Answer:
yes it is the 10th term in the series
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 7 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{14}{7}[/tex] = 2 , then
[tex]a_{n}[/tex] = 7 [tex](2)^{n-1}[/tex]
Equate [tex]a_{n}[/tex] to 3584 and solve for n
7 [tex](2)^{n-1}[/tex] = 3584 ( divide both sides by 7 )
[tex]2^{n-1}[/tex] = 512 , that is
[tex]2^{n-1}[/tex] = [tex]2^{9}[/tex]
Since the bases on both sides are equal, both 2 , then equate the exponents
n - 1 = 9 ( add 1 to both sides )
n = 10
3584 is the 10th term in the series
THIS QS with explanation sum
Answer:
X = 276°
Step-by-step explanation:
Divide X into x1 and x2
then then using the trick of co-interior angles, find the answer of x1 and x2 . then add x1 and x2
Solve the equation 5x + 2(2x -23) = -154
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
5x+2(2x-23)=-1545x+4x-46=-1549x-46=-1549x=-154+469x=-108x=[tex]\sf{\dfrac{-108}{9} }[/tex] x=-12Answer:
x = -12
Step-by-step explanation:
5x + 2(2x - 23) = -154
Distribute;
5x + 4x - 46 = -154
Collect like terms
9x - 46 = -154
Add 46 to both sides;
9x = -108
Divide both sides by 9
x = -12
Which of the following is the number of sides for a regular polygon that will
not form a regular tessellation?
A. 6
B. 4
C. 7
D. 3
Answer:
A
Step-by-step explanation:
A
The number of sides for a regular polygon that will not form a regular tessellation is 7. The correct option is C.
What is a polygon?A polygon is a planar figure characterised by a limited number of straight-line segments joined to create a closed polygonal chain in geometry. A polygon is defined as a bounded planar region, a bounding circuit, or both.
A tessellation or tiling is the seamless covering of a surface, frequently a plane, with one or more geometric shapes, known as tiles. One regular polygon can be used to create a single regular tessellation. Two or more regular polygons are used in a semi-regular tessellation.
Triangles, squares, and hexagons are the only three regular tessellations.
Now, the name of the polygon having 3, 4, and 6 sides is triangle, square, and Hexagon. Therefore, the only regular polygon that will not form a regular tessellation is heptagon, which has 7 sides.
Hence, the number of sides for a regular polygon that will not form a regular tessellation is 7.
Learn more about Polygon here:
https://brainly.com/question/10441863
#SPJ2
7. If the supplement of an angle is 69, then find its complement.
Answer:
no solution
Step-by-step explanation:
Supplementary angles add to 180
Let x be the supplement
x+69 = 180
x = 180-69
x =111
The complement of an angle means they add to 90
111+y = 90
y = 90-111
y =-21
But an angle cannot be negative so there is no solution
Answer:
21 degrees.
Step-by-step explanation:
To find the complementary angle you have to subtract the given angle from 90.
so,
90 - 69 = 21.
Extra info: if you need to find the supplementary angle you need to subtract the given angle from 180.
Use the distributive property to write equivalent expressions.
Someone please help ty!
Answer:
12+27k
Step-by-step explanation:
distribute the 3
Instructions: Find the measure of the indicated angle to the nearest degree.
29 and 17
Answer:
30º
Step-by-step explanation:
because it is a right triangle, we can use trig functions to solve
tan^{-1}=17/29=30.379
find the scale factor
Answer:
I think its 1.4
Step-by-step explanation:
if you divide 42 by 1.4 it makes 30 and if u multiply 30 by 1.4 it makes 42
Answer:
the scale factor is 7/5
Step-by-step explanation:
42/30=
42/30=
then you find a common factor between the two is 6, so you divide both sides of the fraction by 6 to get 7/5. and because they both are the same you know that they both have the same scale factor. Which is 7/5. I am not quite sure if you need to find the missing side length but in case you do multiply 40 by 7/5 so it looks like 40/1 x 7/5. 40 x 7 = 280. 280/5 = 56. so your side length is 56.
Will it matter if I don’t get accelerated pre algebra in 7th grade and get into normal pre algebra? Will it make me less likely to get into top colleges?
Answer:
Maybe, there is a chance, but I don't know for sure.
It might matter, but I wouldn't worry or stress about it too much.
My only advice to you is do not procrastinate and if you need help don't be afraid to ask.
Answer:
It matters but not like you think.
GPA, extracurricular activities, and SAT/ACT are the biggies. Truthfully it won't change a thing if you took accelerated pre-algebra versus normal. In fact, spoiler alert, the SAT/ACT (I'm assuming your american) will matter more than your courses ever did. I took two years of college physics in highschool and i made more off my SAT. Not only that, but an A in an easy class looks better than a C in a hard one on transcripts.
My advise is slow down, relax, and learn it well. Better to learn the concept fully in normal so that you can apply it, than half learn it in advance and struggle in future applications. After all, math ALWAYS builds. Take it slow, take it easy.
I would recommend talking to a school guidance counselor about your academic stress. Im sure their professional insight will help put you at ease. It may also help to get you going in the right direction so that you achieve your goals.
Good luck. Enjoy life
Omg who can help me? Its due tomorrow
What is the vertex of the function f(x) = -|x + 7| − 4?
A.
(-7,-4)
B.
(7,4)
C.
(-7,4)
D.
(7,-4)
Answer:
it would be
D.
(7,-4)
Mark me as brainliest pleases
Answer:
it would be A (-7,-4)
Step-by-step explanation:
simplify m√p + n√p - √p
Answer:
[tex]{ \tt{m \sqrt{p} + n \sqrt{p} - \sqrt{p} }} \\ = { \tt{ \sqrt{p}(m + n - 1) }}[/tex]
would appreciate the help please!
Answer:
I think SAS is the correct Ans
Integrate the following.[tex]\int\limits^a_b {sin(x)} \, dx[/tex]
Answer: -cos(a)+cos(b)
Step-by-step explanation:
To integrate is the same as saying to find the antiderivative.
[tex]\int\limits^a_b {sin(x)} \, dx[/tex] [antiderivative of sinx is -cosx]
[tex]-cos(x)|_b^a[/tex] [include boundaries]
[tex]-cos(a)+cos(b)[/tex]
Therefore, the integral would be -cos(a)+cos(b).
How do you solve this step-by-step?
Answer:
7 1/20OAmalOHopeO
Identify the equation of the circle that has its center at (9, 12) and passes through the origin.
Answer:
(x-9)^2 +(y-12)^2 = 225
Step-by-step explanation:
First find the length of the radius
If is the distance from the center to the point
d = sqrt( (x2-x1)^2 + (y2-y1)^2 )
= sqrt( (0-9)^2 + (0-12)^2)
= sqrt ( 81+144)
= sqrt(225)
= 15
The equation for a circle is
( x-h) ^2+ (y-k)^2 = r^2
(x-9)^2 +(y-12)^2 = 15^2
(x-9)^2 +(y-12)^2 = 225
When the polynomial is written in standard form, what are the values of the leading coefficient and the constant?
5x + 2 – 3x2
Answer:
leading coefficient -3
constant 2
Step-by-step explanation:
Standard from is from largest power to smallest power
-3x^2 +5x +2
The leading coefficient is the number in front of the largest power of x
-3
The constant is the number without a power of x ( or x^0)
2
Solve the system of equations using substitution.
y = x + 6
y = –2x – 3
Answer:
x = -3
y= 3
Step-by-step explanation:
y = x + 6 -----------------------(I)
y = -2x - 3 ---------------------(II)
Substitute y =x +6 in equation (II)
x + 6 = -2x - 3
Add 2x to both sides
x + 2x +6 = -3
Combine like terms
3x + 6 = - 3
Subtract 6 from both sides
3x = - 3 - 6
3x = -9
Divide both sides by 3
x = -9/3
x = -3
Plug in s = -3 in equation (I)
y = -3 + 6
y = 3
What is the exponential form of log3 2187 = 7?
Answer:
2187 = [tex]3^{7}[/tex]
Step-by-step explanation:
Using the rule of logarithms
[tex]log_{b}[/tex] x = n , then x = [tex]b^{n}[/tex] , then
[tex]log_{3}[/tex] 2187 = 7
2187 = [tex]3^{7}[/tex]
Answer:
3 ^7 = 2187
Step-by-step explanation:
log3 2187 = 7
log a (b) = c
a^c = b
3 ^7 = 2187
at a post office always charges a flat one-time fee for any order. One time, Michael sent 35 letters and paid 26 dollars. The next time, he send 18 letters and paid $14.10. How much does the post office charge to send one letter? What is the flat fee?
Answer:
The post office charges $0.7cents to send one letter, and the fee is $1.5
Step-by-step explanation:
Please help 50 points!
d=10
Answer:
Solution given:
[tex]\sqrt{25+3x}=d+2x[/tex]
squaring both side
25+3x=(d+2x)²
when x=-3
25+3*-3=(d+2*-3)²
25-9=(d-6)²
16=(d-6)²
[tex]\sqrt{16}=d-6[/tex]
4=d-6
d=4-6
d=10
Answer:
d = 6
Step-by-step explanation:
[tex] \sqrt{25 + 3( - 3)} = d + 2( - 3) \\ 4 = d - 6 \\ d = 10[/tex]
hopefully this makes sense
:)
Nick works part-time at a bookstore. His pay varies directly with the number of hours worked. In one week, he earned $120 for 8 hours of work.
a) Define two variables for this relation.
b) Describe the rate of change in words.
c) Determine an equation to represent the relation:
d) Use the equation to determine how many hours Nick must work to earn $345
Answer:
23 hoiurs
Step-by-step explanation:
Given data
a. The two variables are
1. Number of hours worked
2. The amount earned
b. The rate is given as
=120/8
=$15 per hour
c. The equation is given as
rate=Amount earned/ number of hours worked
15= 345/hours
make hours subject of the formula we have
hours= 345/15
hours= 23 hours
Hence he must work for 23 hours
Which shows the following expression after the negative exponents have been eliminated?
Answer:
Option A
Step-by-step explanation:
[tex]\frac{1}{a^{-m}}=a^{m}\\[/tex]
[tex]\frac{m^{7}n^{3}}{mn^{-1}}=\frac{m^{7}n^{3}n^{1}}{m}=\frac{m^{7}n^{3}n}{m}[/tex]
Calculate the answer without using a calculator
g) cos 180° + 2 fan 30 sin 60
Answer:
0
Step-by-step explanation:
Tan 30 and Sin 60 are in first quadrant and so their values will be positive.
Cos 180 is in Second quadrant. In second quadrant , value of cos is negative.
Cos 180 = -1 ; Tan 30 = 1/√3 & Sin 60 = √3/2.
Cos 180 + 2 tan 30 + Sin 60 = [tex]-1 + 2* \frac{1}{\sqrt{3}}*\frac{\sqrt{3}}{2}[/tex]
= [tex]-1 + 1 = 0[/tex]
If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the nearest hundredth.
Answer: [tex]7.93[/tex]
Step-by-step explanation:
Given
[tex]f(x)[/tex] is an exponential function. Suppose [tex]f(x)[/tex] is [tex]ae^{bx}[/tex]
[tex]f(1.5)=5\ \text{and}\ f(7.5)=79[/tex]
[tex]\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)[/tex]
Similarly,
[tex]\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)[/tex]
Subtract (i) and (ii)
[tex]\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066[/tex]
Insert the value of [tex]b[/tex]
[tex]\Rightarrow 5=ae^{0.46}\\\Rightarrow a=5\times 0.6312\\\Rightarrow a=3.156\approx 3.16[/tex]
So, the function becomes
[tex]\Rightarrow f(x)=3.16e^{0.3066b}[/tex]
[tex]\Rightarrow f(3)=3.16e^{0.3066\times 3}\\\Rightarrow f(3)=7.927\approx 7.93[/tex]
Answer:
7.93
General Exponential Form: y=ab^x
Plug in both points
divide the equations
cancel out a, subtract exponent of b
HELP PLEASEEE!!!! ASAP!!!!!
To find the inverse of a function, switch the x's and y's, then solve for y again.
y = 2/3x - 17
SWITCH
x = 2/3y - 17
2/3y = x + 17
y = 3(x + 17) / 2
y = x - 10
SWITCH
x = y - 10
y = x + 10
y = cuberoot(2x)
SWITCH
x = cuberoot(2y)
x^3 = 2y
y = x^3 / 2
y = x/5
SWITCH
x = y/5
y = 5x
Hope this helps!
A particular strain of bacteria triples in population every 45 minutes Assuming you start with 50 bacteria in a Petri dish how many bacteria will there be in 4.5 hours
Answer:
4.5 hours in minutes = 270
Every 45 minutes, bacteria triples
You start with 50
Divide 270 (total time) by 45 (every time bacteria triples)
270/45 = 6
36,450 bacteria
its given that s=n(a+c)/2
Express c in terms of s, n and a
{(5,2), (-2,4), (2, -7)}
Domain:
Range:
Answer:
Step-by-step explanation:
The domain are all the x values in order, no repeats allowed:
D = {-2, 2, 5}
Same thing for the range, except these are the y values:
R = {-7, 2, 4}
The coordinates stated this way don't match up to what they are in coordinate form, but they don't have to.
Answer:
Domain : {-2,2,5}
Range:{ -7,2,4}
Step-by-step explanation:
The domain is the inputs
Domain : {-2,2,5}
The range is the outputs
Range:{ -7,2,4}
A boy spent 2/7 of his pocket money on transport and 1/5 on sweet. if he left with 20. what is the amount of money in the boys pocket
Answer:
x = 350
Step-by-step explanation:
x - starting amount
[tex]\frac{2}{7} x[/tex] = after transport
[tex]\frac{1}{5} (\frac{2}{7} x)[/tex] = after sweets
[tex]\frac{1}{5} (\frac{2}{7} x)[/tex] = 20
[tex](\frac{2}{35} x)[/tex] = 20
2x = 700
x = 350
Please Solve:
x^2-4x-5=0