Donna wants to wrap a shipping box shaped like a rectangular prism. The box is 23 inches tall and has a square base with sides that each measure 4 inches. How much paper will she use?​

Answer:

1m=1000 mm.

1m^2=(1000)*(1000)=10^6 mm^2

So just multiply the given result in m^2 by 10^6 to get the result in mm^2.

So ,16 m^2 =16*(10^6)mm^2.

Hope you got it.

Answer:

yes

Step-by-step explanation:

The answer is 19 they worked it out right above the question.

Answer:

19

Step-by-step explanation:

3(x+6) = 5(x-4)

Distribute

3x+18 = 5x-20

Subtract 3x from each side

18 = 2x-20

Add 20 to each side

38 = 2x

Divide by 2

19 = x

The solution is 19

Answer:

question 1:

step #1:divide both sides by x

step #2:multiply both sides by 4

step #3: plug it into equation

Step-by-step explanation:

question 1:

step #1: divide both sides by x

you get x/4 = 1

step #2:multiply both sides by 4

you get x = 4

step #3: plug it into equation

4 squared/4 = 4

Answer:

Step-by-step explanation:

To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y.

To find the x-intercept, set y = 0 \displaystyle y=0 y=0.

To find the y-intercept, set x = 0 \displaystyle x=0 x=0.

Answer:

We have to:

"All of the plots are the same length, x"

L = x

"and the width of each plot is 5 yards less than the length"

W = x-5

"The total number of plots Liam owns is 20 more than the length of a plot"

20 + x

"the total area of all the plots Liam owns is 2,688 square yards"

A = (20 + x) * (x) * (x-5)

A = (20x - 100 + x ^ 2 -5x) * (x)

A = (x ^ 2 + 15x - 100) * (x)

2688 = (x ^ 3 + 15x ^ 2 - 100x)

x ^ 3 + 15x ^ 2 - 100x = 2688

x ^ 3 + 15x ^ 2 - 100x - 2688 = 0

Answer:

*** The equation x3 + 15x2 - 100x - 2.688 = 0 can be used to find the length of each plot.

Answer:x^3+15x^2-100x-2,688=0

Step-by-step explanation:

Answer:

2300 apples

Step-by-step explanation:

2500 - 200 = 2300

Answer:

2300

Step-by-step explanation:

2500 - 200 = 2300

Note: "have left" means the answer after subtraction.

Answer:

[tex]\displaystyle A_\text{shaded}=18-\frac{9}{2}\pi \text{ units}^2[/tex]

Step-by-step explanation:

First, find the area of the rectangle:

[tex]A_\text{rect}=9(3)=18\text{ units}^2[/tex]

In order to find the area of the shaded region, we can subtract the areas of the two sectors from the total area of the rectangle.

Find the area of the sectors. We can use the sector formula:

[tex]\displaystyle A=\pi r^2\cdot \frac{\theta}{360^\circ}[/tex]

The left sector has a radius of three units and an angle of 90°. Hence, its area is:

[tex]\displaystyle A_\text{L}=\pi (3)^2\cdot \frac{90}{360}=9\pi\cdot \frac{1}{4}=\frac{9}{4}\pi[/tex]

The right sector is identical to the left sector. So, the total area of the two sectors is:

[tex]\displaystyle A_{\text{T}}=\frac{9}{4}\pi +\frac{9}{4}\pi =\frac{9}{2}\pi[/tex]

Hence, the area of the shaded region is:

[tex]\displaystyle A_\text{shaded}=18-\frac{9}{2}\pi \text{ units}^2[/tex]

Answer:

5

Step-by-step explanation:

The x coordiantes are the same so

the distance is the difference in the y coordinates

10 - 5 = 5

Answer:x>=-2

Step-by-step explanation:x is also equal to -2 as the dot is closed.

Answer:

v . u = < v1 , v2 > . <u1 , u2> = v1 u1 + v2 u2

Step-by-step explanation:

Answer:

<ABE = 109

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(sum of Intercepted Arcs)

< ABE = 1/2 ( 38+180)

< ABE = 1/2 (218)

<ABE = 109

Answer:

Formula: Half the sum of the two arcs. So, this would be the equation:

[tex]\frac{1}{2}[/tex][tex](38[/tex]+[tex]180[/tex])

Solve:

218 / 2 = 109

Answer: 109

Answer:

D po

Step-by-step explanation:

yan po!sana nakatulong po

Answer:

20 minutes

Step-by-step explanation:

If you add 20 minutes to 7:55 P.M., it becomes 8:15 P.M.

Answer:

20 minutos

Step-by-step explanation:

De 7:55 pm hasta las 8: pasaron 5 minutos, luego de 8:00 a 8:15 pm pasaron 15 minutos.

Así que sería 5 + 15 = 20 minutos

Answer:

x=2

Step-by-step explanation:

Since the base angles are the same, the side lengths are the same, making this an isosceles triangle

7(x+2) = 4(9-x)

Distribute

7x+14 = 36 -4x

Add 4x to each side

7x+4x +14 = 36 -4x+4x

11x +14 = 36

Subtract 14 to each side

11x+14-14 = 36-14

11x = 22

Divide by 11

11x/11 =22/11

x=2

Answer: x=2

Step-by-step explanation:

This is an isosceles triangle. That means both of the sides marked are congruent.

That means we can set up this equation and solve it:

[tex]7(x+2)=4(9-x)[/tex]

First let's use the distributive property

[tex](7)(x)+(7)(2)=(4)(9)-(4)(x)\\7x+14=36-4x[/tex]

Now we can add 4x on both sides

[tex]7x+14+4x=36-4x+4x\\11x+14=36[/tex]

Next we subtract 14 from both sides

[tex]11x+14-14=36-14\\11x=22[/tex]

Finally we divide both sides by 11

[tex]\frac{11x}{11} =\frac{2}{11} \\x=2[/tex]

Answer:

Y=2x+0.5

Step-by-step explanation:

The gradient is 2/1=2x

The y-intercept looks to be around 0.5

Answer:

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (1, 1) ← 2 points on the line

m = [tex]\frac{1-0}{1-(-1)}[/tex] = [tex]\frac{1}{1+1}[/tex] = [tex]\frac{1}{2}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 1 ) , then

1 = [tex]\frac{1}{2}[/tex] + c ⇒ c = 1 - [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{2}[/tex] ← equation of line

Answer:

Step-by-step explanation:

Step 1: Add -4y to both sides.

2x+4y+−4y=1+−4y

2x=−4y+1

Step 2: Divide both sides by 2.

2x

2

=

−4y+1

2

x=−2y+

1

2

Step 1: Add 5y to both sides.

3x−5y+5y=7+5y

3x=5y+7

Step 2: Divide both sides by 3.

3x

3

=

5y+7

3

x=

5

3

y+

7

3

Answer:

65 degree angle but when straight 180 degree angle

Step-by-step explanation:

sry if wrong :)

Answer:

Step-by-step explanation:

Using this same method of solving, solve the rest. I will help you with 2 more.

5. [tex]10^6[/tex] = 1,000,000

8. [tex]10^0[/tex] = 1

Answer:

[tex] {i}^{1} = i \\ {i}^{2} - 1 \\ {i}^{3} = - i \\ {i}^{4} = 1[/tex]

Mark me as Brainliest

Answer:

2x-3

Step-by-step explanation:

f (x) = 3x - 1

g(x) = x + 2

(f - g)(x) = 3x-1 - ( x+2)

Distribute the minus sign

       = 3x-1 -x-2

Combine like terms

       = 3x-x-1-2

       = 2x-3

(f - g )( x ) = 2 x - 3

f ( x ) = 3x - 1

g ( x ) = x + 2

remove unnecessary parantheses

collect like terms

Answer: £3.38

Step-by-step explanation:

In the first year, the pocket money goes up by:

= 1 + (1 * 50%)

= £1.50

In the second year:

= 1.50 + (1.50 * 50%)

= £2.25

In the third year:

= 2.25 * ( 2.25 * 50%)

= £3.38

Answer:

The least amount of fencing needed for the rectangular pen is 72.19 feet.

Step-by-step explanation:

The area and perimeter equations of the pen are, respectively:

[tex]p = 2\cdot (x + y)[/tex] (1)

[tex]A = x\cdot y[/tex] (2)

Where:

[tex]p[/tex] - Perimeter, in feet.

[tex]A[/tex] - Area, in square feet.

[tex]x[/tex] - Width, in feet.

[tex]y[/tex] - Length, in feet.

Let suppose that total area is known and perimeter must be minimum, then we have a system of two equations with two variables, which is solvable:

From (2):

[tex]y = \frac{A}{x}[/tex]

(2) in (1):

[tex]p = 2\cdot \left(x + \frac{A}{x}\right)[/tex]

And the first and second derivatives of the expression are, respectively:

[tex]p' = 2\cdot \left(1 -\frac{A}{x^{2}} \right)[/tex] (3)

[tex]p'' = \frac{4\cdot A}{x^{3}}[/tex] (4)

Then, we perform the First and Second Derivative Test to the function:

First Derivative Test

[tex]2\cdot \left(x - \frac{A}{x^{2}} \right) = 0[/tex]

[tex]2\cdot \left(\frac{x^{3}-A}{x^{2}} \right) = 0[/tex]

[tex]x^{3} - A = 0[/tex]

Given that dimensions of the rectangular pen must positive nonzero variables:

[tex]x^{3} = A[/tex]

[tex]x = \sqrt[3]{A}[/tex]

Second Derivative Test

[tex]p'' = 4[/tex]

In a nutshell, the critical value for the width of the pen leads to a minimum perimeter.

If we know that [tex]A = 169\,ft^{2}[/tex], then the value of the perimeter of the rectangular pen is:

[tex]x = \sqrt[3]{169\,ft^{2}}[/tex]

[tex]x \approx 5.529\,ft[/tex]

By (2):

[tex]y = \frac{A}{x}[/tex]

[tex]y = \frac{169\,ft^{2}}{5.529\,ft}[/tex]

[tex]y = 30.566\,ft[/tex]

Lastly, by (1):

[tex]p = 2\cdot (5.529\,ft + 30.566\,ft)[/tex]

[tex]p = 72.19\,ft[/tex]

The least amount of fencing needed for the rectangular pen is 72.19 feet.

Answer:A

Step-by-step explanation:

m=(14-11)/(8-2)

m=3/6

m=1/2

y = 1/2x+b substitute one of the points

11=1/2(2)+b

11=1 + b

b=10

y = 1/2x+10

Answer:

Step-by-step explanation:

Note : In multiplication if the bases are same u can add their exponent while in division if the bases are same u can subtract their exponent.

Hope this helps u !!

Answer:

a) 38.74% probability that the main printer is operating properly for exactly 9 inspections.

b) Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

c) The expected number of inspections in which the main printer is operating properly is 9.

Step-by-step explanation:

For each inspection, there are only two possible outcomes. Either it is operating correctly, or it is not. The probability of the printer operating correctly for an inspection is independent of any other inspection, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Based on past experience, the main printer in a university computer centre is operating properly 90% of the time.

This means that [tex]p = 0.9[/tex]

Suppose inspections are made at 10 randomly selected times.

This means that [tex]n = 10[/tex]

A) What is the probability that the main printer is operating properly for exactly 9 inspections.

This is [tex]P(X = 9)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874[/tex]

38.74% probability that the main printer is operating properly for exactly 9 inspections.

B) What is the probability that the main printer is operating properly for at least 3 inspections?

This is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.9)^{0}.(0.1)^{10} \approx 0[/tex]

[tex]P(X = 1) = C_{10,1}.(0.9)^{1}.(0.1)^{9} \approx 0[/tex]

[tex]P(X = 2) = C_{10,2}.(0.9)^{2}.(0.1)^{8} \approx 0[/tex]

Thus:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0 = 0[/tex]

Then:

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0 = 1[/tex]

Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

C) What is the expected number of inspections in which the main printer is operating properly?

The expected value for the binomial distribution is given by:

[tex]E(X) = np[/tex]

In this question:

[tex]E(X) = 10(0.9) = 9[/tex]

Answer:

e and f

Step-by-step explanation:

there is a great app to use called algebrator it helps me everyday for things like this <3