Create a class called Hangman. In this class, Create the following private variables: char word[40], progress[40], int word_length. word will be used to store the current word progress will be a dash representation of the the current word. It will be the same length as the current word. If word is set to ‘apple’, then progress should be "‑‑‑‑‑" at the beginning of the game. As the user guesses letters, progress will be updated with the correct guesses. For example, if the user guesses ‘p’ then progress will look like "‑pp‑‑" Create a private function void clear_progress(int length). This function will set progress to contain all dashes of length length. If this function is called as clear_progress(10), this will set progress to "‑‑‑‑‑‑‑‑‑‑". Remember that progress is a character array; don’t forget your null terminator. Create the following protected data members: int matches, char last_guess, string chars_guessed, int wrong_guesses, int remaining. Create a public function void initialize(string start). This function will initialize chars_guessed to a blank string, wrong_guesses to 0. Set remaining to 6. Use strcpy() to set word to the starting word passed as start (You can use start.c_str() to convert it to a character array). Set word_length to the length of word. Call clear_progress in this function.

Answer:

How was the Aswan high dam had an adverse effect on human health? It created new ecosystems in which diseases such as malaria flourished. An environmental challenge facing the Great Man Made River is that pumping water near the coast. ... Water scarcity makes it impossible to grow enough food for the population.

Explanation:

Answer:

C = (3P+1) % 27

so when P will be max 26,when P is 26 the (3P+1) = 79. And 79/27 = 2 so let's give name n = 2.

Now doing reverse process

We get ,

P = ((27*n)+C-1)/3

Where n can be 0,1,2

So substituting value of n one by one and the C=7(corresponding index of h)

For n= 0,we get P=2, corresponding char is 'c'

For n=1,we get P=11, corresponding char is 'l'

For n=2,we get P= 20, corresponding cahr is 'u'.

So beside 'c',the system will generate 'h' for 'l' and 'u' also.

Answer:

You should name it honest and sincere intention

Explanation:

That is a good name for what you are going to talk about in your slideshow.

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

Answer: (a). 11.3137

(b). 22.849

Explanation:

Provided below is a step by step analysis to solving this problem

(a)

clc;close all;clear all;

a=2;x=3.5;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('2^3.5 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

2^3.5 from tailor series=11.3137 after adding n=15 terms

disp('2^3.5 using calculator =11.3137085');

Command window:

2^3.5 from tailor series=11.3137 after adding n=15 terms

2^3.5 using calculator =11.3137085

(b)

clc;close all;clear all;

a=6.3;x=1.7;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('6.3^1.7 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

disp('6.3^1.7 using calculator =22.84961748');

Command window:

6.3^1.7 from tailor series=22.8496 after adding n=16 terms

6.3^1.7 using calculator =22.84961748

cheers i hope this helped !!!

Answer:

1. Logical

2.=

3.IF

Explanation:

just did the assignment

Answer:

Check Explanation.

Explanation:

Immediately there is a connection between your laptop and the wireless hotspot, data will be transferred via the Physical layer that will be used for encoding of the network and the modulation of the network and that layer is called the OSI MODEL.

Another Important layer is the APPLICATION LAYER in which its main aim and objectives is for support that is to say it is used in software supporting.

The next layer is the PRESENTATION LAYER which is used during the process of sending the e-mail. This layer is a very important layer because it helps to back up your data and it is also been used to make connections of sessions between servers of different computers

Answer:

Bits

Explanation:

   //Method definition of words_typed

   //The return type is int

   //Takes two int parameters: typingSpeed and timeInterval

   public static int words_typed(int typingSpeed, int timeInterval) {

       //Get the number of words typed by  

       //finding the product of the typing speed and the time interval

       //and then dividing the result by 60 (since the typing speed is in "words

       // per minute"  and the time interval is in "seconds")

       int numberOfWords = typingSpeed * timeInterval / 60;

       //return the number of words

       return numberOfWords;

   }        //end of method declaration

The code above has been written in Java and it contains comments explaining each of the lines of the code. Please go through the comments.

Answer:

I am writing the program in Python.

def words_typed(typing_speed,time_interval):

   typing_speed>=0

   time_interval>0

   no_of_words=int(typing_speed*(time_interval/60))

   return no_of_words

output=words_typed(20,30)

print(output)

Explanation:

I will explain the code line by line.

First the statement def words_typed(typing_speed,time_interval) is the definition of a function named words_typed which has two parameters typing_speed and time_interval.

typing_speed variable of integer type in words per minute.

time_interval variable of int type in seconds

The statements typing_speed>=0 and time_interval>0 means that value of typing_speed is greater than or equal to zero and value of time_interval is greater than zero as specified in the question.

The function words_typed is used to return the number of words that a  person with typing speed would type in that time interval. In order to compute the words_typed, the following formula is used:

   no_of_words=int(typing_speed*(time_interval/60))

The value of typing_speed is multiplied by value of time_interval in order to computer number of words and the result of the multiplication is stored in no_of_words. Here the time_interval is divided by 60 because the value of time_interval is in seconds while the value of typing_speed is in minutes. So to convert seconds into minutes the value of time_interval is divided by 60 because 1 minute = 60 seconds.

return no_of_words statement returns the number of words.

output=words_typed(20,30) statement calls the words_typed function and passed two values i.e 20 for typing_speed and 30 for time_interval.

print(output) statement displays the number of words a person with typing speed would type in that time interval, on the output screen.

Program explanation:

Program code:

def sum_divisors(n):#defining a method sum_divisors that takes a parameter

   s = 0#defining a variable s that hold a value 0

   for x in range(1,n):#defining a for loop that use n variable to check range value

       if(n%x==0):#use if to check remainder value equal to 0  

           s += x#adding value in s variable

   return s#return s value

print(sum_divisors(6))#calling method

print(sum_divisors(12))#calling method

Output:

Please find the attached file.

Learn more:

brainly.com/question/14704583

Answer:

The answer is 1646

Explanation:

The original code requires 1024 bytes and is called 70 times ,it requires 7 byte and its size is 132 bytes

1024 + (70*7) + 132 = 1024 + 490 +132

= 1646

Answer:

All the classes are mentioned with code and screenshots. . That class is shown at last.

Explanation:

Solution

Class.Java:

Code

**

* atauthor your_name

* This class denotes Class at the college.

*

*/

public class Class {

  private String className,classID;

  private Professor professor;

  /**

  * atparam className

  * atparam classID

  * atparam professor

  */

  public Class(String className, String classID, Professor professor) {

      this.classID=classID;

      this.className=className;

      this.professor=professor;

  }

     /**

  * at return classID of the class

  */

  public String getClassID() {

      return classID;

  }

    /**

  * Override toString() from Object Class

  */

  public String toString() {    

      return classID+" "+className+" "+professor.getName()+" "+professor.getEducation();        

  }  

}

Person.Java:

Code:

/**

* atauthor your_name

* This class represents Person

*

*/

public class Person {    

  protected String name;  

  /**method to fetch name

  * at return

  */

  public String getName() {

      return name;

  }

  /**method to set name

  * at param name

  */

  public void setName(String name) {

      this.name = name;

  }

Professor.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* at author your_name

*

*This class represents professors

*

*/

public class Professor extends Person{    

  private String professorID, education;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * at param name

  * at param professorID

  * at param education

  */

  public Professor(String name,String professorID,String education) {        

      this.name=name;

      this.professorID=professorID;

      this.education=education;        

  }

  /**

  * at return

  */

  public String getEducation() {

      return this.education;

  }    

  /**

  * at return

  */

  public String getprofessorID() {

      return this.professorID;

  }  

  /** to add classes

  * at param Class

  */

  public void addClass(Class c) {

      classes.add(c);

  }  

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+professorID+" - "+education;

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }      

      return result;

  }

}

}

Student.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* This class represents students

*  at author your_Name

*

*/

public class Student extends Person{    

  private String studentID;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * atparam name

  * atparam studentID

  */

  public Student(String name,String studentID) {      

      this.name=name;

      this.studentID=studentID;      

  }  

  /**

  * atreturn

  */

  public String getStudentID() {

      return studentID;

  }

     /**

  * atparam c

  */

  public void addClass(Class c) {

      classes.add(c);

  }    

  /**

  * atreturn

  */

  public int getClassCount() {

      return classes.size();

  }

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+studentID+"\n";

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }    

      return result;

  }  

}

NOTE: Kindly find an attached copy of screenshot of the output, which is a part of the solution to this question

Answer:

Pay raise is an example of the rewards & consequences characteristic of an organization.

Answer:

See explaination

Explanation:

//ReadFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class ReadFile

{

public static void main(String[] args)

{

int elementsCount=0;

//Create a File class object

File file=null;

Scanner fileScanner=null;

String fileName="sample.txt";

try

{

//Create an instance of File class

file=new File(fileName);

//create a scanner class object

fileScanner=new Scanner(file);

//read file elements until end of file

while (fileScanner.hasNext())

{

double value=fileScanner.nextInt();

elementsCount++;

}

//print smallest value

System.out.println(elementsCount+" data values are read");

}

//Catch the exception if file not found

catch (FileNotFoundException e)

{

System.out.println("File Not Found");

}

}

}

Sample output:

sample.txt

10

20

30

40

50

output:

5 data values are read

=======================================================

//Class header definition

public class DisArray {

   //First method with int array as parameter

   public static void convert2D(int[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the

       //length of  the one dimensional array,

       //then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       // number of rows

       int col = ((row * row) >= arraylength) ? row : row + 1;

       //3. Create a 2D int array with the number of rows and cols

       int [ ][ ] twoD = new int [row][col];

       //4. Place the elements in the one dimensional array into

       //the two dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       // two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

              }

              //Otherwise, just pad the array with zeros

               else {

                   twoD[i][j] = 0;

               }

           }

       }

       //You might want to create another pair of loop to print the elements

       //in the  populated two dimensional array as follows

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }     //End of first method

   //Second method with String array as parameter

   public static void convert2D(String[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the length of  

       //the one dimensional array, then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       //number of rows.

       int col = (row * row >= arraylength) ? row : row + 1;

       //3. Create a 2D String array with the number of rows and cols

       String[][] twoD = new String[row][col];

       //4. Place the elements in the one dimensional array into the two

       // dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       //two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

               }

               //Otherwise, just pad the array with null values

               else {

                   twoD[i][j] = null;

               }

           }

       }

       //You might want to create another pair of loop to print the elements  

       //in the populated two dimensional array as follows:

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }    // End of the second method

   //Create the main method

   public static void main(String[] args) {

       //1. Create an arbitrary one dimensional int array

       int[] x = {23, 3, 4, 3, 2, 4, 3, 3, 5, 6, 5, 3, 5, 5, 6, 3};

       //2. Create an arbitrary two dimensional String array

       String[] names = {"abc", "john", "dow", "doe", "xyz"};

       //Call the respective methods

       convert2D(x);

       System.out.println("");

       convert2D(names);

   }         // End of the main method

}            // End of class definition

=========================================================

==========================================================

23 3 4 3  

2 4 3 3  

5 6 5 3  

5 5 6 3  

abc john dow  

doe xyz null

==========================================================

The above code has been written in Java and it contains comments explaining each line of the code. Please go through the comments. The actual executable lines of code are written in bold-face to distinguish them from the comments.

Answer:

Ahhhhh suckkkkkkkkkkk

Answer:

Solid state drive

Explanation:

The term solid-state drive is used for the electronic circuitry made entirely from semiconductors. This highlights the fact that the main storage form, in terms of a solid-state drive, is via semiconductors instead of a magnetic media for example a hard disk.  In lieu of a more conventional hard drive, SSD is built to live inside the device. SSDs are usually more resistant to physical shock in comparison to the electro-mechanical drives and it functions quietly and has faster response time. Therefore,  SSD will be best suitable for the Dave.

Answer: Provided in the explanation segment

Explanation:

Below is a detailed explanation to make this problem more clearer to understand.

(1). We are asked to determine whether the systems have been compromised;

Ans: (YES) From the question given, We can see that the System is compromised. This is so because the plan of communication has different details of scenarios where incidents occur. This communication plan has a well read table of contents that lists specific type of incidents, where each incident has a brief description of the event.

(2). Whether the analyst’s assertion has valid grounds to believe it is Chinese state-sponsored.

Ans: I can say that the analyst uses several different internet protocol address located in so as to conduct its operations, in one instance, a log file recovered  form an open indexed server revealed tham an IP address located is used to administer the command control node that was communicating with the malware.

(3). What other threat intelligence can be generated from this information?

Ans: The threat that can be generated from this include; Custom backdoors, Strategic web compromises, and also Web Server  exploitation.

(4). How would that help shape your assessment?

Ans: This helps in such a way where information is gathered and transferred out of the target network which involve movement of files through multiple systems.

Files also gotten from networks as well as  using tools (archival) to compress and also encrypt data with effectiveness of their data theft.

cheers i hope this helped!!!

Answer:

The java program for the given scenario is as follows.

import java.util.*;

//interface with method area

interface ObjectWithTwoParameters

{

double area (double d1, double d2);

}

class RectangleClass implements ObjectWithTwoParameters

{

//overriding area()

public double area (double d1, double d2)

{

return d1*d2;

}

}

class TriangleClass implements ObjectWithTwoParameters

{

//overriding area()

public double area (double d1, double d2)

{

return (d1*d2)/2;

}  

}

class CylinderClass implements ObjectWithTwoParameters

{

public double area (double d1, double d2)

{

return ( 2*3.14*d1*d1 + d2*(2*3.14*d1) );

}

}

public class Test

{

public static void main(String[] args)

{

//area displayed for all three shapes

ObjectWithTwoParameters r = new RectangleClass();

double arear = r.area(2, 3);

System.out.println("Area of rectangle: "+arear);

ObjectWithTwoParameters t = new TriangleClass();

double areat = t.area(4,5);

System.out.println("Area of triangle: "+areat);

ObjectWithTwoParameters c = new CylinderClass();

double areac = c.area(6,7);

System.out.println("Area of cylinder: "+areac);

}

}

OUTPUT

Area of rectangle: 6.0

Area of triangle: 10.0

Area of cylinder: 489.84

Explanation:

1. The program fulfils all the mentioned requirements.

2. The program contains one interface, ObjectWithTwoParameters, three classes which implement that interface, RectangleClass, TriangleClass and CylinderClass, and one demo class, Test, containing the main method.

3. The method in the interface has no access specifier.

4. The overridden methods in the three classes have public access specifier.

5. No additional variables have been declared.

6. The test class having the main() method is declared public.

7. The area of the rectangle, triangle and the cylinder have been computed as per the respective formulae.

8. The interface is similar to a class which can have only declarations of both, variables and methods. No method can be defined inside an interface.

9. The other classes use the methods of the interface by implementing the interface using the keyword, implements.

10. The object is created using the name of the interface as shown.

ObjectWithTwoParameters r = new RectangleClass();

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

Answer:

Check the explanation

Explanation:

SDLC

SDLC stands for Software Development Life Cycle

It provides steps for developing a software product

It also checks for the quality and correctness of a software

The main aim of SDLC is to develop a software, which meets a customer requirements

SDLC involves various phases to develop a high-quality product for its end user

Phases of SDLC

           There are seven phases in a software development life cycle as follows,

Requirement Analysis   Feasibility Study   Design    Coding    Testing Deployment      Maintenance

kindly check the attached image below

Requirement analysis

This is the first stage in a SDLC.

In this phase, a detailed and precise requirements are collected from various teams by senior team members

It gives a clear idea of the entire project scope, opportunities and upcoming issues in a project

This phase also involves, planning assurance requirements and analyze risk involved in the project

Here, the timeline to finish the project is finalized

Feasibility Study

In this stage, the SRS document, that is “Software Requirement Specification” document is defined, which includes everything to be designed and developed during the life cycle of a project

Design

In this phase as the name indicates, software and system design documents are prepared, based on the requirement specification document

This enable us to define the whole system architecture

Two types of design documents are prepared in this phase as follows,

High-Level Design

Low-Level Design

Coding

In this phase, the coding of project is done in a selected programming language

Tasks are divided into many units and given to various developers

It is the longest phase in the SDLC

Testing

In this stage, the developed coding is tested by the testing team

The testing team, checks the coding in the user point of view

Installation/Deployment

In this stage, a product is released by the company to the client

Maintenance

Once the product is delivered to the client, the maintenance phase work will start by fixing errors, modifying and enhancing the product.

Employee Payroll System

Requirement analysis

Gather information from various team for requirement

Analyze the number of employees to handle the project

Timeline to finish the project, eg.1 month

Feasibility Study

The system requirements such as how many systems are required

Decide which software to be installed to handle the project.

For example, if we are going to develop the software using C language, then software for that has to be installed

The SRS document has to be prepared

Design

In this the HLD and LLD is prepared, the overall software architecture is prepared

The modules involved in coding are decided

Here the modules can be employee, payroll manager, Employee Log time, account details

The input and output are designed, such as employee name is the input and output is the salary for him, based on working hours

Coding

Here the coding is divided into various sections and given to 2 or more employees

One may code employee detail, one will code working hours of employees and one may code the banking details of employee

Testing

The coding is tested for syntax, declaration, data types and various kinds of error

The testing team will test the coding with various possible values

They may even check with wrong values and analyze the output for that

Installation

Now the software is installed in the client system and the client is calculating the payroll for an employee based on working hours in a month

Maintenance

If any error occurs, the team will clear the issue.

When a new employee joins, then the employee data will added to the database and the database is updated

Also if the client asks for any new features, it will done in this phase.

Answer: I would suggest you consider your audience and how you can connect to them. Is your presentation, well, presentable? Is whatever you're presenting reliable and true? Also, no more than 6 lines on each slide. Use colors that contrast and compliment. Images, use images. That pulls whoever you are presenting to more into your presentation.

Explanation:

Answer:

There are no limitation, policies or regulations that limit these tools for use on privately owned machines or home networks. In most businesses networks, intranets or internets the use of them is illegal if used for malicious intent. Penetration testing teams sign rules of engagement before using these tools.

Explanation:

There are no limitation, limitations, policies, or regulations in their use on local machines, privately owned machines or home networks, or small business networks.

In most businesses networks, intranets or internets the use of them is often and mostly illegal especially in a situation where they are been used for malicious intent.

Penetration testing teams would often or always make sure that they sign rules of engagement before using these tools.

Answer:

The output of the code:

Enter a 4 digit integer : 1 2 3 4

The decrypted number is : 0 1 8 9

The original number is : 1 2 3 4

Explanation:

Okay, the code will be written in Java(programming language) and the file must be saved as "Encryption.java."

Here is the code, you can just copy and paste the code;

import java.util.Scanner;

public class Encryption {

public static String encrypt(String number) {

int arr[] = new int[4];

for(int i=0;i<4;i++) {

char ch = number.charAt(i);

arr[i] = Character.getNumericValue(ch);

}

for(int i=0;i<4;i++) {

int temp = arr[i] ;

temp += 7 ;

temp = temp % 10 ;

arr[i] = temp ;

}

int temp = arr[0];

arr[0] = arr[2];

arr[2]= temp ;

temp = arr[1];

arr[1] =arr[3];

arr[3] = temp ;

int newNumber = 0 ;

for(int i=0;i<4;i++)

newNumber = newNumber * 10 + arr[i];

String output = Integer.toString(newNumber);

if(arr[0]==0)

output = "0"+output;

return output;

}

public static String decrypt(String number) {

int arr[] = new int[4];

for(int i=0;i<4;i++) {

char ch = number.charAt(i);

arr[i] = Character.getNumericValue(ch);

}

int temp = arr[0];

arr[0]=arr[2];

arr[2]=temp;

temp = arr[1];

arr[1]=arr[3];

arr[3]=temp;

for(int i=0;i<4;i++) {

int digit = arr[i];

switch(digit) {

case 0:

arr[i] = 3;

break;

case 1:

arr[i] = 4;

break;

case 2:

arr[i] = 5;

break;

case 3:

arr[i] = 6;

break;

case 4:

arr[i] = 7;

break;

case 5:

arr[i] = 8;

break;

case 6:

arr[i] = 9;

break;

case 7:

arr[i] = 0;

break;

case 8:

arr[i] = 1;

break;

case 9:

arr[i] = 2;

break;

}

}

int newNumber = 0 ;

for(int i=0;i<4;i++)

newNumber = newNumber * 10 + arr[i];

String output = Integer.toString(newNumber);

if(arr[0]==0)

output = "0"+output;

return output;

}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.print("Enter a 4 digit integer:");

String number = sc.nextLine();

String encryptedNumber = encrypt(number);

System.out.println("The decrypted number is:"+encryptedNumber);

System.out.println("The original number is:"+decrypt(encryptedNumber));

}

}

Answer:

public class RectangleArea {

   public static void main(String[] args) {

       Rectangle myRectangle = new Rectangle(15.8, 7.9);

       double calArea = myRectangle.calcArea(15.8, 7.9);

       System.out.println("The area is "+ calArea);

   }

}

class Rectangle{

   private double length;

   private double width;

   //Defined Constructor

   public Rectangle(double length, double width) {

       this.length = length;

       this.width = width;

   }

   public double calcArea(double len, double wi){

       return len* wi;

   }

}

Explanation:

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

Answer:

Check the explanation

Explanation:

Let the population mean time on task of original website be [tex]\mu_1[/tex] and that of new prototype be [tex]\mu_2[/tex]

Here we are to test

[tex]H_0:\mu_1=\mu_2\;\;against\;\;H_1:\mu_1<\mu_2[/tex]

The data are summarized as follows:

                                                       Sample 1             Sample 2

Sample size                                        n=20                    n=20

Sample mean                                 [tex]\bar{x}_1=243.4[/tex]             [tex]\bar{x}_2=253.4[/tex]

Sample SD                                     s1=130.8901          s2=124.8199

The test statistic is obtained from online calculator as

t=-0.23

The p-value is given by 0.821

As the p-value is more than 0.05, we fail to reject the null hypothesis at 5% level of significance and hence conclude that there is no statistically significant difference between the original website and the prototype developed by the team at 5% level of significance.