Answer:
answer is 1
Step-by-step explanation:
y∝x
y=kx
15=3k
divide 3 both sides
k=5
so y=5x
when y is 5
5=5×x
divide 5 both sides
x=1
which is a true statement about an exterior angle of a triangle
Answer:
D
Step-by-step explanation:
The exterior angles are out of the triangle at all times and it adds up to make 180 with anyone of the inside angle of the triangle.
The pair also rests on the same flat/straight line and that makes a pair.
Therefore we can say that it is formed by a linear pair/group with one of the interior/inside angles of the triangle.
So, the correct answer would be D.
The true statement about an exterior angle of a triangle is C; It forms a linear pair with one of the interiior angles of the triangle .
What is the Exterior Angle of a Triangle Property?An exterior angle of a triangle is equal to the sum of the opposite interior angles.
We know that the exterior angles are out of the triangle at all times and it adds up to make 180 with anyone of the inside angle of the triangle.
The pair also rests on the same straight line and that makes a pairs.
Therefore we can say that it is formed by a linear pair with one of the interior angles of the triangle.
So, the correct answer would be C.
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Someone pls help me . Will mark brainliest !!
Answer:
3, 10, 1080
Step-by-step explanation:
A coefficient, is the number that is multiplying a variable, such as x. A constant is any other number, not multiplying a variable.
For part one, the number multiplying the variable x is 3, so 3 is the coefficient.
For part two, the only number not multiplying a variable is the 10, so that is the constant.
To find how many miles she drove, we first need to subtract the first 30 dollars from the final payment.
300-30=270
We than need to divide 270 by .25, because that is how much it costed per mile.
270/.25=1080
Answer:
In the first question shown, the answer is 3
In the second question shown, the answer is 10
In the third question shown, the answer is 1080 miles
Step-by-step explanation:
First question - 3 is the number before x, making it the coefficient
Second question - 10 is the only number without a variable, making it a constant
Third question - .25 * 1080 = 270. 270 + 30 = 300.
A. (-2,-1)
B. (-1,-2)
C. (1.-2)
D. (2,-1)
Answer:
D. 2,-1
Step-by-step explanation:
When a line is reflected by y=x, the x and y switch.
Christian ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday, he ran 1 1/3 fewer miles than he ran on Monday. How many miles did he run in all? SHOW YOUR WORK AND EXPLAIN PLEASE I WILL MARK YOU BRAINIEST.
Answer:
9.83 miles
Step-by-step explanation:
Distance covered on Monday = 4.25 miles
Distance covered on Tuesday = 2.66 miles
Distance covered on Wednesday
= 4.25 - 1.33 = 2.92 miles
Total distance covered in Three days = 9.83miles
HELP!! For questions 9-12 evaluate each function for the given value
Answer:
9). h² - 7h + 11
10). 2a² + 14a + 16
11). 3
12). 2h + 4x - 3
Step-by-step explanation:
9). If j(x) = x² + x - 1
j(h - 4) = (h - 4)² +(h - 4) - 1
= h² - 8h + 16 + h - 4 - 1
= h² - 7h + 11
10). If f(x) = 2x² + 2x - 8
f(a + 3) = 2(a + 3)² + 2(a + 3) - 8
= 2(a² + 6a + 9) + 2a + 6 - 8
= 2a² + 12a + 18 + 2a - 2
= 2a² + 14a + 16
11). If f(x) = 3x - 1
[tex]\frac{f(x+h)-f(x)}{h}=\frac{3(x+h)-1-(3x-1)}{h}[/tex]
[tex]=\frac{3x+3h-1-3x+1}{h}[/tex]
= 3
12). If, f(t) = 2t² - 3t + 7
[tex]\frac{f(x+h)-f(x)}{h}=\frac{2(x+h)^{2}-3(x+h)+7-(2x^2-3x+7)}{h}[/tex]
[tex]=\frac{2(x^2+h^2+2hx)-3x-3h+7-2x^2+3x-7}{h}[/tex]
[tex]=\frac{2x^2+2h^2+4hx-3x-3h+7-2x^2+3x-7}{h}[/tex]
[tex]=\frac{2h^2+4hx-3h}{h}[/tex]
= 2h + 4x - 3
Simplify the expression. (3x2 – 4x + 1) + (-x2 + x – 9)
[tex](3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8[/tex]
Consider the equation: 12x=13-x^212x=13−x 2 12, x, equals, 13, minus, x, squared 1) Rewrite the equation by completing the square. Your equation should look like (x+c)^2=d(x+c) 2 =dleft parenthesis, x, plus, c, right parenthesis, squared, equals, d or (x-c)^2=d(x−c) 2 =dleft parenthesis, x, minus, c, right parenthesis, squared, equals, d. 2) What are the solutions to the equation
Answer:
[tex](x + 6)^2 = 49[/tex]
[tex]x = 1[/tex] or [tex]x = -13[/tex]
Step-by-step explanation:
Given
[tex]12x = 13 - x^2[/tex]
Using Completing the Square
[tex]12x = 13 - x^2[/tex] ---- Add [tex]x^2[/tex] to both sides
[tex]x^2 + 12x = 13 - x^2 + x^2[/tex]
[tex]x^2 + 12x = 13[/tex]
Divide the coefficient of x by 2; then add the square to both sides
[tex]x^2 + 12x + 6^2 = 13 + 6^2[/tex]
[tex]x^2 + 12x + 36 = 13 + 36[/tex]
[tex]x^2 + 12x + 36 = 49[/tex]
Factorize
[tex]x^2 + 6x + 6x + 36 = 49[/tex]
[tex]x(x + 6) + 6(x + 6) = 49[/tex]
[tex](x + 6)(x + 6) = 49[/tex]
[tex](x + 6)^2 = 49[/tex]
Hence, the equation is [tex](x + 6)^2 = 49[/tex]
Solving further
Take square root of both sides
[tex](x + 6) = \sqrt{49}[/tex]
[tex]x + 6 = \±7[/tex]
[tex]x = \±7- 6[/tex]
This implies that
[tex]x = 7 - 6[/tex] or [tex]x = -7 -6[/tex]
[tex]x = 1[/tex] or [tex]x = -13[/tex]
HEnce, the solutions are [tex]x = 1[/tex] or [tex]x = -13[/tex]
Answer:
(x+6)^2=49 and x=−6±7
Step-by-step explanation:
Explain how the tangents of complementary angles are related.
Answer:
tan(α) = 1/tan(90°-α)
Step-by-step explanation:
The tangent of one is the reciprocal of the tangent of the other.
__
In a right triangle, ...
tan = opposite/adjacent
For the two complementary acute angles in such a triangle, opposite and adjacent are swapped. That is the tangent of one is the inverse of the tangent of the other. (That inverse is also known as the cotangent.)
tan(α) = cot(90°-α) = 1/tan(90°-α)
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
A. 28.93 units²
B. 29.98 units²
C. 29.79 units²
D. 30.73 units²
Answer:
Area of quadrilateral ABCD = 29.79 units² (Approx)
Step-by-step explanation:
Area of triangle ABD
s = (3.48+8.66+8.6) / 2
s = 10.37
Area of triangle ABD = √10.37(10.37-8.66)(10.37-8.6)(10.37-3.48)
Area of triangle ABD = √212.4616
Area of triangle ABD = 14.5760625 unit²
Area of triangle ACD
s = (3.54+8.84+8.6) / 2
s = 10.49
Area of triangle ACD = √10.49(10.49-8.6)(10.49-8.84)(10.49-3.54)
Area of triangle ACD = √227.3558
Area of triangle ACD = 15.0783222 unit²
Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle ACD
Area of quadrilateral ABCD = 14.5760625 unit² + 15.0783222 unit²
Area of quadrilateral ABCD = 29.6542units²
Area of quadrilateral ABCD = 29.79 units² (Approx)
What is the solution to this system of equations? x+3y−z=6 4x−2y+2z=−10 6x+z=−12 (−4, 0, 12) (0, −2, −12) (2, 1, −3) (−3, 5, 6)
Answer:
Solution : (− 3, 5, 6)
Step-by-step explanation:
We have the following system of equations that we have to solve for,
[tex]\begin{bmatrix}x+3y-z=6\\ 4x-2y+2z=-10\\ 6x+z=-12\end{bmatrix}[/tex]
To solve this problem we can start by writing the matrix with their respective coefficients --- (1)
[tex]\begin{bmatrix}1&3&-1&|&6\\ 4&-2&2&|&-10\\ 6&0&1&|&-12\end{bmatrix}[/tex]
Now we can reduce this to row echelon form, receiving our solution --- (2)
[tex]\begin{pmatrix}1&3&-1&6\\ 4&-2&2&-10\\ 6&0&1&-12\end{pmatrix}[/tex] Swap row 1 and 3,
[tex]\begin{pmatrix}6&0&1&-12\\ 4&-2&2&-10\\ 1&3&-1&6\end{pmatrix}[/tex] Cancel leading coefficient in row 3,
[tex]\begin{pmatrix}6&0&1&-12\\ 0&-2&\frac{4}{3}&-2\\ 0&3&-\frac{7}{6}&8\end{pmatrix}[/tex] Swap row 2 and 3
[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&-2&\frac{4}{3}&-2\end{pmatrix}[/tex] Cancel leading coefficient in row 3
[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&0&\frac{5}{9}&\frac{10}{3}\end{pmatrix}[/tex]
At this point you can see that we have to cancel the leading coefficient in each row, to row echelon form. Continuing this pattern we have the following matrix,
[tex]\begin{bmatrix}1&0&0&|&-3\\ 0&1&0&|&5\\ 0&0&1&|&6\end{bmatrix}[/tex]
As you can see, x = - 3, y = 5, and z = 6, giving us a solution of (− 3, 5, 6). This is the fourth option.
50.For the direct variation such that when y = 2 then x = 3, find the constant of variation ( k ) and then find the value of y when x = –0.5.
Step-by-step explanation:
Since it's a direct variation
y = kx
where k is the constant of proportionality
To find the value of y when x = –0.5 we must first find the relationship between the variables
When
x = 3
y = 2
2 = 3k
Divide both sides by 3
[tex]k = \frac{3}{2} [/tex]
So the formula for the variation is
[tex]y = \frac{3}{2} x[/tex]When x = - 0.5 or - 1/2
[tex]y = \frac{3}{2} ( - \frac{1}{2} )[/tex]
We have the final answer as
[tex]y = - \frac{3}{4} [/tex]Hope this helps you
Please answer this question now
Hi there! :)
Answer:
[tex]\huge\boxed{V = 359.01 mm^{3} }[/tex]
Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:
Find the area of the base:
b = π(7)²
b = 49π
b = 153.86 mm²
Find the volume:
V = 1/3(153.86 · 7)
V = 1/3(1077.02)
V = 359.006 ≈ 359.01 mm³.
BRAINLIEST!! The equation of the line is Y=2.x- 1.8. Based on the graph which of the following are true?
(select all that apply)
A. If tony stays for 30 minutes in the record store it is likely her will spend $70
B. Each additional minute tony spends in the store is associated with an additional cost of $2.40
C. The correlation coefficient for the line of best fits 2.4
D. The line of best fit will have a positive correlation coefficient.
Answer:
b y=2.4x -1.8
Step-by-step explanation:
the equation y=2.4x -1.8 represents 2.4 from it
5. Eight adults and six children travel in a cable car.
Estimate the total mass of the people in the cable car.
Answer: 1880 pounds
Step-by-step explanation: when you take the average adult weight, around 160 lbs. you multiply that by eight. you get 1280. then you estimate that each of the children weigh around 100 lbs, then you add 600 to 1280 and get 1,880 lbs
The Stem-and-Leaf Graph shows the amount of money each student spends on food per day in dollars. What is the median for the data in this Stem-and-Leaf Plot? A. $55 B. $73 C. $81 D. $84
Answer:
B) $73
Step-by-step explanation:
add all of your values and divide by the amount of values
52+55+55+55+59+64+66+68+72+73+73+73+73+75+81+81+83+84+84+86+87=
1,499
1,499 divided by 21 = 71.3809523...
which rounds to 73
HOPE THIS HELPS!!! :)
The median is of $48 in the stem leaf plot and option B is correct.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
The median of a data-set is the value that separates the bottom 50% from the upper 50% of values.
The graph has 16 values, already ordered.
It is an even number, hence the median is the mean of the 8th and the 9th values, which considering the key are both 48,
Hence, the median is of $48 and option B is correct.
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Stem-and-Leaf Plot shows the amount of money each student spends
on travel per day in dollars. What is the median for the data in this graph?
Stem Leaf
A) $35
B) $48
C) $53
D) $54
The dot plots show 9 scores on a 10 question trivia game for two students. Select all the statements that must be true.
..
:
2
3
5
6
7
4.
Noah's scores
...
2
3
5
6
7
Jada's scores
Noah's scores have greater variability than Jada's scores.
The standard deviation of Noah's scores is equal to the standard deviation of Jada's scores.
The mean of Noah's scores is greater than the mean of Jada's scores.
Noah scored better than Jada on every assignment.
Using only Noah's scores, the mean is equal to the median
d
e
Answer:
The correct statements are b, c and e.
Step-by-step explanation:
Consider the dot plot for Noah and Jada's score in the trivia game.
From the dot plot it is quite clear that the data form a bell-shaped curved or a normal curve.
For the normal distribution:
Mean = Median = Mode
Noah's mean score = 5
Jada's mean score = 3
The standard deviation of a data set is the measure of dispersion of the observations of that data set from their mean.
On closely studying the graphs we can see that the Noah and Jada's scores are almost at a same distance from the mean, i.e. the spread of Noah's score is same as the spread of Jada's score.
So, the correct statements are:
b. The standard deviation of Noah's scores is equal to the standard deviation of Jada's scores.
c. The mean of Noah's scores is greater than the mean of Jada's scores.
e. Using only Noah's scores, the mean is equal to the median
Please answer answer question
Answer:
c=13.42
Step-by-step explanation:
[tex]A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42[/tex]
sam ran 63,756 feet in 70 minutes what is sams rate in miles per hour? (there are 5,280 feet in one mile)
Divide total feet by feet in a mile:
63,756/5280 = 12.075 miles
Divide 70 minutes by 60 minutes per hour:
70/60 = 1.166666 hours( round to 1.17)
Miles per hour = total miles/ total hours:
12.075/1.17 = 10.32 miles per hour
please help :) 1) Scientists develop knowledge by making blank about the natural world that may lead to a scientific question. 2) A scientific question may lead to a(n) blank , which can be tested. The results of blank can lead to changes in scientific knowledge.
Answer:
You just answered my question so you can ask yours, what a sped. Now i'm doing the same thing.
Step-by-step explanation:
What are the solutions to the quadratic equation 4x2 = 64? A. x = −16 and x = 16 B.x = −8 and x = 8 C.x = −4 and x = 4 D.x = −2 and x = 2
Answer:
x = ±4
Step-by-step explanation:
4x^2 = 64
Divide each by 4
4x^2 /4= 64/4
x^2 = 16
Take the square root of each side
sqrt(x^2) = ±sqrt(16)
x = ±4
Answer:
[tex]\boxed{\boxed{x=\pm 4}}[/tex]
Step-by-step explanation:
[tex]4x^2 = 64[/tex]
Divide both sides by 4.
[tex](4x^2)/4 = 64/4[/tex]
Simplify.
[tex]x^2 =16[/tex]
Take the square root on both sides.
[tex]\sqrt{x^2 } =\pm \sqrt{16}[/tex]
Simplify.
[tex]x=\pm 4[/tex]
What type of number is that? Multiple answers.
Answer:
A & C
Step-by-step explanation:
-9 is a whole number is rational
Distribute 10 (3x + 8x2).
Answer:
30x+160
simple all you had to do is 10*3x and 8x2=16 and 10*16 and you will get 30x+160
Step-by-step explanation:
Answer:
30x + 80x^2
Step-by-step explanation:
10 (3x + 8x^2)
10 * 3x + 10 * 8x^2
30x + 80x^2
COMPUTE
3 ( 2 1/2 - 1 ) + 3/10
Answer:
[tex] \boxed{ \frac{24}{5} }[/tex]Step-by-step explanation:
[tex] \mathsf{3(2 \frac{1}{2} - 1) + \frac{3}{10} }[/tex]
Convert mixed number to improper fraction
[tex] \mathrm{3( \frac{5}{2} - 1) + \frac{3}{10} }[/tex]
Calculate the difference
⇒[tex] \mathrm{3( \frac{5 \times 1}{2 \times 1} - \frac{1 \times 2}{1 \times 2} }) + \frac{3}{10} [/tex]
⇒[tex] \mathrm{ 3 \times( \frac{5}{2} - \frac{2}{2}) } + \frac{3}{10} [/tex]
⇒[tex] \mathrm{3 \times ( \frac{5 - 2}{2} ) + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{3 \times \frac{3}{2} + \frac{3}{10} }[/tex]
Calculate the product
⇒[tex] \mathrm{ \frac{3 \times 3}{1 \times 2} + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{ \frac{9}{2} + \frac{3}{10}} [/tex]
Add the fractions
⇒[tex] \mathsf{ \frac{9 \times 5}{2 \times 5} + \frac{3 \times 1}{10 \times 1} }[/tex]
⇒[tex] \mathrm{ \frac{45}{10} + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{ \frac{45 + 3}{10 } }[/tex]
⇒[tex] \mathrm{ \frac{48}{10} }[/tex]
Reduce the numerator and denominator by 2
⇒[tex] \mathrm{ \frac{24}{5} }[/tex]
Further more explanation:
Addition and Subtraction of like fractions
While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.
For example :
Add : [tex] \mathsf{ \frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} } = \frac{4}{5} [/tex]
Subtract : [tex] \mathsf{ \frac{5}{7} - \frac{4}{7} = \frac{5 - 4}{7} = \frac{3}{7} }[/tex]
So, sum of like fractions : [tex] \mathsf{ = \frac{sum \: of \: their \: number}{common \: denominator} }[/tex]
Difference of like fractions : [tex] \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }[/tex]
Addition and subtraction of unlike fractions
While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.
For example:
[tex] \mathsf{add \: \frac{1}{2} \: and \: \frac{1}{3} }[/tex]
L.C.M of 2 and 3 = 6
So, ⇒[tex] \mathsf{ \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} }[/tex]
⇒[tex] \mathsf{ \frac{3}{6} + \frac{2}{6} }[/tex]
⇒[tex] \frac{5}{6} [/tex]
Multiplication of fractions
To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.
When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:
[tex] \mathsf{4 \times \frac{3}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6}[/tex]
Multiplication for [tex] \mathsf{ \frac{6}{5} \: and \: \frac{25}{3} }[/tex] is done by the similar process
[tex] \mathsf{ = \frac{6}{5} \times \frac{25}{3} = 2 \times 5 \times 10}[/tex]
Hope I helped!
Best regards!
The two-way frequency table below shows data on years working with the company and college degree status for Tom's coworkers. Complete the following two-way table of row relative frequencies. (If necessary, round your answers to the nearest hundredth.)
Answer:
Lets start with the top row.
First, add the two values.
5+14=19
Now, divide each value by the total.
5/19=0.26315789473
Round the decimal to the nearest hundredth.
5/19=0.26
14/19=0.73684210526
Round it to the nearest hundredth.
14/19=0.74
Now, The second row.
Add the two values.
16+7=23
Divide the first value by the total.
16/23=0.69565217391
Round it to the nearest hundredth.
16/23=0.70
Divide the second value by the total.
7/23=0.30434782608
Round to the nearest hundredth.
7/23=0.30
Done!
Answer:
Row 1: 0.26 0.74
Row 2: 0.70 0.30
Step-by-step explanation:
Khan
I will rate you a brainlest☆
Answer:
A 0.6 0.9 1.2 1.5 1.8
B 3/8 5/8 7/8 9/8 11/8
C -7 -5 -3 -2 -1
D 1, 1 1/3, 1 2/3, 2, 2 1/3
E 0.61 0.72 0.83 0.94 1.05
Step-by-step explanation:
Answer:
A. x x 1.2 1.5 1.8
B. 3/8 x x x 1 2/8
C. x x -3 -2 -1
D. 0 x x x 5 1/3
E. x x 0.83 0.94 1.05
Step-by-step explanation:
hope it helped
Which of the following statements is not true concerning the equation x^2 - c = 0 for c > 0
A. A quadratic system in this form can always be solved by factoring.
B. This equation is not considered to be a quadratic equation because it is not in the form ax^2 + bx + c = 0
C. The left-hand side of this equation is called a difference of two squares
D. A quadratic equation in this form can always be solved using the square root property.
Which of the following steps would not be necessary when using the square root property to solve a quadratic equation?
A. After applying the square root property, solve the resulting equations.
B. Isolate the quantity being squared
C. The square root property may be applied only if the constant is positive
D. When taking the square root of both sides, use plus-minus on the square root of the constant.
Which of the following steps can be performed can be performed so that the square root property may easily be applied to 2x^2 = 16?
A. The square root property requires a quantity squared by itself on one side of the equation. The only quantity is squared by 16, so divide both sides by 2 before applying the square root property
B. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X, so divide both sides by 16 before applying the square root property
C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X, so divide both sides by 2 before applying the square root property
Answer:
The correct option are;
1) D. A quadratic equation of this form can always be solved using the square root property
2) B. Isolate the quantity being squared
3) C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X so divide both sides by 2 before applying the square root property
Step-by-step explanation:
Where the quadratic equation is of the form x² = b, the square root property method can be used to solve the equation. Due to the nature of square roots, putting a plus-minus before the square root of the constant on the right hand side of the equation after taking the square roots of both sides of the equation, two answers are produced.
It is however to first isolate the term with the squared variable, after which the square root of both sides of the equation is taken.
Please answer this question now
Answer:
72°
Step-by-step explanation:
From the figure given, angle D intercepts arc ABC. According to the Inscribed Angle Theorem:
m < D = ½(ABC) = ½(AB + BC)
Thus,
[tex] 56 = \frac{1}{2}(AB + 40) [/tex]
Solve for AB
[tex] 56 = \frac{AB + 40}{2} [/tex]
Multiply both sides by 2
[tex] 56*2 = \frac{AB + 40}{2}*2 [/tex]
[tex] 112 = AB + 40 [/tex]
Subtract both sides by 40
[tex] 112 - 40 = AB + 40 - 40 [/tex]
[tex] 72 = AB [/tex]
Arc AB = 72°
If the area of the rectangle shown below is given by the expression 3x2 + 7x – 6,
and the width is (x + 3), which of the following could represent the length?
Answer:
Step-by-step explanation:
3x² + 7x - 6 = 3x² + 9x - 2x - 2*3
= 3x (x + 3) - 2(x +3)
= (3x - 2)(x + 3)
Area of the rectangle = 3x² + 7x - 6
length * width = 3x² + 7x - 6
length * (x + 3) = (3x -2)(x +3)
length = [tex]\frac{(3x-2)(x+3)}{(x+3)}[/tex]
length = (3x - 2)
a plane is a _ figure
Please help! Algebra 2!!
Mistake found
3x-2(2x-4)=2
3x - 4x - 8 = 2 instead of 3x - 4x + 8 = 2
Correct answer
x= -13 y= -30
Answer:
See below.
Step-by-step explanation:
So we have the system of equations:
[tex]3x-2y=21 \text{ and } y=2x-4[/tex]
The student took the following steps:
[tex]3x-2(2x-4)=21\\3x-4x-8=21\\-x-8=21\\-x=29\\x=-29\\y=2(-29)-4=-58-4=-62[/tex]
The student's mistake is in step 2. He/she distributed incorrectly. You are supposed to distribute the -2 to both terms, so it should be -4x plus 8, since -2 times -4 is positive 8. Fixing that mistake, we will have:
[tex]3x-2(2x-4)=21\\3x-4x+8=21 \\-x+8=21\\-x=13\\x=-13\\y=2(-13)-4=-26-4=-30[/tex]
Thus, the final answers should be (-13, -30).
