Answer:
[tex]P(A\ or\ H) = \frac{4}{13}[/tex]
Step-by-step explanation:
Given
Number of Cards = 52
Required
Determine the probability of picking a heart or ace
Represent Ace with Ace and Heart = H
In a standard pack of cards; there are
[tex]n(A) = 4[/tex]
[tex]n(H) = 13[/tex]
[tex]n(A\ and\ H) = 1[/tex]
[tex]Total = 52[/tex]
Because the events are non mutually exclusive
[tex]P(A\ or\ H) = P(A) + P(H) - P(A\ and\ H)[/tex]
Where
[tex]P(A) = \frac{n(A)}{Total} = \frac{4}{52}[/tex]
[tex]P(H) = \frac{n(H)}{Total} = \frac{13}{52}[/tex]
[tex]P(A\ and\ H) = \frac{n(A\ and\ H)}{Total} = \frac{1}{52}[/tex]
Substitute these values in the above formula
[tex]P(A\ or\ H) = P(A) + P(H) - P(A\ and\ H)[/tex]
[tex]P(A\ or\ H) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52}[/tex]
Take LCM
[tex]P(A\ or\ H) = \frac{4 + 13 - 1}{52}[/tex]
[tex]P(A\ or\ H) = \frac{16}{52}[/tex]
Reduce fraction to lowest term
[tex]P(A\ or\ H) = \frac{4}{13}[/tex]
Hence, probability of a heart or ace is 4/13
To apply Central Limit Theorem on sample proportions in One Sample Proportion test, the sample size and the population proportion under null hypothesis need to satisfy certain conditions. Which of the following scenarios meet the requirement?
A. The sample size is 50 and the population proportion under null hypothesis is 25%.
B. The sample size is 70 and the population proportion under null hypothesis is 90%.
C. The sample size is 50 and the population proportion under null hypothesis is 15%.
D. The sample size is 200 and the population proportion under null hypothesis is 4%.
Answer:
The sample size is 50 and population proportion under null hypothesis is 25% ( A ) meets the requirement
Step-by-step explanation:
when applying the central limit theorem on sample proportions in one sample proportion test .The conditions needed to be satisfied are np > 10, and n( 1-p ) > 10
A) sample size ( n ) = 50
population proportion = 25%
np = 50 * 0.25 = 12.5 which is > 10 ( 1st condition met )
n( 1 - p ) = 50( 1 - 0.25 ) = 37.5 which is > 10 ( second condition met )
B ) sample size (n) = 70
population proportion = 90%
np = 70*0.9 = 63 which is > 10 ( 1st condition met )
n(1-p) = 70 ( 1 - 0.9 ) = 7 which is < 10 ( second condition not met )
C) sample size ( n ) = 50
population proportion = 15% = 0.15
np = 50 * 0.15 = 7.5 which is < 10 ( 1st condition not met )
n ( 1 - p ) = 50 ( 1 - 0.15 ) = 50 * 0.85 = 42.5 which is > 10 ( second condition met )
D) sample size ( n ) = 200
population proportion = 4% = 0.04
np = 200 * 0.04 = 8 which is < 10 ( 1st condition not met )
n ( 1 - p ) = 200 ( 1 - 0.04 ) = 192 which is > 10 ( second condition met )
hence : The sample size of 50 with population proportion under null hypothesis of 25% meets the requirement
Use the Midpoint Rule with n = 10 to approximate the length of c(t) = (5 + sin(4t), 6 + sin(7t)) for 0 ≤ t ≤ 2π. (Round your answer to two decimal places.)
Answer:
34.43
Step-by-step explanation:
A differential of length in terms of t will be ...
dL(t) = √(x'(t)^2 +y'(t)^2)
where ...
x'(t) = 4cos(4t)
y'(t) = 7cos(7t)
The length of c(t) will be the integral of this differential on the interval [0, 2π].
Dividing that interval into 10 equal pieces means each one has a width of (2π)/10 = π/5. The midpoint of pieces numbered 1 to 10 will be ...
(π/5)(n -1/2), so the area of the piece will be ...
sub-interval area ≈ (π/5)·dL((π/5)(n -1/2))
It is convenient to let a spreadsheet or graphing calculator do the function evaluation and summing of areas.
__
The attachment shows the curve c(t) whose length we are estimating (red), and the differential length function (blue) we are integrating. We use the function p(n) to compute the midpoint of the sub-interval. The sum of sub-interval areas is shown as 34.43.
The length of the curve is estimated to be 34.43.
the formula s= I dont know how to type that but I really need helppppp
Answer:
[tex] s = \sqrt{30} - 2\sqrt{5} m [/tex]
Step-by-step explanation:
Given:
Formula for side length of cube, [tex] s = \sqrt{\frac{SA}{6} [/tex]
Where, S.A = surface area of a cube, and s = side length.
Required:
Difference in side length between a cube with S.A of 180 m² and a cube with S.A of 120 m²
Solution:
Difference = (side length of cube with 180 m² S.A) - (side length of cube with 120 m² S.A)
[tex]s = (\sqrt{\frac{180}{6}}) - (\sqrt{\frac{120}{6}})[/tex]
[tex] s = (\sqrt{30}) - (\sqrt{20}) [/tex]
[tex] s = \sqrt{30} - \sqrt{4*5} [/tex]
[tex] s = \sqrt{30} - 2\sqrt{5} m [/tex]
Time
(minutes)
Water
(gallons)
1
16.50
1.5
24.75
2
33
find the constant of proportionality for the second and third row
Answer:
16.50
Step-by-step explanation:
Constant of proportionality = no of gallons of water per 1 minute.
In the first row, we have 16.50 gallons of water per 1 minute.
In the 2nd row, we have 24.75 gallons of water in 1.5 minutes. In 1 minute, we will have 24.75 ÷ 1.5 = 16.50 gallons
In the 3rd row, we have 33 gallons in 2 minutes. In 1 minute, we will have 33 ÷ 2 = 16.50 gallons.
We can see that there seems to be the same constant of proportionality for the 2nd and 3rd row, which is 16.50.
Thus, a relationship between gallons of water (w) and time (t), considering the constant, 16.50, can be written as: [tex] w = 16.50t [/tex]
This means the constant of proportionality, 16.50, is same for all rows.
Last Sunday, the average temperature was 8\%8%8, percent higher than the average temperature two Sundays ago. The average temperature two Sundays ago was TTT degrees Celsius. Which of the following expressions could represent the average temperature last Sunday?
Work Shown:
T = average Celsius temperature two Sundays ago
8% = 8/100 = 0.08
8% of T = 0.08T
L = average Celsius temperature last sunday
L = 8% higher than T
L = T + (8% of T)
L = T + 0.08T
L = 1.00T + 0.08T
L = (1.00 + 0.08)T
L = 1.08T
The 1.08 refers to the idea that L is 108% of T
Answer:
b and d
Step-by-step explanation:
khan
estimate the number 4576
Nearest 1000: 5000
Nearest 100: 4600
Nearest 10: 4580
Hope that helped!!! k
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An ESP experiment used the "Ten Choice Trainer." This is like the Aquarius, but with 10 targets instead of 4. Suppose that in 1,000 trials, a subject scores 173 correct guesses.
Required:
a. Set up the null hypothesis as a box model.
b. The SD of the box is:_______
c. Make the z-test.
d. What do you conclude?
Answer:
a. The H0 is number of correct guesses is 173
b. Standard Deviation of box is 0.3
c. z-test value is 7.70
d. The difference does not appear due to chances of Variation.
Step-by-step explanation:
The standard deviation is :
[tex]\sqrt{0.1 * 0.9}[/tex] = 0.3
The standard deviation of the box is 0.3 approximately.
Z-score is [tex]\frac{x-u}{standard error}[/tex]
Z-score = [tex]\frac{173-100}{9.4868}[/tex]
the value of z-score is 7.70.
How do you find volume for prisms?
Answer:
V =140 units^3
Step-by-step explanation:
The volume of the prism is V = Bh
Where B is the area of the base and h is the height
B is the area of the triangle
B = 1/2 (5 * 7) = 35/2
V = 35/2 * 8
V =140 units^3
Gulnaz plans to use less than 26 eggs while baking. She uses 5 eggs for each cake that she bakes, and 3 eggs for each quiche that she bakes.
Write an inequality that represents the number of cakes (C)left parenthesis, C, right parenthesis and quiches (Q)left parenthesis, Q, right parenthesis Gulnaz can bake according to her plan.
Answer:
5(x) +3(y)<26
Step-by-step explanation:
Let x represent the number of cakes she will bake and let you know represent the nymber of quiche she will bake.
She will use less than 26 eggs while baking and 5 eggs for each cake and 3 eggs for each quiche.
The inequality representing the above statement iz given below.
5(x) +3(y)<26
Find the rectangular coordinates of the point with the given polar coordinates.
Answer:
[tex]( - \sqrt{3} \: an d \: 1)[/tex]
Find an equation of the plane through the point(1, 5,-1) and perpendicular to the vector (1, 5, 1). Do this problem in the standard way.
Answer:
x+5y+z = 25Step-by-step explanation:
Given a plane passing through the point(1, 5,-1) and perpendicular to the vector (1, 5, 1), the equation of the plane can be expressed generally as;
a(x-x₀)+b(y-y₀)+c(z-z₀) = 0 where (x₀, y₀, z₀) is the point on the plane and (a, b,c) is the normal vector perpendicular to the plane i.e (1,5,1)
Given the point P (1, 5, -1) and the normal vector n(1, 5, 1)
x₀ = 1, y₀ =5, z₀ = -1, a = 1, b = 5 and c = 1
Substituting this point in the formula we will have;
a(x-x₀)+b(y-y₀)+c(z-z₀) = 0
1(x-1)+5(y-5)+1(z-(-1)) = 0
(x-1)+5(y-5)+(z+1) = 0
x-1+5y-25+z+1 = 0
x+5y+z-1-25+1 = 0
x+5y+z-25 = 0
x+5y+z = 25
The final expression gives the equation of the plane.
Let a >= b.
show that gcd(a,b) = gcd(a-b, b)
let [tex] \gcd(a,b)= G[/tex] , $a\ge b$
$\therefore a=G\cdot m$ and $b=G\cdot n$
$a-b=Gm-Gn=G(m-n)$
Now, $\gcd(a-b,b)$ clearly is, $G$
You are a great student so you know that you answer probability questions correctly with probability 0.8. A friend told you that "NA" is a correct answer with probability 0.01 in general. Let XX be a random variable that takes on the value 1 if you answer a probability question correctly and 0 otherwise, and let YY be a random variable with takes on the value 1 if "NA" is the correct answer to the probability question and 0 otherwise.Required:a. P [X=0]=_______b. P[Y=1]=________
Answer:
sorry gave wrong answer
Step-by-step explanation:
URGENT At Garcia's Bike Rentals, it costs $ 36 to rent a bike for 9 hours. How many hours of bike use does a customer get per dollar?
Answer:
.25 hour / dollar
Step-by-step explanation:
We want hours per dollar
9 hours/ 36 dollars
1/4 hour / dollar
can anyone show me this in verbal form?
Answer:
2 * (x + 2) = 50
Step-by-step explanation:
Let's call the unknown number x. "A number and 2" means that we need to add the numbers, therefore it would be x + 2. "Twice" means 2 times a quantity so "twice a number and 2" would be 2 * (x + 2). "Is" denotes that we need to use the "=" sign and because 50 comes after "is", we know that 50 goes on the right side of the "=" so the final answer is 2 * (x + 2) = 50.
URGENT, PLEASE HELP! (1/5) -50 POINTS- !please no wrong answers for the points.! A) [tex]y = 6x - \frac{11}{8}[/tex] B) [tex]y = -6x - 2[/tex] C) [tex]y = \frac{3}{2} x - \frac{1}{8}[/tex] D) [tex]y = -3x + 9[/tex]
Answer:
C y = 3/2x - 1/8
Step-by-step explanation:
We know that the line has a positive slope, because it goes up from the lower left to upper right
We can eliminate B and D
For y = 6x - 11/8
A slope of 6 is very steep
Putting in 6
y = 6*6 -approximately 1 = 35 so the value at 3 would be 35
This is too big
Checking C
y = 3/2(6) - 0 = 9 or 9 This would be about right
A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variable W. Assume that the probability of transmitting a +1 is 0.4. Show your work
a) Determine the expected value for W
b) Determine the variance of W
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
Find the value of the expression: −mb −m^2 for m=3.48 and b=96.52
Answer:
The value of the expression when [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex] is 323.779.
Step-by-step explanation:
Let be [tex]f(m, b) = m\cdot b - m^{2}[/tex], if [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex], the value of the expression:
[tex]f(3.48,96.52) = (3.48)\cdot (96.52)-3.48^{2}[/tex]
[tex]f(3.48,96.52) = 323.779[/tex]
The value of the expression when [tex]m = 3.48[/tex] and [tex]b = 96.52[/tex] is 323.779.
For a certain instant lottery game, the odds in favor of a win are given as 43 to 57. Express the indicated degree of likelihood as a probability value between 0 and 1 inclusive.
Answer:
[tex]Win = 0.43[/tex]
Step-by-step explanation:
Given
Odds in favor of win = 43 to 57
Required
Express as a probability
We start by getting the sum of both odds
[tex]Sum = 43 + 57[/tex]
[tex]Sum = 100[/tex]
Next, we divide the required odd by the calculated sum to get the probability
Odds in favor of win is calculated as thus
[tex]Win= \frac{43}{100}[/tex]
[tex]Win = 0.43[/tex]
Hence, the probability is 0.43
I need help will rate you branliest
Answer:
[tex] {x}^{2} + 5x + 10[/tex]
Answer:
[tex]\large \boxed{x^2 +5x+10}[/tex]
Step-by-step explanation:
A polynomial is an expression that has variables, coefficients, and constants.
An example of a polynomial can be x² - 6x + 2.
In a survey of adults in a certain country conducted during a period of economic uncertainty, % thought that wages paid to workers in industry were too low. The margin of error was percentage points with % confidence. For parts (a) through (d) below, which represent a reasonable interpretation of the survey results? For those that are not reasonable, explain the flaw.
Answer:
Hello your question has some missing parts below is the complete question
In a survey of 2065 adults in a certain country conducted during a period of economic uncertainty, 63% thought that wages paid to workers in industry were too low. The margin of error was 4 percentage points with 95% confidence. For parts (a) through (d) below, which represent a reasonable interpretation of the survey results? For those that are not reasonable, explain the flaw.
part a:(We are 95 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low.)
part b: We are 91 % to 99 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low.
part c: We are 95 % confident the proportion of adults in the country during the period of economic uncertainty who believed wages paid to workers in industry were too low was between 0.59 and 0.67. Is the interpretation reasonable?
part d: In 95 % of samples of adults in the country during the period of economic uncertainty, the proportion who believed wages paid to workers in industry were too low is between 0.59 and 0.67. Is the interpretation reasonable?
Answer : For part A :
The interpretation is flawed. No interval has been provided about the population proportion.
part B :
The interpretation is flawed. The interpretation indicates that the level of confidence is varying.
Part C
The interpretation is reasonable.
Part D
The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.
Step-by-step explanation:
Given data: Population = 2065 ,
probability = 63% = 0.6,
margin of error = 4% = 0.04
confidence interval (95%) = ( 0.59,0.67 )
For part A :
The interpretation is flawed. No interval has been provided about the population proportion. this is because the confidence interval is not mentioned
part B :
The interpretation is flawed. The interpretation indicates that the level of confidence is varying. this is because the confidence interval is a fixed value
Part C
The interpretation is reasonable.
this is because the confident level given is fixed
Part D
The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.
To the nearest tenth, what is the area of the figure shown in the image? Segment BF is a line of symmetry of the pentagon ABCDE. Use 3.14 for pi. A. 30.3 in.^2 B. 33.0 in.^2 C. 39.3 in.^2 D. 48.3 in.^2 Please include ALL work! <3
Answer:
C, 39.3 in²
Step-by-step explanation:
Lets first find the area of the rectangle part of the house.
To find the area of a rectangle its base × height.
So its 6×4=24 in².
Now lets find the area of the top triangle.
Area for a triangle is (base × height)/2.
The height is 3 inches, because its 7-4. While the base is 6 inches.
(6×3)/2=9 in².
To find the area of the half circle the formula, (piR²)/2.
The radius of the circle is 2 because its half of the diamter which is 4.
(pi2²)/2=6.283 in².
Now we just need to add up the area of every part,
24+9+6.283=39.283in²
PLS HELP ASAP Solve the inequality and enter your solution as an inequality in the box below 8>4-x>6
Answer:
−4<x<−2
Step-by-step explanation:
8 > 4 − x > 6
8 > −x + 4 > 6
8 + −4 > −x + 4 + −4 > 6 + −4
4 > −x > 2
Since x is negative we need to divide everything by -1 which gives us...
−4 < x < −2
What is the x-value of point A?
━━━━━━━☆☆━━━━━━━
▹ Answer
x = 5
▹ Step-by-Step Explanation
The x-axis and y-axis are labeled on the graph. The x-axis is the horizontal axis. Between 4 and 6, there is a missing number. That number should be 5, leaving us with an x-value of 5 for Point A.
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
Answer:
The x value is 5
Step-by-step explanation:
The x value is the value going across
Starting where the two axis meet, we go 5 units to the right
That is the x value
Choose all properties that were used to simplify the following problem: [38 + 677] + (-38) [677 + 38] + (-38) 677 + [38 + (-38)] 677 + 0 677 Choices: additive identity additive inverse commutative property of addition associative property of addition distributive property
Answer:
Distributive property, addition property
Answer:
additive identity
associative property of addition
distributive property
Step-by-step explanation:
What is the quotient of 35,423 ÷ 15?
Answer: 2361.53
Step-by-step explanation:
Use long division and round.
(The 3 is repeated)
Which of the following is the correct set notation for the set of perfect squares between 1 and 100 (including 1 and 100)?
Select the correct answer below:
{p2∣p∈ℤ and 1≤p≤10}
{p2∣p∈ℤ and 1
Answer:
[tex]\{P^2: P\ E\ Z\ and\ 1\leq p\leq 10\}[/tex]
Step-by-step explanation:
Given
Range: = 1 to 100 (Inclusive)
Required
Determine the notation that represents the perfect square in the given range
Represent the range with P
P = 1 to 100
Such that the perfect squares will be P² and integers
In set notation, integers are represented with Z
The set notation becomes
[tex]\{P^2: P\ E\ Z\ and\ 1\leq p\leq 10\}[/tex]
The [tex]\leq[/tex] shows that 1 and 100 are inclusive of the set
Geometry Help needed Quick!!!!! Will give Brainliest to first answer Solve For X and Y
Answer:
x = 8
y = 2√3
Step-by-step explanation:
Since this is a right triangle
x^2 = (4√3)^2 + 4^2 ➡ x^2 = 64 and x = 8
Using Euclidean theorem
y^2 = (x-6)(x - x - 6) = 6x - 36
y^2 = 6×8 - 36
y^2 = 12
y = 2√3
Answer:
1 ) x = 8,
2 ) y = 2√3
Step-by-step explanation:
Take a look at the outermost triangle. I can tell that this is a 30 - 60 - 90 triangle, as if the leg opposite to the 30 degree angle was x, the other respective leg, opposite to the 60 degree angle, would be x√3. Here this " x " would be 4, but don't let that confuse you with the x we have to solve for.
As this outermost triangle is right, x is present as the hypotenuse and we can solve through Pythagorean Theorem,
( 4√3 )² + ( 4 )² = x²,
48 + 16 = x² = 64,
x = √64 = 8
And an inner triangle, present with y being a leg, has a respective leg length of x - 6, or 8 - 6 = 2. Let's solve for y using Pythagorean Theorem once more,
y² + 2² = 4²,
y² = 16 - 4 = 12,
y = √12 = √2 [tex]*[/tex] 2 [tex]*[/tex] 3 = 2√3
An IQ test is designed so that the mean is 100 and the standard deviation is for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with % confidence that the sample mean is within IQ points of the true mean. Assume that and determine the required sample size.
Complete Question
An IQ test is designed so that the mean is 100 and the standard deviation is 24 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 95% confidence that the simple mean is with in 3 IQ points of the true mean. Assume that standard deviation = 24 and determine the required sample size using technology. Determine if this is a reasonable sample size for a real world calculation.
The required sample size ______ (round up to the nearest integer.
Answer:
The sample size is [tex]n = 246[/tex]
Step-by-step explanation:
From the question we are told that
The mean is [tex]\mu = 100[/tex]
The standard deviation is [tex]\sigma = 24[/tex]
The margin of error is [tex]E = 3[/tex]
Given that the confidence level is 95% then the level of significance is mathematically evaluated as
[tex]\alpha = 100 - 95[/tex]
[tex]\alpha = 5\%[/tex]
=> [tex]\alpha = 0.05[/tex]
Next we obtain the critical value of [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table the value is
[tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]
The sample size is evaluated as
[tex]n = [ \frac{ Z_{\frac{\alpha }{2} } * \sigma }{E }]^2[/tex]
=> [tex]n = [ \frac{ 1.96 * 24 }{3 }]^2[/tex]
=> [tex]n = 246[/tex]
to check if this n is applicable in real world then we calculate E and compare it with the given E
Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorates. When the average furfuryl ether content reaches 6 μg per liter, a typical consumer begins to taste an unpleasant chemical flavor. At α = .05, would the following sample of 12 randomly chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold? 8.92 6.99 5.54 5.73 6.38 5.51 6.45 7.50 8.48 5.56 6.90 6.46
Answer:
As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.
Step-by-step explanation:
We formulate our null and alternative hypotheses as
H0 u≤ 6 ug Ha : u > 6 ug
The significance level ∝ = 0.05
The test statistic used is
t = X` - u / s/ √n
which if H0 is true, has the students' t test with n-1 = 11 degrees of freedom.
The critical region t > t (0.05,11) = 1.796
We compute the t value from the data
Xi Xi²
8.92 79.5664
6.99 48.8601
5.54 30.6916
5.73 32.8329
6.38 40.7044
5.51 30.3601
6.45 41.6025
7.50 56.25
8.48 71.9104
5.56 30.9136
6.90 47.61
6.46 41.7316
80.42 553.0336
Now x` = ∑x/ n = 80.42/12 = 6.70
S²= 1/n-1 ( ∑(xi- x`)²= 1/11 ( 553.034 - (80.42)²/12)
= 1/11 (553.034-538.948) = 1.2805
s= 1.1316
Putting the values in the test statistics
t = X` - u / s/ √n = 6.70- 6 / 1.1316 / √12
= 2.1698
The critical region t > t (0.05,11) = 1.796
As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.
