write a loop that reads positive integers from stands input and that terinated when it reads an interger that is not positive after the loop termpinates

Answer:

Explanation:

The following Java program has the method calcAverage(). It creates a sum variable which holds the sum of all the values in the array and the count variable which holds the number of elements in the array. Then it uses a For Each loop to loop through the array and go adding each element to the sum variable. Finally it calculates the average by dividing the sum by the variable count and returns the average to the user. A test case has been created in the main method using the example in the question. The output can be seen in the image attached below.

class Brainly {

   public static void main(String[] args) {

       int[] myArr = {1, 2, 3, 4, 5};

       System.out.println(calcAverage(myArr));

   }

   public static double calcAverage(int[] myArr) {

       double sum = 0;

       double count = myArr.length;

       for (int x: myArr) {

           sum += x;

       }

       double average = sum / count;

       return average;

   }

}

Answer:

Explanation:

The answer should be 1.16 or 61.1

Answer:

"if" is the right response.

Explanation:

Answer:

Bro this is my area the answer is WPA2 and AES  

Explanation:

its because AES is a more secure encryption protocol introduced with WPA2. AES isn't some creaky standard developed specifically for Wi-Fi networks, either. It's a serious worldwide encryption standard that's even been adopted by the US government.

There are many possible variations in wireless network design depending on the surroundings.

Even in a complicated single site, different wireless networks running on the same hardware as part of the broader wireless LAN environment can have different network configuration fundamentals needed for a successful deployment.

At the same time, a number of essential network configuration activities are part of any successful wireless project's typical chores. Let's look at the broad and specific procedures that wireless experts should take while setting up enterprise-grade Wi-Fi networks.

Therefore, There are many possible variations in wireless network design depending on the surroundings.

To learn more about wifi, refer to the link:

https://brainly.com/question/6145118

#SPJ5

Answer:

it is the process that binds together the data and code into a single unit and keeps both from being safe from outside interference and misuse. In this process, the data is hidden from other classes and can be accessed only through the current class's methods

Answer:

A triangle on the Clock input.

Answer:

The Arduino boards can be programmed in assembly. All you need is an ICSP Cable (In Circuit Serial Programmer) and the AVR toolchain (free from ATMEL) to write to the board. You then get the advantage of on board debugging.

As you suggested, you can just slap an ATMEL chip on a breadboard and go to town.

Explanation: cause i said so

Answer:

Dynamic Router

Explanation:

A dynamic router is a network connection device that can build tables that identify addresses on each network.

Dynamic networks are networks that vary over time; their vertices are often not binary and instead represent a probability for having a link between two nodes.

Statistical approaches or computer simulations are often necessary to explore how such networks evolve, adapt or respond to external intervention.

DNA statistical tools are generally optimized for large-scale networks and admit the analysis of multiple networks simultaneously in which, there are multiple types of nodes (multi-node) and multiple types of links (multi-plex).

Therefore, A dynamic router is a network connection device that can build tables that identify addresses on each network.

To learn more about dynamic router, refer to the link:

https://brainly.com/question/14285971

#SPJ6

Answer:

Here are the top benefits of using the latest leads automation tool for your personal pursuit, professional service, and other types of businesses.

Importance of Leads Automation Tool For LinkedIn

Unlike a traditional and non-automation approach, the best LinkedIn leads automation tool 2020 makes the process far more easier and efficient. It helps to win a good number of connections which would eventually make it easier for businesses to pitch their products and turn newly gained connections into potential customers.  

Moreover, businesses will also get more views and new messages in your LinkedIn inbox. The best leads automation tool free are especially useful when you have multiple LinkedIn accounts as you will get rid of time-consuming hectic tasks.

Answer and Explanation:

public class Main {

int Carmodel;

int Purchaseprice;

int Currentyear;

Public void setPurchasePrice(int Purchaseprice){

this.Purchaseprice=Purchaseprice;

}

Public void getPurchasePrice(){

return Purchaseprice;

}

static void printInfo(int Carmodel int Currentyear ){

this.Carmodel=Carmodel;

this.Currentyear=Currentyear;

System.out.println(getPurchasePrice() Carmodel Currentyear);

}

}

The above java program defines a class that has three methods, a get method that returns purchase price of the object, a set method that sets purchase price of the object, and a print method that print out the information about the car object(model, year, price). The print method also takes arguments and assigns values of the arguments/parameters to the object, then prints all.

Answer:

The answer is "False"

Explanation:

It is put to use Six Sigma had 3.4 defects per million opportunities (DPMO) from the start, allowing for a 1.5-sigma process shift. However, the definition of zero faults is a little hazy. Perhaps the area beyond 3.4 DPMO is referred to by the term "zero faults.", that's why Before being released, large computer programs, such as operating systems, must have no faults the wrong choice.

Answer:

Replace /* Your solution goes here */

with the following:

courseStudent.SetName("Smith");

courseStudent.SetAge(20);

courseStudent.SetID(9999);

courseStudent.PrintAll();

cout <<courseStudent.GetID();

Explanation:

From the given code segment, we have the following methods defined under the StudentData class;

SetName -> It receives name from the main

SetAge -> It receives age from the main

SetID --> It receives ID from the main and passes it to GetID method

printID --> Prints all the required output.

So, we have:

Pass name to setName

courseStudent.SetName("Smith");

Pass age to setAge

courseStudent.SetAge(20);

Pass ID to setID

courseStudent.SetID(9999);

Print all necessary outputs

courseStudent.PrintAll();

Manually print the student ID

cout <<courseStudent.GetID();

Answer:

see your answer in image

mark me brainlist

The amount of disk space in sectors that would be required to store 300,000 records is equal to 75,000 sectors.

Given the following data:

First of all, we would determine the number of logical records that can be held by each sector as follows:

Number of logical records per sector = 512/120

Number of logical records per sector = 4.3 ≈ 4.0.

Now, we can calculate the required disk space to store 300,000 records:

Disk space = 300,000/4

Disk space = 75,000 sectors.

For the tracks, we have:

Disk space in tracks = 75,000/96

Disk space in tracks = 781.25 ≈ 782.

Disk space in tracks = 782 tracks.

For the surfaces, we have:

Disk space in surfaces = 782/110

Disk space in surfaces = 7.10 ≈ 8.

Disk space in surfaces = 8 surfaces.

Read more on disk space here: https://brainly.com/question/26382243

Answer:

if (numCycles < 1){

        System.out.println("Too few.");

     }

     else if (numCycles > 4){

        System.out.println("Too many.");

        }    

  else{

     for(int i = 1; i <= numCycles; i++)

  {

     System.out.println(i + ": Lather and rinse.");

  }

     System.out.println("Done.");

  }

Explanation:

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-

Answer:

Phishing Victim

Explanation:

Replying to this email could make you a victim of a phishing scam. Phishing attacks are common challenges on security that internet users are faced with. It could lead to others getting hold of sensitive information like your password or bank details. email is one way the hackers used to get this information. replying to such an email could lead one to an unsecure website where information could be extracted

Answer:

Explanation:

Freeware and shareware programs are softwares which are either free of charge or consist of a free version for a certain trial period. These programs pose a threat of habouring malware or viruses which could damage one's computer and important files and programs. Therefore, it is imperative that carefulness is maintained when trying to get these softwares.

Some of the necessary safety conditions that should be taken include;

1) Appropriate research about the software including taking more about the vendors and reviews.

2.) Once, a healthy review has been identified ; the download can begin with the Downloader ensuring that the download is from the recommended site.

3) Prior to installation the software should be scanned with an active anti-virus program to determine if there is possibility that a virus has creeped in.

4.) Some softwares may require that computer anti-virus be turned off during installation, this is not always a good idea as this act leaves the system vulnerable a d badly exposed.

(c) 4

The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.

In this case, the string is "Get Well Soon!" while the substring is "Well"

Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".

Therefore, the function strpos("Get Well Soon!", "Well") will return 4.

Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.

Answer:

Speak to a U-Phone representative.

Explanation:

A representative will tell you the necessary details about the U-phone without any biases whatsoever, as they´re the closest to the company when it comes to detail about their products.

Answer:

Following are the solution to the given question:

Explanation:

The common folder called Report has also been shared. Writing access to a shared folder was given to management group members. Mark is a member of a group of managers. We can access the files within your reporting directory, but you really should not access the Confidential.xls file. We want to add Mark Mangum to our ACL files using Deny permissions on Confidential.xls.

Answer:

Following are the code to the given question:

#include<stdio.h>//include header file  

int main() //defining a main method

{  

   int a[100],k,x,s; //defining integer variable and an array  

   printf("Input the number of element want to insert array: ");  //print message

   scanf("%d",&x);  //input value

   printf("Enter array value: \n"); //print message  

   for(k = 0; k<x; k++)  //defining a loop that inputs values

   {  

       scanf("%d",&a[k]);  //use array to input value

   }  

   s = a[0]; //holding first array value in array

   for(k=0;k<x;k++)  //use for loop

   {  

       if(a[k]<s)  //use if block to check the smallest array value

       {  

         s=a[k];//holding smallest array value

       }  

   }  

   printf("smallest number= %d",s);//print smallest value

}  

Output:

Please find the attached file.

Explanation:

In this code an array and another integer variable "a[100], i,n, and s" is is declared, in which the array and n for input the value from the user-end.

In the next step, an "s" variable is declared that inputs the first array element value in s and use a loop to check the smallest array element and prints its value.

Answer:

The function is as follows:

int returnsFixed(int arr [],int n){

   int retVal = -1;

   for(int i = 0; i<n;i++){

       if(i == arr[i]){

           retVal = i;

           break;

       }

   }

   return retVal;

}

Explanation:

This defines the functionl it receives the array and the length of the array

int returnsFixed(int arr [],int n){

This initializes the return value to -1

   int retVal = -1;

This iterates through the array

   for(int i = 0; i<n;i++){

This checks if i equals arr[i]

       if(i == arr[i]){

If yes, the return value (i.e. the fixed point) is set to i

           retVal = i;

And the code is exited

           break;

       } This ends the if condition

   } This ends the iteration

This returns the calculated fixed point

   return retVal;

}

Answer:

You typically create a database during Oracle Database software installation. However, you can also create a database after installation.

Reasons to create a database after installation are as follows:

Answer:

He belongs to the nation

Using the concepts of public and private domains, it means that the photograph of the president can be used by anyone without asking for permission.

---------------

Public and private domains:

A similar question is given at https://brainly.com/question/12202794

Answer:

Explanation:

class Solution {

   public int search(int[] nums, int target) {

       int n = nums.length;

       int low = 0 , high = n - 1;

       While(low < high){//Set virtual node

           int mid = (low + high) / 2;

           if(nums[mid] > nums[high]){

               low = mid + 1;

           }else{

               high = mid;

           }

       }

       int rot = low;

       low = 0;

       high = n - 1;

       while(low <= high){

           int mid = (low + high) / 2;

                        Int real = (mid + rot) % n;//The virtual node is mapped to the real node.

           if(nums[real] == target){

               return real;

           }else if(nums[real] < target){

               low = mid + 1;

           }else{

               high = mid - 1;

           }

       }

       return -1;

   }

}

Solution :

ENTITY 1               CARDINALITY RATIO                                     ENTITY 2

1. Student                        1 to many                                     Social security card

                      A student may have more than one          

                     social security card (legally with the

                      same unique social security number),

                     and every social security number belongs

                   to a unique.

2. Student                   Many to Many                                    Teacher

                    Generally students are taught by many

                    teachers and a teacher teaches many students.

3.ClassRoom               Many to Many                                   Wall

                      Do not forget that the wall is usually

                      shared by adjacent rooms.

4. Country                 1 to 1                                             Current President

                       Assuming a normal country under normal

                       circumstances having one president at a

                      time.

5. Course               Many to Many                               TextBook

                        A course may have many textbooks and

                       text book may be prescribed for different

                      courses.

6. Item                             Many to Many                           Order

                        Assuming the same item can appear

                         in different orders.

7. Student                       Many to Many                          Class

                        One student may take several classes.

                        Every class usually has several students.

8. Class                                 Many to 1                             Instructor

                       Assuming that every class has a unique

                        instructor. In case instructors were allowed

                        to team teach, this will be many-many.

9. Instructor                  1 to 1                                             Office

                       Assuming every instructor has only one

                      office and it is not shared. In case of offices

                     shared by 2 instructors, the relationship

                    will be 2-1. Conversely, if any instructor has a joint

                    appointment and offices in both departments,

                    then the relationship will be 1-2. In a very general

                  case, it may be many-many.

10. E-bay Auction item             1-Many                           E-bay bid

                        1 item has many bids and a bid is unique

                        to an item.

Answer:

Explanation:

Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.

Answer:

a. Youthful

Explanation:

The river gets its water from youth stage fluvial water. The river meanders from side to side. East Brownsville will be less stable in international boundary in terms of physical position on the landscape because its base level drops.