Answer:
It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.
The sandbox of the previous exercises had 10kg of sand. It was initially at 15°C and the specific heat of this sand is 830 j/(kg°C). What will be the final temperature of the sand? (-8100J=|0kg)
Answer:
Sorry I need points [tex] \boxed{}[/tex]
A roller is pushed with a force of 100 N along its handle, which is at an angle of 60 degrees with the horizontal. Find the work done in moving it through 20 m?
Answer:
1 kJ
Explanation:
By definition of work, [tex]W = \vec F \cdot \vec x = |\vec F| |\vec x| cos\angle Fx[/tex]. Let's replace the values: [tex]W = 100N\cdot 20m \cdot cos 60 = 1000 J[/tex]
Please help me thank you
Fr+Cl=FeCl3
Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE
Answer:
A - Juan
Explanation:
I took the test!
PLEASE HELP!!!!
1. Suppose a planet orbits a star at the same distance
as Earth (1 AU) but with a period of roughly 200
Earth days. The mass of the central star is:
a. less than the mass of our sun.
b. the same as the mass of our sun.
c.greater than the mass of our sun.
d. impossible to determine without
knowing the mass of the planet.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C
According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:
The squared of the period is directly proportional to the cube of the radius. That is,
[tex]T^{2} \alpha r^{3}[/tex]
The orbital period formula is expressed as :
[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex] ÷ GM
Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.
In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.
Therefore, the correct answer is option C
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Question 4 of 5
Which pair of objects would repel each other?
O A. A positively charged particle and a neutral particle
OB. A negatively charged particle and a neutral particle
O C. Two positively charged particles
OD. A positively charged particle and a negatively charged particle
Answer:
Two positively charged particles
Explanation:
I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles
Answer: C Two positively charged particles.
Explanation:
just trust me on it, i've done the same quiz.
H is a chemical (blank) and H2 is a chemical (blank)
Please I need help!
Answer:
"H" is a chemical symbol and "H2" is chemical formula.
Convert 9/4 hours into minutes
Am guessing;
9/4 × 60/1 =135
See screen shot...momentum in collision
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the coefficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25
Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.
Explanation: Hope this helped :)
Which type of electromagnetic radiation is useful in communications technology?
A. X-rays
B. visible light
C. radio waves
D. ultraviolet radiation
Watch the video and make a ninja star. Once you have made a ninja star, 5 Point Ninja Star. Explain the energy transfer in the ninja star once it has been assembled.
PLEASE HELP
Answer:
kinetic energy because it is movement
Explanation:
Which layer is the igneous rock type?
options:
A
B
C
D
what is pole of magnet
and
define the term magnetic line of force
Answer:
1. The magnetic pole is the region at each end of a magnet where the external magnetic field is the strongest.
2. magnetic line of force - a line of force in a magnetic field. field line, line of force - an imaginary line in a field of force; direction of the line at any point in the direction of the force
Explanation:
How are particles in liquids, solids, and gases the same? How are they different?
Answer:
Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
Explanation:
#CARRYONLEARNING
What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Answer:
60 meters
Explanation:
If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply
3meters/second*20seconds
cross out the seconds and you have
3 meters*20
60 meters
You place a small sphere with a net charge of 5 space x space 10 to the power of negative 6 end exponent space C at one corner of a square that measures 5 m on each side. What is the magnitude of the electric field at the opposite corner of the square?
900 N/C
9,000 N/C
450 N/C
4,500 N/C
most of the waves in the electromagnetic spectrum are
Answer:
The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
Two Force 16N and 4N acts at rights angle each other calculate the resultant force
Which statement identifies the chemical property of iron that results in the formation of rust?
A. It is nonflammable.
B. It reacts with oxygen to form a new substance.
C. It has a very high melting point.
D. It conducts electricity.
Answer:
B, It reacts with oxygen to form a new substance
Explanation:
B
A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.
Answer:
[tex]V_{2.2} =2.2V[/tex]
Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V
With Ohm's Law
The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]
Determine the force required to move a block if the coefficient of static friction of one block and the floor is 0.35 and the coefficient of the static friction between 2 boxes is 0.25
Answer:
32.5
Explanation:
Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N .
Determine the friction coefficient. ...
Multiply these values by each other: (250 N) * 0.13 = 32.5 N .
You just found the force of friction!
When might people use data tables and graphs in their everyday lives? How are these uses similar to and different from the way in which scientists use these same tools?
Do you think scientists need data tables and graphs to do their work?
Which fields of science do you think might use data tables and graphs more than others?
Answer:
hahaha bisa aja ente gan di download di sini adalah salah satu
What is the Scientific name for Ectoparasites?
Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.
Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.
Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.
Please mark me brainliest.
The position-time graph for two drivers (A and B) are shown in the figure below. Which of the following statements is correct?
a. The two drivers are for sure moving in parallel directions
b. Driver B is moving faster than driver A.
c. Driver A is moving faster than driver B.
d. The two drivers are moving at the same speed
Answer:
A
Explanation:
A plane is flying through the sky at a constant speed. The thrust of the aeroplane (making it go forwards) is 100N. Air resistance is also acting on the plane. What must the resultant (overall) force be on the plane?
A: 0N
B: 50N
C: 100N
D: 150N
Answer: 0N
Explanation: Hope this helps :)
last time i wrote the wrong answer for the wrong problem :)
For the constant speed, the resultant force on the plane is 0N. So, the correct option is A.
What is Force?A force is defined as the parameter that can change the momentum of an object that can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or pull where force has both magnitude and direction, making it a vector quantity.
For above given information, the plane is moving at a constant speed. According to Newton's first law, the net external force on the aircraft due to the thrust generated by the propeller must be zero and air resistance is equal and in opposite directions to produce zero net force.
Thus, for the constant speed, the resultant force on the plane is 0N. So, the correct option is A.
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. A small toy car having 300 grams of mass and going straight with an initial velocity of 13 m/s. When the toy car collides with an obstacle, a resistive force of 4 N acts upon it. The speed of the toy car reduced and reached 8 m/s. Draw its free body diagram and then find the time for the toy car to be into rest position?
The free-body diagram is attached in the image below. The time for the toy car to be in rest position is 0.6 s
From the given information:
The mass of the toy car = 300 g = 0.3 kgThe initial velocity (u) of the car = 13 m/sThe resistive force F_r acting on the car = 4 NThe speed of the car (v) = 8 m/sA force is regarded as a push that causes an alteration in motion of an object within a specified distance. It is usually expressed by the formula:
Force = mass × acceleration∴
acceleration = Force/massacceleration = (4 / 0.3) m/s²acceleration = 13.33 m/s²Using the first equation of motion for the time to bring the car to rest from it reduced speed of 8 m/s;
v' = v + atsince the final speed to bring the car in rest position is (0), then:
0 = 8 - 13.33(t)
13.33(t) = 8
t = 8/13.33
t = 0.6 seconds
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A Rocket took 5 minutes to travel the 185 km. How fast did the Rocket travel in kilometers per minute (km/min)?
Answer:
The rocket travelled 37km per minute
Explanation:
185÷5=37
An object on Earth weighs 600 N and on Mars 100 N. If its mass on Earth is approximately 60 kg what is the mass of the object on Mars?
Answer:
I think its
10 kg
plzz plzz plzz. mark as brainliest
If the mass of an object is approximately 60 kg on earth then its mass remains the same on Mars which is 60 kg because mass does not change from place to place.
What is mass?Mass in physics is a numerical representation of inertia, a fundamental property of all matter. What a body of matter is fundamentally is the resistance it offers to a change in its speed or location brought on by the application of a force. The more mass a body has, the less of a change a force exerts results. The kilogram is the unit of mass in the International System of Units, and it is defined by Planck's constant as being equal to 6.62607015 × 10⁻³⁴ joules second (SI).
According to the question, the weight of an object depends on gravity which is different from place to place so weight also varies from place to place but the mass is constant everywhere it does not change. So, if the mass of an object is 60 kg on earth then it remains the same on mars also.
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could someone answer this
The given kinematic equations of motion are derived from Newton's Laws
of Motion.
A) The ball's speed the instant it left the soccer player's foot is approximately 11.074 m/s.B) The time it took the ball to rise to its maximum height is approximately 1.129 seconds.
Reasons:
The direction the ball is kicked = Upwards in the air
Maximum height to which the ball rises = 6.25 m
A) The speed of the ball the instant it left the soccer player's foot
Solution:
The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²
At the maximum height, y - y₀ = 6.25 m
The velocity at the maximum height, v = 0
v₀ = The speed of the ball the instant it left the soccer player's foot
Which gives;
v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625
v₀² = 122.625
v₀ = √(122.625) ≈ 11.074
The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.
B) Required:
The time it takes the soccer ball to rise to the maximum height.
Solution:
The equation of motion required is v = v₀ + [tex]a_y[/tex]·t
At the maximum height, v = 0
v₀ ≈ 11.074 m/s
v = v₀ + [tex]a_y[/tex]·t
Which gives;
0 = 11.074 - 9.81 × t
[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]
The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds
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