Answer:
Bro what do you mean to represent Mount Everest height by x but if you want to sove a maths sum than you can take any alphabet
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Need the answer please, soon as possible
9514 1404 393
Answer:
(d) 27.4%
Step-by-step explanation:
The desired percentage is ...
(juniors for Kato)/(total juniors) × 100%
= 129/(129 +194 +147) × 100%
= (129/470) × 100% ≈ 27.4%
About 27.4% of juniors voted for Kato.
The firm had 15 billion VND of earnings before interest and tax (EBIT), corporate tax is 20%. The market price of stock is 60.000đ. Knowing that net income will be held 40% before using it for dividend. How much of the net income can be divided for shareholders?
Answer:
was assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
If f(x) = x2 + 7x and g(x) = 3x - 1, what is f(g(x))?
Answer:
f(g(x)) = 9x^2 + 15x - 6
Step-by-step explanation:
We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.
Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side. We obtain:
f(g(x)) = (3x - 1)^2 + 7(3x - 1).
If we multiply this out, we get:
f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or
f(g(x)) = 9x^2 + 15x - 6
PLEASE HELP
Solve the equation for y. Identify the slope and y-intercept then graph the equation.
-3y=3x-9
Y=
M=
B=
Please Include a picture of the graph and show your work if you can
9514 1404 393
Answer:
y = -x +3
m = -1
b = 3
Step-by-step explanation:
To solve the given equation for y, divide by the coefficient of y.
(-3y)/(-3) = (3x -9)/(-3)
y = -x +3
__
The slope is the x-coefficient, M = -1.
__
The y-intercept is the added constant, B = 3.
__
Both equations are graphed in the attachment. Texture has been added to the original so you can see the graphs are the same line.
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes. An operator in the call center is required to answer 76 calls each day. Assume the call times are independent.
What is the expected total amount of time in minutes the operator will spend on the calls each day?
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day? Give your answer to four decimal places.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
Answer:
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n instances of a normally distributed variable:
For n instances of a normally distributed variable, the mean is:
[tex]M = n\mu[/tex]
The standard deviation is:
[tex]s = \sigma\sqrt{n}[/tex]
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes.
This means that [tex]\mu = 2.3, \sigma = 2[/tex]
An operator in the call center is required to answer 76 calls each day.
This means that [tex]n = 76[/tex]
What is the expected total amount of time in minutes the operator will spend on the calls each day?
[tex]M = n\mu = 76*2.3 = 174.8[/tex]
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day?
[tex]s = \sigma\sqrt{n} = 2\sqrt{76} = 17.4356[/tex]
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes?
This is the p-value of Z when X = 166.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
For this problem:
[tex]Z = \frac{X - M}{s}[/tex]
[tex]Z = \frac{166 - 174.8}{17.4356}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.6915.
1 - 0.6915 = 0.3085.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95?
This is X = c for which Z has a p-value of 0.95, so X = c when Z = 1.645. Then
[tex]Z = \frac{X - M}{s}[/tex]
[tex]1.645 = \frac{c - 174.8}{17.4356}[/tex]
[tex]c - 174.8 = 1.645*17.4356[/tex]
[tex]c = 203.4816[/tex]
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]
Chad has a win loss ratio 5:5 across his games what percentage of games did he win
Answer:
Step-by-step explanation:
50%
Answer:
50%
Step-by-step explanation:
Win % = wins / total * 100%
Win% = (5/(5 + 5)) * 100
Win% = 5/10 * 100 = 50%
What is the correct answer?
Answer:
Option D
Only the equation in option D matches with the table
Answered by GAUTHMATH
relationship between the two number
b 70.908
7.908
Which one is greater
Answer:
70.908 is greater than 7.908 .
I hope your day goes nice
Answer:
70.9 0 8 is Greaterboth are different because of different placement of point.
Please help me to find out the answer
9514 1404 393
Answer:
44.66 in
Step-by-step explanation:
The side opposite the marked angle is given, and the side adjacent to it is the one wanted. The relevant trig relation is ...
Tan = Opposite/Adjacent
Solving for the Adjacent side, we find ...
Adjacent = Opposite/Tan
PQ = (29 in)/tan(33°) ≈ 44.66 in
What is a placement form from the school mean
Answer:
Placements are basically extended internships or work experience assignments
Step-by-step explanation:
write an equivalent expression without negative exponent for 5 to the negative 4th power
Hi! I'm happy to help!
To solve this problem, we need to first solve [tex]5^{-4}[/tex].
Negative exponents divide the number by x instead of multiplying. So, [tex]5^{-4}[/tex] is 1/625. Since we can't use another negative exponent, we can use a number that would decrease with a positive exponent. In this situation, we can use the inverse of 5, which is [tex]\frac{1}{5}[/tex], and put this to the fourth power. [tex]\frac{1}{5} ^{4}[/tex]
This expression also equals 1/625.
I hope this was helpful, and keep learning! :D
When A = 200, solve the equation x2 - 40x + A=0 using the quadratic formula. Show all your working and give your answers correct to 2 decimal places.
Answer:
Solution given:
equation is:
x²-40x+A=0
when A=200
equation becomes
x²-40x+200=0
Comparing above equation with ax²+bx+c=0 we get
a=1
b=-40
c=200
By using quadratic equation formulax=[tex]\displaystyle \frac{-b±\sqrt{b²-4ac}}{2a}[/tex]
substituting value
x=[tex]\displaystyle \frac{-*-40±\sqrt{(-40)²-4*1*200}}{2*1}[/tex]
x=[tex]\displaystyle \frac{40±\sqrt{800}}{2}[/tex]
x=[tex]\displaystyle \frac{40±20\sqrt{2}}{2}[/tex]
taking positive
x=[tex]\displaystyle \frac{40+20\sqrt{2}}{2}[/tex]
x=34.14
taking negative
x=[tex]\displaystyle \frac{40-20\sqrt{2}}{2}[/tex]
x=5.86
x=34.14 or 5.86Kế hoạch đi dã ngoại của một gia đình sẽ bị hủy nếu trời có mây hoặc mưa. Biết xác suất để trời có mây là có mưa là có cả mây và mưa là . Tính xác suất để kế hoạch được thực hiện.
Answer:
itditsktxjtcv6tgcxufh-&#€#€($*:'₹€$*^'ditx_*^,tsitsitxmvditxitsitsjfxkhcoucuofoydoy
Help me please thanks guys
Answer:
B, D, F
Step-by-step explanation:
In a rational exponent, the numerator is an exponent, and the denominator becomes the index of the root.
[tex]a^{\frac{m}{n}} = \sqrt[n] {a^m}[/tex]
Answer: B, D, F
Casey's phone service charges a flat monthly fee of $30 for the first 1000 minutes of calls and $0.40 per minute over 1000. Determine Casey's monthly charge if he makes 1,100 minutes of calls?
Answer:
Casey's monthly charge for making 1,100 minutes of calls is $70.
Step-by-step explanation:
We can write a piecewise function to model the situation.
Since Casey's phone service only charges a monthly fee of $30 for the first 1000 minutes, we can write that for calling t minutes:
[tex]\displaystyle C(t) = 30\text{ if } t\leq 1000[/tex]
In other words, the total cost is only $30 is the total minutes of call is less than 1000 minutes.
However, if the total minutes of calls is greater than 1000, then its $0.40 per minute on top of the 30. Thus:
[tex]\displaystyle C(t) = 30 + 0.4(t-1000)\text{ if } t>1000[/tex]
All together, our piecewise function will be:
[tex]\displaystyle C(t) = \begin{cases} 30 & t\leq 1000 \\ 30 + 0.4(t-1000) & t>1000\end{cases}[/tex]
We want to determine Caseys monthly charge if he makes 1,100 minutes of calls. So, t = 1100. Since 1100 > 1000, we will use the second equation. This yields:
[tex]C(1100)= 30+0.4((1100)-1000)[/tex]
Evaluate:
[tex]\displaystyle C(1100) = 30+0.4(100) = 30+40=\$70[/tex]
Casey's monthly charge for using 1,100 minutes of call is $70.
Terrell loves to listen to music, so he buys a subscription to a music-streaming service. He pays $4.99 each month. How much does the streaming service cost per year?
find the exact value of tan(165°) using a difference of two angles
Answer: [tex]-2+\sqrt{3}[/tex]
=========================================================
Work Shown:
Apply the following trig identity
[tex]\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\[/tex]
Now let's rationalize the denominator
[tex]\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\[/tex]
----------------------
As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.
Or you can note how
[tex]\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949[/tex]
which helps us see that they are the same thing.
Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as [tex]\sqrt{3}-2[/tex] but it's the same as above.
find the slope of the line that passes through these two points
Answer:
Step-by-step explanation:
g is a trigonometric function of the form g(x)=acos(bx+c)+d
Below is the graph of g(x). The function has a maximum point at (3.5,-4) and a minimum point at (-1,-5)
Find a formula for g(x). Give an exact expression.
9514 1404 393
Answer:
a = 0.5b = π/4.5c = 7π/9d = -4.5Step-by-step explanation:
The value of d is the average of the maximum and the minimum.
d = (-4 +-5)/2 = -9/2 = -4.5
The value of 'a' is the difference between the maximum and d.
a = -4 -(-4.5) = 0.5
The value of b is 2π divided by the period. Here, the half-period is 3.5 -(-1) = 4.5, so ...
b = 2π/9 = π/4.5
The value of c is the value that makes the cosine argument zero at x=3.5.
(π/4.5)(3.5) +c = 0
c = -7π/9
Find an equation of the circle whose diameter has endpoints (-6, -1) and (-2,3).
Step-by-step explanation:
Let find the distance of the diameter. using distance formula.
[tex](3 + 1) {}^{2} + ( - 2 + 6) {}^{2} = \sqrt{8} [/tex]
The diameter is sqr root of 8 units.
A circle equation is
[tex] {x}^{2} + {y}^{2} = {r}^{2} [/tex]
where r is the radius. The radius is half the diameter so
[tex]r = \frac{ \sqrt{8} }{2} = \frac{ \sqrt{8} }{ \sqrt{4} } = \sqrt{2} [/tex]
[tex] {r}^{2} = { \sqrt{2} }^{2} = 2[/tex]
So our radius is 2.
Now we need to find the midpoint or Center of the diameter.
[tex] \frac{ - 6 - 2}{2} = - 4[/tex]
[tex] \frac{3 - 1}{2} = 1[/tex]
So the center of the circle is (-4,1). So our equation of the Circle us
[tex](x + 4) {}^{2} + (y - 1) {}^{2} = ( \sqrt{2} ) {}^{2} [/tex]
For the given annual rate of change, find the corresponding growth or decay factor. + 300%
Answer:
50% growth would would be (1 + .5)^ n
and 100% growth would be (1+ 1)^n
I assume that the answer would be (1+3)^n
for 300% growth the factor would be 3
Step-by-step explanation:
Write the polynomial in standard form. Then name the polynomial based on its degree and number of
terms.
y-7y3 + 15y9
Answer:
[tex]15y^9 - 7y^3 + y[/tex]
Nonic polynomial
Step-by-step explanation:
Given
[tex]y - 7y^3 + 15y^9[/tex]
Required
Write in standard form
The standard form of a polynomial is:
[tex]ay^n + by^{n-1} + ......... + k[/tex]
So, we have:
[tex]y - 7y^3 + 15y^9[/tex]
The standard form is:
[tex]15y^9 - 7y^3 + y[/tex]
And the name is: Nonic polynomial (because it has a degree of 9)
What is the volume of the cylinder below?
Height 4
Radius 7
Answer:
V ≈ 615.75
r Radius 7
h Height 4
Which decimal is equivalent to
15/100?
A- O 0.015
B- 0.15
C-o 1.5
D- 0.0015
Answer:
D
Step-by-step explanation:
0.0015
hope this helps
How to find Joint and Combined variation?
Answer:
W is multiplied by 8
Step-by-step explanation:
If W varies jointly with x, y, and z, we can say that
W = k (xyz), with k being a constant for our original equation. We are asked what will happen to W if x, y, and z are each doubled. To figure this out, we can go back to our equation,
W = k (xyz)
First, we can double x, meaning that we multiply it by 2. Doing this, we get
W = k (2x * y * z)
Then, we can double y and z in a similar fashion, resulting in
W = k (2x * 2y * 2z)
W = 8 * k (xyz)
The new W, after all the doubling, is equal to 8 * k * x * y * z. The old W is equal to k * x * y * z. It can be determined that the new W is equal to 8 * the old W, so W is multiplied by 8
express 111 as a sum of two primes
Answer:
2 + 109 = 111
Step-by-step explanation:
.............
What is the equation of the line through (4, -3) and (0, -2)?
O A. y = -x + 2
B. Y= -1x – 2
O C. y= - 4x –
D. y = 4x + 2
Answer:
B
Step-by-step explanation:
Pull in -4 and 0 into the variable x. and the 4 and -2 in the variable y and solve to get an equal answer.
Can someone please help me with this math problem
We have [tex]f\left(f^{-1}(x)\right) = x[/tex] for inverse functions [tex]f(x)[/tex] and [tex]f^{-1}(x)[/tex]. Then if [tex]f(x) = 2x+5[/tex], we have
[tex]f\left(f^{-1}(x)\right) = 2f^{-1}(x) + 5 = x \implies f^{-1}(x) = \dfrac{x-5}2[/tex]
Then
[tex]f^{-1}(8) = \dfrac{8-5}2 = \boxed{\dfrac32}[/tex]
A window has the shape of a semicircle. The base of the window is measured as having diameter 64 cm with a possible error in measurement of 0.1 cm. Use differentials to estimate the maximum error possible in computing the area of the window.
a. 1.3π cm^2
b. 2.4 πcm^2
c. 2.6 πcm^2
d. 3.2 πcm^2
e. 1.6 πcm^2
f. 1.2 πcm^2
Answer:
e. 1.6π cm²
Step-by-step explanation:
Since the window is in a semi-circular shape, its area A = πD²/4 ÷ 2 = πD²/8 where D = diameter of window = 64 cm
Now, the error in the area dA = dA/dD × dD where dD = error in the diameter = 0.1 cm and dA/dD = derivative of A with respect to D.
So, dA/dD = d(πD²/8)/dD = 2 × πD/8 = πD/4
So, the differential dA = dA/dD × dD
dA = πD/4 × dD
Substituting D = 64 cm and dD = 0.1 cm into the equation, we have
dA = πD/4 × dD
dA = π × 64 cm/4 × 0.1 cm
dA = π × 16 cm × 0.1 cm
dA = π × 1.6 cm²
dA = 1.6π cm²
So, the maximum error in computing the area of the window is 1.6π cm²
Difference between 5429 and 5907 to the greatest place.
answer- u have to subtract the great no. from the smaller one
Given numbers are 5429 and 5907..
To find the difference we should subtract..
5907
- 5429
-------------
478
_______
#Answered by: Cutest Ghost