Can someone help me with this?

Answer:

Tan(28) = x/210

Step-by-step explanation:

111.65^2 + 210^2 = hyp^2

opposite = 111.65

hypotenuse = 237.83  

Answer:

hypotenuse =237.84

opposite =111.66

Step-by-step explanation:

cos‐¹(210/x)=28

210/x =cos28

210=cos28x

divide by cos28

x=237.84 (hypotenuse)

sin28= x/237.84

x=sin28×237.84

x=111.66 (opposite)

(another way to do it)

Answer:

Hypothenus = 22

Step-by-step explanation:

From the question given above, we were told that the triangles are congruent (i.e same size). Thus,

AC = EF

BC = DE

To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:

For y:

AC = y + 3

EF = 2y + 1

AC = EF

y + 3 = 2y + 1

Collect like terms

3 – 1 = 2y – y

2 = y

y = 2

For x:

BC = 5x + 7

DE = 6x + 2y

y = 2

DE = 6x + 2(2)

DE = 6x + 4

BC = DE

5x + 7 = 6x + 4

Collect like terms

7 – 4 = 6x – 5x

3 = x

x = 3

Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:

Hypothenus = BC

Hypothenus = 5x + 7

x = 3

Hypothenus = 5x + 7

Hypothenus = 5(3) + 7

Hypothenus = 15 + 7

Hypothenus = 22

OR

Hypothenus = DE

DE = 6x + 2y

y = 2

x = 3

Hypothenus = 6(3) + 2(2)

Hypothenus = 18 + 4

Hypothenus = 22

9514 1404 393

Answer:

  n = 2

Step-by-step explanation:

The ratio of side lengths in a 30°-60°-90° triangle is ...

  1 : √3 : 2

We have the ratio ...

  n : 2√3 : hypotenuse

from which we can see the basic ratio has been multiplied by 2. That is, n = 2 so the sides of the triangle shown have the ratio ...

  2 : 2√3 : 4

Complete Question

Complete Question is attached below

Answer:

[tex]UCL= 0.25[/tex]

Step-by-step explanation:

From the question we are told that:

Sample size[tex]n=150[/tex]

Sample Variants [tex]s=7[/tex]

Sigma control limits  [tex]Z = 3[/tex]

Therefore

Total number of observations is Given as

[tex]T_o=n*s[/tex]

[tex]T_o=150 *7[/tex]

[tex]T_0=1050[/tex]

Generally

Summation of defectivee

[tex]\sum np=23+34+15+30+25+22+18[/tex]

[tex]\sum np= 167[/tex]

Generally the equation for P-bar is mathematically given by

[tex]P-bar=\frac{\sum np}{T_o}[/tex]

[tex]P-bar=\frac{167}{1050}[/tex]

[tex]P-bar=0.16[/tex]

Therefore

[tex]Sp=\sqrt{\frac{P-bar(1-P-bar)]}{ n}}[/tex]

[tex]Sp=\sqrt{\frac{[0.159(1-0.159)]}{150}}[/tex]

[tex]Sp=0.03[/tex]

Generally the equation for 3-sigma upper control limit of the process is mathematically given by

[tex]UCL = P-bar + Z*Sp[/tex]

[tex]UCL= 0.16 + 3*0.03[/tex]

[tex]UCL= 0.25[/tex]

Answer:

im so confused

Step-by-step explanation:

Answer:

what is this goat saying

answer:

a. 400

b. 342.5

Step-by-step explanation:

The mean in this question has been given as

μ=300+10M−100B+50H

where M = 10

B = 0.5

H = 1

we put these into the formula of the mean above

μ=300+10(10)−100(0.5)+50(1)

μ = 300 + 100 - 50 + 50

= 400

So the mean of G in november is = 400

b.  We are to find E[G] here

= E[ 300+10M−100B+50H]

m = 8

B = 0.5 or 1/2

h = 1/4

E[ 300+10x8−100x0.5+50*0.25]

= 300+80-50+12.5

= 342.5

the value for E[G] is therefore 342.5

thank you

Answer: The answers are option 1 and option 3

Hope it helps

Answer:i would say A & C

Step-by-step explanation: makes the most sense

List of possible integral roots = 1, -1, 2, -2, 3, -3, 6, -6

List of corresponding remainders = 0, -16, -4, 0, 0, 96, 600, 1764

Check out the table below for a more organized way to represent the answer. The x values are the possible roots while the P(x) values are the corresponding remainders.

====================================================

Explanation:

We'll use the rational root theorem. This says that the factors of the last term divide over the factors of the first coefficient to get the list of all possible rational roots.

We'll be dividing factors of 6 over factors of 1. We'll do the plus and minus version of each. Since we're dividing over +1 or -1, this means that we're basically just looking at the plus minus of the factors of 6.

Those factors are: 1, -1, 2, -2, 3, -3, 6, -6

This is the list of possible integral roots.

Basically we list 1,2,3,6 with the negative versions of each value thrown in as well.

---------------------------------

From there, you plug each value into the P(x) function

If we plugged in x = 1, then,

P(x) = x^4 - 3x^3 - 3x^2 + 11x - 6

P(1) = (1)^4 - 3(1)^3 - 3(1)^2 + 11(1) - 6

P(1) = 1 - 3 - 3 + 11 - 6

P(1) = 0

This shows that x = 1 is a root, since we get a remainder 0. Do the same for the other possible rational roots listed above. You should find (through trial and error) that x = -2 and x = 3 are the other two roots.

To find S or T add them together:

3/5 + 1/3

Rewrite the fractions to have a common denominator

9/15 + 5/15 = 14/15

Answer: 14/15

Step-by-step explanation:

Here is your answer . Hope it helps.

Answer:

y"-6y'+18y=0

Second order

Step-by-step explanation:

Since there are 2 constants, the order of the differential equation will be 2. This means we will need to differentiate twice.

y = e^(3x) (acos3x +bsin3x)​

y'=3e^(3x) (acos3x+bsin3x)

+e^(3x) (-3asin3x+3bcos3x)

Simplifying a bit by reordering and regrouping:

y'=e^(3x) cos3x (3a+3b)+e^(3x) sin3x (3b-3a)

y"=

3e^(3x) cos3x (3a+3b)+-3e^(3x) sin(3x) (3a+3b)

+3e^(3x) sin3x (3b-3a)+3e^(3x) cos(3x) (3b-3a)

Simplifying a bit by reordering and regrouping:

y"=

e^(3x) cos3x (9a+9b+9b-9a)

+e^(3x) sin3x (-9a-9b+9b-9a)

Combining like terms:

y"=

e^(3x) cos3x (18b)

+e^(3x) sin3x (-18a)

Let's reorder y like we did y' and y".

y = e^(3x) (acos3x +bsin3x)

y=e^(3x) cos3x (a) + e^(3x) sin3x (b)

Objective is to find a way to combine or combine constant multiples of y, y', and y" so that a and b are not appearing.

Let's start with the highest order derivative and work down

y"=

e^(3x) cos3x (18b)

+e^(3x) sin3x (-18a)

We need to get rid of the 18b and 18a.

This is what we had for y':

y'=e^(3x) cos3x (3a+3b)+e^(3x) sin3x (3b-3a)

Multiplying this by -6 would get rid of the 18b and 18a in y" if we add them.

So we have y"-6y'=

e^(3x) cos3x (-18a)+e^(3x) sin3x (-18b)

Now multiplying

y=e^(3x) cos3x (a) + e^(3x) sin3x (b)

by 18 and then adding that result to the y"-6y' will eliminate the -18a and -18b

y"-6y'+18y=0

Also the characteristic equation is:

r^2-6r+18=0

This can be solved with completing square or quadratic formula.

I will do completing the square:

r^2-6r+18=0

Subtract 9 on both sides:

r^2-6r+9=-9

Factor left side:

(r-3)^2=-9

Take square root of both sides:

r-3=-3i or r-3=3i

Add 3 on both sides for each:

r=3-3i or r=3+3i

This confirms our solution.

Another way to think about the problem:

Any differential equation whose solution winds up in the form y=e^(px) (acos(qx)+bsin(qx)) will be second order and you can go to trying to figure out the quadratic to solve that leads to solution r=p +/- qi

Note: +/- means plus or minus

So we would be looking for a quadratic equation whose solution was r=3 ×/- 3i

Subtracting 3 on both sides gives:

r-3= +/- 3i

Squaring both sides gives:

(r-3)^2=-9

Applying the exponent on the binomial gives:

r^2-6r+9=-9

Adding 9 on both sides gives:

r^2-6r+18=0

Answer:

25

Step-by-step explanation:

5:20  

We want to get the second number to 100

100/20 = 5

Multiply each term by 5

5*5 : 20*5

25 : 100

x is 25

Given that,

→ 5 : 20 :: x : 100

Then we have to,

find the second number to 100.

→ 100/20

→ 5

Now multiply each term by 5 in 5:20,

→ 5 × 5 : 20 × 5

→ 25 : 100

→ x = 25

Now these ratio will be,

→ 5 : 20 :: 25 : 100

Hence, the value of x is 25.

Answer:

The p-value of the test if 0.0131, which is less than the standard significance level of 0.05, meaning that these data indicates that the self-worth of heroin addicts is less than that of the general population.

Step-by-step explanation:

On a test designed to measure self-worth, the mean for the general population is 48.6.

At the null hypothesis, we test if the mean is of 48.6, that is:

[tex]H_0: \mu = 48.6[/tex]

A psychologist suspects that heroin addicts have a different assessment of self-worth than others in the general population. Test if it is lower.

At the alternative hypothesis, we test if the mean is lower, that is:

[tex]H_1: \mu < 48.6[/tex]

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

48.6 is tested at the null hypothesis:

This means that [tex]\mu = 48.6[/tex]

The psychologist obtains a random sample of 40 test scores produced by heroin addicts and found the sample mean and the sample standard deviations are 45.5 and 8.5, respectively.

This means that [tex]n = 40, X = 45.5, s = 8.5[/tex]

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{45.5 - 48.6}{\frac{8.5}{\sqrt{40}}}[/tex]

[tex]t = -2.31[/tex]

P-value of the test:

The p-value of the test is a one-tailed test(mean lower than a value), with t = -2.31 and 40 - 1 = 39 df.

Using a t-distribution calculator, this p-value is of 0.0131.

The p-value of the test if 0.0131, which is less than the standard significance level of 0.05, meaning that these data indicates that the self-worth of heroin addicts is less than that of the general population.

Answer:

Step-by-step explanation:

Hope this helps :)!

Answer:

Rate of slower bus; 90 km/h

Rate of faster bus; 102 km/b

Step-by-step explanation:

We know that formula do distance is;

Distance = speed/time

We are told that One bus travels 12h slower than the other.

Let speed of slower bus be x.

Thus;

Speed of faster bus = x + 12

Speed of slower bus = x

After 3 hours, distance by faster bus = 3(x + 12)

Speed of slower bus = 3x

Since the towns are 576 km apart, then;

3(x + 12) + 3x = 576

Divide through by 3 to get;

x + 12 + x = 192

2x + 12 = 192

2x = 192 - 12

2x = 180

x = 180/2

x = 90 km/h

Faster bus speed = 90 + 12 = 102 km/h

Answer:

0.0064

0.00032

Step-by-step explanation:

Given the details:

P(X > 3), n = 5, p = 0.2

The binomial distribution is related using the formula:

P(x = x) = nCx * p^x * q^(n-x)

q = 1 - p = 1 - 0.2 = 0.8

P(X > 3) = p(x = 4) + p(x = 5)

P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064

P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032

Answer:

[tex]n = 12h[/tex]

Step-by-step explanation:

Given

[tex]r = 12/hr[/tex] --- rate

[tex]h \to hours[/tex]

[tex]n \to amount[/tex]

Required

Determine which solution is correct or incorrect

The solutions are not given. So, I will provide a general explanation

The amount (n) is calculated as:

[tex]n = r * h[/tex]

So, we have:

[tex]n = 12 * h[/tex]

[tex]n = 12h[/tex]

The above is the general equation to solve for the amount, given h hours

When h = 2.5, we have:

[tex]n = 12*2.5[/tex]

[tex]n = 30[/tex]

Answer:

going to add a picture

Step-by-step explanation:

:)

A: 25.

Explanation: Check the attached image.

For synthetic division, you just need to multiply the 1st number of the polynomial by the divisior, and then, add it up to the next number; then, the coefficient will be multiplied by the divisor, and so on and so forth until you reach the last number... that last coefficient at the end is the reminder that you've been asked for

Answer:

N = 50 +4d

Step-by-step explanation:

Take the original number of stamps and add the stamps per days times the number of days

N = 50 +4d

Answer:

The coefficient of the squared term is 1/25.

Step-by-step explanation:

We are given that the vertex of a parabola is at (2, -4). We also know that y = -3 when x = -3.

And we want to determine the coefficient of the squared term of the equation.

Since we are given the vertex, we can use the vertex form of the quadratic:

[tex]\displaystyle y = a(x-h)^2+k[/tex]

Where (h, k) is the vertex and a is the leading coefficient. The leading coefficient is also the coefficient of the squared term, so we simply need to find the value of a.

Since the vertex is at (2, -4), h = 2 and k = -4. Substitute:

[tex]\displaystyle y = a(x-2)^2-4[/tex]

y = -3 when x = -3. Solve for a:

[tex]\displaystyle (-3) = a((-3)-2)^2-4[/tex]

Simplify:

[tex]\displaystyle 1 = a(-5)^2\Rightarrow a = \frac{1}{25}[/tex]

Therefore, our function in vertex form is:

[tex]\displaystyle f(x) = \frac{1}{25}\left(x-2)^2-4[/tex]

Hence, the coefficient of the squared term is 1/25.

Answer:

-5

Step-by-step explanation:

from a p e x

Answer:

28

Step-by-step explanation:

10/14 mph no wind

20 wind

14 x 2 = 28

28 mph with wind

Answer:

a) 0% probability that one car chosen at random will have less than 49.5 tons of coal.

b) 0% probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 88, \sigma = 0.5[/tex]

a. What is the probability that one car chosen at random will have less than 49.5 tons of coal?

This is the p-value of Z when X = 49.5, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{49.5 - 88}{0.5}[/tex]

[tex]Z = -77[/tex]

[tex]Z = -77[/tex] has a p-value of 0.

0% probability that one car chosen at random will have less than 49.5 tons of coal.

b. What is the probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal?

Now [tex]n = 35, s = \frac{0.5}{\sqrt{35}}[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{49.5 - 88}{\frac{0.5}{\sqrt{35}}}[/tex]

[tex]Z = -455.5[/tex]

[tex]Z = -455.5[/tex] has a p-value of 0.

0% probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal

Answer:

1780 ft

Step-by-step explanation:

We need to find the perimeter of the rectangle, given by

P= 2(l+w)  where l is the length and w is the width

The units need to be the same

Change 230 yds to ft

230 yd * 3 ft/ y = 690 ft

P = 2(690+200)

P = 2(890)

P =1780

9514 1404 393

Answer:

  21

Step-by-step explanation:

The number who bought expensive tickets is 3/5 of the number who bought cheap tickets.

  (3/5)(35) = 21

21 people bought the more expensive ticket.

Answer:

21 people

Step-by-step explanation:

       $9.75      $14.50

  5 people to 3 people

 35 people to ? people

consider the proportions: 5/3 = 35/?

we need the equivalent fraction of 5/3 that has 35 on the denominator

so 5/3 = (5/3)(7/7)  because 7/7 =1, and 5*3 =35

5/3 = 5*7/3*7 = 35/21

Answer:

7.5 inches wide. I wasnt wrong. for a second i thought it was asking for the width of each individual sneaker.

Answer:

each pair of sneakers are 7.5 inches wide

Answer:

The Answer of the above question is 30.25

Step-by-step explanation:

Hope it helps you.

Answer:

n = 5

Step-by-step explanation:

Since this is a right triangle, we can use trig

tan theta = opp /adj

tan 30 = n / 5 sqrt(3)

5 sqrt(3) tan 30 = n

5 sqrt(3) * 1/ sqrt(3) = n

5 = n

Now we have to,

find the required value of n.

Now we can,

Use the trigonometric functions.

→ tan(θ) = opp/adj

Let's find the required value of n,

→ tan (θ) = opp/adj

→ tan (30) = n/5√3

→ n = 5√3 × tan (30)

→ n = 5√3 × √3/3

→ n = 5√3 × 1/√3

→ [n = 5]

Hence, the value of n is 5.