Find the missing number?

Answer:

1. 0.1684 = 16.84%.

2. 0.2568 = 25.68%

3. 0.0013 = 0.13%

4. 0.0126 = 1.26%.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have blood that is Group O, or they do not. The probability of a person having blood that is Group O is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

45% of them have blood that is Group O

This means that [tex]p = 0.45[/tex]

Question 1:

This is P(X = 6) when n = 16. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 6) = C_{16,6}.(0.45)^{6}.(0.55)^{10} = 0.1684[/tex]

So 0.1684 = 16.84%.

Question 2:

This is P(X = 3) when n = 8. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{8,3}.(0.45)^{3}.(0.55)^{5} = 0.2568[/tex]

So 0.2568 = 25.68%.

Question 3:

This is P(X = 16) when n = 20. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 16) = C_{20,16}.(0.45)^{16}.(0.55)^{4} = 0.0013[/tex]

So 0.0013 = 0.13%.

Question 4:

This is P(X = 9) when n = 11. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{11,9}.(0.45)^{9}.(0.55)^{2} = 0.0126[/tex]

So 0.0126 = 1.26%.

Answer:

2.2763 x 10 to the power of 4

for some reason it doesn't let me put in the explanation

Answer:

c) tan

Step-by-step explanation:

For the 63-deg angle, YZ is the opposite leg. The unknown side, AY, is the adjacent leg. The trigonometric ratio that relates the opposite and adjacent legs is the tangent.

Answer: c) tan

9514 1404 393

Answer:

  b. No; the domain values are not at regular intervals although the range values have a common factor.

Step-by-step explanation:

The differences between x-values are ...

  -1, -1, -1, -2 . . . . not a constant difference

The ratios of y-values are ...

  2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference

The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.

Answer:

|a|

Step-by-step explanation:

For any positive or negative a, when you square it, the answer is positive.

The square root symbol means the principal square root. For a positive number, the principal square root is positive. To make sure the square root is always non-negative, use absolute value.

Answer: |a|

Answer:

[tex]\displaystyle f(3x) = \frac{6x + 5}{3x + 4}[/tex]

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f(x) = \frac{2x + 5}{x + 4}[/tex]

Step 2: Find

Answer:

The answer is B since the chance is expontential since it gets bigger over time and each one is farther apart

The best-fitting regression model for the scatterplot is Exponential, the correct option is B.

When the data shows some trend, either linear (making a line), or non-linear (a predictable curve), we fit a mathematical curve(exponential) on that data set, as a representative of the pattern in that data set, to predict the output based on the inputs.

We are given;

The graph representation

Now,

By visual inspection of the scatterplot, we can see that the points do not follow a clear pattern that suggests an exponential or quadratic relationship. However, there appears to be a linear relationship between the variables.

Therefore, the answer will be exponential.

Learn more about exponential regression here:

https://brainly.com/question/12608685

#SPJ7

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements:                                                Reasons:

[tex]\displaystyle 1)\, \angle 4\cong \angle 2[/tex]                                                   Given

[tex]\displaystyle 2)\, \angle 3 \cong \angle 4[/tex]                                                   Vertical Angles are Congruent

[tex]\displaystyle 3) \, \angle 1 + \angle 2 = 180[/tex]                                          Linear Pair

[tex]\displaystyle 4)\, \angle 1 + \angle 4 = 180[/tex]                                          Substitution

[tex]\displaystyle 5) \, \angle 1 + \angle 3 = 180[/tex]                                          Substitution

[tex]\displaystyle 6) \, \text{$\angle 3$ and $\angle 1$ are supplementary}[/tex]                  Definition of Supplementary Angles

9514 1404 393

Answer:

  517 minutes

Step-by-step explanation:

There are 60 minutes in an hour, so 8×60 = 480 minutes in 8 hours.

In 8 hours 37 minutes, there are ...

  480 min + 37 min = 517 minutes

Answer:

Costco

Step-by-step explanation:

We find the cost per egg for each of the three stores.

Costco:

$9.35/(60 eggs) = $0.15583/egg

Safeway:

$4.79/(12 eggs) = $0.39917/egg

Trader Joe's:

$6.18/(18 eggs) = $0.34333/egg

The best deal is Costco.

Answer:

Costco

Step-by-step explanation:

[tex]\frac{60}{9.35}: \frac{1}{y}[/tex]

60 × y = 1 × 9.35

60y = 9.35

60y ÷ 60 = 9.35 ÷ 60

[tex]y=\frac{187}{1200}[/tex]

[tex]\frac{12}{4.79}: \frac{1}{y}[/tex]

12 × y = 1 × 4.79

12y = 4.79

12y ÷ 12 = 4.79 ÷ 12

[tex]y=\frac{479}{1200}[/tex]

[tex]\frac{18}{6.18}: \frac{1}{y}[/tex]

18 × y = 1 × 6.18

18y = 6.18

18y ÷ 18 = 6.18 ÷ 18

[tex]y=\frac{103}{300}=\frac{412}{1200}[/tex]

Answer:

[tex] \frac{67}{30} \: \text{or} \:2 \frac{7}{30} [/tex]

Step-by-step explanation:

5/6 ÷ 1/3 - 2/3 (2/5)

Hope it helps you! ＼(^ᴥ^)／

Answer:

1. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -1

B is the answer.

The triangles doesnt creates a SSS,SAS,SAA, scenario.

This triangle isn't ASA because the triangles share the same side but it have different angles that include the side.

Answer:

On a coordinate plane, a rectangle is 3 units high and 6 units wide.

Answer:

option "B"

You Welcome

Step-by-step explanation:

Answer:

The participants can be assigned in 224 different ways.

Step-by-step explanation:

Given that you are designing an experiment using human subjects, and the study will include 30 participants, of which 16 will be placed in the experimental group and the remaining 14 will be placed in the control group, to determine in how many ways can you assign participants to the two groups the following calculation must be performed:

16 x 14 = X

224 = X

Therefore, the participants can be assigned in 224 different ways.

Answer:

Step-by-step explanation:

Let take a look at the given function y = 4x - 1 whose point is located between (1,3) and (4,15) on the graph.

Here, the function of y is non-negative. Now, expressing y in terms of x in y = 4x- 1

4x = y + 1

[tex]x = \dfrac{y+1}{4}[/tex]

[tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

By integration, the required surface area in the revolve is:

[tex]S = \int^{15}_{ 3} 2 \pi g (y) \sqrt{1+g'(y^2) \ dy }[/tex]

where;

g(y) = [tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

∴

[tex]S = \int^{15}_{ 3} 2 \pi \Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big)'\Bigg)^2 \ dy }[/tex]

[tex]S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}\Big ) \Bigg)^2 \ dy } \\ \\ \\ S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \dfrac{\sqrt{17}}{4} \ dy[/tex]

[tex]S = \dfrac{\sqrt{17}}{8} \pi \int^{15}_{ 3} (y+1) \ dy[/tex]

[tex]S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(y+1)^2)\Big|^{15}_{3} \\ \\ S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(15+1)^2-\dfrac{1}{2}(3+1)^2 ) \\ \\ S = \dfrac{\sqrt{17} \pi}{8} *120 \\ \\\mathbf{ S = 15 \sqrt{17}x}[/tex]

Answer:

[tex]( \frac{1}{3})^{3} [/tex]

Step-by-step explanation:

There are many expressions that can be equivalent to 1/27.

For example, 2/54, 3/81 etc

But I think the expression you are looking for is

[tex] \frac{1}{27} = \frac{1 \times 1 \times 1}{3 \times 3 \times 3} = \frac{ {1}^{3} }{ {3}^{3} } = ( \frac{1}{3} )^{3} [/tex]

Hope this is helpful

Answer:

[tex]x = - \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]x = \frac{ - b}{2a} = \frac{1}{ - 2} [/tex]

Answer:

B

Step-by-step explanation:

B is the correct equation

Step-by-step explanation:

how many layers of bricks are used ?

also, I assume, the thickness of bricks means actually their height when laid.

but still, I cannot answer that, as nothing indicates if there is only one layer of bricks or 2 or 3 or 4 or ...

Answer:

79.5, 110.5, 141.5, 172.5, 203.5, 234.5

Step-by-step explanation:

Given

The attached distribution

Required

The lower class limits

To do this, we simply subtract 0.5 from the lower interval

From the attached distribution, the lower intervals are:

80.0, 111.0, 142.0, 173,0 .......

So, the lower class limits are:

[tex]80.0-0.5 = 79.5[/tex]

[tex]111.0-0.5 = 110.5[/tex]

[tex]142.0-0.5 = 141.5[/tex]

[tex]173.0-0.5 = 172.5[/tex]

[tex]204.0-0.5 = 203.5[/tex]

[tex]235.0-0.5 = 234.5[/tex]

Answer:

Step-by-step explanation:

There are only 2 angle values  that <1 to <8 can be. The two values add up to 180

In this case <6 and <7 are equal.

<6 = 4x - 15

<7 = x + 30

4x - 15 = x + 30             Subtract x from both sides

4x-x - 15 = 30                Add 15 to both sides

3x = 30 + 15

3x = 45                         Divide by 3

x = 45 / 3                          

x = 15

<6 = 4x - 15

<6 = 4*15 - 15

<6 = 60 - 15

<6 = 45

Answer:i think its 20

Step-by-step explanation: 20 x 2 is 40 plus 5 is 45

Answer:

✓ x - the number 5 + 2x = 45 2x = 45 - 5 2x = 40 x = 20 5 + 2(20) = 45 5 + 40 = 45 45 = 45 Hope this helps. :-) the answer is 20

Step-by-step explanation: Algebra.com

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(c) Neither requirement:

(all students) - (M or S) = 150 - 80 = 70

Answer:

10

Step-by-step explanation:

Sorry. I needed to answer this question to get access.

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = [tex]\frac{\sqrt{13} }{2}[/tex],  cos A = [tex]\frac{\sqrt{13} }{3}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

b. sin A = [tex]3\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]2\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

c. sin A = [tex]\frac{\sqrt{13} }{3}[/tex],  cos A = [tex]\frac{\sqrt{13} }{2}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

i. First calculate the value of the missing side AB.

Using Pythagoras' theorem;

⇒ (AB)² = (AC)² + (BC)²

Substitute the values of AC and BC

⇒ (AB)² = (36)² + (24)²

Solve for AB

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = [tex]\sqrt{1872}[/tex]

⇒ AB = [tex]12\sqrt{13}[/tex] ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of [tex]12\sqrt{13}[/tex] ft (43.27ft).

ii. Calculate the sine of ∠A (i.e sin A)

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex]             -------------(i)

In this case,

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (i) as follows;

sin A = [tex]\frac{24}{12\sqrt{13} }[/tex]

sin A = [tex]\frac{2}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

sin A = [tex]\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

sin A = [tex]\frac{2\sqrt{13} }{13}[/tex]

iii. Calculate the cosine of ∠A (i.e cos A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = [tex]\frac{adjacent}{hypotenuse}[/tex]             -------------(ii)

In this case,

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (ii) as follows;

cos A = [tex]\frac{36}{12\sqrt{13} }[/tex]

cos A = [tex]\frac{3}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

cos A = [tex]\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

cos A = [tex]\frac{3\sqrt{13} }{13}[/tex]

iii. Calculate the tangent of ∠A (i.e tan A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = [tex]\frac{opposite}{adjacent}[/tex]             -------------(iii)

In this case,

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

Substitute these values into equation (iii) as follows;

tan A = [tex]\frac{24}{36}[/tex]

tan A = [tex]\frac{2}{3}[/tex]

Answer:

a) 0.4658 = 46.58% probability that the chosen ball is blue

b) 0.322 = 32.2% probability that it came from the first urn

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability that the chosen ball is blue?

6/20 = 0.3 of 0.5(first urn)

12/19 = 0.6316 out of 0.5(second urn).

So

[tex]P(A) = 0.3*0.5 + 0.6316*0.5 = 0.4658[/tex]

0.4658 = 46.58% probability that the chosen ball is blue.

b. If the chosen ball is blue, what is the probability that it came from the first urn?

Event A: Blue Ball

Event B: From first urn

From item a., [tex]P(A) = 0.4658[/tex]

Probability of blue ball from first urn:

0.3 of 0.5. So

[tex]P(A \cap B) = 0.3*0.5 = 0.15[/tex]

Probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.4658} = 0.322[/tex]

0.322 = 32.2% probability that it came from the first urn

In cylindrical coordinates, W is the set of points

W = {(r, θ, z) : 0 ≤ r ≤ 2 and 0 ≤ θ ≤ 2π and -2 ≤ z ≤ 5}

(A) Then the integral of f(x, y, z) over W is

[tex]\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

(B)

[tex]\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}[/tex]