Answer:
ಠ_ಠ
Step-by-step explanation:
Johnny tripled his baseball card collection. Then he added 6 more cards to the collection. Now he has 24 cards. How many cards did he start with?
9514 1404 393
Answer:
6
Step-by-step explanation:
Work backward.
If he has 24 after adding 6, he had 18 before that addition.
If he had 18 after tripling his collection, he had 18/3 = 6 cards to start with.
__
Note that this is the same process you would use if you started with an equation.
3c +6 = 24 . . . . where c is the number of cards Johnny started with
3c = 24 -6 = 18 . . . . . subtract 6 from the final number
c = 18/3 = 6 . . . . . . . . divide the tripled value by 3 to see the original value
Johnny started with 6 cards.
A small insurance company has determined that on average it receives 6 property damage claims per day. P left parenthesis X equals k right parenthesis space equals space fraction numerator lambda to the power of k e to the power of negative lambda end exponent over denominator k factorial end fraction k space i s space t h e space g i v e n space n u m b e r space o f space e v e n t space o c c u r r e n c e s lambda space i s space t h e space a v e r a g e space r a t e space o f space e v e n t space o c c u r r e n c e s What is the probability that the company will receive 7 property damage claims on a randomly selected day? Answer choices are rounded to the hundredths place.
Answer:
The probability that the company will receive 7 property damage claims on a randomly selected day is 0.137
Step-by-step explanation:
Given,
[tex]\lambda=6[/tex],
The probability mass function of Poisson distribution is used for evaluating the probability of the company will receive 7 property damages claims on any selected day is,
[tex]\begin{aligned}P(X=K)&=e^{-6} \times \dfrac{6^7}{7!}\\&=0.002478\times\dfrac{279936}{5040}\\&=\dfrac{693.89136}{5040}\\P(X=7)&=0.1365927874\\P(X=7)&=0.137\; (\rm{rounded \;off})\end{aligned}[/tex]
To learn more about this, please refer to the below link:
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1) Prepare a post merger financial position for METRO using the pooling of interest method.
Answer:
Metro and Medec
METRO
Post-merger Financial Position, using the pooling of interest method:
Pre-merger Financial Positions:
Metro (RM ‘000)
Assets
Current assets 120
Fixed assets 830
Total assets 950
Liabilities and Equities
Current liabilities 40
Long term debt 200
Common stock (RM1 par) 480
Capital surplus 120
Retained earnings 110
Total liabilities and equity 950
Earnings available to
common stockholders 230
Common Dividends 150
Addition to Retained Earnings 80
Step-by-step explanation:
Pre-merger Financial Positions:
Metro (RM ‘000) Medec(RM ‘000)
Assets
Current assets 50 70
Fixed assets 650 180
Total assets 700 250
Liabilities and Equities
Current liabilities 30 10
Long term debt 140 60
Common stock (RM1 par) 400 80
Capital surplus 50 70
Retained earnings 80 30
Total liabilities and equity 700 250
Earnings available to
common stockholders 100 130
Common Dividends 50 100
Addition to Retained Earnings 50 30
Exchange ratio = 1:2
Which histogram represents the following data set?
31, 67, 8, 37, 12, 87, 14, 34, 105, 57, 42, 8, 16, 54, 17, 20, 72, 23,
27, 63, 24, 52, 14, 44, 27, 5, 28, 22, 33, 15, 6, 36, 41, 21, 46
Answer:
Option A
Step-by-step explanation:
Histogram shows the range of data on the x-axis while the frequency of occurrence is on the y-axis.
We have the following ranges from the Histogram ;
0 to 11
11 to 22
22 to 33
33 to 44
44 to 55
55 to 66
66 to 77
77 to 88
88 to 99
99 to 110
From the given set of data, the frequency according to the range is as follows;
0 to 11; 4
11 to 22; 8
22 to 33; 7
33 to 44; 6
44 to 55; 4
55 to 66; 2
66 to 77; 2
77 to 88; 1
88 to 99; 0
99 to 110; 1
The only Histogram that corresponds to these frequency is option A
What is the value of x
Answer:
52/3
Step-by-step explanation:
Use basic Thales therom,
[tex]\frac{3x}{4x}=\frac{3x+7}{5x-8}\\\\\frac{3}{4}=\frac{3x+7}{5x-8}\\[/tex]
Cross multiply,
3*(5x-8)=4*(3x+7)
3*5x - 3*8 = 4*3x + 4*7
15x - 24 = 12x +28
Add 24 to both sides
15x = 12x + 28 + 24
15x = 12x + 52
Subtract 12x from both sides
15x-12x =52
3x = 52
Divide both sides by 3
x = 52/3
PLEASE ANSWER ASAP!!! FULL ANSWERS ONLY!!!!!! WILL GIVE BRAINLIEST!!!!!!!!!
Two cyclists, 68 miles apart, start riding toward each other at the same time. One cycles 3 miles per hour faster than the other, and they meet after 4 hours of riding.
a. Write an equation using the information as it is given above that can be solved to answer this problem.
Use the variable r to represent the speed of the slower cyclist. b. What are the speeds of the two cyclists? _______________
Answer:
4r + 4(r + 3) = 68
r = 7 miles per hour
r + 3 = 10 miles per hour
Step-by-step explanation:
distance = rate * time
a)
4r + 4(r + 3) = 68
Distribute
4r + 4r + 12 = 68
8r + 12 = 68
8r = 56
r = 7 miles per hour
r + 3 = 10 miles per hour
Please look at the included picture, show me your work and please include a good explanation. It would really help me out here.
These are indeed equivalent, and this identity is one of DeMorgan's laws.
The 6th column is the negation of the 5th column. For example, the first row says
not p or q
is true (T), so the negation would be false (F). The 5th column reads {T, F, T, T}, so the next column should be {F, T, F, F}.
Then in the 7th/last column, you are checking the truth value of the statement
p and not q
For example, in the first row, both p and q are true (T). This means (not q) is false, so (p and not q) is false (F). The last column should end up reading {F, T, F, F}, same as the previous column.
Find the angle between the vectors ????=????+???? and ????=−????+????. (Give an exact answer. Use symbolic notation and fractions where needed.)
Answer:
The angle between them is 60 degrees
Step-by-step explanation:
Given
[tex]a = 2i + j -3k[/tex]
[tex]b = 3i - 2j -k[/tex]
Required
The angle between them
The cosine of the angle between them is:
[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]
First, calculate a.b
[tex]a \cdot b =(2i + j -3k) \cdot (3i - 2j -k)[/tex]
Multiply the coefficients of like terms
[tex]a \cdot b =2 * 3 - 1 * 2 - 3 * -1[/tex]
[tex]a \cdot b =7[/tex]
Next, calculate |a| and |b|
[tex]|a| = \sqrt{2^2 + 1^2 + (-3)^2[/tex]
[tex]|a| = \sqrt{14[/tex]
[tex]|b| = \sqrt{3^2 + (-2)^2 + (-1)^2}[/tex]
[tex]|b| = \sqrt{14}[/tex]
Recall that:
[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]
This gives:
[tex]\cos(\theta) = \frac{7}{\sqrt{14} * \sqrt{14}}[/tex]
[tex]\cos(\theta) = \frac{7}{14}[/tex]
[tex]\cos(\theta) = 0.5[/tex]
Take arccos of both sides
[tex]\theta =\cos^{-1}(0.5)[/tex]
[tex]\theta =60^o[/tex]
Using the graph below, if f(x) = 4, find x.
Can you help me answer this question? Screenshot is added.
9514 1404 393
Answer:
(c)
Step-by-step explanation:
[tex]\displaystyle\sqrt[3]{xy^5}\sqrt[3]{x^7y^{17}}=\sqrt[3]{x^{1+7}y^{5+17}}=\sqrt[3]{x^6x^2y^{21}y}=\sqrt[3]{x^6y^{21}}\sqrt[3]{x^2y}\\\\=\boxed{x^2y^7\sqrt[3]{x^2y}}[/tex]
What is equal to 30- 6v - 13w
Công ty T vừa đưa vào sản xuất một loại sản phẩm mới với định mức giờ máy là 2 giờ/sản phẩm. Tài liệu về sản phẩm trong năm như sau (đồng):
Chi phí nguyên vật liệu trực tiếp/sp
30.000
Chi phí nhân công trực tiếp/sp
27.000
Chi phí sản xuất chung/sp
12.000(25% là biến phí)
Bao bì/sp (ở khâu SX)
5.000
Lương quản lý và bán hàng
83.300.000
Quảng cáo
34.700.000
Chí phí khác bằng tiền
30.000.000
Vốn đầu tư bình quân
1.200 triệu
ROI mong muốn
16%
Tổng số giờ máy hoạt động cho sản xuất
40.000 giờ
Yêu cầu:
1. Hãy định giá bán theo biến phí?
2. Để sản xuất sp mới này, Cty tự chế tạo 1 chi tiết để lắp vào sản phẩm với thông tin như sau:
- Biến phí sản xuất của Chi Tiết = 40% biến phí sp
- KH TSCĐ cho việc sản xuất chi tiết là 42.000.000đ
- Chi phí quản lý chung phân bổ cho việc sản xuất chi tiết là 19.040.000đ.
Có một doanh nghiệp khác đến chào hàng chi tiết với giá chỉ bằng 70% so với giá thành cty tự sản xuất và đảm bảo đủ số lượng, chất lượng theo yêu cầu. Các phương tiện sản xuất chi tiết có thể cho thuê 13.000.000đ/năm. Cty nên tự sản xuất hay mua ngoài?
Answer:
??????
Step-by-step explanation:
What do you know to be true about the values of p and ?
p"
q
601
454
45
A. p> 9
B. p<9
C. p= 9
D. Can't be determined
find 9 rational no. between 8/7 and 17/10.
Answer:
[tex]\dfrac{81}{70},\dfrac{82}{70},\dfrac{83}{70},\dfrac{84}{70},\dfrac{85}{70},\dfrac{86}{70},\dfrac{87}{70},\dfrac{88}{70},\dfrac{89}{70}[/tex]
Step-by-step explanation:
We need to find 9 rational number between [tex]\dfrac{8}{7}\ \text{and}\ \dfrac{17}{10}[/tex]
We make the denominators of both fractions same. So,
[tex]\dfrac{8}{7}\times \dfrac{10}{10}=\dfrac{80}{70}[/tex]
and
[tex]\dfrac{17}{10}\times \dfrac{7}{7}=\dfrac{119}{70}[/tex]
The rational number are:
[tex]\dfrac{81}{70},\dfrac{82}{70},\dfrac{83}{70},\dfrac{84}{70},\dfrac{85}{70},\dfrac{86}{70},\dfrac{87}{70},\dfrac{88}{70},\dfrac{89}{70}[/tex]
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled
Answer:
6546 students would need to be sampled.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.
This means that [tex]n = 200, \pi = \frac{118}{200} = 0.59[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?
n students would need to be sampled, and n is found when M = 0.01. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}[/tex]
[tex]0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}[/tex]
[tex]\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2[/tex]
[tex]n = 6545.9[/tex]
Rounding up:
6546 students would need to be sampled.
Find the solution set.
The solution set for 5v2 – 125 = 0
Answer:
5v2 – 125 = 0
5(v2−25)=0
v2−25=0
a couple more steps and the answer is...
v=-5
If the angles (4x + 4)° and (6x – 4)° are the supplementary angles, find the value of x.
Answer:
18
Step-by-step explanation:
Supplementary angles means sum of angles is 180.
4x + 4 + 6x - 4 = 180
4x + 6x + 4 - 4 = 180
10x = 180
x = 180 / 10
x = 18
Answer:
x=18 degree
Step-by-step explanation:
If they are supplementary angles, then their sum = 180 degree
4x+4 + 6x-4 =180
4x+6x + 4-4 = 180
10x = 180
x=180/10
x=18
Lolz please help me I would gladly appreciate it
Pentagon has sum of 540°
Plz help I’ll mark you
Answer:
A 1/2
Step-by-step explanation:
Ratio of short length to hypotenuse
= cos60
= 1/2
insert a digit in place of each ... to make a number that is divisible by 6
4 . . . 6
Answer:
2
Step-by-step explanation:
Circle Theorems 1! need help
Answer:
45°
Step-by-step explanation:
<lmk=90°
angles in a triangle add up to 180
45+90+<o=180
<o=180-135
<o=45
Answer:
∠ O = 45°
Step-by-step explanation:
The angle between the tangent and the radius at the point of contact is 90°
The sum of the 3 angles in Δ OML is 180° , then
∠ O = 180° - (90 + 45)° = 180° - 135° = 45°
f(x) = 4x3 + 7x2 – 2x – 1
g(x) = 4x – 2
Find (f - g)(x).
please help
9514 1404 393
Answer:
(f-g)(x) = 4x^3 +7x^2 -6x +1
Step-by-step explanation:
(f -g)(x) = f(x) -g(x)
= (4x^3 +7x^2 -2x -1) -(4x -2)
= 4x^3 +7x^2 +(-2-4)x +(-1+2)
(f -g)(x) = 4x^3 +7x^2 -6x +1
Coliform bacteria are randomly distributed in a river at an average concentration of 1 per 20cc of water. What is the variance of the number of Coliform bacteria in a sample of 40cc of water
Answer:
[tex]Var = 1.9[/tex]
Step-by-step explanation:
Given
[tex]p = \frac{1}{20}[/tex] i.e. 1 per 20cc of water
[tex]n = 40[/tex] -- sample size
Required
The variance
This is calculated using:
[tex]Var = np(1 - p)[/tex]
So, we have:
[tex]Var = 40 * \frac{1}{20} * (1 - \frac{1}{20})[/tex]
[tex]Var = 40 * \frac{1}{20} * \frac{19}{20}[/tex]
[tex]Var = 2 * \frac{19}{20}[/tex]
[tex]Var = \frac{38}{20}[/tex]
[tex]Var = 1.9[/tex]
14. The Elizabeth Tower is 320 feet tall. At what time or times during your ride on the London Eye are you at the same height as the top of the tower? Show your work. (4 points: 2 points for finding the correct time(s), 2 points for work shown)
Answer:
Ok so on a clock there is 12 numbers where 12 is on top so at 12 am and 12 pm noon and midnight you will be at the top of the clock
Hope This Helps!!!
During the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.
To determine the time(s) during the ride on the London Eye when you are at the same height as the top of the Elizabeth Tower (commonly known as Big Ben), we need to consider the height of the London Eye and its rotational motion.
Given that the Elizabeth Tower is 320 feet tall, we need to find the position of the London Eye when its height aligns with the top of the tower.
The London Eye has a height of 443 feet, and it completes one full rotation in approximately 30 minutes (or 1800 seconds). This means that it moves at a constant angular velocity of 360 degrees per 1800 seconds.
To find the time(s) when the heights align, we can set up a proportion:
(Height of the Elizabeth Tower) / (Height of the London Eye) = (Angle covered by the London Eye) / 360 degrees
Substituting the given values:
320 / 443 = (Time to align) / 1800
Simplifying the equation:
(Time to align) = (320 / 443) * 1800
Calculating the value:
(Time to align) ≈ 1303.16 seconds
Converting the time to minutes and seconds:
(Time to align) ≈ 21 minutes and 43.16 seconds
Therefore, during the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.
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Pierre Martina is comparing the cost of credit to the cash price of an item. If Pierre makes a down payment of $70 and pays $34 a
month for 24 months, how much more will that amount be than the cash price of $695? (Input the amount as a positive value.)
Amount of difference
Answer:
$191
Step-by-step explanation:
Find how much she will be paying over the 24 months:
34(24)
= 816
Add the down payment to this:
816 + 70
= 886
Find the difference between this and 695:
886 - 695
= 191
So, the difference will be $191 more
What is the measure of angle WZY? 54.5° 71° 125.5° 180°
Answer:
71
Step-by-step explanation:
The measure of angle WXY will be thee ame as the measure of the intercepted arc, 109°.
W and Y are both tangent to the circle; this means angle XWZ and angle XYZ are both 90°.
Every quadrilateral has a total measure of 360°; to find the measure of WZY, we subtract:
360-90-90-109 = 71°
The measure of angle WZY (∠WZY) is; 71°
What is the measure of the angle?From the attached image, we can say that the measure of ∠WXY will be the same as the measure of the intercepted arc, 109°.
Now, W and Y are both tangent to the circle and this means that ∠XWZ and ∠XYZ are both equal to 90°.
Now, every quadrilateral has a total internal sum of angles as 360°.
Thus, ∠WZY is gotten from;
∠WZY = 360 - (90 + 90 + 109)
∠WZY = 71°
Read more about angles in cyclic quadrilaterals at; https://brainly.com/question/24368895
The number of hurricanes that will hit a certain house in the next ten years is Poisson distributed with mean 4. Each hurricane results in a loss that is exponentially distributed with mean 1000. Losses are mutually independent and independent of the number of hurricanes. Calculate
Answer:
The variance of total loss is 8000000
Step-by-step explanation:
Let
[tex]X \to[/tex] Number of hurricane
Poisson [tex]E(X) = 4[/tex]
[tex]Y \to[/tex] Loss in each hurricane
Exponential [tex]E(Y) = 1000[/tex]
[tex]T \to[/tex] Total Loss
Required
The variance of the total loss
This is calculated as:
[tex]Var(T) = Var(E(T|X)) + E(Var(T|X))[/tex]
Where:
[tex]E(T|X) \to[/tex] Expected total loss given X hurricanes
And it is calculated as:
[tex]E(T|X) = E(Y) *N[/tex] --- Expected Loss in each hurricane * number of loss
[tex]Var(T|X) \to[/tex] Variance of total loss given X hurricanes
And it is calculated as:
[tex]Var(T|X) = Var(Y) * N[/tex] ---- --- Variance of loss in each hurricane * number of loss
So, we have:
[tex]Var(T) = Var(E(T|X)) + E(Var(T|X))[/tex]
[tex]Var(T) = Var(E(Y) * N) + E(Var(Y) * N)[/tex]
For exponential distribution;
[tex]Var(Y) = E(Y)^2[/tex]
So, we have:
[tex]Var(T) = Var(E(Y) * X) + E(E(Y)^2 * X)[/tex]
Substitute values
[tex]Var(T) = Var(1000 * X) + E(1000^2 * X)[/tex]
Simplify:
[tex]Var(T) = Var(1000 * X) + 1000^2E(X)[/tex]
Using variance formula, we have:
[tex]Var(T) = 1000^2Var(X) + 1000^2E(X)[/tex]
For poission distribution:
[tex]Var(X) = E(X)[/tex]
So, we have:
[tex]Var(X) = E(X) = 4[/tex]
The expression becomes:
[tex]Var(T) = 1000^2*4 + 1000^2*4[/tex]
[tex]Var(T) = 1000000*4 + 1000000*4[/tex]
[tex]Var(T) = 4000000 + 4000000[/tex]
[tex]Var(T) = 8000000[/tex]
A box contains 5 white balls, 3 black balls, and 2 red balls.A-What is the probability of drawing a white ball?B- How many white balls must be added to the box so that the probability of drawing a white ball is 3/4?C-How many black balls must be added to the original assortment so that the probability of drawing a white ball is 1/4?
Answer:
[tex](a)\ P(White) = \frac{1}{2}[/tex]
(b) 10 additional white balls
(c) 10 additional black balls
Step-by-step explanation:
Given
[tex]White = 5[/tex]
[tex]Black =3[/tex]
[tex]Red = 2[/tex]
Solving (a): P(White)
This is calculated as:
[tex]P(White) = \frac{White}{Total}[/tex]
[tex]P(White) = \frac{5}{5+3+2}[/tex]
[tex]P(White) = \frac{5}{10}[/tex]
[tex]P(White) = \frac{1}{2}[/tex]
Solving (b): Additional white balls, if [tex]P(White) = \frac{3}{4}[/tex]
Let the additional white balls be x
So:
[tex]P(White) = \frac{White+x}{Total+x}[/tex]
This gives:
[tex]\frac{3}{4} = \frac{5+x}{10+x}[/tex]
Cross multiply
[tex]30+3x = 20 + 4x[/tex]
Collect like terms
[tex]4x - 3x = 30 - 20[/tex]
[tex]x = 10[/tex]
Hence, 10 additional white balls must be added
Solving (c): Additional black balls, if [tex]P(White) = \frac{1}{4}[/tex]
Let the additional black balls be x
So:
[tex]P(White) = \frac{White}{Total+x}[/tex]
So, we have:
[tex]\frac{1}{4} = \frac{5}{10+x}[/tex]
Cross multiply
[tex]10+x = 5 * 4[/tex]
[tex]10+x = 20[/tex]
Collect like terms
[tex]x = 20 -10[/tex]
[tex]x = 10[/tex]
Hence, 10 additional black balls must be added
which of the following is a geometric sequence -3,3,-3,3... 11,16,21,26, ... 6, 13, 19, 24, ... -2,6,14,22, ...
Answer:
p and q are two numbers.whrite down an expression of
solve the inequality x(x+6) >16
please show steps and interval notation!
Answer:
x > 2, x < -8
Interval notation:
( -infinity, -8) U (2, infinity)
Step-by-step explanation:
x(x+6) > 16
distribute x into x+6, multiply
x^2 + 6x > 16
bring 16 to left side, subtract
x^2 + 6x - 16 > 0
factors of -16 that add to +6 is -2 and +8
(x - 2)(x + 8) > 0
solve for x:
x < -8, x > 2
Interval notation:
( -infinity, -8) U (2, infinity)