Answer:
101 degrees
Step-by-step explanation:
the sum of all angles in a triangle is always 180 degrees.
the other not-shaded angle in the lower triangle is also 42 degrees.
the shaded angle is therefore
180 - 37 - 42 = 101 degrees
Overline MD cong overline LS additional information is necessary to show that triangle MTD cong triangle LGS by SSS?
Answer:
[tex]TD \cong GS[/tex]
Step-by-step explanation:
See comment for complete question
Given:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
Required
The information that shows [tex]\triangle MTD \cong \triangle LGS[/tex] by SSS
By SSS implies that, the three sides of both triangles are congruent
Already, we have:
[tex]TM \cong GL[/tex]
[tex]MD \cong LS[/tex]
The third side of [tex]\triangle MTD[/tex] is [tex]TD[/tex]
The third side of [tex]\triangle LGS[/tex] is [tex]GS[/tex]
So, for both to be congruent by SSS, the third sides must be congruent
i.e.
[tex]TD \cong GS[/tex]
Find the median of :- 25, 37, 27, 38, 29, 20, 39
Answer: The median is 29
Step-by-step explanation:
I started by arranging the data points from smallest to largest to get 20, 25, 27, 29, 37, 38, 39. Then I found the middle number in the data set and got 29.
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fasttt
Answer: [tex]864\ m^2,\ 24\ m[/tex]
Step-by-step explanation:
Given
Perimeter of the rhombus is [tex]120\ m[/tex]
Length of one of the diagonal is [tex]d_1=36\ m[/tex]
All the sides of the rhombus are equal
[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]
Area of the rhombus with side and one diagonal is
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]
Insert the values
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]
Area with two diagonals length can be given by
[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]
Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]
Solve: 3/x-4 >0
x < 4
x > -4
x > 4
x < -4
Answer:
x>4
Step-by-step explanation:
3/(x-4) >0
Divide each side by 3
3/(x-4) * 1/3 >0*1/3
1/(x-4) >0
We know if 1/(x-4) >0 then x-4 > 0
x-4>0
Add 4 to each side
x-4+4 >0+4
x>4
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]
Make six prime numbers using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 once each.
~can you plz explain?!
Answer:
2, 3, 5, 7, 11, 13.
Step-by-step explanation:
A prime number is a number that you don't get a whole number when divided by 2 but you do get a whole number when divided by prime numbers such as 3,5,7,11... Basically a number with two factors, it can only be divided by 1 or themselves. for example:
9/2 = 4.5 (this is not a whole number so it might be a prime.
9/3 = 3 (it works when divided by a prime number.
another:
8/2 = 4 (it gives a whole number when divided by 2 therefor, it can't be a prime number.
Answering:
There are 6 prime numbers at the top^^^^.
One possible answer is 2, 3, 5, 41, 67, 89
Another possible answer is 2, 3, 5, 47, 61, 89
Other answers may be possible.
=============================================================
Explanation:
This is a trial and error type of problem. Though with practice it's not as blind of randomly guessing.
We have 9 values here. If we paired them up, then we can form at most 4 pairs (since 9/2 = 4.5 rounds down to 4). That means we won't be able to form six two-digit primes. Some of the primes must be single digits.
We can have 3 single digit primes and 3 two-digit primes since 3+2*3 = 9.
The single digit primes are: 2, 3, 5, 7
Let's say 2 and 5 are definitely locked down to be the single digit group. I'm doing this since we can't have 2 or 5 as the units digit. If the units digit is 2, then 2 is a factor and it's not prime. Similarly, if 5 is the units digit, then 5 is a factor and that two digit value is not prime.
For good measure, we'll throw 3 in there as well and see what happens.
------------------
The digits we have left are: 1, 4, 6, 7, 8, 9
The number 14 isn't prime, but 41 is prime
67 is prime so that's another two values off the list
lastly, 89 is prime so that works as well.
So one possible sequence is 2, 3, 5, 41, 67, 89
Notice how we can swap the 1 and 7 to go from 41,67 to 47,61; this gets us two other primes. So another possible answer is 2, 3, 5, 47, 61, 89
------------------
Side note: having the list of primes on a reference sheet is a handy recommendation. You only need to go up as high as 97 which is the largest two digit prime.
Angles 4 and 6 are
because they are
angles.
Answer: Is this a question? Or statement Yes they can be angles
Step-by-step explanation:
For each relation, decide whether or not it is a function.
Answer:
Step-by-step explanation:
Relation 1 is a function
Relation 2 is not a function
Relation 3 is a function
Realation 4 is not a function
PLS HELP 19 POINTS!!!!!!!!
Answer:
Step-by-step explanation:
15. = 2.39
and jus use mathaway lma
Instructions: Find the missing side. Round your answer to the nearest tenth.
24°
х
27
Answer:
x = 60.6 units
Step-by-step explanation:
Hi there!
In this right triangle, we're given the measure of an angle, the side opposite that angle and another side adjacent to that angle (that is not the hypotenuse). In this circumstance, we can use the tangent ratio to help us solve for the missing side:
[tex]tan\theta=\frac{opp}{adj}[/tex]
Plug in the given information:
opp = 27, adj = x, θ = 24
[tex]tan(24)=\frac{27}{x}\\x=\frac{27}{tan(24)} \\x=60.6[/tex]
Therefore, the length of the missing side is 60.6 units when rounded to the nearest tenth.
I hope this helps!
(06.04 MC) Dennis drew the line of best fit on the scatter plot shown below: What is the approximate equation of this line of best fit in slope-intercept form?
Answer:
Step-by-step explanation:
In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:
[tex]m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}[/tex]
Since there's only one choice with that slope, that is the choice you want.
If you have seven dimes how much money do you have
Answer:
70 cents or 0.70 dollars
Step-by-step explanation:
one dime is 10 cents so if you have 7 than you have 70 cents
Thank you so much, my friend
Answer:
Step-by-step explanation:
This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.
The table will look like this before we even fill anything in:
d = r * t
SUV
sedan
Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:
d = r * t
SUV 120
sedan 120
The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:
24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:
d = r * t
SUV 120 = r + .4
sedan 120 = r
They left at the same time, so now the table looks like this:
d = r * t
SUV 120 = r + .4 * t
sedan 120 = r * t
We will put in the time difference of 25 minutes in just a sec.
If d = rt, then the equation for each row is as follows:
SUV: 120 = (r + .4)t
sedan: 120 = rt
Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.
Solving the first equation for time:
sedan: [tex]\frac{120}{r}=t[/tex] That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is
[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:
[tex]\frac{120}{r+.4}+25=t[/tex]
Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:
[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]
I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:
[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to
[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex] So maybe it's not so nice. Let's keep going:
[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:
[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:
[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:
[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.
[tex]25r^2+10r-48=0[/tex]
That factors to
r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:
[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get
r = 72 km/h, choice B.
Wow...what a pain THAT was, right?!
HELP PLEASE 50 POINTS DONT ANSWER IF YOU DONT KNOW
The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.
3/2 = 1.5
The photocopied image is 1.5 times larger than the original.
Side BG on the original is side FG on the copy:
14 x 1.5 = 21 meters
FG = 21 meters
Answer:
FG = 21
Step-by-step explanation:
The ratio is 2:3
2 BC
----- = ----------------
3 FG
2 14
----- = ----------------
3 FG
Using cross products
2FG = 3*14
2FG = 42
Divide by 2
FG = 21
How do you solve this step-by-step?
Answer:
7 1/20OAmalOHopeO
A plan of a house is drawn to a scale of 1:50
a) On the plan, the dining room is 14 cm long and 12.4 cm wide. Find, in metres, the real length and width of the dinning room.
b) The lounge is 8 m long and 6.8 m wide. Find, in centimetres, its length and its width on the plan.
Answer:
I tried out part a) not so sure though. I also think that for part b) u have to convert the m to cm then divide the answers by 50
The real length and width of the dinning room is 7 m and 6.2 m.
The length and width of the lounge in centimeters is 800 cm and 680 cm.
How to convert meters to centimeter and vice versa?To convert the meter to cm, multiply the given meter value by 100 cm.
To convert the measurement from centimeters to meters, divide the number of centimeters by 100 or multiply the number of centimeters by 0.01.
According to the question
A plan of a house is drawn to a scale of 1:50
On the plan, the dining room is 14 cm long and 12.4 cm wide.
In meters:1 m = 100 cm
a. Length of the dinning room = 14 cm = [tex]\frac{14}{100}[/tex] = 0.14 m
Width of the dinning room = 12.4 cm = [tex]\frac{12.4}{100}[/tex] = 0.124 m
Actual length = 0.14 × 50 = 7 m
Actual width = 0.124 × 50 = 6.2 m
Hence, the real length and width of the dinning room is 7 m and 6.2 m
b. Length of lounge = 8 m
Width of lounge = 6.8 m
In centimeters:1 m = 100 cm
Length of lounge (cm) = 8 × 100 = 800 cm
Width of lounge (cm) = 6.8 × 100 = 680 cm
Hence, the length and width of the lounge is 800 cm and 680 cm.
Find out ore information about meters to centimeter here
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Solve the equation 5x + 2(2x -23) = -154
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
5x+2(2x-23)=-1545x+4x-46=-1549x-46=-1549x=-154+469x=-108x=[tex]\sf{\dfrac{-108}{9} }[/tex] x=-12Answer:
x = -12
Step-by-step explanation:
5x + 2(2x - 23) = -154
Distribute;
5x + 4x - 46 = -154
Collect like terms
9x - 46 = -154
Add 46 to both sides;
9x = -108
Divide both sides by 9
x = -12
Shilpa's gym membership includes a one-time fee of $20. She then pays a discounted fee of $5 for each visit. The function that shows her average cost after x visits is: Recall the general form of a rational function: Which statement defines the horizontal asymptote? m < n, so y = 0 is the horizontal asymptote. m = n, so y = am / bn is the horizontal asymptote. m = n, so y = 0 is the horizontal asymptote. m > n, so there is no horizontal asymptote.
Answer:
See explanation
Step-by-step explanation:
Given
[tex]Flat = 20[/tex]
[tex]Visit = 5[/tex]
Required
The function to represent x visits
This is calculated as:
[tex]f(x) = Flat + Visit * x[/tex]
So, we have:
[tex]f(x) = 20 + 5 * x[/tex]
[tex]f(x) = 20 + 5x[/tex]
The second question is incomplete; however, I will explain how to calculate the horizontal asymptote of a rational function.
For polynomials with the same degree (i.e. m = n), the horizontal asymptote is calculated by dividing the coefficients of the highest degrees.
e.g.
[tex]f(x) = \frac{6x^2 + 1}{3x^2 + 4}[/tex] ---the degrees of both is 2
So, the horizontal asymptote is:
[tex]y = 6/3[/tex]
[tex]y =2[/tex]
If the numerator has a higher degree, then there is no horizontal asymptote.
If the denominator has a higher degree, then the horizontal asymptote is:
[tex]y = 0[/tex]
Answer:
First one is B, Second is 5
Step-by-step explanation:
got it right on edge
Concrete is made by mixing screenings, cement and sand in the ratio 3:1:15. How much sand would be needed to make 125 tonnes of concrete?
Step-by-step explanation:
it still remains 125 it doesn't change
HELP ASAP
1.
(8,4)
(-4,2)
(4,-8)
(-8,4)
2.
(6,6)
(12,-12)
(-12,12)
(12,12)
3.
(-2,6)
(-4,12)
(4,12)
(12,-4)
Answer:
A(-2,1)》A1(-8, 4)
B(-3,3)》B1(-12,12)
C(-1,3)》C1(-4,12)
HOPE IT HELPS....
An artisan wants to split his equilateral triangular-shaped piece of glass into four equally sized pieces as part of a window design. Explain to him, with a diagram, how to design an inscribed triangle, and show him that the pieces all have equal area.
The triangle QPR having inscribed triangle STU will allow the artisan to divided his glass piece into four equal triangular pieces.
In order to divide an equilateral triangle into four equal triangular glass pieces, the artisan must;
Take S as the mid-point on PA, T as the mid-point on PR, and U as the mid-point on QR. Thus, S, T, and U are the three mid-points on each side of the equilateral triangle QPR. Now, by joining these mid-points S, T, and U, four equal triangles are made(as shown in the figure).Since the triangle is equilateral,
PQ = QR = RP
Mid-point divides the lines into equal parts. So,
PS = SQ = QU = UR = RT = TP
Thus, it is proved that
ΔPST = ΔSTU = ΔTUR = ΔQSU
Learn more about 'Equilateral Triangle' here:
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Here is Question Two
AB= 9 UNITS
hope it helps you...
Answer:
by Pythagoras theorem
in first
a²+ b² = c²
6² + 9² = c²
36 + 81 = 117
AD = 117
and in second
a² + b² = c²
a² + 6² = 117
a² = 117 - 36
AB² = 81
AB = 9
at a post office always charges a flat one-time fee for any order. One time, Michael sent 35 letters and paid 26 dollars. The next time, he send 18 letters and paid $14.10. How much does the post office charge to send one letter? What is the flat fee?
Answer:
The post office charges $0.7cents to send one letter, and the fee is $1.5
Step-by-step explanation:
Which best explains why all equilateral triangles are similar?
O All equilateral triangles can be mapped onto each other using dilations.
O All equilateral triangles can be mapped onto each other using rigid transformations.
O All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
O All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
Answer:
the correct answer is option 1.
The correct explanation is: All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
What are similar triangles?Those triangles look the same but are different in size.
And in similar triangles,
the corresponding sides are in proportion to each other and the corresponding angles are equal to each other.
In an equilateral triangle, all three sides are congruent, and all three angles are congruent.
Therefore, any equilateral triangle can be transformed into any other equilateral triangle through a combination of translations, rotations, and reflections, without changing the size or shape of the triangle.
Thus, all equilateral triangles are similar, with side lengths in a 1:1 ratio, since they have the same shape but may differ in size.
To learn more about similar triangles;
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Which side lengths form right triangles? Please help
Answer:
Step-by-step explanation:
The total enclosed area is ____ square units. Round to the nearest tenths place (1 decimal place).
Answer: 47.6
Is this right?
Answer:
siis corretoed
Step-by-step explanation:
-2(5x + 1) > 49
Solve for the inequality and enter your solution
Answer:
x < -51/10
General Formulas and Concepts:
Pre-Algebra
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityStep-by-step explanation:
Step 1: Define
Identify
-2(5x + 1) > 49
Step 2: Solve for x
[Division Property of Equality] Divide -2 on both sides: 5x + 1 < -49/2[Subtraction Property of Equality] Subtract 1 on both sides: 5x < -51/2[Division Property of Equality] Divide 5 on both sides: x < -51/10Answer:
x < -51/10
Step-by-step explanation:
-10x -2 > 49
-10x > 51
x < -51/10
Nick works part-time at a bookstore. His pay varies directly with the number of hours worked. In one week, he earned $120 for 8 hours of work.
a) Define two variables for this relation.
b) Describe the rate of change in words.
c) Determine an equation to represent the relation:
d) Use the equation to determine how many hours Nick must work to earn $345
Answer:
23 hoiurs
Step-by-step explanation:
Given data
a. The two variables are
1. Number of hours worked
2. The amount earned
b. The rate is given as
=120/8
=$15 per hour
c. The equation is given as
rate=Amount earned/ number of hours worked
15= 345/hours
make hours subject of the formula we have
hours= 345/15
hours= 23 hours
Hence he must work for 23 hours
Find the H.C.F of these expressions.(2a²+6ac,4a²c+12ac²)
Answer:
Hello,
Answer 8a²c(a+3c) =8a³c+24a²c
Step-by-step explanation:
2a²+6ac=2a(a+3c)
4a²c+12ac²=4ac(a+3c)
H.C.F=2a(a+3c)*4ac=8a²c(a+3c)
Answer:
1st expression:2a×a+2×3×a×c
2nd expression:2×2×a×a+2×2×3×a×c×c
here,
2×a×a+2×3×a×c
2a^a+6ac
E) Si una mujer en Suiza gana 1300 francos, ¿cuánto gana un hombre en el mismo puesto y con la misma categoría profesional? f) Un hombre, por término medio, gana en España un sueldo mensual de 1102 euros netos. ¿Cuánto ganaría si fuese mujer?
Answer:
Para responder esta pregunta, necesitamos utilizar el gráfico que se ve en la imagen de abajo.
En dicho gráfico, se presenta el porcentaje que gana, en promedio, una mujer comparado con lo que ganaría un hombre en el mismo puesto.
a) Si una mujer en Suiza gana 1300 francos, ¿cuánto gana un hombre en el mismo puesto y con la misma categoría profesional?
Viendo el gráfico, podemos ver que en Suiza una mujer gana el 68% de lo que gana un hombre.
Entonces, si un hombre gana una cantidad X, tendremos:
X = 100%
y la mujer gana 1300 francos, que es el 68%, entonces podemos escribir:
X = 100%
1300 francos = 68%
Ahora podemos tomar el cociente entre esas dos ecuaciones, para así obtener:
X/(1300 francos) = (100%/68%)
Ahora podemos resolver esto para X:
X = (100%/68%)*(1300 francos) = 1911.76 francos.
Un hombre en la misma posición ganaría 1911.76 francos.
b) Un hombre, por término medio, gana en España un sueldo mensual de 1102 euros netos. ¿Cuánto ganaría si fuese mujer?
Viendo el gráfico, podemos ver que una mujer en España gana el 67% de lo que ganaría un hombre en la misma posición.
El sueldo del hombre es 1102 euros, y en este caso, esto es el 100%, entonces:
1102 euros = 100%
Y sea X el sueldo de la mujer, el cual sabemos que representa el 67%, entonces escribimos:
X = 67%
Así, tenemos dos ecuaciones:
X = 67%
1102 euros = 100%
Tomando el cociente, obtenemos:
X/(1102 euros) = (67%/100%)
Resolviendo para X obtenemos:
X = (67%/100%)*(1102 euros) = 738.34 euros
Una mujer en la misma posición ganaría 738.34 euros.
need help asap plz
A rectangle ABCD has a width of 3 inches and a length of 7 inches.
Answer the following questions:
a) What is the Perimeter of the rectangle?
b) What is the Perimeter of the new rectangle if you double the width of rectangle ABCD? How did you find it? How many times bigger or smaller did the new Perimeter get? (You can divide the new Perimeter over the old one to find the times of increase/decrease)
c) What is the Perimeter of the new rectangle if you double the width and length of rectangle ABCD? How did you find it? How many times bigger or smaller did the new Perimeter get compared to the perimeter of rectangle ABCD?
d) Now choose a different shape of your liking and give it your own dimensions. Answer questions a), b), c) and d) for the shape you chose.
e) Can you generalize what happens to the Perimeter if you change one of the dimensions of a shape and what happens when you change both dimensions of the shape?
Answer:
I'm sorry but i only know a) so yeah
anyway a) is 20 in.
Step-by-step explanation:
Hope it helps!