Can someone pls help me

Answer:

[tex]f^{-1}(6) = 50[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \sqrt{2x} - 4[/tex]

Required

Find [tex]f^{-1}(6)[/tex]

First, we calculate the inverse function

[tex]f(x) = \sqrt{2x} - 4[/tex]

Express f(x) as y

[tex]y = \sqrt{2x} - 4[/tex]

Swap the positions of x and y

[tex]x = \sqrt{2y} - 4[/tex]

Solve for y: Add 4 to both sides

[tex]4 + x = \sqrt{2y} - 4+4[/tex]

[tex]4 + x = \sqrt{2y}[/tex]

Square both sides

[tex](4 + x)^2 = 2y[/tex]

Divide both sides by 2

[tex]y = \frac{(4 + x)^2}{2}[/tex]

Express y as an inverse function

[tex]f^{-1}(x) = \frac{(4 + x)^2}{2}[/tex]

Next, solve for: [tex]f^{-1}(6)[/tex]

Substitute 6 for x

[tex]f^{-1}(6) = \frac{(4 + 6)^2}{2}[/tex]

[tex]f^{-1}(6) = \frac{(10)^2}{2}[/tex]

[tex]f^{-1}(6) = \frac{100}{2}[/tex]

[tex]f^{-1}(6) = 50[/tex]

Answer:

Ha: μ < 24

The test statistic is z = -1.75.

The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.

Step-by-step explanation:

A recent survey reported that small businesses spend 24 hours a week marketing their business.

This means that the null hypothesis is:

[tex]H_0: \mu = 24[/tex]

A local chamber of commerce claims that small businesses in their area are not growing because these businesses are spending less than 24 hours a week on marketing.

This means that the alternate hypothesis is:

[tex]H_a: \mu < 24[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

24 is tested at the null hypothesis:

This means that [tex]\mu = 24[/tex]

The chamber conducts a survey of 93 small businesses within their state and finds that the average amount of time spent on marketing is 23.0 hours a week.

This means that [tex]n = 93, X = 23[/tex]

The population standard deviation is 5.5 hours

This means that [tex]\sigma = 5.5[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{23 - 24}{\frac{5.5}{\sqrt{93}}}[/tex]

[tex]z = -1.75[/tex]

The test statistic is z = -1.75.

Do we reject the null hypothesis? Is there sufficient or insufficient evidence?

The pvalue of the test is the probability of finding a sample mean below 23, which is the pvalue of z = -1.75.

Looking at the z table, z = -1.75 has a pvalue of 0.0401

The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.

Answer:

2

Step-by-step explanation:

on Edge

Answer: 2

Step-by-step explanation:

have a great day!

Answer:

I've never had to deal with this before but I would say C

Answer:

The best option is C ( y=(1/4) x +3)

Answer:

C) Increase the amplitude to 2xo and stand 2 meters from the source.

Step-by-step explanation:

Correct on Edge

Answer: The answer is 3.

Step-by-step explanation: You would multiply 9x1/3 which would give you 3. If you want to understand even better here's how to do so: Put 3(the answer that you got from multiplying 9x1/3) into the fraction 1/3 as 1. In other words,  it would look something like this 3/3. Then, just multiply the two numbers 3x3 and that equals 9, the number you started with.

Hope that this helped!!:)

Considering the provided information in the given question, we have :

We need to find how many seashells did Saniyah have left.

⇒ Number of seashells Saniyah have left = Total seashells – Number of seashells she gave to her sister

⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup \dfrac{1}{3} \times 9 \Bigg \rgroup } [/tex]

⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup 1 \times 3 \Bigg \rgroup } [/tex]

⇒ Left seashells = 9 – 3

⇒ Left seashells = 6

Therefore, Saniyah have left [tex] \bf {6 \: seashells } [/tex].

Answer:

0.125 = 12.5% probability that they are a great match now.

Step-by-step explanation:

To solve this question, we need the probability of a person being a great match, which i will use 0.1.

This question is solved using conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Is kind to animals.

Event B: Is a great match.

Probability of being kind to animals:

0.9 of 0.1(Is a great match).

0.7 of 1 - 0.1 = 0.9(is not a great match). So

[tex]P(A) = 0.9*0.1 + 0.7*0.9 = 0.72[/tex]

Probability of being kind to animals and a great match:

0.9 of 0.1. So

[tex]P(A \cap B) = 0.9*0.1 = 0.09[/tex]

What is the probability that they are a great match now?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09}{0.72} = 0.125[/tex]

0.125 = 12.5% probability that they are a great match now.

D-Salary(33) or S(33)

D is correct hope this helps

Answer:

8b = 48

Step-by-step explanation:

this is because you would substitute the b for the 6 and then multiply straight across giving you a total of 48.

Answer:

8b = 48

Step-by-step explanation:

8 x 6 = 48

Answer:

A

Step-by-step explanation:

Answer:

later ill answer this .. read and understand

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

[tex]r = 3[/tex] -- radius

[tex]h = 7[/tex] --- height

[tex]Rate = 14in^3/min[/tex]

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

[tex]V = \frac{1}{3} \pi r^2h[/tex]

This gives:

[tex]V = \frac{1}{3} * 3.14 * 3^2 * 7[/tex]

[tex]V = \frac{1}{3} * 197.82[/tex]

[tex]V = 65.94in^3[/tex]

To calculate the time, we make use of the following rate formula.

[tex]Rate = \frac{Volume}{Time}[/tex]

Make Time the subject

[tex]Time= \frac{Volume}{Rate }[/tex]

This gives:

[tex]Time= \frac{65.94in^3}{14in^3/min}[/tex]

[tex]Time= \frac{65.94in^3}{14in^3}min[/tex]

Cancel out the units

[tex]Time= \frac{65.94}{14} min[/tex]

[tex]Time= 4.71 min\\[/tex]

Answer:

The time it will take for all the liquid to pass through is 4.71 minutes.

-Don't worry it's been already verified by myself .

Answer: c is the answer

C: 0.560

Step-by-step explanation:

Answer:

Step-by-step explanation:

b

Answer:

b hope it helps make brainlliest ty

Step-by-step explanation:

can you make me brainlliest

Answer:

1/4

Step-by-step explanation:

2x=-1/10 + 3/5

2x=1/2

x=1/4

Answer:

The bottom table.

Step-by-step explanation:

It's the only one that shows options for heads and tails for every number.

Answer:

D the last one

Answer:

Option C

Step-by-step explanation:

From the picture attached,

In ΔABC,

m∠BAC + y° = 180° [Linear pair of angles are supplementary]

m∠BAC = 180° - y°

m∠ABC = x° [Vertically opposite angles]

m∠ACB = z° [Vertically opposite angles]

By triangle sum theorem,

m∠BAC + m∠ABC + m∠ACB = 180°

(180 - y)° + x° + z° = 180°

x - y + z = 180 - 180

x - y + z = 0

Option C will be the answer.

Answer:

Part A

Yes

Part B

He will land at a point 30 meters from Cannon

Step-by-step explanation:

Part A

The given function that represent the path of the Cannon, which is the path of a parabolic arc, is presented as follows;

f(x) = -0.05·(x² - 26·x - 120)

We note that the height, 'h', of the path of a parabola at a horizontal distance, 'x' from the origin is equal to f(x)

Therefore, given that at the ground level, at the start and end of the flight, the f(x) = 0, we can write;

-0.05·(x² - 26·x - 120) = 0

∴ x² - 26·x - 120 = 0

x = (26 ± √((-26)² - 4 × 1 × (-120)))/(2 × 1)

Which gives;

x = 30 or x = -4

Therefore, he lands at a point 30 meters from the starting point

Therefore, the function gives enough information to tell where he will land

Part B

He lands at the point, x = 30 from the point the cannon was fired.

Answer:

The chocolate covered pretzels in Sophie's bag weighed [tex]\frac{2}{3} = 0.6667[/tex] kilograms.

Step-by-step explanation:

Sophie filled a bag with 2 2/3 kilograms of candy.

This means that the total weight is of:

[tex]2\frac{2}{3} = 2 + \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3}[/tex]

The total weight is of 8/3 kilograms.

1/4 of the weight of the candy was from chocolate covered pretzels. How much did the chocolate covered pretzels in Sophie's bag weigh?

1/4 of 8/3. So

[tex]\frac{1}{4} \times \frac{8}{3} = \frac{1*8}{4*3} = \frac{2}{3} = 0.6667[/tex]

The chocolate covered pretzels in Sophie's bag weighed [tex]\frac{2}{3} = 0.6667[/tex] kilograms.

Answer:

990 cars

Step-by-step explanation:

Find how many cars pass through at 6am, t=0:

r(0)= 300+600(0)-90(0²) = 300

Find how many cars pass through at 9am, t=3:

r(3)= 300+600(3)-900(3²)=300+1800-810=1290

Find the difference (how many cars pass between 6am and 9am): 1290-300=990

Answer:

b+c+h=50

Step-by-step explanation:

Its the first one because you need to have the same amount of hats as cupcakes cause the hat really stands for people.

Answer:

d.1.96(0.0632)

Step-by-step explanation:

The margin of error for a 95% confidence interval for the population proportion calculated as below:

Given that x = 8

n = Size of the sample = 40 (Large sample)

Sample population: P=x/n = 8/40 = 0.2; q = 1-p = 0.8

Standard error = [tex]\sqrt{pq/n}[/tex] = [tex]\sqrt{0.2(0.8)}/40[/tex] = 0.0682

95% of confidence Z∝ = 1.96

Margin of Error = Z∝ .[tex]\sqrt{pq/n}[/tex]

Margin of Error = 1.96(0.0682)

So, therefore, option d is correct.

Answer:

can you post the graph so I can answer to the best o my ability

Answer: 3.5 inches

Step-by-step explanation:

Answer:

Answer is in the step by step explanation

Step-by-step explanation:

Since we are given parallel lines, we know <BCA is congruent to <DAC because of alternate interior angles

Then AC is congruent to AC, that's reflexive prop

Now we have SAS, so Tri. ABC cong to tri. CDA,

Then you're done

Answer:

Step-by-step explanation:

BC = AD                           Given

<BCA = <CAD                  Alternate interior angles of parallel lines cut by a transversal.

AC = AC                           That's the reflexive property. A line is equal to itself

Triangle BCA = Triangle CAD    SAS

Notice that the angle is included inside the two lines that define it (the angle). That's a very important consideration when using SAS. SAA doesn't always work. You can draw exceptions. SAS has no exceptions. It always works.

Answer: Because the question uses the word “distinct” meaning obvious, and clear, I would select AB, AC, CB. (If it’s asking for all the possible line segments, I would select AB, AC, CB, BA, CA, BC).

Answer:

B

Step-by-step explanation:

The interior angles of a triangle always add up to 180 degrees.

We have two angles already and they add up to 60+63=123 degrees

180-123=57

so the remaining angle is 57 degrees

9514 1404 393

Answer:

  D.  123°

Step-by-step explanation:

The external angle is equal to the sum of the remote internal angles.

  m∠1 = 60° +63°

  m∠1 = 123°

Answer:

Step-by-step explanation:

3x = 12

x=4

x+y =5y

4+y = 5y

4 = 4y

1=y

Answer:

x-5 = y

72 -5 = 67

y=67

x = 72

Step-by-step explanation:

In a parallelogram, the diagonals bisect each other.

That being the case,

6x = 72

x = 12 In a parallelogram, the diagonals bisect each other.

That being the case,

6x = 72

x = 12 and the diagonals measure

144 and 134

i hope this helps!! ^_^