1024 < 3/1664 < 1/512, and

3/1664 = 1/1024 + 11/13312

==>   111001₂/1101₂ = 100.0110001001₂ + 11/13312

• 1/2048 < 11/13312 < 1/1024, and

11/13312 = 1/2048 + 9/26624

==>   111001₂/1101₂ = 100.01100010011₂ + 9/26624

• 1/4096 < 9/26624 < 1/2048, and

9/26624 = 1/4096 + 5/53248

==>   111001₂/1101₂ = 100.011000100111₂ + 5/53248

and so on.

It turns out that this pattern repeats, so that

[tex]\displaystyle \frac{111001_2}{1101_2} = 100.\overline{011000100111}_2[/tex]

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