Find the points at which the function f(x)=x^2/3 has a maximum or minimum or a minimum value in the interval [-1,2].

Answer:

not differentiable

Explanation:

as you can see from the graph below the function is not differentiable.

The values of x are the function discontinuous is 3. The points at which the function f(x)=x^2/3 has a maximum or minimum or a minimum value in the interval [-1,2].

When the graph is known to have an interrupted curve, that is, with gaps, breaks, or jumps, the function is said to be discontinuous.

It is discontinuous because the function cannot be further simplified or broken down, canceling the denominator number in the process. A function is a relationship between a set of fixed inputs and a set of fixed outputs that must have exactly one output for each input.

Discontinuous at x=-1, 0, 1

First, factor the function's numerator and denominator. When a number is 0 in the numerator as well as the denominator, a point of discontinuity is reached. There is a point of discontinuity there since both the numerator and the denominator are zeros.

Therefore, The values of x are the function discontinuous is 3. The points at which the function f(x)=x^2/3 has a maximum or minimum or a minimum value in the interval [-1,2].

To learn more about function discontinuous, refer to the link:

brainly.com/question/2750981

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By "the ruling power in the United States" (paragraph 3, sentence 2) the speaker means the
A. majority of voters

B. legal system

C. influential writers

D. critics of the government

E. wealthiest landowners

BRAINLIESTTTTT IF RIGHTTT

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