Answer:
a) month salary = RM(18×800+2000)
= RM 16400
b) his salary = RM(800n+2000)
Hope it helps
what percentage of undergraduates students in Calculus 1 are required to do computer assignments in their classes
Full question:
Every 5 years the Conference Board of the Mathematical Sciences surveys college math departments. In 2000 the board reported that 51% of all undergraduates taking Calculus I were in classes that used graphing calculators and 31% were in classes that used computer assignments. Suppose that 16% used both calculators and computers. a) What percent used neither kind of technology? b) What percent used calculators but not computers? c) What percent of the calculator users had computer assignments? d) Based on this survey, do calculator and computer use appear to be independent events? Explain.
Answer:
a. 34%
b. 35%
c. 31.4%
d. Independent events
Explanation:
a. To calculate percentage that used neither kind of technology, we already know those that use the technologies and total taking calculus so:
100%-51%-31%-16%= 34%
b. Percentage that used calculators but not computers.
= 51%-16%=35%
c. Percentage of the calculator users that had computer assignments?
= 16/51×100=31.4% (there are 16 people using both so that as a percentage of 51 people using calculators)
d. Independent events are events that do not affect the other, such that occurrence of one does not define occurrence of the other. Since percentage of calculator and computer assignment users is close to those who are not using any, we can say they are independent events.
why mathematics is the very important in a small business? is mathematics is helpful to you? explain
Answer:
Mathematics is very important in a small business is because when you make money transactions with other people you need to know how to count money correctly and your calculations can’t be wrong. When we sign up for jobs like police, or firefighter, we need to use math. Math helps us solve real-world problems.
Step-by-step explanation:
Hattie had $3,000 to invest and wants to earn 10.6% interest per year. She will put some of the money into an account that earns 12% per year and the rest into an account that earns 10% per year. How much money should she put into each account?
Answer:
900 at 12%
2100 at 10%
Step-by-step explanation:
Let x= amount invested at 12%
let y= amount invested at 10%
with that being said we can write the two equation
Equation 1: x+y=3000
Equation 2: 3000*.106=.12x+.1y
isolte x from equation 1
x= 3000-y
plug this into equation 2
318=.12(3000-y)+.1y
318=360-.12y+.1y
-42= -.02y
y= 2100
Plug this into equation 1
x+2100=3000
x=900
she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
How to determine How much money should she put into each accountLet's denote the amount of money Hattie invests at 12% as \(x\) dollars, and the amount she invests at 10% as \(\$3000 - x\) dollars.
The formula for calculating interest is: \(\text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time}\).
For the 12% account:
Interest_12% = \(x \times 0.12 \times 1\) (1 year)
For the 10% account:
Interest_10% = \((3000 - x) \times 0.10 \times 1\) (1 year)
Hattie wants to earn 10.6% interest on the total investment, so we can set up the equation:
\(\text{Total Interest} = \text{Interest}_12% + \text{Interest}_10%\)
\(3000 \times 0.106 = x \times 0.12 + (3000 - x) \times 0.10\)
Now, solve for \(x\):
\(318 = 0.12x + 300 - 0.10x\)
\(318 = 0.02x + 300\)
\(18 = 0.02x\)
\(x = 900\)
Hattie should invest $900 at 12% and \(3000 - 900 = 2100\) at 10%.
Therefore, she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
Learn more about interest at https://brainly.com/question/29451175
#SPJ3
The equation y - 5 = 6X + 1 is written as point-slope form. What is the equation written in slope intercept form
Answer:
y = 6x + 6
Step-by-step explanation:
The general formula is y = mx +cso; the y as seen will be constant as well as the x
With change of subject the 5 will be moved to the other side having y= 6x +1 + 5 .Given us y = 6x + 6.
A right rectangular prism has a length of 5 centimeters, a width of 8 centimeters, and a height of 4 centimeters. What is the volume of the prism?
Answer:
volume of prism is 160 cm
Round 948070 to the nearest hundred? Hurry please
Answer:
9.48
Step-by-step explanation:
What is the area of area of 7 meters, 15 meters and 9 meters?
Answer:
10
Step-by-step explanation:
10-7 do it yourself and don't vheat
Rearrange 2x = y/w to make w the subject
Julie and Mona know that that Earth’s average distance from the Sun is approximately 93 million miles and it takes 1 year to complete an orbit of the Sun. A new asteroid has been discovered orbiting the Sun at an average distance of 1,488 million miles. How long will it take for the asteroid, in Earth years, to complete one orbit of the Sun.
Answer:
16 years
Step-by-step explanation:
Given that :
Earth's distance from sun = 93 million miles
Number of years to complete an orbit = 1 year
Average orbiting distance of new asteroid = 1488 million miles
Number of years to complete an orbit = x
93,000,000 Miles = 1
1488000000 miles = x
Cross multiply :
93000000x = 1488000000
x = 1488000000 / 93000000
x = 16 years
Period taken to orbit the sun = 16 years
Answer: 64 Earth years...
A little help?? It’s trig
Answer:
12 [tex]\pi[/tex] = 37.699 f/s
Actually, the more interesting question
would have been how fast is the ball going in MPH?
25.7 MPH
Step-by-step explanation:
C = 2[tex]\pi r[/tex]
C = 2 [tex]* \pi * 1.2[/tex]
C = 2.4 [tex]\pi feet[/tex]
C (per second) = (5)(2.4 [tex]\pi feet[/tex])
C(per second) = 12 [tex]\pi[/tex] = 37.699 f/s
Diana adds either 2 or 5 to every whole number from 1 to 9. She wants to achieve as few different sums as
possible. What is the minimum number of different values she obtains?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Please help NO LINKS
[tex]\bar{x} = 0[/tex]
[tex]\bar{y} =\dfrac{136}{125}[/tex]
Step-by-step explanation:
Let's define our functions [tex]f(x)\:\text{and}\:g(x)[/tex] as follows:
[tex]f(x) = x^2 + 1[/tex]
[tex]g(x) = 6x^2[/tex]
The two functions intersect when [tex]f(x)=g(x)[/tex] and that occurs at [tex]x = \pm\frac{1}{5}[/tex] so they're going to be the limits of integration. To solve for the coordinates of the centroid [tex]\bar{x}\:\text{and}\:\bar{y}[/tex], we need to solve for the area A first:
[tex]\displaystyle A = \int_a^b [f(x) - g(x)]dx[/tex]
[tex]\displaystyle \:\:\:\:\:\:\:=\int_{-\frac{1}{5}}^{+\frac{1}{5}}[(x^2 + 1) - 6x^2]dx[/tex]
[tex]\displaystyle \:\:\:\:\:\:\:=\int_{-\frac{1}{5}}^{+\frac{1}{5}}(1 - 5x^2)dx[/tex]
[tex]\displaystyle \:\:\:\:\:\:\:=\left(x - \frac{5}{3}x^3 \right)_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]
[tex]\:\:\:\:\:\:\:= \dfrac{28}{75}[/tex]
The x-coordinate of the centroid [tex]\bar{x}[/tex] is given by
[tex]\displaystyle \bar{x} = \dfrac{1}{A}\int_a^b x[f(x) - g(x)]dx[/tex]
[tex]\displaystyle \:\:\:\:\:\:\:= \frac{75}{28}\int_{-\frac{1}{5}}^{+\frac{1}{5}} (x - 5x^3)dx[/tex]
[tex]\:\:\:\:\:\:\:=\dfrac{75}{28}\left(\dfrac{1}{2}x^2 -\dfrac{5}{4}x^4 \right)_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]
[tex]\:\:\:\:\:\:\:= 0[/tex]
The y-coordinate of the centroid [tex]\bar{y}[/tex] is given by
[tex]\displaystyle \bar{y} = \frac{1}{A}\int_a^b \frac{1}{2}[f^2(x) - g^2(x)]dx[/tex]
[tex]\displaystyle \:\:\:\:\:\:\:=\frac{75}{28}\int_{-\frac{1}{5}}^{+\frac{1}{5}} \frac{1}{2}(-35x^4 + 2x^2 + 1)dx[/tex]
[tex]\:\:\:\:\:\:\:=\frac{75}{56} \left[-7x^5 + \frac{2}{3}x^3 + x \right]_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]
[tex]\:\:\:\:\:\:\:=\dfrac{136}{125}[/tex]
A ball is thrown vertically upward with an initial velocity of 19 m/s. Its height, h(t)metres after t seconds, is given by the equation h(t) = -3t2 + 20t + 2.0.
The time taken by the ball to reach the maximum height is ________ seconds. Round your answer to the nearest tenth.
Answer:
Step-by-step explanation:
There are 2 different ways to do this: calculus and by completing the square. In this particular instance, calculus is WAY easier, and since I don't know for what class you are doing this, I'll do both ways. First the calculus way. We know the position equation, and the first derivative of the position is velocity. We also know that when the velocity is equal to 0 is when the object is at its max height. So we'll find the derivative first, then solve it for t:
If [tex]s(t)=-3t^2+20t+2[/tex] then the first derivative is
v(t) = -6t + 20 Solving for t requires that we set the velocity equal to 0 (again, this is where the object is at its max height), so
0 = -6t + 20 and
-20 = -6t so
t = 3.3 seconds. Now that we know that at 3.3 seconds the object is at its highest point, we sub that time into the position function to see where it is at that time:
s(3.3) = [tex]-3(3.3)^2+20(3.3)+2[/tex] and
s(3.3) = 35.3 meters.
Now onto the more difficult way...completing the square. Begin by setting the position function equal to 0 and then move over the constant to get:
[tex]-3t^2+20t=-2[/tex] Since the leading coefficient is not a 1 (it's a 3), we have to factor out the 3, leaving us with:
[tex]-3(t^2-\frac{20}{3}t)=-2[/tex] Now the rule is to take half the linear term, square it, and add it to both sides. Our linear term is [tex]\frac{20}{3}[/tex] and half of that is [tex]\frac{20}{6}[/tex]. Squaring that:
[tex](\frac{20}{6})^2=\frac{400}{36}=\frac{100}{9}[/tex]. We will add that in to both sides. On the left it's easy, but on the right we have to take into account that we still have that -3 sitting out front, refusing to be ignored. So we have to multiply it in when we add it to the right. Doing that gives us:
[tex]-3(t^2-\frac{20}{3}t+\frac{100}{9})=-2-\frac{100}{3}[/tex] We will clean this up a bit now. The reason we do this is because on the left we have created a perfect square binomial which will give us the time we are looking for to answer this question. Simplifying the right and at the same time writing the perfect square binomial gives us:
[tex]-3(t-\frac{20}{6})^2=-\frac{106}{3}[/tex] Now the last step is to move the constant back over and set the quadratic back equal to y:
[tex]y=-3(t-\frac{20}{6})^2+\frac{106}{3}[/tex]. The vertex of this quadratic is
[tex](\frac{20}{6},\frac{106}{3})[/tex] where
[tex]\frac{20}{6}=3.3[/tex] as the time it takes for the ball to reach its max height of
[tex]\frac{106}{3}=35.3[/tex] meters.
I'd say if you plan on taking calculus cuz you're not there yet, you'll see that many of these types of problems become much simpler when you know it!
If one table and two lamps cost $88, and two
tables and three lamps cost $153, how much
does a lamp cost?
Answer:
One lamp is equal to 23 dollars
One table is equal to 42 dollars.
Step-by-step explanation:
We can solve this by first organizing what we have.
1 table (t) + 2 lamps (l) = 88.
2 tables (t) + 3 lamps (l) = 153.
_____________
===============
1t + 2l = 88
2t + 3l = 153
===============
-------------------------
If we multiply both sides by 2 on the first equation of
1t + 2l = 88
we could get
2t + 4l = 176.
If that is true, we can subtract the second equation of
2t + 3l = 153 from the new equation to get the price of a lamp.
2t + 4l = 176
- 2t + 3l = 153
____________
= 0t + l = 23
One lamp is equal to 23.
We can check this by plugging it into an equation.
1 + 2(23) = 88
1t + 46 = 88
1t + 46 - 46 = 88 - 46
1t = 42
If one table equals 42, we can put this back into the second equation to check.
2 (42) + 3 (23) = 153
84 + 69 = 153
That is correct.
Another way to solve is to put this like a system of equations in a graph, by replacing "t" by "x" for example, and "l" by y.
Then you could put it into a graphing calculator and solve by looking for the place where the two lines converge or meet.
Since we put "x" for "t", that means that whatever the x-value is on the solution point, that is the cost of a table, and the y-value is the cost of the lamps.
Another way to solve, is to find the unit rate first by subtracting the first equation from the second equation.
2t + 3l = 153
- 1t + 2l = 88
____________
= t + l = 65
If t + l = 65, we can rearrange that equation to be something like t = 65 - l.
That means "t" is equal to 65 bucks minus a lamp.
We put this back into the first equation of
1t + 2l = 88
and replace "t" with the previous expression.
1(65 - l) + 2l = 88
Simplify/distributive property
65 - l + 2l = 88
65 - 65 - l + 2l = 88 - 65
-l + 2l = 23
l = 23
One lamp is equal to 23 bucks.
Confirmed :)
A lamp cost $23
Let the cost of a table be represented by x
Let the cost of a lamp be represented by y.
Since one table and two lamps cost $88, this can be represented as:
x + 2y = 88 ........ equation i
Since two tables and three lamps cost $153, this can be represented as:
2x + 3y = 153 ........ equation ii
Therefore, the equations are:
x + 2y = 88 ....... i
2x + 3y = 153 ....... ii
From equation i,
x + 2y = 88
x = 88 - 2y ...... iii
Put the value of x into equation ii
2x + 3y = 153
2(88 - 2y) + 3y = 153
176 - 4y + 3y = 153
Collect like terms
-4y + 3y = 153 - 176
-y = -23
y = 23
Therefore, a lamp cost $23
Read related question on:
https://brainly.com/question/15165519
8) If 150% of a number is 75, then what is the 80% of that number?
A. 40
B. 50
C. 70
D. 85
Answer:
A. 40
Step-by-step explanation:
Answer:
A. 40
Step-by-step explanation:
75 ÷ 1.5 = 50 = original number
80% of 50 = 50 × 0.8 = 40
what number must you add to complete the square x^2+12x=40
Step-by-step explanation:
x²+12x=40
(x+6)²-6²-40=0
(x+6)²-76 = 0
Find functions f(x) and g(x) so the given function can be expressed as
h(x) = f(g(x)).
(Use non-identity functions for
f(x) and g(x).)
h(x) = 5/x-4
Answer:
[tex]f(x) = \frac{5}{x}[/tex]
[tex]g(x) = x - 4[/tex]
Step-by-step explanation:
Composite function:
[tex]h(x) = f(g(x)) = (f \circ g)(x)[/tex]
h(x) = 5/x-4
We have x on the denominator and not the numerator, so the outer function is given by:
[tex]f(x) = \frac{5}{x}[/tex]
The denominator is x - 4, so this is the inner function, so:
[tex]g(x) = x - 4[/tex]
A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no more than . Suppose that we suspect otherwise and carry out a hypothesis test. State the null hypothesis and the alternative hypothesis that we would use for this test.
Answer:
The null hypothesis is [tex]H_0: p \leq x[/tex], in which x is the proportion tested.
The alternative hypothesis is [tex]H_1: p > x[/tex]
Step-by-step explanation:
A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no more than x.
This means that at the null hypothesis, we test if the proportion is of at most x, that is:
[tex]H_0: p \leq x[/tex]
Suppose that we suspect otherwise and carry out a hypothesis test.
The opposite of at most x is more than x, so the alternative hypothesis is:
[tex]H_1: p > x[/tex]
(Will mark brainliest!!!) 20 PTS !!
Sixty percent of all children in a school do not have cavities. The probability, rounded to four decimal places, that in a random sample of 9 children selected from this school, at least 6 do not have cavities is:
Answer:
probability[Number of 6 random sample do not have cavities] = 0.8
Step-by-step explanation
Given:
Number of student do not have cavities = 60%
Number of random sample = 9 children
Find:
Probability[Number of 6 random sample do not have cavities]
Computation:
n = 9
p = 60% = 0.6
P(At least 6)
Probability[Number of 6 random sample do not have cavities] = 1 - P(Less than 6)
Probability[Number of 6 random sample do not have cavities] = 1 - P(Less than or equal to 6)
Probability[Number of 6 random sample do not have cavities] = 0.8
whats the x and y value? I thought it would be choice d but I'm not sure
please help asap . my question is timed
Answer:
cos(60°) = [tex]\frac{adjacent}{hypotenuse}=\frac{y}{10\sqrt{3} }[/tex]
[tex]cos(60)=\frac{y}{10\sqrt{3} } \\y=cos(60) * 10\sqrt{3} \\y=\frac{1}{2} * 10\sqrt{3}\\y=\frac{10\sqrt{3}}{2} =5\frac{\sqrt{3} }{2} =8.66[/tex]
sin(60°) = [tex]\frac{opposite}{hypotenuse} =\frac{x}{10\sqrt{3} }[/tex]
[tex]sin(60)=\frac{x}{10\sqrt{3} } \\x=sin(60)*10\sqrt{3} \\x=\frac{\sqrt{3} }{2} *10\sqrt{3} \\x=\frac{10(\sqrt{3} ) (\sqrt{3} )}{2} \\x=\frac{10*3}{2} =\frac{30}{2} =15[/tex]
The population of a bacteria colony is growing exponentially, doubling every 6 hours. If there are 150 bacteria currently present, how many (to the nearest ten bacteria) will be present in 10 hours
Answer:
If rounded to the nearest 10 bacteria, then it would be 500 bacteria.
Step-by-step explanation:
First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.
Ivan is playing a skee-ball game. Different points are awarded depending on which hole the ball goes through. When the ball goes in the smallest hole, it is worth 100 points. When it goes in the bigger hole, it is worth 10 points, and when it does not go in either hole, it is worth 1 point. Ivan earned 352 points in the last game.
Which combination will result in a score greater than his current score?
2 balls in the smallest hole, and 8 balls in the bigger hole
4 balls in the smallest hole, and 6 balls in neither hole
3 balls in the smallest hole, 4 balls in the bigger hole, and 3 balls in neither hole
3 balls in the smallest hole, 3 balls in the bigger hole, and 4 balls in neither hole
Answer:
B.
Step-by-step explanation:
I don't know for a fact but i think its B. Sorry if I got it wrong.
Given: CD is an altitude of triangle ABC.
Prove: a^2 = b^2 +c^2 = 2bccos A
Answer:
Step-by-step explanation:
Statements Reasons
1). CD is an altitude of ΔABC 1). Given
2). ΔACD and ΔBCD are right 2). Definition of right triangles.
triangles.
3). a² = (c - x)² + h² 3). Pythagoras theorem
4). a² = c² + x² - 2cx + h² 4). Square the binomial.
5). b² = x² + h² 5). Pythagoras theorem.
6). cos(x) = [tex]\frac{x}{a}[/tex] 6). definition of cosine ratio for an angle
7). bcos(A) = x 7). Multiplication property of equality.
8). a² = c² - 2c(bcosA) + b² 8). Substitution property
9). a² = b² + c² - 2bc(cosA) 9). Commutative properties of
addition and multiplication.
PLEASE ANSWER QUICKLY Find the distance between points (4, 2) and (7, 2) on the coordinate
plane.
Answer:
3 units
Step-by-step explanation:
(4,2) (7,2)
Subtract 4 from 7 = 3
Subtract 2 from 2 = 0
This means that (7,2) is 3 units up from (4,2).
:) ur welcome
Answer:
Step-by-step explanation:
D=√(x2-x1)²+(y2-y1)²
D=√(7-4)²+(2-2)²
D=√(3)²+0
D=3²*½
D=3
For the function, tell whether the graph opens up or opens down, identify the vertex, and tell whether the graph is wider, narrower, or the same width as the graph of y = |x|.
y = 2|x – 1| - 3
opens up, (1, 3), wider
opens up, (1, 3), narrower
opens up, (-1, -3), wider
opens up, (1, -3), narrower
Answer:
The answer is D, the last one.
9514 1404 393
Answer:
(d) opens up, (1, -3), narrower
Step-by-step explanation:
The factor of +2 multiplying the function tells you the graph is expanded vertically by a factor of 2. The parent function opens upward, and the positive sign on this expansion factor does not change that. The expansion means that y-values will be farther from the vertex for the same x-value distance from the vertex. This give the appearance of a narrower graph.
As always, the transformation ...
f(x -h) +k
moves the vertex from (0, 0) to (h, k). Here, you have (h, k) = (1, -3), so that is the location of the vertex of the transformed function.
How is the graph of
y=-3(5)*-
- 3 translated from the graph of y=
=30594?
A. reflected across the y-axis and 3 units down
B. reflected across the x-axis and 3 units down
C. reflected across the x-axis and 3 units left
D. reflected across the y-axis and 3 units right
Answer:
Purplemath
Introduces reflections in the x- and y-axes. ... To see how this works, take a look at the graph of h(x) = x2 + 2x – 3. ... The previous reflection was a reflection in the x-axis. ... f (x – b) shifts the function b units to the right.
Some number times 7 is equal to the number increased by 9
Write out the equation. Do not solve the equation.
Answer:
7x = x + 9.
Step-by-step explanation:
7 × something = something + 9, right?
So, 7x = x + 9.
A machine has two components both of which have a lifespan, in months, that is exponentially distributed with mean 8. The lifespan of the two components are independent. Find the probability both components are functioning in 12 months.
Answer:
0.0498
Step-by-step explanation:
In this question,
x~exponential
we have
mean = 1/λ = 8
from here we cross multiply, when we do
such that
λ = 1/8
probability of x functioning in 8 months
= e^-λx
= e^-1/8x12
= e^-1.5
= 0.2231
i got this value through the use of a scientific calculator
then the probability that these two are greater than 12
= 0.2231²
= 0.04977
= approximately 0.0498
therefore the probability that both components are functioning in 12 months is 0.0498
Perpendicular lines
What is the segment
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be pounds. Assume that the population is normally distributed. Can we support, at the level of significance, the claim that the mean breaking strength has increased
The question is incomplete. The complete question is :
The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?
Solution :
Given data :
Mean, μ = 1900
Standard deviation, σ = 65
Sample size, n = 150
Sample mean, [tex]$\overline x$[/tex] = 1902
Level of significance = 0.01
The hypothesis are :
[tex]$H_0 : \mu = 1900$[/tex]
[tex]$H_1 : \mu > 1900$[/tex]
Test statics :
We use the z test as the sample size is large and we know the population standard deviation.
[tex]$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$[/tex]
[tex]$z=\frac{1902-1900}{65 / \sqrt{150}}$[/tex]
[tex]$z=\frac{2}{5.30723}$[/tex]
[tex]$z=0.38$[/tex]
Finding the p-value:
P-value = P(Z > z)
= P(Z > 0.38)
= 1 - P(Z < 0.38)
From the z table. we get
P(Z < 0.38) = 0.6480
Therefore,
P-value = 1 - P(Z < 0.38)
= 1 - 0.6480
= 0.3520
Decision :
If the p value is less than 0.01, then we reject the [tex]H_0[/tex], otherwise we fail to reject [tex]H_0[/tex].
Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject [tex]H_0[/tex].
Conclusion :
At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.
