Answer:
8 * 8 * 8 * 8 * 8
Step-by-step explanation:
8^5 is basically 8 times itself five times.
Allie rode her bike up a hill at an average speed of 12 feet/second. She then rode back down the hill at an average speed of 60 feet/second. The entire trip took her 2 minutes. What is the total distance she traveled. [Hint: use t = time traveling down the hill]
Answer:
The total distance Allie traveled was 0.81 miles.
Step-by-step explanation:
Since Allie rode her bike up a hill at an average speed of 12 feet / second, and she then rode back down the hill at an average speed of 60 feet / second, and the entire trip took her 2 minutes, to determine what is the total distance she traveled, the following calculation must be performed:
12 + 60 = 72
72 x 60 = 4320
1000 feet = 0.189394 miles
4320 feet = 0.8181818 miles
Therefore, the total distance Allie traveled was 0.81 miles.
Is this a function? Yes or no?
Answer:
NO
Step-by-step explanation:
NO
What is 233,193 rounded to the nearest thousand
Select the correct answer.
Tom gets $12 off a box of chocolates that had an original price of $48. What percentage is the discount
Answer:
25
Step-by-step explanation:
divide 48 by 4 which is 25%
The function in the table is exponential:
True
False
Answer:
true ...
believe it or not there is an exponential sequence that can make that
result
f(x) = [tex]2^{(2(x+2) -1)}[/tex]
x /// 2(x+2) -1
-1 /// 1
0 /// 3
1 /// 5
2 /// 7
[tex]2^{1} = 2\\2^{3} = 8\\\\2^{5} = 32\\\\2^{7 = 128\\\\[/tex]
Step-by-step explanation:
find the slope of a line perpendicular to the line below. y=2x+4
Consider the probability that no less than 37 out of 295 cell phone calls will be disconnected. Choose the best description of the area under the normal curve that would be used to approximate binomial probability.
a. Area to the right of 36.5
b. Area to the right of 37.5
c. Area to the left of 36.5
d. Area to the left of 37.5
e. Area between 36.5 and 37.5
==========================================================
Explanation:
The phrasing "no less than" means the same as "at least".
Saying "at least 37" means 37 is the lowest we can go.
If x is the number of disconnected calls, then [tex]x \ge 37[/tex] and we want to find the probability of this happening (the max being 295).
We could use the binomial distribution to find the answer, but that would require adding 295-37+1 = 259 different values which could get tedious. So we could use the normal approximation to make things relatively straight forward.
Assuming this binomial meets the requirements of the normal approximation, then we'd look under the normal curve for the area to the right of 36.5; which is why the answer is choice A.
Why 36.5 and not 37? This has to do with the continuity correction factor when translating from a discrete distribution (binomial) to a continuous one (normal).
If we used 37, then we'd be missing out on the edge case. So we go a bit beyond 37 to capture 36.5 instead. It's like a fail safe to ensure we do account for that endpoint of 37. It's like adding a buffer or padding.
------------
Side notes:
Choice B would be the answer if we wanted to excluded 37 from the group, ie if we wanted to calculate [tex]P(x > 37)[/tex] instead of [tex]P(x \ge 37)[/tex]. So we're moving in the opposite direction of choice A to avoid that edge case. We go with "right" instead of "left" since this is what the inequality sign says.Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1/3)
Answer:
First term=1
Second term=-x
Third term=[tex]2x^2[/tex]
Fourth term =[tex]-\frac{28}{3!}x^3[/tex]
Step-by-step explanation:
We are given that function
[tex]f(x)=(1+3x)^{-1/3}[/tex]
We have to find the first four non zero terms of the Maclaurin series for the binomial.
Maclaurin series of function f(x) is given by
[tex]f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....[/tex]
[tex]f(0)=(1+3x)^{\frac{-1}{3}}=1[/tex]
[tex]f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}[/tex]
[tex]f'(0)=-1[/tex]
[tex]f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}[/tex]
[tex]f''(0)=4[/tex]
[tex]f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}[/tex]
[tex]f'''(0)=-28[/tex]
Substitute the values we get
[tex](1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...[/tex]
[tex](1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...[/tex]
First term=1
Second term=-x
Third term=[tex]2x^2[/tex]
Fourth term =[tex]-\frac{28}{3!}x^3[/tex]
what is 3 squared ÷ 48 - 6
Answer:
[tex] {3}^{2} \div 48 - 6 \\ 9 \div 48 - 6 \\ = - 5.8125[/tex]
Which is a stretch of an exponential decay function?
f(x) =4/5(5/4)
f(x) = 4/5(4/5)
f(x) =5/4(4/5)
fx) = 5/4(5/4)
Answer:
f(x) = 4/5(5/4)Step-by-step explanation:
correct me if I am wrong
write an equation in slope intercept form for the line with slope 1/4 and y-intercept -6.
Answer:
y=¼x-6
Step-by-step explanation:
y=mx+c
y=¼x+-6
y=¼x-6
Find the distance from the vertices of AABC to the corresponding vertices of the other three triangles, and enter them in the table. For AJKL-
you'll need to use the distance formula da (01 – 12) + (y1 - y2) . Verify your calculations using the tools available in GeoGebra.
Answer:
See explanation
Step-by-step explanation:
The question is incomplete, as the vertices of the triangle are not given.
A general explanation is as follows;
To calculate distance between two points, we use:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]
Take for instance;
[tex]A = (1,4)[/tex]
[tex]B = (3,-2)[/tex]
Distance AB is:
[tex]AB = \sqrt{(1 - 3)^2 + (4 - -2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (4 +2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (6)^2}[/tex]
Evaluate the exponents
[tex]AB = \sqrt{4 + 36}[/tex]
[tex]AB = \sqrt{40}[/tex]
[tex]AB = 6.32[/tex]
Answer:
for edmentum
Step-by-step explanation:
The degree of polynomial 8x^2y^2-5x^2y^2-x^3y is
Answer:
The degree is the highest number exponent....
that is hard to see in your question...
it does appear to be a 2?
Step-by-step explanation:
The table shows the relationship between the number of faculty members and the number of students at a local school. What is the missing value?
Faculty
Students
1
17
2
34
3
51
4
?
17
68
85
102
Answer:
68
Step-by-step explanation:
I did it on my test
The missing value in the table is 68. The correct answer would be option (B).
What is the linear relationship?A linear relationship is a connection that takes the shape of a straight line on a graph between two distinct variables - x and y. When displaying a linear connection using an equation, the value of y is derived from the value of x, indicating their relationship.
The table shows the relationship between the number of faculty members and the number of students at a local school.
Faculty Students
1 17
2 34
3 51
4 ?
The relationship between the number of faculty members and the number of students at the local school is that for every faculty member, there are 17 students.
Therefore, if there are 4 faculty members, we can find the number of students by multiplying 4 by 17, which gives us 68.
Thus, the missing value in the table is B. 68.
Learn about the linear relationship here :
https://brainly.com/question/11663530
#SPJ6
GIVING OUT BRAINLIEST IF GIVEN AN ANSWER WITH THOUROUGH EXPLANATION AND NOT JUST AN ANSWER! THANKS!
During the first part of a 6-hour trip, you travel 240 miles at an average speed of r miles per hour. For the next 72 miles of the trip, you
increase your speed by 10 miles per hour. What were
your two average speeds?
9514 1404 393
Answer:
50 mph for 4.8 hours60 mph for 1.2 hoursStep-by-step explanation:
One way to write the relationship between time, speed, and distance is ...
time = distance/speed
For the first part of the trip, the time is ...
t1 = 240/r
For the second part of the trip, the time is ...
t2 = 72/(r+10)
The total time is 6 hours, so we have ...
t1 +t2 = 6
240/r +72/(r+10) = 6
We can simplify this a bit by multiplying by (r)(r+10)/6 to get ...
40(r+10) +12(r) = r(r+10)
r² -42r -400 = 0 . . . . . . . . subtract the left side and collect terms
(r -50)(r +8) = 0 . . . . . . . . factor
r = 50 . . . . . the positive solution of interest.
The two average speeds were 50 mph and 60 mph.
Help please I don’t get may I please have help with this
Answer:
[tex]1)\:2\frac{2}{3} ft[/tex]
[tex]2)\:4[/tex]
[tex]3)\:\frac{20}{3} ft^{2}[/tex]
[tex]4)\:10\frac{2}{3} ft^{2}[/tex]
------------------------
hope it helps...
have a great day!!
Amy types at an average speed of 38 words per rinute. She has already typed 1,450 words of her final paper, which will be more than 4,000
words. Which inequality can be used to solve for x, the number of minutes it will take Amy to finish typing her paper?
ОА.
38x-1,450 > 76
OB.
38[X+1,450) > 4,000
Ос. .
38x> 4,000
OD.
38x + 1,450 > 4,000
Reset
Next
ntum. All rights reserved.
o
74°F Mostly cloudy
I
о
m
De here to search
Answer: D. 38x + 1,450 > 4,000
Step-by-step explanation:
It has to be greater than 4,000 so A makes no sense
The parentheses are in the wrong place completely changing the meaning for B
C disregards the info we have about how she's already typed 1,450 words
The answer has to be D
Solve the right triangle ABC, with C = 90.00◦ , a = 15.21 cm, b = 17.34 cm. Round to two decimal places.
Answer:
the hypotenuse side, c = 23.1 cmangle A = 41.26 ⁰angle B = 48.74 ⁰Step-by-step explanation:
Given;
first leg of the right triangle, a = 15.21 cm
second leg of the right triangle, b = 17.34 cm
Angle C = 90 ⁰
The missing parameters;
the hypotenuse side = cangle Aangle BUse Pythagoras theorem to calculate the missing side "c", which is the hypotenuse
c² = a² + b²
c² = (15.21)² + (17.34)²
c² = 532.02
c = √532.02
c = 23.1 cm
The missing angle A is calculated as;
[tex]tan(A) = \frac{a}{b} \\\\tan(A) = \frac{15.21}{17.34} \\\\tan(A) = 0.8772 \\\\A = tan^{-1} (0.8772)\\\\A = 41.26^0[/tex]
The missing angle is calculated as;
B = 90⁰ - A
B = 90⁰ - 41.26⁰
B = 48.74⁰
find the slope of the tangent line [tex]m_{tan}[/tex] = f'(a) and then find the equation of the tangent line to f at x = a
f(x) = [tex]\frac{10}{x}[/tex] ; a = 3
9514 1404 393
Answer:
10x +9y = 60
Step-by-step explanation:
The equation for the tangent line at a point is ...
y -f(a) = f'(a)(x -a)
For the given function,
f(x) = 10/x
The derivative is ...
f'(x) = -10/x^2
Then the equation of the tangent line is ...
y -10/3 = -10/9(x -3) . . . . equation of the tangent line (point-slope form)
Clearing fractions, we have ...
9y -30 = -10(x -3) = -10x +30
10x +9y = 60 . . . . . equation in standard form
The ratio of the number of cherry tomatoes in a tossed salad to people served is 7:15. If Waldo wants to serve 105 people, how many cherry tomatoes will Waldo use
Answer: 49 cherry tomatoes.
Step-by-step explanation:
7 x
— = — cross multiply and done.
15 105
Compute the total cost per year of the following pair of expenses. Then complete the sentence: On an annual basis, the first set of expenses is _______% of the second set of expenses.
Vern buys seven lottery tickets each week at a cost of $3 each and spends $900 per year on his textbooks.
Answer:
So 912$ is 58% of 1584 $
Step-by-step explanation:
rotation 90° clockwise about the origin
Answer:
Take the picture you uploaded.
Click the rotate 'button' once.
Change the x to y and y to x on the graph. (axis labels)
Done
J (0, -1)
K(-4,-3)
I ( -4,-1)
What was the original price of the car? Show all work
Answer:
I got u, it is litearly 16540/83.8 = $19737.5
Step-by-step explanation:
its very simple sincen 100-16.2=83.8
change the following basis to Base 10 134 in base seven
Answer:
74 base 10.
Step-by-step explanation:
134 base 7 = 7^2 + 3*7 + 4
= 49 + 21 + 4
= 74 base 10
Using the following image, solve for x.
Answer:
please provide an image.
Please help me in this question
Answer:
3/8
Step-by-step explanation:
the total number of possible results is 4×4=16.
out of these 16 only the results
1 2
1 3
1 4
2 2
2 3
3 2
are desired results. these are 6.
so the probability of a desired result is 6/16 = 3/8
Suppose 42% of the population has myopia. If a random sample of size 442 is selected, what is the probability that the proportion of persons with myopia will differ from the population proportion by less than 3%
Answer:
0.7994 = 79.94% probability that the proportion of persons with myopia will differ from the population proportion by less than 3%.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Suppose 42% of the population has myopia.
This means that [tex]p = 0.42[/tex]
Random sample of size 442 is selected
This means that [tex]n = 442[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.42[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.42*0.58}{442}} = 0.0235[/tex]
What is the probability that the proportion of persons with myopia will differ from the population proportion by less than 3%?
Proportion between 0.42 + 0.03 = 0.45 and 0.42 - 0.03 = 0.39, which is the p-value of Z when X = 0.45 subtracted by the p-value of Z when X = 0.39.
X = 0.45
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.45 - 0.42}{0.0235}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997
X = 0.39
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.39 - 0.42}{0.0235}[/tex]
[tex]Z = -1.28[/tex]
[tex]Z = -1.28[/tex] has a p-value of 0.1003
0.8997 - 0.1003 = 0.7994
0.7994 = 79.94% probability that the proportion of persons with myopia will differ from the population proportion by less than 3%.
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they charged a total of $1125. What was the rate charged per hour by each mechanic if the sum of the two rates was $140 per hour?
Answer:
The first mechanic charged $ 85 an hour, and the second mechanic charged $ 55 an hour.
Step-by-step explanation:
Given that two mechanics worked on a car, and the first mechanic worked for 10 hours, and the second mechanic worked for 5 hours, and together they charged a total of $ 1125, to determine what was the rate charged per hour by each mechanic if the sum of the two rates was $ 140 per hour, the following calculation must be performed:
1125/15 = X
75 = X
80 x 10 + 60 x 5 = 800 + 300 = 1100
85 x 10 + 55 x 5 = 850 + 275 = 1125
Therefore, the first mechanic charged $ 85 an hour, and the second mechanic charged $ 55 an hour.
Private nonprofit four-year colleges charge, on average, $26,208 per year in tuition and fees. The standard deviation is $7,040. Assume the distribution is normal. Let X be the cost for a randomly selected college. Round all answers to 4 decimal places where possible.
a. What is the distribution of X? X ~ N(
26208
Correct,
7040
Correct)
b. Find the probability that a randomly selected Private nonprofit four-year college will cost less than 22,924 per year.
c. Find the 60th percentile for this distribution. $
(Round to the nearest dollar.)
Answer:
#########
Step-by-step explanation:
When 4(9y − 5) = 10(3y + 17) − 40 is solved, the result is:
A=20.
B=25.
C=-10.
D=10.
Answer:
B = 25
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
4(9y - 5) = 10(3y + 17) - 40
Step 2: Solve for y
[Distributive Property] Distribute 4: 36y - 20 = 10(3y + 17) - 40[Distributive Property] Distribute 10: 36y - 20 = 30y + 170 - 40Combine like terms: 36y - 20 = 30y + 130[Subtraction Property of Equality] Subtract 30y on both sides: 6y - 20 = 130[Addition Property of Equality] Add 20 on both sides: 6y = 150[Division Property of Equality] Divide 6 on both sides: y = 25[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{4(9y - 5) = 10(3y + 17) - 40}\\\\\large\textsf{4(9y) + 4(-5) = 10(3y) + 10(17) - 10(40)}\\\\\large\textsf{36y - 20 = 30y + 170 - 40}\\\\\large\textsf{COMBINE the LIKE TERMS}\\\\\large\textsf{36y - 20 = (30 y)+ (170 - 40)}\\\\\large\textsf{36y - 20 = 30y + 130}\\\\\large\textsf{SUBTRACT 30y to BOTH SIDES}\\\\\large\textsf{36y - 20 - 30y = 30y + 130 - 30}}\\\\\large\textsf{Cancel out: 30y - 30y because that gives you 0}\\\\\large\textsf{Keep: 20 - 30y because helps solve for the y-value}[/tex]
[tex]\large\textsf{NEW EQUATION: 6y - 20 = 130}\\\\\large\textsf{ADD 20 to BOTH SIDES}\\\\\large\textsf{6y - 20 + 20 = 130 + 20}\\\\\large\textsf{Cancel out: -20 + 20 because that gives you 0}\\\\\large\textsf{Keep: 130 + 20 because that helps solve for the y-value}\\\\\large\textsf{130 + 20 = \bf 150}\\\\\large\textsf{NEW EQUATION: 6y = 150}\\\\\large\textsf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6y}{6}= \dfrac{150}{6}}\\\\\large\textsf{Cancel: }\mathsf{\dfrac{6}{6}\large\textsf{ because that gives you 1}}[/tex]
[tex]\large\textsf{Keep: }\mathsf{\dfrac{150}{6}}\large\textsf{ because it helps solve for the y-value}\\\\\large\textsf{\bf y = }\mathsf{\dfrac{150}{6}}\\\\\large\textsf{OR }\\\\\mathsf{\dfrac{150}{6} }\large\textsf{ = \bf y}\\\\\\\large\textsf{SIMPLIFY ABOVE AND TOU YOU HAVE YOUR Y-VALUE}\uparrow\\\\\\\\\boxed{\boxed{\large\textsf{\huge\textsf{Answer: \bf y = 25} (Option B.)}}}\huge\checkmark\\\\\\\\\large\text{Good luck on your assignment and enjoy your day!}\\\\\\\\\\\frak{Amphitrite1040:)}[/tex]
