data in the bar graph to solve the following problems. Choose the letter of the correl answer.
Distance from Churh (meters)
250
210
190
200
175
150
150
100
50
C. 25m
1. How much farther does Paolo walk thạnIgpher? Joshua
Topher
A. 20m
B. 15 m
C. 10m
D. 5m
2. How much farther does Joshua walk than Lucas?
A. 15m
B. 20m
D. 30m
3. How much farther does Topher than Lucas?
A. 50m
B. 40m
C. 30m
D. 20m
4. If you combine Paolo's and Lucas' distance from the church and compare it against the combined
distance walked by Joshua and Topher, which combined distance is farther
from the church?
A. Joshua and Topher
C. Joshua and Paolo
B. Paolo and Lucas
D. Topher and Lucas
5. Find the average distance of the houses of the 4 friends from the church?
A. 181
B. 191
C. 180​

Answer:

is it going to be 10.5

Step-by-step explanation:

I do not have any explanation

Answer: 0 (zero)

Step-by-step explanation:

Start Learning & start growing! edge2023

*DROPS THE MIC*

Answer:

D. 750(0.75)ˣ

Step-by-step explanation:

Let the new brightness be L'. Since our initial brightness L₀ reduces by 25 %, we have that L' = L₀ - 25% of L₀

L' = L₀ - 0.25L₀

L' = 0.75L₀

Adding the second screen, the new intensity is L" = L' - 25 % of L'  

L" = L' - 0.25 L'

L" = 0.75L'.

Since L' = 0.75L₀,

L" = 0.75L' = 0.75(0.75L₀) = 0.75²L₀

Adding the third screen, the new intensity is L"' = L'' - 25 % of L''  

L'" = L" - 0.25 L"

L"' = 0.75L".

Since L" = 0.75L' = 0.75²L₀

L"' = 0.75L" = 0.75(0.75²L₀) = 0.75³L₀

So, we see a pattern here.

The intensity after x screens is L = (0.75)ˣL₀

Since L₀ = 750 lumens,

L = 750(0.75)ˣ

Answer:

x^2+y^2=r^2 is quation of circle whose centre is (0,0)

Answer:

Step-by-step explanation:

every thing looks good,  except the question says  "round"   and soooooo,  if you are rounding to the 2nd decimal place,  then the next two decimal places are  54,      or  50.2654   so, to round that, round up , so your final answer would look like   50.27   :)  see?

9514 1404 393

Answer:

  50.24 inches  (or 50.2 inches)

Step-by-step explanation:

The formula for circumference in terms of radius is ...

  C = 2πr

Using the given values for radius and for pi, the circumference is ...

  C = 2(3.14)(8 in) = 50.24 in

__

Additional comment

If you use a more accurate value of pi, the rounded value is 50.27 in. That is not the value requested by this problem. It helps to follow directions.

If you like, you can round to 50.2, since only one decimal place is required in the result.

Answer:

t = [tex]\frac{75}{n}[/tex]

Step-by-step explanation:

Use the inverse variation equation, y = [tex]\frac{k}{x}[/tex]

Replace y with t, and replace x with n, since those are the variables in this situation:

t = [tex]\frac{k}{n}[/tex]

Plug in 3 as t and 25 as n, and solve for k:

3 = [tex]\frac{k}{25}[/tex]

75 = k

Create the equation by plugging in 75 as k:

t = [tex]\frac{75}{n}[/tex]

So, the equation is t = [tex]\frac{75}{n}[/tex]

Answer:

[tex]m = 12[/tex]

[tex]n =3[/tex]

Step-by-step explanation:

Given

[tex]P(x) = x^3 + mx^2 - nx - 10[/tex]

Required

The values of m and n

For x - 1;

we have:

[tex]x - 1 = 0[/tex]

[tex]x=1[/tex]

So:

[tex]P(1) = (1)^3 + m*(1)^2 - n*(1) - 10[/tex]

[tex]P(1) = 1 + m*1 - n*1 - 10[/tex]

[tex]P(1) = 1 + m - n - 10[/tex]

Collect like terms

[tex]P(1) = m - n + 1 - 10[/tex]

[tex]P(1) = m - n -9[/tex]

Because x - 1 divides the polynomial, then P(1) = 0;

So, we have:

[tex]m - n -9 = 0[/tex]

Add 9 to both sides

[tex]m - n = 9[/tex] --- (1)

For x + 2;

we have:

[tex]x + 2 = 0[/tex]

[tex]x = -2[/tex]

So:

[tex]P(-2) = (-2)^3 + m*(-2)^2 - n*(-2) - 10[/tex]

[tex]P(-2) = -8 + 4m + 2n - 10[/tex]

Collect like terms

[tex]P(-2) = 4m + 2n - 10 - 8[/tex]

[tex]P(-2) = 4m + 2n - 18[/tex]

x + 2 leaves a remainder of 36, means that P(-2) = 36;

So, we have:

[tex]4m + 2n - 18 = 36[/tex]

Collect like terms

[tex]4m + 2n = 36+18[/tex]

[tex]4m + 2n = 54[/tex]

Divide through by 2

[tex]2m + n=27[/tex] --- (2)

Add (1) and (2)

[tex]m + 2m - n + n = 9 +27[/tex]

[tex]3m =36[/tex]

Divide by 3

[tex]m = 12[/tex]

Substitute [tex]m = 12[/tex] in (1)

[tex]m - n =9[/tex]

Make n the subject

[tex]n = m - 9[/tex]

[tex]n = 12 - 9[/tex]

[tex]n =3[/tex]

Answer:

RA = 24

Step-by-step explanation:

Since the triangle is isosceles ( 2 equal sides ) , then LU is a perpendicular bisector , so

AU = RU , that is

4r = 18 - 2r ( add 2r to both sides )

6r = 18 ( divide both sides by 6 )

r = 3

Then

RA = 18 - 2r + 4r = 18 + 2r = 18 + 2(3) = 18 + 6 = 24

Answer:

10. CD + DE = CE

11. BC + CE = BE

Step-by-step explanation:

10. CD and DE lie on a straight line, therefore, CD + DE = CE based on the segment addition postulate.

11. BC and CE lie on a straight line, therefore, BC + CE = BE based on the segment addition postulate.

In cylindrical coordinates, W is the set of points

W = {(r, θ, z) : 0 ≤ r ≤ 2 and 0 ≤ θ ≤ 2π and -2 ≤ z ≤ 5}

(A) Then the integral of f(x, y, z) over W is

[tex]\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

(B)

[tex]\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}[/tex]

FINAL ANSWER:

1

Step-by-step explanation:

[tex]\frac{2}{3} +\frac{1}{3}[/tex]

the denominators are the same so all we need to do is add.

[tex]\frac{2}{3} + \frac{1}{3} =\frac{3}{3}[/tex]

[tex]\frac{3}{3} =[/tex] 1 whole

final answer: 1

hope this answer helps you :)

have a great day and may God Bless You!

Answer:

3/8

Step-by-step explanation:

the total number of possible results is 4×4=16.

out of these 16 only the results

1 2

1 3

1 4

2 2

2 3

3 2

are desired results. these are 6.

so the probability of a desired result is 6/16 = 3/8

Answer:

Step-by-step explanation:

Given that:

[tex]f_x = \dfrac{x^2}{a^7-x^7}[/tex]

[tex]= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}[/tex]

[tex]= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}[/tex]

since  [tex]\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)[/tex]

Then, it implies that:

[tex]\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n[/tex]

[tex]= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}[/tex]

[tex]= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}[/tex]

[tex]\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}[/tex]

Answer:

-1

Step-by-step explanation:

1-2=-1

y=mx+b

b= y intercept

Answer:

-1

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

ITS OPTION (A)

PLZ MARK ME BRAINLIEST..

Answer:

C. 17 units

Step-by-step explanation:

Surface area of rectangular prism is given as:

A = 2lw + 2lh + 2wh

A = 930 square units

l = 12 units

h = 9 units

w = ? (We're to find the width)

Plug in the value into the formula

930 = 2*12*w + 2*12*9 + 2*w*9

930 = 24w + 216 + 18w

Add like terms

930 - 216 = 42w

714 = 42w

Divide both sides by 42

714/42 = 42w/42

17 = w

w = 17 units

Answer:

its a

Step-by-step explanation:

trust did test

Answer:

79.5, 110.5, 141.5, 172.5, 203.5, 234.5

Step-by-step explanation:

Given

The attached distribution

Required

The lower class limits

To do this, we simply subtract 0.5 from the lower interval

From the attached distribution, the lower intervals are:

80.0, 111.0, 142.0, 173,0 .......

So, the lower class limits are:

[tex]80.0-0.5 = 79.5[/tex]

[tex]111.0-0.5 = 110.5[/tex]

[tex]142.0-0.5 = 141.5[/tex]

[tex]173.0-0.5 = 172.5[/tex]

[tex]204.0-0.5 = 203.5[/tex]

[tex]235.0-0.5 = 234.5[/tex]

Hello!

[tex]\large\boxed{P = 300m}[/tex]

Use the following formula for the perimeter:

P = 2l + 2w, where:

l = length

w = width

Therefore:

P = 2(90) + 2(60)

Simplify:

P = 180 + 120 = 300 m

Answer:

well how about you use common sense 100 yards long on each side 200 yards then add 5o yards since the the that is how wide it is then add another 50 and you get 300 yards then convert that to meters

Answer:

Dependent Samples t test

Step-by-step explanation:

The dependent samples t test also called the paired t test are employed in statistical analysis when sample measurement in a certain group is to be paired with the sample measurement on the other group. This is possible because the samples used in the two groups are usually the same. Hence, pairing the samples is feasible in this case. This is different from independent t test as the samples in the groups are entirely different and distinct. Hence, giving no chance to match the samples together. In the scenario described above, the same 20 people(samples) formed the same group of measurement.

Answer:

domain:-16,-8,0,12

range:0,-11,12,14

9514 1404 393

Answer:

  P'(-1, -2)

Step-by-step explanation:

The transformation for 270° CCW rotation is ...

  (x, y) ⇒ (y, -x)

Then the image of the given point is ...

  P(2, -1) ⇒ P'(-1, -2)

9514 1404 393

Answer:

  66 m

Step-by-step explanation:

The perimeter is the sum of the measures of all of the sides. There are two side measures that are missing from the diagram.

The missing horizontal measure is ...

  17 m - 8 m = 9 m

The missing vertical measure is ...

  16m -7 m = 9 m.

If you add these to the sum you already calculated, you will get the correct answer:

  48 m + 9 m + 9 m = 66 m . . . perimeter of the figure

_____

If you're paying attention, you see that the sum of the measures of the two shorter horizontal segments is the same as the measure of the longer horizontal segment. Likewise, the sum of the measurements of the two shorter vertical segments is the same as that of the longer vertical segment.

In other words, the perimeter of this (and any) L-shaped figure is the same as the perimeter of a rectangle having the same horizontal and vertical dimensions as the long sides of the figure.

  P = 2(17 m +16 m) = 2(33 m) = 66 m

Answer:

1. C

2. B

3 A

4. A

Step-by-step explanation:

#1

Brady starts off with 12 coins

And buys 6 more coins every year

So add 6 to find number of coins he will have the next year until we've done it five times ( because we want to find how many he will have after 5 years )

12 ( 1st year )

Add 6

12 + 6 = 18 ( 2nd year )

Add 6

18 + 6 = 24 ( 3rd year )

Add 6

24 + 6 = 30 ( 4th year )

Add 6

30 + 6 = 36 ( 5th year )

By the fifth year he will have 36 coins and the sequence would be

12, 18, 24, 30, 36

Which corresponds with answer choice C

2

15, 19, 23, 27, ?

We want to find the next term

To do so we must find the common difference

We can do this by subtracting the last given term by the term before it

27 - 23 = 4

Just to clarify we can do the terms before those

19 - 15 = 4

So the common difference is 4

Now to find the next term we simply add 4 to the last given term

27 + 4 = 31

The next term would be 31

3. Cumulative property of addition states that you can add any 3 numbers in a different order and they will be the same

a + b + 2 = 2 + a + b

Same variables and numbers just different order

Therefore this is an example of cumulative property of addition

4. The GCF ( greatest common factor ) is the greatest number that the two numbers can be divided by

18a and 24ab

Factors of 18

2 , 9 , 6, 3 , 1 and 18

Factors of 24

24, 1, 2, 12, 6, 4, 3 and 8

The greatest factor that both 18 and 24 have is 6

The GCF would be 6a ( not 6 ) because both numbers share a common variable (a) ( 18a , 24ab )

Answer:

main age = total age/total people

if Main age is = 27

[tex]27 = \frac{ \times }{5} [/tex]

and x = 135

Total age is = 135

then main age is 35

[tex][35 = \frac{y}{6} [/tex]

and y = 210

first main age - second main age = age of the person participating

210 - 135 = 75

HAVE A NİCE DAY

Step-by-step explanation:

GREETINGS FROM TURKEY

(Q.1)

[tex]y = \dfrac{C - e^x}{2x} \implies y' = \dfrac{-2xe^x-2C+2e^x}{4x^2} = \dfrac{-xe^x-C+e^x}{2x^2}[/tex]

Then substituting into the DE gives

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{2\left(\dfrac{C-e^x}{2x}\right) + e^x}{2x}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{C-e^x + xe^x}{2x^2}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = \dfrac{-C+e^x - xe^x}{2x^2}[/tex]

and both sides match, so y is indeed a valid solution.

(Q.2)

[tex]\ln\left(y^x\right)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

This DE is separable, since you can write [tex]\ln\left(y^x\right)=x\ln(y)[/tex]. So you have

[tex]x\ln(y)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

[tex]\dfrac{\ln(y)}y\,\mathrm dy = 3x\,\mathrm dx[/tex]

Integrate both sides (on the left, the numerator suggests a substitution):

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 + C[/tex]

Given y (2) = e ³, we find

[tex]\dfrac12 \ln^2(e^3) = 6 + C[/tex]

[tex]C = \dfrac12 \times3^2 - 6 = -\dfrac32[/tex]

so that the particular solution is

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 - \dfrac32[/tex]

[tex]\ln(y) = \pm\sqrt{3x^2 - 3}[/tex]

[tex]\boxed{y = e^{\pm\sqrt{3x^2-3}}}[/tex]

(Q.3) I believe I've already covered in another question you posted.

Answer:

the wording (punctuation) of the question can lead to different interpretations....

I assume that the question was >17 & even which is "5/19",

BUT... it can also be read as two questions

first >17 which is "10/19"

and second an even number which is "9/19"

BUT !!! I think that the question answer is 5/19

Step-by-step explanation:

Even Number  = 18/38 = 9/19

greater 17 = 20/38 = 10/19

Even & greater 17 = 10/38 = 5/19

Answer:

[tex]\sigma = 121.53[/tex]

Step-by-step explanation:

Required

The population standard deviation

First, calculate the population mean

[tex]\mu = \frac{\sum x}{n}[/tex]

This gives:

[tex]\mu = \frac{148+ 329+ 491 +167+ 228+285+ 441}{7}[/tex]

[tex]\mu = \frac{2089}{7}[/tex]

[tex]\mu = 298.43[/tex]

The population standard deviation is:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma = \sqrt{\frac{(148 - 298.43)^2 + ..........+ (441- 298.43)^2}{7}}[/tex]

[tex]\sigma = \sqrt{\frac{103387.7143}{7}}[/tex]

[tex]\sigma = \sqrt{14769.6734714}[/tex]

[tex]\sigma = 121.53[/tex]