Answer:
17311, 17315
Step-by-step explanation:
Explanation,
Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.List Of CPT Codes For Mohs Surgery
CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.
Description Of CPT Code 17311
Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocksDescription Of CPT Code 17315 (addon)
CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)Extras
Description Of CPT Code 17312 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)
Description of CPT Code 17313
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks
Description Of CPT Code 17314 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).
simplify the ratio 4.5: 3 1/2 in its simplest form
Answer:
9 : 7
Step-by-step explanation:
Given
4.5 : 3 [tex]\frac{1}{2}[/tex] ( multiply both parts by 2 to clear the fractions )
= 9 : 7
A pair of earbuds cost 43$. They are on sale for 20% off. What is the discount and the final price of the earbuds
Answer:
the discount of the earbuds is $8.60
the final price is $34.40
Step-by-step explanation:
1. find 20% of 43:
43 x 0.2 = 8.60
2. subtract that from $43:
$43 - 8.60 = $34.40
the discount of the earbuds is $8.60
the final price is $34.40
2p -5q=8.. 3p-7q=11 use substitution
Answer:
p = -1 q = -2
Step-by-step explanation:
3p - 7q = 11 -7q = -3p + 11 q = 3/7p - 11/7
2p - 5(3/7p - 11/7) = 8
2p - 15/7p + 55/7 = 8
-1/7p + 55/7 = 8
-1/7p = 1/7
p = -1
2(-1) - 5q = 8
-2 - 5q = 8
-5q = 10
q = -2
common denominator for 3/4 and 7/6
Answer:
12
Step-by-step explanation:
3/4 = 9/12
7/6 = 14/12
12 is a suitable common denominator for these fractions.
__
4 = 2·2
6 = 2·3
The common denominator must include all these factors (and no more than necessary), so must be ...
LCD = 2·2·3 = 12
Helpppppp and explain tooo thank you :)
Answer:
{5, 6, 7}
Step-by-step explanation:
When we have a given relation, the domain is the set of inputs, and the range as the set of the outputs.
so for a function f(x), and a domain {a. b. c}
The range is:
{f(a), f(b), f(c)}
In this case, we have:
f(x) = x + 6
and the domain is {-1, 0, 1}
Then the range is:
{ f(-1), f(0), f(1) }
{-1 + 6, 0 + 6, 1 + 6}
{5, 6, 7}
The correct option is the third one.
(a) A pentagon ABCDE has sides AE and CD parallel and the line EC
is parallel to side AB. Sides ED and BC, when extended, meet at a
point F. ZABC is equal to ZCDE. Show that ZAEC = ZCFD.
(b) If, furthermore, triangles EDC and DFC are both isosceles, with
ED = DC and DF = FC, find the angles of the pentagon.
(a) ∠AEC = ∠CFD, by transitive property of equality
(b) ∠CDE = 108°, ∠DCB = 108°, ∠ABC = 108°,∠EAB = 144°, ∠AED = 72°
The reason the above values are correct is as follows:
(a) The given parameters are;
Figure ABCDE is a pentagon
The sides AE is parallel to side CD
Line EC is parallel to side BC
The point of intersection of the extension off side ED and BC = Point F
∠ABC = ∠CDE
Required:
To show that ∠AEC = ∠CFD
Method:
Draw the pentagon ABCDE and include the added construction
Analyze the drawing
Solution:
∠ECF and ∠ABC are corresponding angles between parallel lines EC ║BC
∴ ∠ECF ≅ ∠ABC by corresponding angles formed by parallel lines are congruent
∠ECF = ∠ABC by definition of congruency
∠ABC = ∠CDE = ∠ECF by transitive property
∠ECD ≅ ∠AEC by alternate angles formed between parallel lines having a common transversal
∠ECD = ∠AEC by definition of congruency
∠ECF = ∠FCD + ∠ECD by angle addition postulate
∠CDE = ∠FCD + ∠CFD by exterior angle theorem
From ∠CDE = ∠ECF above, we have;
∠ECF = ∠FCD + ∠ECD = ∠FCD + ∠CFD
∴ ∠ECD = ∠CFD by addition property
∠ECD = ∠AEC, therefore;
∠AEC = ∠CFD, by transitive property
(b) Given that ΔEDC and ΔDFC are both isosceles triangles, with sides;
ED = DC, and DF = FC;
Let r represent ∠CFD, we have;
∠FCD = ∠CDF by base angles of isosceles triangle ΔDFC
∠ECD = ∠CED by base angles of isosceles triangle ΔEDC
∠AEG = ∠CDE by corresponding angles formed by parallel lines having a common transversal
∠AEC = ∠ECD by alternate angles
∴ ∠AEG + ∠AEC + ∠CED = 180° Sum of angles on a straight line
∠CDE = ∠CFD + ∠FCD
∠CDE + ∠CDF = 180° (linear pair angles)
∴ ∠AEG + ∠CDF = 180° by transitive property
∠AEC + ∠CED = ∠CDF by transitive property
∠AEC = ∠ECD = ∠CED = ∠CFD = r
∴ ∠CFD + ∠CFD = ∠CDF
2·r = ∠CDF
∠CDE = ∠FCD + ∠CFD
∠FCD = ∠CDF = 2·r
∴ ∠CDE = 2·r + r = 3·r
∠CDE = 3·r
The angles of the pentagon are;
∠CDE + ∠DCB + ∠ABC + ∠EAB + ∠AED = 540° sum of angles in a pentagon
∠DCB = 180° - ∠FCD
∠DCB = 180° - 2·r
∠ABC = ∠CDE = 3·r
∠EAB = ∠CEH corresponding angles
∠CEH = 180 - ∠AEC
∴ ∠EAB = 180° - ∠AEC
∴ ∠EAB = 180° - r
∠AED = ∠AEC + ∠CED = r + r = 2·r
∠AED = 2·r
Therefore, we have;
3·r + 180° - 2·r + 3·r + 180° - r + 2·r = 540°
5·r + 360° = 540°
r = (540° - 360°)/5 = 36°
r = 36°
∠CDE = 3 × 36° = 108°
∠DCB = 180° - 2×36° = 108°
∠ABC = 3 × 36° = 108°
∠EAB = 180° - 36° = 144°
∠AED = 2 × 36° = 72°
Learn more about geometry word problems here:
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HELP ME !
Please!
Which of the following tables represents a function?
18 - (-f) = 91 (With work please)
18 - (-f) = 91
Subtracting a negative value changes to addition:
18 + f = 91
Subtract 18 from both sides:
F = 73
Answer:
f = 73
Step-by-step explanation:
Solve for f
18 - ( - f ) = 91
Remove the parantheses and change their sign.18 + f = 91
subtract each side by 1818 - 18 + f = 91 - 18
calculatef = 73
A local hamburger shop sold a combined total of 688 hamburgers and cheeseburgers on Thursday. There were 62 fewer cheeseburgers sold than hamburgers How many hamburgers were sold on Thursday?
Answer:
626
Step-by-step explanation:
So 62 fewer right so 688 combined- 62 cheeseburger =626 hamburger
PLEASE HELP! Use the graph to solve the system of equations.
A. (-5,0)
B. (0,5)
C. (0,0)
D. (2,3)
Answer:
D
Step-by-step explanation:
Look for the intersection point of the two graphs
Another way:
You can just substitute each pair in both equations and u will find that d is the correct answer
yall still in school? i ended may 27th hbu?
Answer:
mine ended june 9th but i got summer school for 2 classes lol
School ended the 15 of June but I'm in summer school rn it ends this Friday
Max earned $8 for each hour of work he completed. His mom put $120 in his savings account at the end of the summer. By the end of the summer, Max had $400 in his savings account. Write an equation to determine the number of hours Max worked over the summer.
Answer:
8x +120= 400
Step-by-step explanation:
Let the number of hours Max worked over the summer be x.
Assuming that he had $0 in his bank at the start of summer,
Total savings= 8(number of hours) +120
400= 8x +120
8x +120= 400
To find the value of x, first bring all the constants to one side of the equation.
8x= 400 -120
Simplify:
8x= 280
Divide both sides by 8:
x= 280 ÷8
x= 35
∴ Max worked for 35 hours over the summer.
What is the shape of this distribution? A. Unimodal skewed B. Uniform C. Bimodal symmetric D. Unimodal symmetric E. Bimodal skewed
Answer:
D
Step-by-step explanation:
It can't be C and B since it doesn't have two parts, and if it was uniform it would have another part attached to the bottom. Moreover, it can't be A since it isn't positively skewed or negatively skewed, so it must be D.
The shape of this distribution is Unimodal symmetric.
Option D is the correct answer.
What is a histogram?A histogram is a representation of the distribution of data with intervals.
We have,
In statistics, a distribution is considered unimodal symmetric if it has a single mode or peak and is symmetric around that mode.
This means that the data is evenly distributed on both sides of the mode and is equally likely to occur on either side.
A common example of a unimodal symmetric distribution is the normal distribution, also known as the Gaussian distribution or bell curve.
Thus, the shape of this distribution is Unimodal symmetric.
Learn more about histograms here:
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Help me please im struggling I will mark as brainliest
Answer:
In picture
Step-by-step explanation:
Brainliest please ~
Answer: y = [tex]\frac{5}{3}x +5[/tex]
Step-by-step explanation:
This is how you find the slope: [tex]slope=\frac{rise}{run}=\frac{y1-y2}{x1-x2}[/tex]
Find two coordinate points. Let's use (-3,0) and (0,5). Based on this, we know that y1 is 0, y2 is 5, x1 is -3, and x2 is 0. Plug these into the formula:
[tex]\frac{0-5}{-3+0} =\frac{-5}{-3} =\frac{5}{3}[/tex]
So, the slope is [tex]\frac{5}{3}[/tex]
The y intercept is where the line hits the y graph. We can see that the y intercept is 5 (or (0,5))
Slope intercept form: y = mx + b, m = slope, b = y intercept
Plug everything in:
y = [tex]\frac{5}{3}x +5[/tex]
In a group of 36 pupils, 10 play the flute only. 15 play the piano only. 4 play neither instrument. A student is selected at random. What is the probability the student plays both instruments?
Answer:
9
Step-by-step explanation:
First you would need to subtract all the irrelevant students.
So, subtract 4 from 36, which is 34.
34 - (10 + 15) =
34 - 25 =
9
The answer is 9 pupils.
Please help. I’m lost with this.
Answer:
35 miles
Step-by-step explanation:
You add up all of the miles on the chart to get 35 miles. Have a great day! I hope this helped.
Which is the largest three-digit number of the form 9k + 1, where k is any positive integer?
Answer:
991
Step-by-step explanation:
We are looking for a number that is one more than a multiple of 9(denoted by the 9k) and is a three digit number. We can start by looking for 3-digit number divisible by 9 which are close to 1,000, since that is the next number larger than the largest three-digit number. We can tell that 999 is divisible by 9 because when divided it does not leave a remainder(you can also figure this out with divisibility tricks). We add one to get 1,000. This is not a three-digit number, so we need to look for a smaller multiple of 9. Subtracting 9 from 999, we get the next largest multiple of 9. We can add 1, and this time, the number, 991, is a three digit number, and the largest that can be in the form 9k + 1.
the area of a circle is 616 m square find the radius 5 equals to 22/7
Step-by-step explanation:
[tex]here \: is \: your \: solution : - \\ \\ GIVEN \: \: -:- \\ \\ = > \: area \: of \: circle \: = 616 \: m {}^{2} \\ \\ \ = > pi = 22 \div 7 \\ \\ = > we \: need \: to \: find \: radius \: \\ \\ = > area \: of \: circle \: = \pi \: r {}^{2} \\ \\ = > \: \pi \: r {}^{2} = 616 \: m {}^{2} \\ \\ = > \: r {}^{2} \times (22 \div 7) = 616 \\ \\ = > \: r {}^{2} =( 616 \times 7) \div 22 \\ \\ = > \: r { }^{2} = 4312 \div 22 \\ \\ = > r {}^{2} = 196 \\ \\ = > \: r = \sqrt{196} \\ \\ = > \: r = 14 \: \: \: (ANSWER✓✓✓) \\ \\ HOPE \: IT \: HELPS \: YOU \: (◕ᴗ◕✿)[/tex]
If the volume of a cubical room is 2700 cm^3 . Find its length
Step-by-step explanation:
If the volume of a cubical room is 2700 cm³ .
l³=2700
l=3 (100)⅓
Someone pls help me ill give out brainliest pls don’t answer if you don’t know
Answer:
y < -7
Step-by-step explanation:
You balance it like a normal equation:
8y + 3 > 15y + 52
8y + 3 (-8y) > 15y + 52 (-8y)
3 (-52) > 7y + 52 (-52)
-49 (÷7) > 7y (÷7)
y < -7
Need help on this question asap please
Answer:
8 m
-----------------Work--------------
2*3 = 6
Ratio
2*4 = 8
What degree of rotation about the origin will cause the triangle below to map
onto itself?
A.90
B.270
C.360
D.180
HJ = 18 and MN = 28. Solve for LK
Answer:
LK = 38
Step-by-step explanation:
MN is the midsegment, and the midsegment is the average length of the top and bottom, so:
[tex]\frac{18 + LK}{2} =28[/tex]
solve for LK:
[tex]18+LK=56\\\\LK=38[/tex]
Use the Theorem of Pythagoras twice to calculate the lengths marked x. Give your answers accurate to 4sf.
It take 4 people 40 minutes to clean a garden. How long will it take 6 people to clean the same garden
Answer:
4/9 of an hour (26.666 minutes)
Step-by-step explanation:
4 * x * 40/60 = 1
x * 160/60 = 1
x=60/160 = 6/16 = 3/8 (this is the rate for one worker)
~~~~~~~~~~~~~~~~
6 * (3/8) * x = 1
x = 4/9
Find the greatest common factor of the
following monomials:
36m3n4. 2m5n3. 4m6n6
Answer:
2m^3n^3
Step-by-step explanation:
Let us start with the number parts
36 , 2 and 4
2 is common here as it can divide all
The smallest m factor is m^3 so it is common for all
The smallest n factor is n^3 which is also common for all
So, we have the greatest common factor as;
2 * m^3 * n^3 = 2m^3n^3
prime numbers that can be expressed as a sum and difference of 2 prime numbers
ASAP
Given:
Prime numbers can be expressed as a sum and difference of 2 prime numbers.
To find:
The prime numbers that can be expressed as a sum and difference of 2 prime numbers.
Solution:
Prime numbers are the positive integers which are greater than 1, divisible by only 1 and itself.
Prime numbers are 2, 3, 5, 7, 11, 13, 17, 19,... .
Only 2 is the even prime number.
The sum and difference of two odd integers is always an even number. So, we need to take one even prime number and one odd prime number to add and subtract the numbers to get a prime number.
[tex]2+3=5[/tex]
[tex]7-2=5[/tex]
Therefore, 5 is the only prime number that can be expressed as a sum and difference of 2 prime numbers.
find area of the figure
thanks for any help
Answer:
8050 m²
Step-by-step explanation:
We can divide the diagram up into two components: a rectangle with a width of 60 m and a height of 80 m, and a triangle with a base of 130 m (190 - 60) and a height of 50 m (80 - 30).
The area of the rectangle:
A = lw
A = 60 m (80 m)
A = 4800 m²
The area of the triangle:
A = 1/2 b*h
A = 1/2 (130 m) (50 m)
A = 1/2 (6500 m²)
A = 3250 m²
Now, we can add the areas of the two separate components:
A = 4800 m² + 3250 m²
A = 8050 m²
10 y is directly proportional to the cube of x. Given that y = 1512 when x = 6, find the equation for the y in terms of x.
Answer:
[tex]{ \tt{y \: \alpha \: {x}^{3} }} \\ { \tt{y = k {x}^{3} }} \\ { \bf{k \: is \: a \: proportionality \: constant}} \\ { \tt{1512 = (k \times {6}^{3}) }} \\ { \tt{k = 7}} \\ { \boxed{ \bf{y = 7 {x}^{3} }}}[/tex]
Graph this function: y= -5/3x+6
Answer:
(0,6) and (3,1)
Step-by-step explanation:
The equation is already in slope intercept form.
y = mx + b
Since the y-intercept is '6', the first point would be (0, 6).
-----------------------------------
We can move three units to the right and 5 units down to get our second point, (3,1).
Note that slope is rise over run.
(0 + 3, 6 - 5) - > (3, 1).
The points would be (0,6) and (3,1). After plotting, you would draw a continuous line through them.
Hope this helps.