How's The online class?

Answers

Answer 1

Answer:

weak

Step-by-step explanation:

i dont be having fun at all

Answer 2
Ehhhhh it’s okay I guess

Related Questions

what is the value of -2(7-15)/4

Answers

the value is 4 hope it helps
the value is 4 hope this helps

8th Grade Which expression is equivalent to 1/27​

Answers

Answer:

[tex]( \frac{1}{3})^{3} [/tex]

Step-by-step explanation:

There are many expressions that can be equivalent to 1/27.

For example, 2/54, 3/81 etc

But I think the expression you are looking for is

[tex] \frac{1}{27} = \frac{1 \times 1 \times 1}{3 \times 3 \times 3} = \frac{ {1}^{3} }{ {3}^{3} } = ( \frac{1}{3} )^{3} [/tex]

Hope this is helpful

Consider the following game: You reach into a jar of money, and select a single bill at random to keep. There are 9 five-dollar bills, 5 ten-dollar bills, and 3 twenty-dollar bills in the jar. What should the cost of this game be in order for the game to be fair

Answers

Answer:

[tex]E(x)=\$9.118[/tex]

Step-by-step explanation:

From the question we are told that:

Available bills

 [tex]\$5=N0 9\\\\\$10=N0 5[/tex]

 [tex]\$20=N0 3[/tex]

Therefore

Total Bills

 [tex]n=5+9+3[/tex]

 [tex]n=17[/tex]

Probability of selecting each bill

 [tex]For\$5[/tex]

 [tex]P(\$5)=\frac{9}{17}[/tex]

 [tex]For\$10[/tex]

 [tex]P(\$10)=\frac{5}{17}[/tex]

 [tex]For\$20[/tex]

 [tex]P(\$20)=\frac{3}{17}[/tex]

Generally the equation for Expected winning is mathematically given by

 [tex]E(x)=\sum(X)*P(X)[/tex]

 [tex]E(x)=5*\frac{9}{17}+10*\frac{5}{17}+20*\frac{3}{17}[/tex]

 [tex]E(x)=\$9.118[/tex]

Solve the system, or show that it has no solution. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, enter the general solution in terms of x, where x is any real number.)
20x − 80y = 100
−14x + 56y = −70
(x, y) =

Answers

Answer:

The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]

Step-by-step explanation:

From the first equation:

[tex]20x - 80y = 100[/tex]

[tex]20x = 100 + 80y[/tex]

[tex]x = \frac{100 + 80y}{20}[/tex]

[tex]x = 5 + 4y[/tex]

Replacing on the second equation:

[tex]-14x + 56y = -70[/tex]

[tex]-14(5 + 4y) + 56y = -70[/tex]

[tex]-70 - 56y + 56y = -70[/tex]

[tex]0 = 0[/tex]

This means that the system has an infinite number of solutions, considering:

[tex]x = 5 + 4y[/tex]

[tex]4y = x - 5[/tex]

[tex]y = \frac{x - 5}{4}[/tex]

The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]

2(-x-4)+3=-7x+5+5x

Pls help!!!!!!!!

Answers

4 I hope this helps you

1 Simplify

7
x
+
5
+
5
x
−7x+5+5x to

2
x
+
5
−2x+5.
2
(

x

4
)
+
3
=

2
x
+
5
2(−x−4)+3=−2x+5

2 Expand.

2
x

8
+
3
=

2
x
+
5
−2x−8+3=−2x+5

3 Simplify

2
x

8
+
3
−2x−8+3 to

2
x

5
−2x−5.

2
x

5
=

2
x
+
5
−2x−5=−2x+5

4 Cancel

2
x
−2x on both sides.

5
=
5
−5=5

5 Since

5
=
5
−5=5 is false, there is no solution.
No Solution

Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour. What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ? (Hint: Think exponential.)
a) e e-2 = 0.1353
b) e-13/15 = 0.4204
c) e-1 = 0.3679
d) 1-2-1 = 0.6321

Answers

Answer:

0.4204 probability, option b.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour

13 arrivals during an hour, which means that the mean time between arrivals, in minutes is of [tex]\mu = \frac{13}{60} = 0.2167[/tex]

What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ?

This is P(X > 4). So

[tex]P(X > 4) = e^{-0.2167*4} = 0.4204[/tex]

So the correct answer is given by option b.

A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the speed of the dog to catch with the cat in 1 minute?

Answers

Answer:

[tex]3.8\:\mathrm{m/s}[/tex]

Step-by-step explanation:

Use the formula [tex]d=rt[/tex] (distance is equal to rate/speed multiplied by time) to solve this problem.

We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to [tex]d=3\cdot 60=180\text{ meters}[/tex].

To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover [tex]180+48=228[/tex] meters in one minute.

Therefore, we have:

[tex]228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}[/tex]

Answer:

[tex] \boxed{3.8 \: m/s} [/tex]

Explanation

The first step is to set the speed and the distance equal to the unknown rate of the dog.

3 m/s + 48 m = x m/60s.

Then substitute 60s in for both rates to get distance.

180m + 48m = x m/60

228m = 60x m

÷60 ÷60

3.8m = x m/s.

x = 3.8m/s





Which expression has a value of 15 when it equals
2
49-57
3--5
61-28
28
19

Answers

Answer:

it is 61-28 but I not sure u can scan for any application to make sure u get it ur answer thx for

Here are the test scores for 8 students in Mr. M's class. 87, 55, 96, 38, 83, 64, 44, 81. What is the percentage of these test scores that are less than 84?

Answers

Answer:

75%

Step-by-step explanation:

Given that the score of 8 students in Mr. M's class are 87, 55, 96, 38, 83, 64, 44, 81, the scores less than 84 are 55, 38, 83, 64, 44, 81.

These means that 6 student had scores less that 84 of the 8 students hence the percentage of these test scores that are less than 84

= 6/8 * 100%

= 75%

This means that 75% of the students had scores less than 84

Which rectangle has an area of 18 square units? On a coordinate plane, a rectangle is 2 units high and 7 units wide. On a coordinate plane, a rectangle is 2 units high and 6 units wide. On a coordinate plane, a rectangle is 3 units high and 5 units wide. On a coordinate plane, a rectangle is 3 units high and 6 units wide.

Answers

Answer:

On a coordinate plane, a rectangle is 3 units high and 6 units wide.

Answer:

option "B"

You Welcome

Step-by-step explanation:

100
During a basketball practice, Steph Curry made 234 three point shots in 45 minutes.
In the same practice, his teammate Klay Thompson made 168 three point shots in 34 minutes.
1) Find the unit rates of both players of shots made per each minute.
2) Which player was making more shots at a higher rate?

Answers

Answer:

it was very nice step so they wine so anther bed boys decided to take his legs and round and round to good boys

Is this a function? Yes or no?

Answers

Answer:

NO

Step-by-step explanation:

NO

Suppose f(x,y,z) = x2 + y2 + z2 and W is the solid cylinder with height 7 and base radius 2 that is centered about the z-axis with its base at z = −2. Enter θ as theta.

A) As an iterated integral, ∭WfdV = ∫BA∫DC∫FE dzdrdθ with limits of integration.

B) Evaluate the integral.

Answers

In cylindrical coordinates, W is the set of points

W = {(r, θ, z) : 0 ≤ r ≤ 2 and 0 ≤ θ ≤ 2π and -2 ≤ z ≤ 5}

(A) Then the integral of f(x, y, z) over W is

[tex]\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

(B)

[tex]\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}[/tex]

From the table below, determine whether the data shows an exponential function. Explain why or why not.
x
3
2
1
–1
y
8
2
0.5
0.125
a. No; the domain values are at regular intervals and the range values have a common factor 0.25. b. No; the domain values are not at regular intervals although the range values have a common factor. c. Yes; the domain values are at regular intervals and the range values have a common factor 4. d. Yes; the domain values are at regular intervals and the range values have a common factor 0.25.

Answers

9514 1404 393

Answer:

  b. No; the domain values are not at regular intervals although the range values have a common factor.

Step-by-step explanation:

The differences between x-values are ...

  -1, -1, -1, -2 . . . . not a constant difference

The ratios of y-values are ...

  2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference

The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.

You need
1
1
4
feet of string to make 20 holiday ornaments.

To make 14 holiday ornaments, you will need
feet of string.

Answers

Answer:

79.8

Step-by-step explanation:

math

Ms. Ambrose paid $10 for 1.25 pounds of almonds. How much did the almonds cost per pound???

Answers

I think it’s 8 dollars because 10/1.25 is 8

A radio transmission tower is 180 feet high. How long should a guy wire be if it is to be attached to the tower 11 feet from the top and is to make an angle of 45° with the ground?​

Answers

Answer:

Step-by-step explanation:

Question 2
A force F=5i+3j-2k is applied to move a block of cement from A(0,1,1) to B(4.-1,3).
Determine the work done by the force.

Answers

The work is simply the dot product of the force and displacement (which I assume are given in Newtons and meters, respectively):

W = F • d

W = (5i + 3j - 2k) N • ((4i - j + 3k) m - (j + k) m)

W = (5i + 3j - 2k) • (4i - 2j + 2k) Nm

W = (20 - 6 - 4) Nm

W = 10 J

Q.No.4. Ali is hiking on the hill, whose height is given by f(u,v)=n^2 e^((u+n)/(v+n)). Currently, he is positioned at point (3,5). Find the direction at which he moves down the hills quickly. (5 points) Where n is the product of first and second digit of your arid number e.g. 19-arid-435 take n=4x3=12

Answers

Answer:

///////

Step-by-step explanation:

In 2013, the Public Religion Research Institute conducted a survey of 1,033 adults, 18 years of age or older, in the continental United States. One of the questions on their survey was as follows:

Answers

Answer:

Probability[Number of people from church] = 0.26 (Approx.)

Step-by-step explanation:

Given:

Total number of adult in survey = 1,033

Missing information:

Number of people from church = 269

Find:

Probability[Number of people from church]

Computation:

Probability of an event = Number of favourable outcomes / Number of total outcomes

Probability[Number of people from church] = Number of people from church / Total number of adult in survey

Probability[Number of people from church] = 269 / 1,033

Probability[Number of people from church] = 0.2604

Probability[Number of people from church] = 0.26 (Approx.)

A three-dimensional object's measurement(s) include which of the following?
Check all that apply.
A. Width
B. Length
C. Height
D. None of these

Answers

A B C are the right answers

Answer:

A.

B.

C.

Step-by-step explanation:

all three are used in 3 dimensional objects hence the name 3 dimensions.

Need the answers from a - e

Answers

Answer:

10

Step-by-step explanation:

Sorry. I needed to answer this question to get access.

6. Aerial photography is to be taken of a tract of land that is 8 x 8 mi2. Flying height will be 4000 ft above average terrain, and the camera has focal length of 6 inches. If the focal plane opening is 9 x 9 in., and minimum side overlap is 30%, how many flight lines will be needed to cover the tract for the given data

Answers

Answer:

the number of flight lines needed is approximately 72

Step-by-step explanation:

Given the data in the question;

Aerial photography is to be taken of a tract of land that is 8 x 8 mi²

L × B = 8 x 8 mi²

Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in

focal length f = 6 in

[tex]l[/tex] × b = 9 × 9 in²

side overlap = 30% = 0.3

meaning remaining side overlap = 100% - 30% = 70% = 0.7

{ not end to end overlap }

we take 100% { remaining overlap }

[tex]l[/tex]' = 9 × 100% = 9 in

b' = 9 × 70% = 6.3 in

Now the scale will be;

Scale = f/H

we substitute

Scale = 6 in /  48000 in = 1 / 8000

so our scale is; 1 : 8000

⇒ 1 in = 8000 in

⇒ 1 in = (8000 / 63360)mi

⇒ 1 in = 0.126 mi

so since

L × B = 8 x 8 mi²

[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi

b' = ( 6.3 × 0.126 mi ) = 0.7938 mi

Now we get the flight lines;

N = ( L × B ) / ( [tex]l[/tex]' × b' )

we substitute

N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )

N = 64 / 0.9001692

N = 71.0977 ≈ 72

Therefore, the number of flight lines needed is approximately 72

PLEASE HELP I WILL MARK YOUR ANSWER AS BRAINLIEST PLEASE BE CORRECT BEFORE ANSWERING

LOOK AT THE BOTTOM

Answers

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

The figure must be flipped top-to-bottom, so the line of reflection must be a horizontal line. Point B must be reflected to itself, so it is on the line of reflection. That means the line of reflection is y = 2.

__

You can draw the line of reflection using any two points that have y-coordinates of 2, for example, (0, 2) and (2, 2).

Please help, been stuck on this for a while.

Answers

Answer:its blurry

Step-by-step explanation:

cant see it

Answer:

x = 34.6

Step-by-step explanation:

[tex]x\:=\:\frac{\left(20\cdot \:sin\left(60\right)\right)}{sin\left(30\right)}[/tex]

How many orders are possible to view 6 videos from a stack of 8 videos?

Answers

Answer:

28

Step-by-step explanation:

We know that ,

n C r = n! / ( n - r)! r!

8! / ( 8 - 6)! 6!

8! / 2! × 6!

7 × 8 / 2 × 1

28

Find the product of the given polynomials. (5 x +8 -6x) (4+ 2x 87)
a. -2x2+19x -24
b-2x2 -24x +19
c- 2x2 +19x +24
d- 2x2 +13x -24

Answers

Answer:

[tex]- 2x^2 +19x -24[/tex]

Step-by-step explanation:

Given

[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]

Required

Evaluate

We have:

[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]

Collect like terms

[tex](5x - 6x+ 8 )(4 - 7+ 2x )[/tex]

[tex](- x+ 8 )(- 3+ 2x )[/tex]

Expand

[tex]3x - 2x^2 -24 + 16x[/tex]

Rewrite as:

[tex]- 2x^2 + 3x+ 16x -24[/tex]

[tex]- 2x^2 +19x -24[/tex]

Give at least four different symbols that have been used to represent specific statistical measures. Describe what measure each represents.

Answers

can you show a picture of the symbols

Find the expected value of the winnings
from a game that has the following
payout probability distribution:
Payout($) 2 46 8 10
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]

Answers

The expected payout is

2 × 0.5 + 4 × 0.2 + 6 × 0.15 + 8 × 0.1 + 10 × 0.05

= 1 + 0.8 + 0.9 + 0.8 + 0.5

= 4

The expected value of the winnings from this game is $3.90.

What is probability?

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

To find the expected value of the winnings, we multiply each possible payout by its probability and then sum these products.

So,

Expected Value = (2 x 0.5) + (4 x 0.2) + (6 x 0.15) + (8 x 0.1) + (10 x 0.05)

Expected Value = 1 + 0.8 + 0.9 + 0.8 + 0.5

Expected Value = 3.9

Therefore,

The expected value of the winnings from this game is $3.90.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ7

Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Answers

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

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