Answer:
reduce the temperature of the gas
Explanation:
when you reduce the temperature of the gas the pressure will decrease
which of the following is an example of an arrthenius acid
Answer:
The common examples of Arrhenius acid includes HCl (hydrochloric acid), H2SO4 (sulphuric acid), HNO3 (nitric acid), etc.Oct 21, 2020
Explanation:
El tipo de enlace se puede determinar mediante la diferencia de electronegatividades de los átomos que lo forman. Basado en eso, si se unen un átomo de Calcio y un átomo de Bromo, el enlace será del tipo:
Answer:
Cuando se unen un átomo de calcio y un átomo de bromo, forman bromuro de calcio que se compone de Ca2 + y 2Br-. El tipo de enlace que se forma es el enlace iónico.
A thief who has stolen large quantities of uranium-235 may have increased
the threat of what?
A. Alpha decay
B. Nuclear fusion
C. Nuclear waste
D. Proliferation
Since uranium - 235 decays by alpha decay, the thief runs a risk of exposure to alpha decay.
What is alpha decay?Radioactive decay is the sponteanous disintergration of a nuclide to yiled daughter nuclide and release energy.
We can see the decay of Uranium -235 in the image attached to this answer. Hence, it then follows that the theif here runs the risk of exposure to alpha decay.
Learn more about alpha decay: https://brainly.com/question/9904853
Answer:
D. Prolideration
Explanation:
Just took the test
Which pair of substances would react the
fastest?
a. Copper sheet and concentrated
nitric acid.
b. Copper powder and dilute nitric acid
C. Copper powder and concentrated
nitric acid.
Answer:
C. It has the highest rate of reaction. Copper has the highest TSA/V and concentrated nitric acid has huggest num of solute
What is the percent yield of a reaction?
O A. The difference between measured and calculated amounts
OB.
The amount of produd obtained
amount possible
* 100
C. The amount of product actually obtained in a reaction
D. The amount of product that is possible from a reaction
Answer:
B. The amount of produd obtained/amount possible * 100
Explanation:
In chemistry, the yield of a chemical reaction is the quantity or amount of products obtained in that chemical reaction. It is calculated by using the following formula:
Percentage yield = Actual yield/theoretical yield × 100
- The actual yield is the amount of products got from a chemical reaction
- The theoretical yield is the amount of product got from using the balanced equation (stoichiometry).
What happens if kinetic energy of a gas is lowered
Answer:
"If you lower the kinetic energy of a gas its temperature will decrease because temperature is a measure of the average kinetic energy of a substance."
Explanation:
Which is a mixture?
Sodium metal
chlonne gas
sodium metal and chlonne gas
sodium chlonde (salt) and water
Answer:
I believe it's salt and water
Explanation:
not sure
Answer:
Mixture is a electronic device used to peel the things such as onion ,tomato,ginger, garlic etc.
Hiii please help me for balancing chemical equations:
potassium iodide + chlorine ------> potassium chloride + iodine
Answer:
KI + Cl2 = KCl + I2
Explanation:
hope this helps!!!
Answer:
2KI +Cl₂ → 2KCl +I₂
Explanation:
Potassium ion: K+
Iodide ion: I-
Thus, potassium iodide is KI.
Chlorine exist as a diatomic molecule thus it is written as Cl₂.
Chloride ion: Cl-
Thus, potassium chloride is KCl.
Iodine also exist as a diatomic molecule, thus it is written as I₂.
Write an unbalanced equation:
KI +Cl₂ → KCl +I₂
Now balance by ensuring the number of atoms of each element on each side is the same.
LHS
K: 1 ×2= 2
I: 1 ×2= 2
Cl₂: 2
RHS:
K: 1 ×2= 2
I: 2
Cl: 1 ×2= 2
Thus, the balanced equation is:
2KI +Cl₂ → 2KCl +I₂
CORRECT ANSWER ONLY ND WILL GIVE BRAINLIEST✌
Calculate the mass of nitrogen dioxide gas that would occupy
the same volume as 10g of hydrogen gas at ē same pressure and temperature
(H= 1.0 N = 14.0 O= 16.0) GAS LAWS/MOLES
Answer:
150g
Explanation:
Assuming they are ideal gases at the same temperature and pressure, equal moles of gasses have equal volume. IN this case, if we have 10g of hydrogen gas, that is 5 moles of H2 gas. That means 5 moles og NO2 will occupy the same volume which is 5*(14.0 + 16.0*2) = 230 g
In the laboratory, concentrated hydrogen chloric acid reacted with aluminum. Hydrogen gas was collected over water at 25 degrees Celsius and had a volume of 355 cm33 at a total pressure of 750 mm Hg. The vapor pressure of water at 25 degrees Celsius is 24 mm Hg. Find the partial pressure of hydrogen gas.
Answer:
i dont no this one plz the question is hard
La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)
Explanation:
The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)
The mass of aluminum present in the pot is:
[tex]300 g * 90/100\\=270 g[/tex]
Hence, in the given pot 270g Al is present.
[tex]Number of moles of Al=\frac{given mass ofAl}{its molar mass}[/tex]
The gram atomic mass of Al -27 g/mol
Given the mass of Al is 270 g
Substitute these values in the above formula:
[tex]Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol[/tex]
Answer is 10.0 mol of Al is present.
Fumaric acid, which occurs in many plants, contains, by mass, 41.4% carbon, 3.47% hydrogen, and 55.1% oxygen. The molecular mass of this compound is 116 amu. The molecular formula of this compound is
Question 15 options:
CHO
C3H3O
C3H3O3
C4H4O4
C6H6O6
Answer:
Explanation:
C = 41.4/12 = 3.43
H = 3.47/1 = 3.47
O = 55.1/16 =3.44
CHO is the skeletal formula (divide each by the lowest number above). The results are close enough to 1 to be 1.
(CHO)_x = 116
C + H + O = 29
(29) _ x = 116
x = 116/29
x = 4
So there area 4 carbons 4 hydrogens and 4 oxygens.
The correct formula is C4H4O4
Scoring Scheme: 3-3-2-1 Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available in the amount of starting solution you used
Answer:
The solution has 0.00994 moles of Co[H2O]6Cl2
Explanation:
Complete question: Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available in the amount of starting solution you used?
mL= 7.95
Step 1: Data given
Concentration of the starting solution = 1.25 M
Starting solution = Co[H2O]6Cl2
Step 2: Calculate molar mass of Co[H2O]6Cl2
Atomic mass of Co = 58.93 g/mol
Atomic mass of H = 1.01 g/mol
Atomic mass of O = 16.00 g/mol
atomic mass of Cl = 35.45 g/mol
Molar mass of Co[H2O]6Cl2 =
1*58.93 + 12*1.01 + 6*16.00 + 2*35.45 = 237.95 g/mol
Step 3: Calculate number of moles
C = n/v
⇒with C = the Concentration of the starting solution = 1.25 M
⇒with n= the number of moles = to be determined
⇒with v = the volume = 7.95 mL = 0.00795 L
n = C * V
n = 1.25 M * 0.00795 L
n = 0.00994 moles
The solution has 0.00994 moles of Co[H2O]6Cl2
what is another name for hard water?
Answer:
Hyponym is the another name for hard water.
Explanation:
Please Mark me brainliest
Which of the following changes in the state of a substance results in an increase in the entropy?
Gas to solid
Gas to liquid
Liquid to solid
Solid to liquid
Answer:
the correct answer is
D. solid to liquid
Liquids have a(n)____shape and A(n)_____volume.
A. indefinite, indefinite
B. indefinite, definite
C. definite, definite
D. definite, indefinite
Which of these hypotheses cannot be tested?
A. The percentage of salt in ocean water stays the same throughout the ocean.
O B. Doubling the amount of salt in a bread recipe will cause the dough to rise faster.
C. Cooks should use sea salt in recipes instead of regular table salt.
O D. Increasing the amount of salt in salt water will increase the boiling point.
Cooks should use sea salt in recipes instead of regular table salt.
What is the name of this compound
Answer:
horizontal
Explanation:
If an atom contains more
electrons than protons, it is
Answer:
If an atom has the same number of electrons as protons, it is a neutral atom.
Explanation:
neutral radicals examples
Neutral radicals are always electropositive
some examples of neutral radicals are:-
Ca±±Mg±±Ba ±±Al±±NH4±Hope it is helpful to you
For a reaction: aA → Products, [A]o -4.3 M, and the first two half-lives are 56 and 28 minutes, respectively. Calculate k (without units). Show Work!
A. 7.7 x 10^-2
B. 4.2 x 10^-3
C. 3.8 x 10^-2
D. 8.3 x 10^-3
E. None of these
Answer:
C.[tex]3.8\times 10^{-2}[/tex]
Explanation:
We are given that
Initial concentration, [tex][A]_o=4.3 M[/tex]
First half life, [tex]t_{\frac{1}{2}}=56[/tex]minutes
Second half life, [tex]t'_{\frac{1}{2}}=28[/tex]minutes
We have to find K.
The given reaction is zero order reaction.
We know that for zero order reaction
[tex]t_{\frac{1}{2}}=\frac{[A]_o}{2k}[/tex]
Using the formula
[tex]56=\frac{4.3}{2k}[/tex]
[tex]k=\frac{4.3}{2\times 56}[/tex]
[tex]k=3.8\times 10^{-2}[/tex]
Hence, option C is correct.
Zero-order reactions are the reactions when a surface or a catalyst is required for the reaction to proceed and is saturated by the reactant chemicals. The result of the concentration versus the time plot will be a straight line in a zero-order reaction.
[tex]3.8 \times 10 ^{-2}[/tex] is the value of k.
How to calculate the value of k?Given,
Initial concentration [tex][A_{0}][/tex] = 4.3 MThe first half-life of the reactant [tex](t \dfrac{1}{2})[/tex] = 56 minutesThe second half-life of the reactant [tex](t \dfrac{1}{2})[/tex] = 28 minutesThe given reaction in the question is of zero-order and for that, we know that,
[tex]t \dfrac{1}{2} = \dfrac{[A_{0}] }{2\;\rm k}[/tex]
Substituting the values in the equation we get:
[tex]\begin{aligned}56 &= \dfrac{4.3 }{2\; \rm k}\\\\\rm k &= {4.3 }{2 \times 56}\\\\\rm k &= 3.8 \times 10^{ -2}\end{aligned}[/tex]
Therefore, option C is correct.
Learn more about the zero-order reaction here:
https://brainly.com/question/4638382
write molecular formula
1)aurric cloride
2)aluminium hydroxide
3)potassium thiosulphate
4)magnesium bicarbonate
5)magnesium sulphate
6)sodium oxide
7)cuprous oxide
8)mercuric oxide
9)calcium nitrate
10)aluminium oxide
11)ferric chloride
12)ammoium oxide
13)silver chloride
14)hydrogen bromide
15)magnesium nitride
16)hydrogen peroxide
17)sodium sulphate
18)ammonium sulphate
19)ferrous sulphate
20)sodium carbonate
21)zinc carbonate
22)calcium silicate
23)zinc carbonate
24)potassium clorate
25)aluminium hydroxide
26)ammonium hydroxide
27)sodium silicate
Okay.
Here's your below answers.
1) AuCl3.
2) Al(OH)3.
3) K2S2O3.
4) Mg(HCO3)2.
5) MgSO4.
6) Na2O.
7) CuO.
8) HgO.
9) Ca(NO3)2.
10) Al2O3.
11) FeCl2.
12) (NH4)2O.
13) AgCl.
14) HBr.
15) Mg3N2.
16) H2O2.
17) Na2SO4.
18) (NH4)2SO4.
19) FeSO4.
20) Na2CO3.
21) ZnCO3.
22) CaSiO3.
23) ZnCO3.
24) KClO3.
25) Al(OH)3.
26) NH4OH.
27) Na2SiO3.
Electron transition can be likened to moving up and down a ladder. Which of the following statements best describes how an electron transitions in an electron cloud?
A. An electron can only gain or lose energy to move between quantized energy levels.
B. An electron can only gain or lose charge in integers when ions are formed.
C. An electron can only change its mass in quantized amounts when it gains or loses energy.
D. An electron can only change into certain types of particles when it gains or loses charge.
Answer:
C. An electron can only change its mass in quantized amounts when it gains or loses energy.
Explanation:
The electron mostly acts in a wave form and shales the orbit and in other worlds the electron transition to lower energy change its wave shape and sinks less but it does not leap or bounce back anywhere.If 0.8 g of gas Z occupies 0.56 dm at s.1.p., calculate its relative molecular mass. (Molar volume of gas is 22.4 dm.)
Answer:
32
Explanation:
0.56dm of gas has 0.8g
22.4dm of gas Z has a mass of 22.4/0.56X0.8
the relative molecular mass of gas Z is 32
TIMED PLS PLS HELP ASAP
The scattering of sunlight by the mixture of gas molecules in air results in the blue color of the sky. Calculate the energy (in Joules) of a single photon of blue light with a frequency of 6.00 × 10¹⁴ Hz. (h = 6.626 × 10⁻³⁴ J • s)
Answer:
It's me mario
Explanation:
The graph shows the volume of a gaseous product formed during two trials of a reaction. A diferent concentration of reactant was used during each trial, whereas the other factors were kept constant. Trial 2 Amount of Product Trial 1 Time Which of the following statements explains which trial has a lower concentration of the reactant? O Trial 1, because the average rate of the reaction is lower. O Trial 1, because this reaction lasted for a longer duration than Trial 2. O Trial 2, because this reaction was initially fast and later slowed down. O Trial 2, because the volume of product formed per unit time was higher
Answer:
A). Trial 1, because the average rate of the reaction is lower.
Explanation:
The first sentence elaborates that 'trial 1 had a lower level of concentration of the reactant that eventually led the reaction's average rate to fall.'
A trial having a higher level of concentration of a specific reactant will cause the concentration's average rate to rise. As per the graph provided, trial 2's average reaction rate is higher which shows that its concentration is greater and more reactive. However, the opposite happens in trial 1 where the amount of reactant is lesser in the concentration that leads the concentration to possess a lower rate of reaction. Thus, option A is the correct answer.
!!!!!!URGENT!!!!!!
What do the coefficients in the following balanced chemical equation mean?
2H2 + O2 + 2H2O
A) 2 moles of hydrogen and 1 mole of oxygen in the reactants
B) 2 moles of oxygen and 1 mole of hydrogen in the reactants
C) 2 moles of oxygen and 1 mole of hydrogen in the products
D) 2 moles of hydrogen and 1 mole of oxygen in the products
Answer:
2moles of hydrogen and 1 mole of oxygen in the reactants
Jonny Jonny.
Yes papa?
Eating Sugar?
What comes next?
(A) Yes Papa
(B) No Mama
(C) Yes Mama
(D) No Papa
Answer:
(B) No papa
arafgzhzhsjdjkskbdjzjsj
Answer:
(D) No Papa
Explanation:
is this even chemistry pffttt
Help please i beg someone answer and explain
Answer:
Q,N,1) lithium + hydrochloric -> lithium chloride + Hydrogen.
word equation ( 2li + 2HCl -> 2liCl + H2)If we burn 1 gr of ethyl alcohol (C2H5OH) this will translate into a release of about 50 W of thermal energy of the flame that raise the temperature of the hot and cold reservoirs of a Sterling engine at 55 °C and 95 °C respectively. If at steady state the engine turns at about 240 rpm, its gears are shaped as rings of radius ~2 cm and weigh 50 gr, how efficient (in %) is the transfer of energy via flame?
Answer:
0.116%
Explanation:
efficiency of sterling engine = 1 - ( 55 + 273 )k / ( 95 + 273 ) k
= 1 - ( 328 / 368 ) = 0.10869
Determine how efficient the transfer of energy via flame is
apply this relation ; energy of steady state / energy output ---- ( 1 )
where; energy output = efficiency of sterling engine * energy
= 0.10869 * 50 = 5.4345 J/sec
energy of steady state = 1/2 * I * w^2 ------ ( 2 )
I = moment of inertia of engine = 2 * 10^-5 kgm^2
back to equation 2 :
energy of steady state = 1/2 * ( 2 * 10^-5 ) * ( 240 * 2π / 60 )^2
= 630.88 * 10^-5 J /sec
Input values into equation 1
= [ (630.88 * 10^-5 ) / 5.4345 ] * 100
= 0.116%
