Correct answer gets 5 stars and brainliest

Answer:

Cost with 45 songs: $46.75

Cost with s songs: $13 + (s * $0.75)

Step-by-step explanation:

First multiply the number of songs by the cost per song (45 * $0.75 = $33.75), then add the monthly service cost to that number ($13 + $33.75 = $46.75) to get the total monthly cost to Pedro.

========================================================

Explanation:

For any inscribed quadrilateral like this, the opposite angles are always supplementary. This means the angles add to 180

B+D = 180

(2x-1) + (3x-59) = 180

(2x+3x) + (-1-59) = 180

5x-60 = 180

5x = 180+60

5x = 240

x = 240/5

x = 48

Use this x value to find angle A

A = 2x+4

A = 2*48+4

A = 96+4

A = 100

This then means,

A+C = 180

C = 180-A

C = 180-100

C = 80 degrees

Side note: The term "cyclic quadrilateral" is the same as "inscribed quadrilateral".

Step-by-step explanation:

Solution

First equation x ² - 4

= (x+2) (x-2)

Second equation = x ³ +8 + = x³+2^3

= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)

3 Third equation = x ² + 5x + 6

= x² + 6x= x +6 = x(x+6)-1(x+6)

(x-1) (x+6)

H.C. F= x-2

Answer:

65°

Step-by-step explanation:

The sum of angles in a triangle =180

53°+62°+?°=180°

115°+?°=180°

?°=180°-115°

Rate the answer If you love everything I did n explanation

Answer:

65 degrees

Step-by-step explanation:

Angles in a triangle add up to 180, so 180 - 53 - 62 = 65.

Answer:

All you gotta do is go to "desmos" and type in all of the 4 solutions. A, B, C, and D. and see which answer matches the graph

Step-by-step explanation:

Step-by-step explanation:

L.H.S

tanA * cosecA

=sinA/cosA * 1/sinA

now cancel sinA and sinA

then,

1/cosA

= secA

= RHS

hence proved

Answer:

3850 of those 6 person teams contain at most 3 men.

Step-by-step explanation:

The order in which the people are selected is not important, which means that the combinations formula is used to solve this question.

It drove 30.08 kilometers in an hour.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

0 men:

6 women from a set of 8. So

[tex]C_{8,6} = \frac{8!}{2!6!} = 28[/tex]

1 men:

5 women from a set of 8

1 men from a set of 7. So

[tex]C_{8,5}C_{7,1} = \frac{8!}{3!5!} \times \frac{7!}{1!6!} = 392[/tex]

2 men:

4 women from a set of 8

2 men from a set of 7. So

[tex]C_{8,4}C_{7,2} = \frac{8!}{4!4!} \times \frac{7!}{2!5!} = 1470[/tex]

3 men:

3 women from a set of 8

3 men from a set of 7. So

[tex]C_{8,3}C_{7,3} = \frac{8!}{5!3!} \times \frac{7!}{3!4!} = 1960[/tex]

How many 6 person teams contain at most 3 men?

28 + 392 + 1470 + 1960 = 3850

3850 of those 6 person teams contain at most 3 men.

I'm just going to start writing the email XD (btw, bold = non-email parts/me talking)

Hey (Friend name),

You kinda missed math the other day, and being the nice friend I am, I decided to catch you up on what we learned.

We learned how to solve a system of equations using the substitution method.

A system of equations is a set of two or more equations with common variables. We use those two equations to solve for the variables.

One example might be:

3x+y=3

4x+3y=10

Solving each of these two equations by themselves would be impossible, so this is where the substitution method comes in.

Solving by substitution means that you first solve one equation for a variable, and then you substitute the value of that variable into the other equation. You might understand better if you see how I use this method to solve the previous system.

Step 1: Solve for y.

 3x+y=3

 Subtract 3x from each side.

 y=3-3x

Step 2: Use the substitution method (plug in the y value).

 4x+3y=10

 4x+3(3-3x)=10

 See how we plugged in the right side of the equation that is equal to y? Now       only the x variable is left and we can easily solve it!

Step 3: Simplify to get x.

 4x+9-9x=10

 -5x=1

 x=-1/5

Step 4: Use the substitution method AGAIN (for the y).

 Now we plug in the x value into the equation for y.

 y=3-3x

 y=3-3(-1/5)

 y=3-(-3/5)

 y=18/5

The final answer is x=-1/5, y=18/5.

As you can see, using the substitution method to solve two impossible equations is how we can get the values of the variables they share! It's simple, quick, and easy!

Sincerely,

(your name)

I hope this helped! :D

Answer:

6x + y = 24

Step-by-step explanation:

that is the procedure above

Answer:

66.6666666667

Step-by-step explanation:

answer is 66.6666666667

The solution of the division of 5⁻² by 8^(1/3) will be 50.

The mathematical expression is the combination of numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also be used to denote the logical syntax's operation order and other properties.

Given numbers will be solved as:-

Division = ( 8 ^ (1/3) / 5⁻²

Division = 2 x5²

Division = 50

Therefore, the solution of the division of 5⁻² by 8^(1/3) will be 50.

To know more about an expression follow

https://brainly.com/question/20066515

#SPJ5

Step-by-step explanation:

Answer with explanation is in the attachment

Hope my answer is helpful to you

Answer:

D; 2 * 3; -4

Step-by-step explanation:

The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column

In a row, we have 2 elements, in a column , we have 3 elements

So the matrix is of 2 * 3 dimension

a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4

Answer:

-3x + y = -14

Step-by-step explanation:

m = 3/1 = 3

1 = 15 + b

b = -14

Y = 3x - 14

-3x + y = -14

Answer:

26.124

Step-by-step explanation:

SOH CAH TOA

tan 43 = about 0.933

than times it by 28 and get

26.124

Answer:

3.803% Profit

Step-by-step explanation:

First let us calculate total sales, then calculate the total cost, and then divide the two.

Sale: 120*1.1=132 and 52*.9=46.8

Cost: 120 and 52

Profit equation:

[tex]\frac{Net sales-COGS}{Net Sales} =Profit[/tex]

[tex]\frac{(132+46.8)-(120+52)}{(132+46.8)}[/tex]

Simplify:

[tex]\frac{6.8}{178.8} =.03803[/tex] or 3.803% Profit

9514 1404 393

Answer:

  A.  $674.43

Step-by-step explanation:

The account balance is given by ...

  A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years

  A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)

  A ≈ $674.43

Answer:

Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a

F

=m

a

. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form

(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S

1

=v

1

⋅t

1

+a

2

t

1

2

, where S_1=8m, t_1=2s S

1

=8m,t

1

=2s , other quantities we don't know. The similar equation we can write for next time interval

(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S

2

=v

2

⋅t

2

+a

2

t

2

2

. where S_2=8.5m, t_2=1s S

2

=8.5m,t

2

=1s

Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.

(3) v_2=v_1+a\cdot t_1v

2

=v

1

+a⋅t

1

Substitute (3) to (2) we get

(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S

2

=(v

1

+a⋅t

1

)⋅t

2

+a

2

t

2

2

=v

1

⋅t

2

+a⋅t

1

⋅t

2

+a

2

t

2

2

From equation (1) and (4) we can exclude unknown quantity v_1v

1

, then remain only one unknown aa. For determine aa we dived (1) by t_1t

1

, (4) by t_2t

2

to find the average speed at time intervals and subtract (1) from (4).

(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-

t

2

S

2

−

t

1

S

1

=v

1

+a⋅t

1

+a

2

t

2

−(v

1

+a

2

t

1

)=a

2

t

1

+t

2

− For acceleration we get

(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(

t

2

S

2

−

t

1

S

1

)/(t

1

+t

2

)=2⋅

3s

(8.5m/s−4m/s)

=3ms

−2

For mass from second Newton's law we get

(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=

a

F

=

3ms

−2

45N

=15kg

Answer: The mass of the block is 15 kg

Answer:

Below

Step-by-step explanation:

From the graph the first local minimum is -16.18

The local maximum is 3.75

The second local minimum is -3.

Answer:

----------------------

Hope it helps..

Have a great day!!

Given:

The given equation is:

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

To find:

The value of p.

Solution:

We have,

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

Multiply both sides by 3.

[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]

[tex]48-9p=2p+15[/tex]

Isolating the variable terms, we get

[tex]48-15=2p+9p[/tex]

[tex]33=11p[/tex]

Divide both sides by 11, we get

[tex]\dfrac{33}{11}=p[/tex]

[tex]3=p[/tex]

Therefore, the required solution is [tex]p=3[/tex].

Answer:

p=3

Step-by-step explanation:

i got it right on khan

Answer:

I think it is D which is the order does not matter

9514 1404 393

Answer:

  a. the stretch

Step-by-step explanation:

The function 2f(x+1) -4 represents a vertical stretch by a factor of 2, a horizontal translation left 1 unit, and a vertical translation down 4 units.

Either the horizontal translation or the vertical stretch can be done first, because their effects are independent of one another. If the vertical translation is done first, the stretch will double it—which is not what you want.

__

Since the vertical stretch must be done before the vertical translation, it is reasonable to claim the vertical stretch must be done first.

_____

Additional comment

If you claim the horizontal stretch must be done first, that places no restriction on the sequence of vertical transformations. Hence the graph may be incorrect when only that restriction is applied.

Answer:

30-5ab-14+6ab

16-ab ans

Answer:

[tex] \boxed{ab + 16} [/tex]

Step-by-step explanation:

5 (6 – ab) + 2 (-7 + 3ab)

[distribution property]

(6)(5) – (ab)(5) + (-7)(2) + (3ab)(2)

30 – 5ab – 14 + 6ab

[group like terms]

(6ab – 5ab) + (30 – 14)

ab + 16

Answer:

I think it is either B or C

Sorry if it is wrong

Step-by-step explanation:

Answer:

[tex]\text{(D) }\frac{\sin 110^{\circ}}{x}=\frac{\sin 40^{\circ}}{20}[/tex]

Step-by-step explanation:

We can use the Law of Sines to solve this problem. The Law of Sines works for any triangle and states that the ratio of any angle and its opposite side is maintained throughout all angles of the triangle:

[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]

In the figure, the angle marked 110 degrees has an opposite side labelled [tex]x[/tex]. However, the angle opposite to the side marked 20 is still unknown, so let's find it.

The sum of the interior angles of a triangle is always 180 degrees. Therefore, let the third angle be [tex]\theta[/tex]. We have:

[tex]\theta + 110^{\circ}+30^{\circ}=180^{\circ},\\\theta+140^{\circ}=180^{\circ},\\\theta=40^{\circ}[/tex]

Now we have the relevant angle and we can set up the proportion:

[tex]\boxed{\frac{\sin 110^{\circ}}{x}=\frac{\sin 40^{\circ}}{20}}[/tex]

Answer:

6x-5 if x<5

Step-by-step explanation:

If x<5, then x-5<0.

If x-5 is negative, then |x-5)=-(x-5) or -x+5.

5x - |x - 5|

5x-(-x+5) provided x<5

5x+x-5 by distributive property

6x-5 combined liked terms

Answer:

dddjshsbs zhzusushwbsgzyzhsbssbs s hsbd d dhd ssbshebebs shyshs s sbshss s s

Step-by-step explanation:

shshshsnsnsjzj shsjs s sjsn s s snsnsbzbznnz ssjs s snsnsmkzkxnz

Step-by-step explanation:

here's the answer to your question

Answer:

LP = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values

[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]

[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )

5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )

3LQ = 18 ( divide both sides by 3 )

LQ = 6

Then

LP = LQ + QP = 6 + 9 = 15