Answer:
960 Watt
Explanation:
From the question,
Electric power = Voltage squared/Resistance
P = V²/R ..................... Equation 1
Where P = power, V = Voltage, R = Resistance
Given: V = 120 volts, R = 15 ohms.
Substitute these values into equation 1
P = 120²/15
P = 14400/15
P = 960 Watt
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Answer:
[tex]\boxed {\boxed {\sf 252.5 \ Newtons }}[/tex]
Explanation:
Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.
[tex]F=m*a[/tex]
The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:
[tex]m= 50.5 \ kg[/tex][tex]a= 5.0 \ m/s^2[/tex]Substitute the values into the formula.
[tex]F= 50.5 \ kg * 5.0 \ m/s^2[/tex]
Multiply.
[tex]F=252.5 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.[tex]F= 252.5 \ N[/tex]
The force required is 252.5 Newtons.
All waves change speed when they enter a new medium, but they don't always bend. When does bending occur?
Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction
The only major country that does not use the metric system
A.
France
B.
United States
C.
Russia
D.
England
An object has a weight of 1550N when it is on the surface of a planet of radius R. What will be the gravitational force on the object after it has been moved to a distance of 4R from the surface of the planet?
Answer:
W = 96.875 N
Explanation:
For this exercise let's use the law of universal gravitation
F = [tex]G \frac{m M }{r^2}[/tex]
we substitute this force in Newton's second law
F = m a
G \frac{m M }{r^2} = m a
a = [tex]G \frac{M}{r^2}[/tex]
This sidewalk we will call it gravity acceleration
g₀ = a
the weight of a body is
W₀ = m g₀
if we change the cario of r ’= 4r
a’= [tex]G \frac{M}{r'^2 }[/tex]
a ’= G \frac{M}{(4r)^2 }
a' = [tex]G \frac{M}{r^2} \ \frac{1}{16}[/tex]
a ’= [tex]\frac{g_o}{16}[/tex]
therefore the weight of the body must be
W = m g = [tex]m \ \frac{g_o}{16}[/tex]
W = W₀ / 16
W = 1550/16
W = 96.875 N
A 100 L ball is blown up inside at 200K. It is then taken outside in the hot sun, and the volume increases to 150 L. What is the new temperature?
Answer:
Temperature, T2 = 300 Kelvin
Explanation:
Given the following data;
Initial volume = 100 Liters
Initial temperature = 200 Kelvin
Final volume = 150 Liters
To find the final temperature T2, we would use Charles' law.
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles is given by;
[tex] \frac {V}{T} = K[/tex]
[tex] \frac{V1}{T1} = \frac{V2}{T2}[/tex]
Making T2 as the subject formula, we have;
[tex] T_{2}= \frac{V_{2}}{V_{1}} * T_{1}[/tex]
Substituting into the formula, we have;
[tex] T_{2}= \frac{150}{100} * 200[/tex]
[tex] T_{2}= 1.5 * 200 [/tex]
Temperature, T2 = 300 Kelvin
How can seismographs be used to predict hurricane intensity?
Answer: The earth is a noisy place. Seismometers, which measure ground movements to detect earthquakes, volcanic eruptions, and manmade explosives, are constantly recording smaller vibrations caused by ocean waves, rushing rivers, and industrial activity.
Explanation:
A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically equal to the instantaneous velocity. The mass is initially released from a point foot above the equilibrium position with a downward velocity of ft/s. Determine the time at which the mass passes through the equilibrium position. Find the time at which the mass attains its extreme displacement from the equilibrium position. What is the position of the mass at this instant
Answer:
hello your question has some missing values attached below is the complete question with the missing values
answer :
a) 0.083 secs
b) 0.33 secs
c) 3e^-4/3
Explanation:
Given that
g = 32 ft/s^2 , spring constant ( k ) = 2 Ib/ft
initial displacement = 1 ft above equilibrium
mass = weight / g = 4/32 = 1/8
damping force = instanteous velocity hence β = 1
a)Calculate the time at which the mass passes through the equilibrium position.
time mass passes through equilibrium = 1/12 seconds = 0.083
b) Calculate the time at which the mass attains its extreme displacement
time when mass attains extreme displacement = 1/3 seconds = 0.33 secs
c) What is the position of the mass at this instant
position = 3e^-4/3
attached below is the detailed solution to the given problem
Blackie, a cat whose mass is 6-kg, is napping on top of the refrigerator when he rolls over and fall. Blackie has a KE of 90-J just before he lands on his feet on the floor.
How tall is the refrigerator?
To answer this question, you need to understand the law of conservation of energy. Essentially, the law states that energy cannot be created or destroyed; it is always conserved.
Knowing this law, how can we answer this question? Well, let's look at what the question tells us. We know that Blackie was initially at the top of a refrigerator before rolling over and falling to the ground. At ground level, he only has Kinetic energy when he lands. Since we know that he started at the top of the fridge, we know that Blackie started off with potential gravitational energy.
That would make sense, right? Written out as an equation, it'd be:
[tex]U_{g}[/tex] = [tex]K_{E}[/tex]
This follows the law of conservation of energy, as all the potential gravitational energy is converted into Kinetic energy.
Now, we know what energies are converted. What can we do with it? Recall the equation of potential gravitational energy:
[tex]U_{g}[/tex] = [tex]F_{g}[/tex]∆H
[tex]U_{g}[/tex] = mg∆H
Do you see it now? ∆H is the distance that Blackie falls, and since Blackie jumps from the fridge to the ground, ∆H must be the height of the fridge!
Let's start solving for ∆H:
[tex]U_{g}[/tex] = [tex]K_{E}[/tex]
Substitute potential gravitational energy with our equation:
mg∆H = [tex]K_{E}[/tex]
We were given the value of Kinetic Energy:
mg∆H = 90
Isolate ∆H by dividing both sides by mg:
∆H = [tex]\frac{90}{mg}[/tex]
Input values for 'm' and 'g' (m is the mass of Blackie and g is Earth's acceleration)
∆H = [tex]\frac{90}{6*9.80}[/tex]
∆H = [tex]\frac{90}{58.8}[/tex]
∆H = 1.53
The refrigerator is 1.53 meters tall.
And that's it! Let me know if you need me to explain anything I did here.
- breezyツ
A 2.5m long steel piano wire has a diameter of 0.5cm how great is the tention in the wire if it stretches by 0.45cm when tightened taking the young's modulus to be 2.0×10^11 N/m^2
Answer: Their u go i found it their was about 3 pages i did not no what pages u had to do.
Explanation:
Static electricity is an excess of charge.
A. True
B. False
Answer:
Its true
Explanation:
A force of 50N on a particle of mass 'm' the particles starts from rest and travels in a straight line through a distance of 25m in 5 seconds what is the mass of the object
Answer:
Explanation:1N=9,8kg
50*9,8=?
M=490KG
[N]s.i.=M
A 5 kg ball is sitting on top of a hill. It has a Potential Energy of 6000J. What is the height of the ball?
Explanation:
mass=5 kg
potential energy=6000j
height=?
Now
potential energy =m.g.h
or 6000=5*9.8*h
or 6000=49h
or 6000÷49=h
or h= 122.45m
what are the uses of convex lens
Answer:A convex lens is employed in microscopes and magnifying glasses to converge all incoming light rays to a particular point. ...
The convex lens is used in cameras. ...
A convex lens is used for the correction of hyperopia. ...
The converging lens is used in the projector as well.
An object is located 20.0 cm from a convex lens. The lens focuses light at a
distance of 10.0 cm. What is the image distance?
A. 6.67 cm
B. -6.67 cm
C. -20.0 cm
D. 20.0 cm
The Answer Is : D. 20.0 cm
My Reason : These types of problems can all be solved using the lens or mirror equation.
1/20 +1/q= 1/10
q=20 cm
The image is formed behind the lens at 2f or the center of curvature.
It is real, inverted, and the same size as the object
The Answer Is: D. 20.0 cm
Explanation: I did the test :)
SE UM CORPO ELETRICAMENTE NEUTRO É CARREGADO COM PROTONS, entao afirmamos; a) fica carregado negativamente b) fica carregado só com cargas positivas c) fica carregado positivamente d) fica com excesso de eletrons e) continua eletricamente neutro
Answer:
c) It gets positively charged
Explanation:
If an electrically neutral body is loaded with protons so it gets positively charged because proton has positive charge. When the protons is added to the neutral body, it can't remain neutral because the quantity of positive charges increases in the nucleus and it gets positively charged while on the other hand, the atom from which protons are taken will acquire negative charge due to presence of more number of electrons and we know that electrons has negative charge.
A meter is larger than a
A.
hectometer
B.
kilometer
C.
decimeter
D.
dekameter
PLZZZ HELP ME ASAP!!!
Answer:
the correct answer would be D
Explanation:
D is the correctly balanced
Which type of map best shows the three dimensions of Earth’s surface?
Answer:
please give me brainlist and follow
Explanation:
topographic map
A topographic map shows a three-dimensional representation of a flat surface. It has contour lines joining points of equal elevation; the closer the lines are the steeper the elevation is.
how slow would a 60,000 kg freight car have to roll to have the same momentum as an 80 kg person running 6.5 m/s
(8 and 2/3) millimeters per second.
That's about 0.02 mile per hour.
Why would you have trouble breathing at high altitudes?
A. it is colder at the top of a mountain
B. the oxygen molecules are spread farther apart
C. the oxygen molecules are closer together
Answer:
A. It is colder at the top of a mountain
Explanation:
The magnitude of the gravitational acceleration at the surface of a planet of mass M and radius R is g. What is the magnitude of the gravitational acceleration at the surface of a planet of mass 2M and radius 2R?
The half-life of technetium-99 is 6 hours.How much of a 100 milligram sample of
technetium-99 will remain after 30 hours? *
O 3.125 mg
O 12.5 mg
O 6.25 mg
O 1.56 mg
A squash ball with an initial velocity of 19.21 m/s [W] is hit by a squash racket, changing its velocity to 40.22 m/s [E] in 0.312 s. What is the squash ball’s average acceleration?
Acceleration = (change in velocity) / (time for the change)
Change in velocity = 59.43 m/s East
Time for the change = 0.312 s
Acceleration = 190.5 m/s^2 East
Friction and air resistance are forces that always:
1.) Balance out, having no effect on the net force.
2.) Act in the opposite direction to an object's motion, tending to slow it down.
3.) Pull objects down towards the center of the Earth.
4.) Cause objects to speed up.
9.) This 200 kg
stag that weighs
1,960 N on earth
would only weigh
324 N on the
moon. Calculate the moon's
acceleration due to gravity.
Answer:
Mass on moon = 33.06 kg
Explanation:
Given the following data;
Mass on earth = 200 kg
Weight on earth = 1960 N
Weight on moon = 324 N
To find the mass on moon;
First of all, we would determine the acceleration due to gravity.
Weight = mass * acceleration due to gravity
1960 = 200 * g
g = 1960/200
g = 9.8 m/s²
Next, we find the mass on moon;
Mass on moon = weight on moon/acceleration due to gravity
Mass on moon = 324/9.8
Mass on moon = 33.06 kg
A rock at the edge of a cliff has 10 Joules of potential energy. A goat comes along and kicks the rock off the edge. At the moment right before the rock hits the ground about how much kinetic energy does it have? (remember, a Joule is the SI unit for measuring energy).
Answer:
27 J
Explanation:
Light waves are
A.rotating waves.
B.longitudinal waves.
C.circular waves.
D.transverse waves
SHOCKING
Explanation:
Answer:
D i promises.
Explanation:
light waves can go 2 direction
how fossils influence and change our understanding of the history of Earth and it's species.
Answer:
Fossils are the preserved remains or traces of animals, plants, and other organisms from the past. Fossils are important evidence for evolution because they show that life on earth was once different from life found on earth today.
Explanation:
Activity
Launch the Wave on a String simulation again to investigate the relationship between amplitude and damping force.
To begin:
• Select Oscillate and No End.
• Set Amplitude to 1.00 cm and Frequency to 1.00 Hz,
• Set Damping to None and Tension to low.
• Select Rulers to measure the amplitude of the waves.
For each measurement described below, pause the wave when the oscillator arm is at or just past its maximum
Part A
You can see that each wave has a crest and a trough. Measure the amplitude at the first crest to the center of the ball and record your reading in
the table below. Record amplitude measurements for every subsequent trough and crest, as identified in the table.
Finally, vary the Damping as indicated in the table and record your amplitude readings again for each different damping value to complete the
table. Each division is 5 units of dampening force, where None = 0, and Lots = 50.
illustration
Amplitude of Wave 1 E Amplitude of Wave 2 Amplitude of Wave 3
(crest)
(crest)
(crest)
