A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct

Answer:

[tex]{ \tt{y \: \alpha \: {x}^{3} }} \\ { \tt{y = k {x}^{3} }} \\ { \bf{k \: is \: a \: proportionality \: constant}} \\ { \tt{1512 = (k \times {6}^{3}) }} \\ { \tt{k = 7}} \\ { \boxed{ \bf{y = 7 {x}^{3} }}}[/tex]

Answer:

mine ended june 9th but i got summer school for 2 classes lol

School ended the 15 of June but I'm in summer school rn it ends this Friday

Answer:

p = -1          q = -2

Step-by-step explanation:

3p - 7q = 11      -7q = -3p + 11           q = 3/7p - 11/7

2p - 5(3/7p - 11/7) = 8

2p - 15/7p + 55/7 = 8

-1/7p + 55/7 = 8

-1/7p = 1/7

p = -1

2(-1) - 5q = 8

-2 - 5q = 8

-5q = 10

q = -2

Step-by-step explanation:

If the volume of a cubical room is 2700 cm³ .

l³=2700

l=3 (100)⅓

Answer:

LK = 38

Step-by-step explanation:

MN is the midsegment, and the midsegment is the average length of the top and bottom, so:

[tex]\frac{18 + LK}{2} =28[/tex]

solve for LK:

[tex]18+LK=56\\\\LK=38[/tex]

Answer:

(0,6) and (3,1)

Step-by-step explanation:

The equation is already in slope intercept form.

y = mx + b

Since the y-intercept is '6', the first point would be (0, 6).

-----------------------------------

We can move three units to the right and 5 units down to get our second point, (3,1).

Note that slope is rise over run.

(0 + 3, 6 - 5) - > (3, 1).

The points would be (0,6) and (3,1). After plotting, you would draw a continuous line through them.

Hope this helps.

Step-by-step explanation:

[tex]here \: is \: your \: solution : - \\ \\ GIVEN \: \: -:- \\ \\ = > \: area \: of \: circle \: = 616 \: m {}^{2} \\ \\ \ = > pi = 22 \div 7 \\ \\ = > we \: need \: to \: find \: radius \: \\ \\ = > area \: of \: circle \: = \pi \: r {}^{2} \\ \\ = > \: \pi \: r {}^{2} = 616 \: m {}^{2} \\ \\ = > \: r {}^{2} \times (22 \div 7) = 616 \\ \\ = > \: r {}^{2} =( 616 \times 7) \div 22 \\ \\ = > \: r { }^{2} = 4312 \div 22 \\ \\ = > r {}^{2} = 196 \\ \\ = > \: r = \sqrt{196} \\ \\ = > \: r = 14 \: \: \: (ANSWER✓✓✓) \\ \\ HOPE \: IT \: HELPS \: YOU \: (◕ᴗ◕✿)[/tex]

Answer:

8050 m²

Step-by-step explanation:

We can divide the diagram up into two components: a rectangle with a width of 60 m and a height of 80 m, and a triangle with a base of 130 m (190 - 60) and a height of 50 m (80 - 30).

The area of the rectangle:

A = lw

A = 60 m (80 m)

A = 4800 m²

The area of the triangle:

A = 1/2 b*h

A = 1/2 (130 m) (50 m)

A = 1/2 (6500 m²)

A = 3250 m²

Now, we can add the areas of the two separate components:

A = 4800 m² + 3250 m²

A = 8050 m²

Answer:

4/9 of an hour (26.666 minutes)

Step-by-step explanation:

4 * x * 40/60 = 1

x * 160/60 = 1

x=60/160 = 6/16 = 3/8 (this is the rate for one worker)

~~~~~~~~~~~~~~~~

6 * (3/8) * x = 1

x = 4/9

Answer:

the discount of the earbuds is $8.60

the final price is $34.40

Step-by-step explanation:

1. find 20% of 43:

43 x 0.2 = 8.60

2. subtract that from $43:

$43 - 8.60 = $34.40

the discount of the earbuds is $8.60

the final price is $34.40

Answer:

626

Step-by-step explanation:

So 62 fewer right so 688 combined- 62 cheeseburger =626 hamburger

Answer:

D

Step-by-step explanation:

Look for the intersection point of the two graphs

Another way:

You can just substitute each pair in both equations and u will find that d is the correct answer

Answer:

8 m

-----------------Work--------------

2*3 = 6

Ratio

2*4 = 8

Answer:

9 : 7

Step-by-step explanation:

Given

4.5 : 3 [tex]\frac{1}{2}[/tex] ( multiply both parts by 2 to clear the fractions )

= 9 : 7

Answer:

9

Step-by-step explanation:

First you would need to subtract all the irrelevant students.

So, subtract 4 from 36, which is 34.

34 - (10 + 15) =

34 - 25 =

9

The answer is 9 pupils.

18 - (-f) = 91

Subtracting a negative value changes to addition:

18 + f = 91

Subtract 18 from both sides:

F = 73

Answer:

f = 73

Step-by-step explanation:

Solve for f

18 - ( - f ) = 91

18 + f = 91

18 - 18 + f = 91 - 18

f = 73

Answer:

D

Step-by-step explanation:

It can't be C and B since it doesn't have two parts, and if it was uniform it would have another part attached to the bottom. Moreover, it can't be A since it isn't positively skewed or negatively skewed, so it must be D.

The shape of this distribution is Unimodal symmetric.

Option D is the correct answer.

A histogram is a representation of the distribution of data with intervals.

We have,

In statistics, a distribution is considered unimodal symmetric if it has a single mode or peak and is symmetric around that mode.

This means that the data is evenly distributed on both sides of the mode and is equally likely to occur on either side.

A common example of a unimodal symmetric distribution is the normal distribution, also known as the Gaussian distribution or bell curve.

Thus, the shape of this distribution is Unimodal symmetric.

Learn more about histograms here:

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#SPJ7

Answer:

991

Step-by-step explanation:

We are looking for a number that is one more than a multiple of 9(denoted by the 9k) and is a three digit number. We can start by looking for 3-digit number divisible by 9 which are close to 1,000, since that is the next number larger than the largest three-digit number. We can tell that 999 is divisible by 9 because when divided it does not leave a remainder(you can also figure this out with divisibility tricks). We add one to get 1,000. This is not a three-digit number,  so we need to look for a smaller multiple of 9. Subtracting 9 from 999, we get the next largest multiple of 9. We can add 1, and this time, the number, 991, is a three digit number, and the largest that can be in the form 9k + 1.

Answer:

{5, 6, 7}

Step-by-step explanation:

When we have a given relation, the domain is the set of inputs, and the range as the set of the outputs.

so for a function f(x), and a domain {a. b. c}

The range is:

{f(a), f(b), f(c)}

In this case, we have:

f(x) = x + 6

and the domain is {-1, 0, 1}

Then the range is:

{ f(-1), f(0), f(1) }

{-1 + 6, 0 + 6, 1 + 6}

{5, 6, 7}

The correct option is the third one.

Answer:

35 miles

Step-by-step explanation:

You add up all of the miles on the chart to get 35 miles. Have a great day! I hope this helped.

Answer:

2m^3n^3

Step-by-step explanation:

Let us start with the number parts

36 , 2 and 4

2 is common here as it can divide all

The smallest m factor is m^3 so it is common for all

The smallest n factor is n^3 which is also common for all

So, we have the greatest common factor as;

2 * m^3 * n^3 = 2m^3n^3

Answer:

y < -7

Step-by-step explanation:

You balance it like a normal equation:

8y + 3 > 15y + 52

8y + 3 (-8y) > 15y + 52 (-8y)

3 (-52) > 7y + 52 (-52)

-49 (÷7) > 7y (÷7)

y < -7

Answer:

  12

Step-by-step explanation:

3/4 = 9/12

7/6 = 14/12

12 is a suitable common denominator for these fractions.

__

4 = 2·2

6 = 2·3

The common denominator must include all these factors (and no more than necessary), so must be ...

  LCD = 2·2·3 = 12

Answer:

8x +120= 400

Step-by-step explanation:

Let the number of hours Max worked over the summer be x.

Assuming that he had $0 in his bank at the start of summer,

Total savings= 8(number of hours) +120

400= 8x +120

8x +120= 400

To find the value of x, first bring all the constants to one side of the equation.

8x= 400 -120

Simplify:

8x= 280

Divide both sides by 8:

x= 280 ÷8

x= 35

∴ Max worked for 35 hours over the summer.

Answer:

In picture

Step-by-step explanation:

Brainliest please ~

Answer: y = [tex]\frac{5}{3}x +5[/tex]

Step-by-step explanation:

This is how you find the slope: [tex]slope=\frac{rise}{run}=\frac{y1-y2}{x1-x2}[/tex]

Find two coordinate points. Let's use (-3,0) and (0,5). Based on this, we know that y1 is 0, y2 is 5, x1 is -3, and x2 is 0. Plug these into the formula:

[tex]\frac{0-5}{-3+0} =\frac{-5}{-3} =\frac{5}{3}[/tex]

So, the slope is [tex]\frac{5}{3}[/tex]

The y intercept is where the line hits the y graph. We can see that the y intercept is 5 (or (0,5))

Slope intercept form: y = mx + b, m = slope, b = y intercept

Plug everything in:

y = [tex]\frac{5}{3}x +5[/tex]

Given:

Prime numbers can be expressed as a sum and difference of 2 prime numbers.

To find:

The prime numbers that can be expressed as a sum and difference of 2 prime numbers.

Solution:

Prime numbers are the positive integers which are greater than 1, divisible by only 1 and itself.

Prime numbers are 2, 3, 5, 7, 11, 13, 17, 19,... .

Only 2 is the even prime number.

The sum and difference of two odd integers is always an even number. So, we need to take one even prime number and one odd prime number to add and subtract the numbers to get a prime number.

[tex]2+3=5[/tex]

[tex]7-2=5[/tex]

Therefore, 5 is the only prime number that can be expressed as a sum and difference of 2 prime numbers.

(a) ∠AEC = ∠CFD, by transitive property of equality

(b) ∠CDE = 108°, ∠DCB = 108°, ∠ABC = 108°,∠EAB = 144°, ∠AED = 72°

The reason the above values are correct is as follows:

(a) The given parameters are;

Figure ABCDE is a pentagon

The sides AE is parallel to side CD

Line EC is parallel to side BC

The point of intersection of the extension off side ED and BC = Point F

∠ABC = ∠CDE

Required:

To show that ∠AEC = ∠CFD

Method:

Draw the pentagon ABCDE and include the added construction

Analyze the drawing

Solution:

∠ECF and ∠ABC are corresponding angles between parallel lines EC ║BC

∴ ∠ECF ≅ ∠ABC by corresponding angles formed by parallel lines are congruent

∠ECF = ∠ABC by definition of congruency

∠ABC = ∠CDE = ∠ECF by transitive property

∠ECD ≅ ∠AEC by alternate angles formed between parallel lines having a common transversal

∠ECD = ∠AEC by definition of congruency

∠ECF = ∠FCD + ∠ECD by angle addition postulate

∠CDE = ∠FCD + ∠CFD by exterior angle theorem

From ∠CDE = ∠ECF above, we have;

∠ECF = ∠FCD + ∠ECD = ∠FCD + ∠CFD

∴ ∠ECD = ∠CFD by addition property

∠ECD = ∠AEC, therefore;

∠AEC = ∠CFD, by transitive property

(b) Given that ΔEDC and ΔDFC are both isosceles triangles, with sides;

ED = DC, and DF = FC;

Let r represent ∠CFD, we have;

∠FCD = ∠CDF by base angles of isosceles triangle ΔDFC

∠ECD = ∠CED by base angles of isosceles triangle ΔEDC

∠AEG = ∠CDE by corresponding angles formed by parallel lines having a common transversal

∠AEC = ∠ECD by alternate angles

∴ ∠AEG + ∠AEC + ∠CED = 180° Sum of angles on a straight line

∠CDE = ∠CFD + ∠FCD

∠CDE + ∠CDF = 180° (linear pair angles)

∴ ∠AEG + ∠CDF = 180° by transitive property

∠AEC + ∠CED = ∠CDF by transitive property

∠AEC = ∠ECD = ∠CED = ∠CFD = r

∴ ∠CFD + ∠CFD = ∠CDF

2·r = ∠CDF

∠CDE = ∠FCD + ∠CFD

∠FCD = ∠CDF = 2·r

∴ ∠CDE = 2·r + r = 3·r

∠CDE = 3·r

The angles of the pentagon are;

∠CDE + ∠DCB + ∠ABC + ∠EAB + ∠AED = 540° sum of angles in a pentagon

∠DCB = 180° - ∠FCD

∠DCB = 180° - 2·r

∠ABC = ∠CDE = 3·r

∠EAB = ∠CEH corresponding angles

∠CEH = 180 - ∠AEC

∴ ∠EAB = 180° - ∠AEC

∴ ∠EAB = 180° - r

∠AED = ∠AEC + ∠CED = r + r = 2·r

∠AED = 2·r

Therefore, we have;

3·r + 180° - 2·r + 3·r + 180° - r + 2·r = 540°

5·r + 360° = 540°

r = (540° - 360°)/5 = 36°

r = 36°

∠CDE = 3 × 36° = 108°

∠DCB = 180° - 2×36° = 108°

∠ABC = 3 × 36° = 108°

∠EAB = 180° - 36° = 144°

∠AED = 2 × 36° = 72°

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