In a test,correct answers carry +3 marks and wrong answers carry -1 marks.Ramesh answered all the questions.He scored 79 marks,though he maked 5 mistakes.Find the number of correct answers?

Answer:

f(2) = - 5

Step-by-step explanation:

Using the recursive rule and f(1) = - 3 , then

f(2) = 2f(1) + 1 = 2 × - 3 + 1 = - 6 + 1 = - 5

Answer:

(2-a)^2

(2+a) (2-a)...

Answer:

Step-by-step explanation:

Use the identity:  a² - b² = (a+ b)(a - b)

4 - a² = 2² - a²        {Here a = 2 and b = a}

        = (2 +a) (2 - a)

Answer:

The balance after the 6 years of investment will be $ 15,442.08.

Step-by-step explanation:

Given that $ 13,700 was invested at a rate of 2% compounded quarterly during 6 years, to determine the final result of the investment, the following calculation must be performed:

13,700 x (1 + 0.02 / 4) ^ 4x6 = X

13,700 x (1 + 0.005) ^ 24 = X

13,700 x 1,005 ^ 24 = X

13,700 x 1.1271 = X

15,442.08 = X

Therefore, the balance after the 6 years of investment will be $ 15,442.08.

Answer:

x = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]\frac{1}{x} + \frac{1}{3x} = 4[/tex] (Multiply everything by LCM)

[tex]3x*\frac{1}{x} + 3x*\frac{1}{3x}=3x*4[/tex] (Simplify the fractions)

[tex]3+1=12x\\4=12x\\x=4/12\\x=\frac{1}{3}[/tex]

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

Answer:

Part 1;

(0, 0)

Part 2;

(0, 2.5)

Step-by-step explanation:

Part 1

The given system of inequalities is presented as follows;

f(x) < x + 4; f(x) > -x - 3; and f(x) < 5

We check each of the points as follows;

The point (0, 0) in the inequality f(x) < x + 4, gives;

f(0) < 0 + 4

f(0) = 0 < (is less than) 0 + 4 = 4

Therefore, (0, 0) is a solution of the inequality f(x) < x + 4

The point (0, 0) in the inequality f(x) > -x - 3, gives;

f(0) < -0 - 3

f(0) = 0 > (is larger than) -0 - 3 = -3

Therefore, (0, 0) is a solution of the inequality f(x) > -x - 3

The point (0, 0) in the inequality f(x) < 5, gives;

f(0) < 5

f(0) = 0 < (is less than) 5

Therefore, (0, 0) is a solution of the inequality f(x) < 5

The point (-6, 0) in the inequality f(x) > -x - 3, gives;

f(-6) = -6 - 3 = 3

The point (-6, 0) with y = 0 < (is less than) f(-6) = 3, therefore (-6, 0) is not a solution to (not included in the graph of) the inequality f(x) > -x - 3 and therefore to the system of inequalities because at x = -6, the values of f(x) > -x - 3 are larger than 3

The point (-3, 4) in the inequality f(x) < x + 4, gives;

f(-3) = -3 + 4 = 1

The point (-3, 4) with y = 4 < (is larger than) f(-2) = 1, therefore (-3, 4) is not a solution to (not included in the graph of) the inequality f(x) < x + 4  and therefore to the system of inequalities because at x = -3, the values of f(x) < x + 4 are less than 1

The point (4, 6) is not a solution to (not included in the graph of) the inequality f(x) < 5  and therefore to the system of inequalities because f(x) is larger than 5 for all x

Therefore, the point which is part of the solution set of the system of inequalities is (0, 0)

Part 2

The given system of inequalities are, f(x) ≥ 2·x + 2; f(x) ≤ -4·x + 3; and f(x) ≤ 6·x + 5

Plotting the given system of inequalities on MS Excel the point which is part of the solution is given by points which are within the triangular intersection area of the three inequalities, with coordinates, (1/6, 7/3), (-3/4, 1/2), and (-1/5, 19/5)

Therefore, the points, (0, 0), (-2.5, 0) are not solutions because, the y-value of the solution area are all higher than the line y = 0

The point (0. 6.5) is not a solution because the points in the triangular solution area all have x-values lesser than x = 6.5

The point which is part of the solution by examination is the point (0, 2.5) which is a point between the lines y = 19/5 = 3.8, y = 1/2, x = -3/4, and x = 1/6.

Answer:

I hope this helps

Step-by-step explanation:

Answer:

[tex]x=1[/tex]

[tex]y=2[/tex]

Step-by-step explanation:

[tex]y=x^2+3x-2[/tex] , [tex]y+3=5x[/tex]

Replace all occurrences of [tex]y[/tex] in [tex]y+3=5x[/tex] with [tex]x^2+3x-2.[/tex]

[tex](x^2+3x-2)+3=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Add [tex]-2[/tex] and 3.

[tex]x^2+3x+1=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from both sides of the equation.

[tex]x^2+3x+1-5x=0[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from 3x.

[tex]x^2-2x+1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite 1 as [tex]1^2[/tex].

[tex]x^2-2x+1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

[tex]2x=2[/tex] · [tex]x[/tex] · [tex]1[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite the polynomial.

[tex]x^2-2[/tex] · [tex]x[/tex] · [tex]1[/tex] [tex]+[/tex] [tex]1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Factor using the perfect square

trinomial rule [tex]a^2-2ab+b^2=(a-b)^2,[/tex]

where a = x and b = 1.

[tex](x-1)^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Set the [tex]x-1[/tex] equal to 0.

[tex]x-1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Add 1 to both sides of the equation.

[tex]x=1[/tex]

[tex]y=x^2+3x-2[/tex]

Replace all occurrences of [tex]x[/tex] in

[tex]y=x^2+3x-2[/tex] with 1.

[tex]y=(1)^2+3(1)-2[/tex]

[tex]x=1[/tex]

[tex]y=2[/tex]

Answer:

(centre = (3, - 1 ) and radius = 7

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 6x + 2y - 39 = 0 ( collect x/ y terms and add 39 to both sides )

x² - 6x + y² + 2y = 39

Using the method of completing the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(- 3)x + 9 + y² + 2(1)y + 1 = 39 + 9 + 1

(x - 3)² + (y + 1)² = 49 ← in standard form

with centre (3, - 1 ) and r = [tex]\sqrt{49}[/tex] = 7

Answer:

Cost of each pencil = $12.5

Cost of each eraser = $7.5

Step-by-step explanation:

Given:

Number of eraser bought = 3

Number of pencil bought = 2

Total amount paid = $47.50

Cost of one pencil and one eraser = $20

Find:

Each cost

Computation:

Let;

Cost of each eraser = e

Cost of each pencil = p

So,

e + p = 20

e = 20 - p .................................... eq1

3e + 2p = 47.50

3(20 - p) + 2p = 47.50

60 - 3p + 2p = 47.50

-p = -12.5

Cost of each pencil = $12.5

e = 20 - p

e = 20 - 12.5

e = 7.5

Cost of each eraser = $7.5

Answer:

[tex] \frac{ - 81}{9} [/tex]

[tex] - 9[/tex]

EF is tangent to the circle we'll assume; otherwise there's no progress.

Call the center C. ECD is isosceles, formed from two radii and the chord.

Angle CED is complementary to DEF

CED = 90 - 65 = 25 degrees

CDE is congruent, isosceles triangle and all that: CDE=25

That leaves DCE=180-25-25=130 degrees

That's the measure of arc DE as well:

Answer: 130 degrees, choice A

Answer:

130

Step-by-step explanation:

Answer:

you need to solve for 'X'

mean 49 = 55 + 42 + 32 +48 + 55 + X

49 = (232+X) / 6

49 * 6 = 232 + X

294 = 232 + X

294 - 232 = X

62 = X

so therefore X is 62

Step-by-step explanation:

please give me a brainliest

the solution is in the picture ☝️

ANSWER: 240 hours

this is for n.12

Answer:

4/9

Step-by-step explanation:

First of all we need to get rid of the -2 exponent and make it positive in order  to solve this equation.

Therefore to do this we just use the reciprocal of 3/2 which is 2/3

Now we have (2/3)^2

Since 2/3 is being squared we used the following equation below:

(2/3) * (2/3)

We multiply 2/3 by itself twice since 2 is the exponent.

Then we get:

2^2

-----

3^2

2 squared is 4 and 3 squared is 9.

Therefore the final answer is 4/9.

I hope this helps have a good rest of your day!

Answer:

4/9

Step-by-step explanation:

(3/2)^(-2)

(3/2)^2=(3/2)(3/2)=9/4

However, ^(-2) means 1/(9/4), which gives you 4/9.

Answer: B. Square

Step-by-step explanation:

The answer is B.), because if you have two pairs of parallel sides that means it looks like a square 1. || 2. _

                                                            _

- Chilio

Answer:

4

Step-by-step explanation:

7h-15h+40=-72

-8h=-32

h=4

SSS (side-side-side) requires that all three sides of the potentially congruent triangles be congruent.

Triangle WVU & Triangle UBW are our two triangles.

The middle line, UW and WU are congruent by the reflexive property, so that is not the information we need to prove SSS.

For SSS, we need to know that sides WV and UB are congruent.

Hope this helps!

Answer:

0.395

Step-by-step explanation:

We need to solve the given expression.

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}-\dfrac{1}{2}\times\dfrac{1}{4}+\dfrac{4}{5}\times \dfrac{7}{5}[/tex]

We can also write it as :

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}+\dfrac{4}{5}\times \dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}(\dfrac{-3}{4}+\dfrac{7}{5})-\dfrac{1}{2}\times\dfrac{1}{4}[/tex](Distributive property is used)

So,

[tex]=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{8}\\\\=\dfrac{13}{25}-\dfrac{1}{8}\\\\=0.395[/tex]

So, the value of the given expression is equal to 0.395.

Answer:

Find the area of the triangle from the coordinate plane.

Y

A

10-

5-1

с

B.

0

-20

-15

-10

-5Step-by-step explanation:

Answer:

57°,123°,57°,123°

Step-by-step explanation:

as vertical angles are equal

so one angle=114/2=57°

other angle=180-57=123°

Answer:

pic pls

Step-by-step explanation:

Answer: the correct answer is A. Between 0 and 90

If an angle is between 0 and 90 it is acute

If an angle is EXACTLY 90 it is a right angle

If an angle is between 90 and 180 it is obtuse angle

If it's 360 then it is a full circle

4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?

a. What are they asking for?

how big was the original group?

b. identify all the necessary numbers.

28,5

c. write the equation or problem in numeric form.

x=28*5

d. solve the math.

x=140

e.write the answer

. the original group contains 140 people.

5. If he difference is 589 and the subtrahend is 339,what is the minuend?

a. What are they asking for?

what is the minuend?

b. identify all the necessary numbers.

589,339

c. write the equation or problem in numeric form.

x=589-339

d. solve the math.

x=250

e.write the answer.

minuend=250

6. If the quotient is 17 and the dividend 765, what is the divisor?

a. What are they asking for?

what is the divisor?

b. identify all the necessary numbers.

17,765

c. write the equation or problem in numeric form.

x=765/17

d. solve the math.

x=45

e.write the answer.

divisor is 45.

4. Solution

a. How big was the original group?

b. 28 and 5

c. x = 28×5

d. x = 140

e. There are 140 people in original group.

5. Solution

a. What is the minuend?

b. 589 and 339

c. x = 589-339

d. x = 250

e. The minuend is 250.

6. Solution

a. What is the divisor?

b. 17 and 765

c. x = 765/17

d. x = 45

e. Hence, 45 is the divisor.

option A.55°

Answer:

Solution given:

<x+<y=<z

exterior angle of a triangle is equal to the sum of two opposite interior angle

4n-18+n+8=133-6n

5n+6n=133+10

11n=143

n=143/11

n=13

exterior angle =133-6*13=55°

option A.55°

Answer:

y = 25

Step-by-step explanation:

Given y = kx and k = 5 then

y = 5x ← equation of variation

When x = 5 , then

y = 5 × 5 = 25

The equation of the line will be y = 1/3x. The correct option is F.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

The slope of the line is calculated as,

[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]

The two points are (6,2) and (0,0). Calculate the slope of the line,

[tex]m = \dfrac{0 - 2}{0-6}[/tex]

m = 1 / 3

The equation of the line can be written as,

y = mx +c

y = 1/3x + 0

y = 1/3x

To know more about an equation of the line follow

https://brainly.com/question/18831322

#SPJ7

Answer:

12 liters per min

Step-by-step explanation:

Math

27/4 = x

9/16      1

27/4=(9/16)x

Divide both sides by 9/16

12=x