Iliana rotated trapezoid WXYZ 180° about the origin.

On a coordinate plane, trapezoid W X Y Z has points (negative 4, 2), (negative 3, 4), (negative 1, 4), (0, 2).

What is the correct set of image points for trapezoid W’X’Y’Z’?

W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)

Answers

Answer 1

Answer:

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2)

Step-by-step explanation:

Its A Your Welcome :)

Answer 2

Answer:

A.

Step-by-step explanation:


Related Questions

Hope made 3 different yo-yo's. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string

Answers

Answer:

See explanation

Step-by-step explanation:

Your question is different from the attachment

Statement 1

1 adult + 5 Children

$4 for adult and total of $16 for both adult and children

Let

Cost of children skating = x

The equation is

4 + 5x = 16

Statement 2:

Cost of making a bike bag= $4

Selling price of the bike bag = $5

Profit = $16

Let x = number of bike bag

Profit = selling price - cost price

16 = 5x - 4x

16 = x(5 - 4)

Also written as

(5 - 4)x = 16

Statement 3:

Initial temperature = 16°C

Change in temperature per hour = 4°C

Final temperature = 5°C

Let

x = number of hours it changes

16 - 4x = 5

Hope made 3 different yo-yos. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string for the second yo-yo, and a total of meters of string 4 1/3

length of first yo-yo = 1 3/4

length of second yo-yo = 1

Length of third yo-yo = x

Total = 4 1/3

Total length = length of first yo-yo + length of second yo-yo + length of third yo-yo

4 1/3 = 1 3/4 + 1 + x

4 1/3 = 2 3/4 + x

4 1/3 - 2 3/4 = x

13/3 - 11/4 = x

(52-33) / 12 = x

19/12 = x

x = 1 7/12

The value of w???????

Answers

Answer:

Step-by-step explanation:

The angle bisector of a triangle divides the opposite side in 2 segments that are proportional to the other 2 sides of the triangle. Namely:

[tex]\frac{15}{18}=\frac{w}{30}[/tex] and cross multiply.

18w = 450 so

w = 25

Can somebody help me PLEASE IM BEGGING YOU !!

Answers

Answer:

37

Step-by-step explanation:

360 -(110+110+66) = 74

74/2 = 37

If x−2/4=2, then x=10

Answers

Answer:

True.

Step-by-step explanation:

[tex]\frac{(10)-2}{4}=2\\\\\frac{8}{4}=2\\\\2=2[/tex]

If you plug 10 in for x your equation is:
(10-2)/4=2
8/4=2
2=2
So this true! X does equal 10

Help pleaseeeee like ASAP

Answers

Answer:

m is slope and y is the intercept

Find the value of x.
B
10-X
3
D
х
2.
A
С
x = [?]

Answers

Answer:

3/(10-x) = 5/(10-x+x)

3/(10-x) = 1/2

6 = 10-x

x = 4

Hope this helps!

if 1cm on a map represents 37 1/2 km what does a length of 2/5cm on the map represent​

Answers

Answer:

15

Step-by-step explanation:

[tex]37 \frac{1}{2} \times \frac{2}{5} = \frac{75}{2} \times \frac{2}{5} = 15[/tex]

If the length of the shorter arc AB is 22cm and C is the center of the circle then the circumference of the circle
is:

Answers

Answer:

22= 2(pi)(r)(45/360)

28.01

C=176

Step-by-step explanation:

Find the slope of
(-3,6)(5,-4)

Answers

Answer:

Slope: -5/4

Step-by-step explanation:

Slope formula: [tex]\frac{y^2-y^1}{x^2-x^1}[/tex]

Plug in:

[tex]\frac{-4-6}{5-(-3)}[/tex]

Solve:

[tex]\frac{-4-6}{5-(-3)}[/tex]

-4 - 6 = -10

5-(-3) = 8

-10              5

-----   =   -  -----

8               4

The answer is -5/4

Hope this helped.

if a+1/a=3
What is the answer? a⁵+1/a⁵

Answers

Answer:

123

Step-by-step explanation:

We can square and cube the equation, then multiply the results together.

(a + [tex]\frac{1}{a}[/tex]) = 3 ← square both sides

a² + 2 + [tex]\frac{1}{a^2}[/tex] = 9 ( subtract 2 from both sides )

a² + [tex]\frac{1}{a^2}[/tex] = 7 → (1)

-----------------------

Now cube both sides

a³ + [tex]\frac{1}{a^3}[/tex] + 3(a + [tex]\frac{1}{a}[/tex]) = 27

a³ + [tex]\frac{1}{a^3}[/tex] + 3(3) = 27

a³ + [tex]\frac{1}{a^3}[/tex] + 9 = 27 ( subtract 9 from both sides )

a³ + [tex]\frac{1}{a^3}[/tex] = 18 → (2)

------------------------------

Multiply (1) and (2)

(a² + [tex]\frac{1}{a^2}[/tex] )(a³ + [tex]\frac{1}{a^3}[/tex] ) = 7(18)

[tex]a^{5}[/tex]  + ( [tex]\frac{1}{a}[/tex] + a) + [tex]\frac{1}{a^5}[/tex] = 126

[tex]a^{5}[/tex] + 3 + [tex]\frac{1}{a^5}[/tex] = 126 ( subtract 3 from both sides )

[tex]a^{5}[/tex] + [tex]\frac{1}{a^5}[/tex] = 123

how do i find perimeter and area of this triangle?

Answers

Answer:

u should use a ruler and multiplied

Step-by-step explanation:

I dont know the step by step sorry

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER

Answers

The answer would be 66km³

Answer:

V=l×w×h

so the answer is 66km

11×2×3=66

Determine what type of model best fits the given situation: A retirement account that is expected to

grow by $1,000 per year.

Answers

Answer:

Step-by-step explanation:

If the account grows steadily, this is a linear representation, where the constant, steady growth translates to the slope of a line.

Evaluate 5⁰-5¹ in positive index form

Answers

Step-by-step explanation:

5⁰ - 5¹ = -4¹

(1/3)^‐1 + 2^-1 = 3 + 1/2 = (7/2)¹

Answer: -5

Step-by-step explanation: 5^0 is 0 and 5^1=5

0-5=-5

Can someone help me ASAP this is almost due

Answers

Answer:

5

Step-by-step explanation:

8-1-(18-2)÷8

PEMDAS says parentheses first

8-1-16÷8

Then divide

8-1-2

Then subtract from left to right

7-2

5

can i get some help please

Answers

Hi there!

[tex]\large\boxed{102^o}[/tex]

Using the triangle exterior angle theorem, we know that:

∠4 = the other two angles of the triangle combined (both are given)

Thus:

∠4 = 51 + 51 = 102°

Angle 4 is an outside angle.

An outside angle of a triangle is equal to the sum of the two opposite inside angles.

The two opposite inside angles to angle 4 are shown as 51 and 51

Angle 4 = 51 + 51

Angle 4 = 102 degrees.

Find derivative of 3x^2+4 using limits

Answers

The derivative of a function f(x) is defined as

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]

For f(x) = 3x ² + 4, we have

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]

Chase took a taxi from his house to the airport. The taxi company charged a pick-up fee of $1.20 plus $4.75 per mile. The total fare was $48.70, not including the tip. Write and solve an equation which can be used to determine x, the number of miles in the taxi ride. write the equation

Answers

48.70=1.20+4.75x is the equation for this problem

Tính giá trị của I = [tex]\lim_{x \to \infty}[/tex] ([tex]\frac{4^{n} - 5.3^{n} + 1}{2.4^{n} + 2}[/tex])

Answers

I assume you're supposed to find the limit as n approaches infinity, not x.

You have

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]

For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.

On the other hand, perhaps you meant to write

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]

The same algebraic manipulation gives us

[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]

Again the exponential terms converge to 0, but this time we're left with the limit 1/2.

3. A straight line passes through two points with
coordinates (6,8) and (0,5).
Work out the equation of the line.

Answers

Answer:

Step-by-step explanation:

Find the slope of the line

(x₁ , y₁) = (6 , 8)   & (x₂ , y₂) = (0 , 5)

[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{5-8}{0-6}\\\\=\frac{-3}{-6}\\\\=\frac{1}{2}[/tex]

m = 1/2  ;(x₁ , y₁) = (6 , 8)

y - y₁ = m(x - x₁)

[tex]y - 8 = \frac{1}{2}(x - 6)\\\\y - 8 =\frac{1}{2}x -\frac{1}{2}*6\\\\y - 8 =\frac{1}{2}x- 3\\\\y = \frac{1}{2}x - 3 + 8\\\\y = \frac{1}{2}x + 5[/tex]

A, B and C, in that order, are three-consecutive whole numbers. Each is greater that 2000. A is a multiple of 4. B is a multiple 5. C is a multiple of 6. What is the smallest possible value of A?

Answers

Answer:

[tex]A=2044[/tex]

Step-by-step explanation:

Note that [tex]x\in\mathbb{W}[/tex] denotes that [tex]x[/tex] is a whole number.

By definition, consecutive numbers follow each other when we count up (e.g. 1, 2, 3).

Let's consider our conditions:

A, B, and C are consecutive whole numbers greater than 2,000A is a multiple of 4B is a multiple of 5C is a multiple of 6

Since B is a multiple of 5, the ones digit of B must be either 0 or 5. However, notice that the number before it, A, needs to be a multiple of 4. The ones digit of a number preceding a ones digit of 0 is 9. There are no multiples of 4 that have a ones digit of 9 and therefore the ones digit of B must be 5.

Because of this, we've identified that the ones digit of A, B, and C must be 4, 5, and 6 respectively.

We can continue making progress by trying to identify the smallest possible whole number greater than 2,000 with a units digit of 6 that is divisible by 6. Notice that:

[tex]2000=2\mod6[/tex]

Therefore, [tex]2000-2=1998[/tex] must be divisible by 6. To achieve a units digit of 6, we need to add a number with a units digit of 8 to 1,998 (since 8+8 has a units digit of 6).

The smallest multiple of 6 that has a units digit of 8 is 18. Check to see if this works:

[tex]C=1998+18=2016[/tex]

Following the conditions given in the problem, the following must be true:

[tex]A\in \mathbb{W},\\B\in \mathbb{W},\\C\in \mathbb{W},\\A+1=B=C-1,\\A=0\mod 4,\\B=0\mod 5,\\C=0\mod 6,[/tex]

For [tex]C=2016[/tex], we have [tex]B=2015[/tex] and [tex]A=2014[/tex]:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2014\neq 0\mod 6, \times\\B=2015=0\mod 5,\checkmark\\C=2016=0\mod 6\checkmark\\[/tex]

Not all conditions are met, hence this does not work. The next multiple of 6 that has a units digit of 8 is 48. Adding 48 to 1,998, we get [tex]C=1998+48=2046[/tex].

For [tex]C=2046[/tex], we have [tex]B=2045[/tex] and [tex]A=2044[/tex]. Checking to see if this works:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2044=0\mod 4,\checkmark\\B=2045=0\mod 5,\checkmark\\C=2046=0\mod 6\checkmark[/tex]

All conditions are met and therefore our answer is [tex]\boxed{2,044}[/tex]

If (x + 1) is a factor of 2x - kx²-8x + 5, find the value of k.
[ Using Factor Theorem ]​

Answers

Answer:

k = 11

Step-by-step explanation:

What the factor theorem is telling us is that if x + 1 is a factor of 2x - kx²-8x + 5 then when x = - 1 is put into the equation, the result will be 0. That's because x +1 = 0 when x  = - 1

f(-1) = 2(-1) - k(-1)^2 - 8(-1) + 5

f(-1) = -2 - k(1) + 8 + 5 = 0

-k*(1) + 11 = 0

-k = -11

k = 11

In the class interval 5-10, find the
(i) lower limit
(ii) upper limit
(iii) class mark
(iv) class size

Answers

Answer:

lower limit = 5

upper limit = 10

class mark = lower limit + upper limit ÷ 2 = 7.5

class size = upper limit - lower limit

= 10-5 = 5

Step-by-step explanation:

I hope this help you have an great day and safe health

(i) lower limit = 5
(ii) upper limit = 10
(iii) class mark = 15
(iv) class size = 5

A tank is capable of holding 36,18 and 72 litres of milk . Determine which is the greatest vessel which can be uses to fill each one of them on exact number of times

Answers

Answer:

Greatest vessel to fill each in exact number of times is 6 litres

Step-by-step explanation:

To solve this, we will find the greatest common factor of 36,18 and 72

Thus;

Their prime factors are;

18: 2, 3

36: 2, 2, 3, 3,

72: 2, 2, 2, 3, 3

The factors common to all of them are 2 & 3.

Thus;

GCF = 2 × 3 = 6

What is the equation of the line that passes through (-1, 5) and (3, -7)?

Answers

Answer:

[tex] 3x + y = 2 [/tex]

Step-by-step explanation:

[tex] y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1) [/tex]

[tex] y - 5 = \dfrac{-7 - 5}{3 - (-1)}(x - (-1)) [/tex]

[tex] y - 5 = \dfrac{-12}{4}(x + 1) [/tex]

[tex] y - 5 = -3(x + 1) [/tex]

[tex] y - 5 = -3x - 3 [/tex]

[tex] 3x + y = 2 [/tex]

Allowing 20 % discount on the marked price of an article and levying 15 % VAT. a buyer has to pay Rs 9.200 for the article. Find the marked price of the article.​

Answers

Answer:

here I'm confused that whether the selling price is Rs.9,200 or Rs.9.200

any ways you can take the help of below procedure

Step-by-step explanation:

here,

let marked price be X

discount(d)=20%

VAT=15%

SP with VAT= 9200

now,

SP without VAT= SP - VAT of SP

= 9200-15/100 ×9200

= 9200- 1380

=Rs. 1380

again,

SP= MP - D of MP

or,7820= x- 20/100 × x

or, 7820× 100 = 100x- 20x

or,782000=80x

or, 782000/80=X

or, X= 9775.

hence MP is Rs 9775

What is the total surface area of a cuboid with length 16cm, width 8cm and height 6cm?

Answers

Answer:

Step-by-step explanation:

The dimensions as a pair, appear twice for each combination.

SA = 2* 16 * 8 + 2 * 16 * 6 + 2*8* 6

That's because when you look at the figure, there are 2 places each face is positioned.

SA = 256 + 192 + 96

SA = 544

YujiC this is incorrect
5x and -4x
Paul wants M₁ and M₂ to have a total that is +x, and a product that is -20x². The values of M₁ and M₂ that will do that are ...
5x and -4x

Answers

Answer: 5x and -4x

Step-by-step explanation:

= 5x + (-4x)

= 5x -4x

= +x

= 5x × (-4x)

= -20x²

please click thanks and mark brainliest if you like :)

Please help explanation if possible

Answers

Answer: x = 2 and y = -4

x + 2y = -6

x = -6-2y

Putting this in value of x in

6x + 2y = 4

6(-6-2y) + 2y = 4

-36-12y+2y = 4

-10y = 4+36

y = 40/(-10)

y = -4

Now putting this value of y in

x + 2y = -6

x + 2(-4) = -6

x -8 = -6

x = -6+8

x = 2

Therefore x = 2 and y = -4

If we put these values we can check this

x + 2y = -6

2 + 2(-4) = -6

2 -8 = -6

-6 = -6

please click thanks and mark brainliest if you like :)

find x:
x+2y= -6 => 2y= -6-x
so substitute 2y into the equation 6x+2y=4
=> 6x-6x-x=4
x=2
find y:
6(2) + 2y= 4
y= -4

-there u go! :)

A fruit stand has to decide what to charge for their produce. They decide to charge \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 111 orange. They also plan to charge \$14$14dollar sign, 14 for 222 apples and 222 oranges. We put this information into a system of linear equations. Can we find a unique price for an apple and an orange?

Answers

Answer:

a + b = 5.30

a + b = 7

No

Step-by-step explanation:

Expressing the information as system of linear equation :

Let apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we have ;

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges, then we have ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.

From (1)

a = 5.30 - b

Put a = 5.30 - b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14 - - - - - (variables cancels out).

Answer:No the System has no solution

Step-by-step explanation:

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