Answer:
augmented
Step-by-step explanation:
In the field of linear algebra, the augmented matrix is defined as the matrix that is [tex]\text{obtained by appending}[/tex] the given columns of any two given matrices, that is usually for the [tex]\text{purpose of performing the same elementary row operations on each of the given matrices. }[/tex]
Here, each row forms an equation having a constant and the column have the coefficients for the single variable.
Thus an augmented matrix is obtained from a system of linear equation in matrix.
pls help me asap!!!!!!!!
Answer:
Center: (9,3)
Radius: 9 units
Step-by-step explanation:
[tex]x^{2} -y^{2} -18x-6y+9=0[/tex]
[tex]x^{2} -18x+81+y^{2} -6y+9=-9+81+9[/tex]
[tex](x-9)^{2} +(y-3)^{2} =81[/tex]
Center: (9,3)
[tex]r^{2} =81[/tex] → [tex]r=9[/tex]
Radius : 9 units
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Find an equation for the line with the given properties.
x-intercept = 2; y-intercept = -3. y =
Answer:
[tex]y=\displaystyle\frac{3}{2}x-3[/tex]
Step-by-step explanation:
Hi there!
Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0)
We're given:
⇒ x-intercept = 2
⇒ y-intercept = -3
1) Determine the slope (m)
[tex]m=\displaystyle\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Given the x- and y-intercepts, we can rewrite them as points:
x-intercept = 2
⇒ (2,0)
y-intercept = -3
⇒ (0,-3)
Plug these points into the equation:
[tex]m=\displaystyle\frac{0-(-3)}{2-0}\\\\m=\displaystyle\frac{0+3}{2}\\\\m=\displaystyle\frac{3}{2}[/tex]
Therefore, the slope of the line is [tex]\displaystyle\frac{3}{2}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=\displaystyle\frac{3}{2}x+b[/tex]
2) Plug in the y-intercept (b)
[tex]y=\displaystyle\frac{3}{2}x+b[/tex]
We're given the y-intercept: -3. Plug this into [tex]y=\displaystyle\frac{3}{2}x+b[/tex]:
[tex]y=\displaystyle\frac{3}{2}x+(-3)\\\\y=\displaystyle\frac{3}{2}x-3[/tex]
I hope this helps!
11. PLEASE HELP ME
A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h= -16t2 + 48t + 6. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
A. 1.5 s; 42 ft
B. 1.5 s; 114 ft
C. 3 s; 6 ft
D. 1.5 s; 54 ft
Answer:
A. 1.5 s; 42 ft
Step-by-step explanation:
1.5 sec and will reach a height of 42 feet
that is the vertex
for y=ax^2+bx+c
the x value of teh vertex is
the y value is found by subsituting the x value of the vertex for x
so
h=-16t^2+48t+6
a=-16
b=48
c=6
x value of vertex is
subsituting it for x we get
it reaches the max height of 42ft at 1.5 seconds
what is the equation of the line that is parallel to the given line and passes through the point (-3,2)? no links.
Answer:
D) 4x +3y = -6
Step-by-step explanation:
paralell lines so m1 and m2 are equal
m = (3 +1 )/ (0 - 3 )
m = -4/ 3
y -2 = -4/3 (x +3)
y =-4x/3 -2
3y = -4x -6
4x +3y = -6
Full working out for this question please.
On Monday Farmer Tom collected 6 times as many eggs as Farmer Jack. On Tuesday, Farmer Tom sold 425 eggs. Farmer Jack then had three times as many eggs as Farmer Tom. How many eggs did farmer Jack have?
a.150
b.175
c.125
d.25
e.75
Answer:
75
Step-by-step explanation:
Let farmar jack collected x eggs, then farmar Tom collect 6x eggs
farmar Tom sold 425 eggs, so he left with 6x-425 eggs, now farmar jack has 3 times of what farmar Tom has, so
3(6x-425)=x
or, x=75
so farmar jack had 75 eggs
Answered by GAUTHMATH
Helpppp and explain pls and ty
Step-by-step explanation:
2 gallons are needed for 10 galloms of lemonade
x+y=4
x-2y=-5
If the first equation is multiplied by 2 and then the equations are added, the result is
=3
3 = 13
o3х=3 3
Answer:
3x = 3
Step-by-step explanation:
x + y = 4 × 2
= 2x + 2y = 8
2x + 2y = 8 + x - 2y = -5
3x = 3
the area of a parallelogram shape land is on the square and length of its two adjacent sides are 25 m and 17 M find its diagonal
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
230% of 99 hours is what?
Answer:
227.7 hours
Step-by-step explanation:
of means multiply and is means equals
230% * 99 = what
Change the percent to decimal form
2.30 * 99 = what
227.7= what
[tex]\\ \sf\longmapsto 230\%\:of\:99[/tex]
[tex]\\ \sf\longmapsto \dfrac{230}{100}\times 99[/tex]
[tex]\\ \sf\longmapsto \dfrac{230(99)}{100}[/tex]
[tex]\\ \sf\longmapsto \dfrac{22777}{100}[/tex]
[tex]\\ \sf\longmapsto 227.7hours[/tex]
Please answer:
Joanna bakes a cake in the shape of a
cylinder. The cake is 10 inches in
diameter and 4.5 inches tall. She
wants to put frosting on the entire
cake that is not resting on the tray.
How many square inches of frosting
will she need?
The cake has a cylindrical format, and the outside of the cake will be frosted, which means that the total surface area has to be found, and doing this, we find that she will need 298.5 square inches of frosting.
Surface area of a cylinder:
The surface area of a cylinder of radius r and height h is given by:
[tex]S = 2\pi r^2 + 2\pi rh[/tex]
The cake is 10 inches in diameter and 4.5 inches tall.
Radius is half the diameter, so [tex]r = \frac{10}{2} = 5[/tex].
The height is [tex]h = 4.5[/tex].
How many square inches of frosting will she need?
This is the surface area, so:
[tex]S = 2\pi(5)^2 + 2\pi(5)(4.5) = 50\pi + 45\pi = 95\pi = 298.5[/tex]
She will need 298.5 square inches of frosting.
A similar problem can be found at https://brainly.com/question/24332238
Answer:
Step-by-step explanation:
First of all, we need the formula of a cylinder which is: 2[tex]\pi[/tex]rh + 2[tex]\pi[/tex][tex]r^{2}[/tex]
BUT also remember we are solving for one base since we do not count the bottom of the tray. That formula would look like this: 2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex] since we are using 1 base instead of 2.
Now input the missing values into the formula and solve:
2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex]
2[tex]\pi[/tex](5)(4.5) + [tex]\pi[/tex][tex](5^{2})[/tex]
45[tex]\pi[/tex] + 25[tex]\pi[/tex] = 70[tex]\pi[/tex]
Our Answer is 70[tex]\pi[/tex], or 219.91 [tex]in^{2}[/tex]
Evaluate f-g+(-2) where f = -3.005 and g = 4.7
Answer:
-9.705
Step-by-step explanation:
f-g+(-2)
Let f = -3.005 and g = 4.7
-3.005 -4.7 -2
-9.705
Make x the subject of the formula
I need help on this one too
E=7x+8f
Thank you so much if you answer!
Answer:
Step-by-step explanation:
To make x the subject, isolate x
7x + 8f = E
Subtract 8f from both sides
7x = E - 8f
Divide both sides by 7
[tex]x =\frac{E-8f}{7}[/tex]
Answer:
x = [tex]\frac{E-8f}{7}[/tex]
Step-by-step explanation:
Given
E = 7x + 8f ( subtract 8f from both sides )
E - 8f = 7x ( isolate x by dividing both sides by 7 )
[tex]\frac{E-8f}{7}[/tex] = x
Select the correct answer from the drop-down menu.
Z1 = 4cis (pi/2) and Z2=3cis(3pi/2)
The product of Z1 and Z2 is
Answer:
z₁ × z₂ = 12·cis(2·π)
Step-by-step explanation:
z₁ = 4·cis(π/2), z₂ = 3·cis(3·π/2)
We have;
z₁ = 4·cis(π/2) = 4·(cos(π/2) + i·sin(π/2))
z₂ = 3·cis(3·π/2) = 3·(cos(3·π/2) + i·sin(3·π/2))
According to De Moivre's Theorem,
z₁ × z₂ = 4×3×(cos(π/2 + 3·π/2) + i·sin(π/2 + 3·π/2)) = 12·(cos(2·π) + i·sin(2·π))
∴ z₁ × z₂ = 12·cis(2·π)
256x²+² - x²y² + 49y²+²
[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49y^2x^2[/tex]
[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49x^2y^2[/tex]
[tex]\\ \sf\longmapsto (256-1+49)x^2y^2[/tex]
[tex]\\ \sf\longmapsto 304x^2y^2[/tex]
James is studying the decline of a certain bird species. James’ observations are as follows: Year 1900 1950 1990 2005 Population (in thousands) 6012 72 2 .5 What is the best fit exponential decay equation for this decline? 5=6012(1-0.06)105 At what year did the population first drop below 1,000,000? If this trend continues, what will be the population in 2020?
can someone help me figure out how much my final exam is weighted?
in the grade book there are:
6 assignments for 10 points each
52 assignments for 20 points each (it’s not a typo i promise there was actually 52)
5 assignments for 30 points each
5 assignments for 40 points each
and 1 assignment for 60 points (aka the final exam)
my grade is an average of all of these different assignments combined. How much is my exam weighted- can you even calculate this? (i just want to know so i can see what score i need to get to pass with an a)
Answer:
About 4%
Step-by-step explanation:
6x10=60
52x20=1040
5x30=150
5x40=200
1x60=60
Total Points available:1510
Final Exam is 60 points
60/1510=0.0397
Members of a soccer team raised $1946.50 to go to a tournament. They rented a bus for $974.50 and budgeted $60.75 per player for meals. Write and solve an equation which can be used to determine pp, the number of players the team can bring to the tournament.
Answer:
16 players can be brought to the tournament. The equation is written within my step-by-step explanation.
Step-by-step explanation:
Variable p = number of players
Set up an equation:
974.50 + 60.75p = 1946.50
Isolate variable p:
60.75p = 972
Divide:
p = 16
Check your work:
974.50 + 60.75(16) = 1946.50
974.50 + 972 = 1946.50
1946.50 = 1946.50
Correct!
Answer:
Step-by-step explanation:
What is the probability of getting ALL 2 red balls in a bag containing 24 balls?
Answer:
1 / 276
Step-by-step explanation:
The total Number of balls in the bag = 24
Number of red balls = 2
Assume the number of picks required = 2 and selection is performed without replacement ;
The probability of :
Choosing a red on first pick = (number of red balls / total number of balls) = 2 / 24
After first pick, red balls left = 1 ; total number of balls = 23
Choosing a red on second pick = (number of red balls / total number of balls = 1 / 23
Hence,
(2/24) * (1/23) = 2 / 552 = 1/276
6.17 greater or less 61 87/100
Answer:
Less
Step-by-step explanation:
[tex]6.17 < 6.187 [/tex]
please help meeeeeeeeeeeeee
Answer:
a)-2x(x+4x²)+3(x²+2x)
-2x²-8x³+3x²+6x
-2x²+3x²+6x-8x³
x²-8x³+6x
in descending order
-8x³+x²+6x
b)(4x-3)(4x+3)
4x(4x+3)-3(4x+3)
16x²+12x-12x-9
16x²-9
I hope this helps and sorry if it's wrong
please just (c)fog-¹
f(x) = 1/(1 - x)
g(x) = (x - 1)/x
The inverse functions f ⁻¹(x) and g ⁻¹(x), if they exist, are such that
f( f ⁻¹(x) ) = x
g( g ⁻¹(x) ) = x
So we have
f( f ⁻¹(x) ) = 1/(1 - f ⁻¹(x) ) = x
Solve for f ⁻¹(x) :
1 = (1 - f ⁻¹(x) ) x
1 - f ⁻¹(x) = 1/x
f ⁻¹(x) = 1 - 1/x
f ⁻¹(x) = (x - 1)/x
and so f ⁻¹(x) = g(x).
Similarly, you can solve for g ⁻¹(x) :
g( g ⁻¹(x) ) = (g ⁻¹(x) - 1) / g ⁻¹(x) = x
1 - 1/g ⁻¹(x) = x
1/g ⁻¹(x) = 1 - x
g ⁻¹(x) = 1/(1 - x)
So we know f(x) and g(x) are inverses of one another,
f ⁻¹(x) = g(x)
g ⁻¹(x) = f(x)
Then
(a) (f o g)(x) = x
(b) (g o f ⁻¹)(x) = g(g(x)) = (g(x) - 1)/g(x) = 1 - 1/g(x) = 1 - x/(x - 1) = 1/(1 - x)
(c) (f o g ⁻¹)(x) = f(f(x)) = 1/(1 - f(x) ) = 1/(1 - 1/(1 - x)) = 1/(x/(x - 1)) = (x - 1)/x
hi! can i get some help with this question! :)
Hi there!
[tex]\large\boxed{log_b3b = 1.8397}[/tex]
Keep in mind the following log property:
logₓab = logₓa + logₓb
Thus:
[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]
We know the value of log_b3, and a log with the same values for the base equals 1. Thus:
[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]
can someone please help me? this is confusing
Answer:
S=(-2, -9)
T=(-8, -9)
U=(-9, -5)
V=(-6, -5)
Step-by-step explanation:
rotating counter clockwise 90 degrees has a simple formula: (-y, x) simply take your ordered pair and rearrange it to match this formula.
ex. (3, 4) would become (-4, 3)
(-y, x) the negative symbol in front of the y means to switch the sign from either positive or negative to its opposite. since there is no symbol in front of the x you keep that numbers sign the same.
Verificar que el volumen de ambas figuras es el mismo, para ello lleva a cabo el siguiente procedimiento:
a) Obtén una expresión para el volumen de la primera figura.
b) Transforma la expresión como una multiplicación de polinomios.
c) Identifica en tu resultado el área de la base prisma y su altura para concluir una igualdad.
Answer:
English for fast response
Solve the equation involving simple interest
Answer:
4%
Step-by-step explanation:
(8700 - 7500)/4 = 300
300/7500 = .04
What is the expected number of tails when a fair coin is tossed 100 times?
Answer:
50 times
Step-by-step explanation:
Assuming a fair coin (probability of heads = 1/2), the expected number of heads (in the sense of mathematical expectations) is 100*1/2 = 50.
Find the missing side. PLEASE HELP FAST !
Answer:
It is 28.5m. Hope this helps!! Have a good day..
please help me answer this math question, it is really important
Answer:
3 three point baskets
9 two point baskets
4 one point baskets
Step-by-step explanation:
Since you cannot have a 1/3 or 2/3 of a three point basket, finding multiples of threes for the initial two point baskets is the easiest way to start.
help me fast pleaseee
Answer:
A
Step-by-step explanation:
The answer is A. Answered by Gauthmath
Find the slope (rate of change) of each representation. Please explain how you got it.
Answer:
m = -3/2
Step-by-step explanation:
To find the slope of the representation, use the slope formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
I'll pick (-4, 9) and (-2, 6) in this instance.
[tex]m=\frac{9-6}{-4-(-2)}\\\\m=-\frac{3}{2}[/tex]
Therefore, the slope of the representation is -3/2.
Answer:
-3/2
Step-by-step explanation:
To find the slope, we can use the formula
m = ( y2-y1)/(x2-x1)
= ( -6 -9)/(6 - -4)
= (-6-9)/(6+4)
-15/10
-3/2