Need a little help with this one

Answer

500,000 + 500,000 = 1,000,000

Step-by-step explanation:

Answer:

6x + y

Step-by-step explanation:

6x + 3y/3​

6x + y

Answer:

6x + y

Step-by-step explanation:

6x + 3y / 3

cancel 3y by 3

6x + y

Answer:

0.18431525 = 18.4%

Step-by-step explanation:

General Formula :

total trials Cn⋅p(success)^n⋅p(fail)^total−n

1198144* (.0218)^3 * (1-.0218)^191

Step-by-step explanation:

Part A:

The two factors in 9(7+2x) are 9 and 7+2x

Part B:

First term: 9

Second term: 7+2x

Part C:

9(7+2x)

Open bracket

63+18x

The coefficient is 18x

A. The two factors are 9 and (7+2x).

B. In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

C. The coefficient of the variable term is 18.

Given expression is;

                         [tex]9(7+2x)[/tex]

In given expression, there are two factors fist is 9 and second one is [tex](7+2x)[/tex]

In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.

To find the coefficient of variable term, we have to to expand given expression.

             [tex]9(7+2x)=63+18x[/tex]

The coefficient of the variable term is 18.

Learn more about the algebraic expression:

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Answer:

linear function

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The graph is a straight line, so it's a linear function.

Answer: B

Answer:

yeah u forgot to add the picture ig

Answer:

5b^2-(5+6)b+6=0

5b^2-5b-6b+6=0

5b(b-1)-6(b-1)=0

(5b-6)(b-1)=0

either

(5b-1)=0

5b=1

b=1/5

or

b-1=0

b=1

Step-by-step explanation:

firstly find out the mid term factor i e in above qn 11 should be break down so that its multiple should be coefficient of b and constant and additiqn should be equals to 11 .so we find out 5 and 6

Answer:

[tex]31y^{3} -28y^{2}[/tex]+35y

Step-by-step explanation:

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

Answer:

Discrete random variable.

Step-by-step explanation:

Answer:

division is right i hope you understand

9514 1404 393

Answer:

  Multiplication

Step-by-step explanation:

The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.

Jaylene got back ...

  90% × $20 = $18

Answer:

4075

Step-by-step explanation:

Answer:

p=c(1+r)^t so the population will be 4679.43424 or rounded to 4679

Step-by-step explanation:

p=c(1+r)^t

p=4,000(1+.04)^t

p=4,000(1.04)^t

p=4,000(1.04)^4

p=4679.43424

p= the population you are solving for

c= the initial amount of the population

(1+r)= the rate of change

t= the period of time

The exponential equation that represents the population of the town in terms of the number of years : [tex]p=4000 (1+0.4)^{t}[/tex]

An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.

It is similar to the amount received after investing a certain amount compounded annually.

Given,

Initial population = 4000

Rate of increase = 4%

Let current population be p.

Let number of years passed be t.

The exponential equation will be: [tex]p=4000 (1+0.4)^{t}[/tex]

(The population of the town has grown exponentially. This means that:

Initial population = 4000

Population in year I = 4000 + 4% of 4000 = 4000(1 + 0.4)

Population in year II = 4000 + 4% of 4000(1 + 0.4) = 4000(1 + 0.4)(1+0.4)

and this goes on.)

Learn more about exponential equation here

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Answer:

the operating characteristics have been solved below

Step-by-step explanation:

we have an average of 10 minutes per customers

μ = mean service rate = 60/10 = 6 customers in one hr

the average number of customers that are waiting in line

mean arrival λ = 2.5

μ = 6

[tex]Lq = \frac{2.5^{2} }{6(6-2.5)} \\[/tex]

= 6.25/21

= 0.2976

we calculate the average number of customers that are in the system

[tex]L=Lq+\frac{2.5}{6}[/tex]

= 0.2976+0.4167

= 0.7143

we find the average time that a customer spends in waiting

[tex]Wq=\frac{0.2976}{2.5}[/tex]

= 0.1190 hours

when converted to minutes = 0.1190*60 = 7.1424 minutes

[tex]0.1190+\frac{1}{6}[/tex]

=0.2857

probability that arriving customers would wait for the service

= 2.5÷6 = 0.4167

Answer:

$10

Step-by-step explanation:

5 toys = $1

Zach wants 50 of these

50 ÷ 5 = 10

10 x 1 = 10

= $10

Answer:

10 dollars

Step-by-step explanation:

We can use a ratio to solve

5 rings     50 rings

----------  = --------------

1 dollar         x dollars

Using cross products

5*x = 1 * 50

5x = 50

Divide by 5

5x/5 = 50/5

x = 10

Answer:

z(max) =  2996.13  $

x₁  = 968      x₂  =  430       ( quantities of regular and Decaf coffee respectevely)

Total quantity of BN = 898 pounds

Total quantity of CM =  500 pounds

Step-by-step explanation:

Cost of the beans

Brazilian natural   =  Price market + 10 %    =  0.47 + 0.047  

BN  Cost   = 0.517 $/lb

Clombian Mild      =  Price market + 10 %    =  0.62  +  0.062

CM Cost   =  0.682  $/lb

Composition of the coffee blend

Regular coffee     0.75 BN  +  0.25 CM

De Caf   coffee     0.40 BN + 0.60  CM

PRICES

Regular Roman  =  3.60  $

Decaf                   =  4.40  $

Production costs:

Regular Roman  =  0.80  $/lb

Decaf                   =  1.05  $/lb

Packaging costs:   0.25  $/Lb       both

Profit  =  Price  -  cost

Profit  of regular coffee  =  3.60 - 0.80 - 0.25 -Cost of bean

for regular coffee cost of BN + CM

BN   is :   0.75*BN cost  = 0.75*0.517  =  0.38775       and

CM  is : 0.25*0.682   =   0.1705

Profit  of regular coffee  =  1.99175  $

Profit for Decaf coffee  =  4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)

Profit for Decaf coffee  =  4.4  - 1.30 - 0.616

Profit for Decaf coffee  =  2.484  $

Let´s call  x₁  pounds of regular coffee   and  x₂   pounds of Decaf coffee then:

 Objective Function is:  

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

Availability of beans for 1000 pounds of Regular coffee means:

750 pounds of BN  +  250 pounds of CM

Availability of beans for 500 pounds of Decaf coffee means

200 pounds of BN  +   300 pounds of CM

Then   750 + 200  =  900 pounds of BN

And     250 + 300 =  550  pounds of CM

Availability of beans for 1000 pounds of Decaf  coffee correspond to

0.75 *x₁  +  0.40*x₂  ≤ 900

Availability of beans for 500 pounds of Regular  coffee correspond to

0.25*x₁  +  0.60*x₂  ≤ 500

Then the model is:

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

0.75 *x₁  +  0.40*x₂  ≤ 900

0.25*x₁  +  0.60*x₂  ≤ 500

General constraints  x₁ ≥ 0      x₂ ≥   0  both integers

After 6 iterations optimal solution  ( maximum z) is

z(max) =  2996.13  $

x₁  = 968      x₂  =  430  

x₁   and  x₂  are quantities of  Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild

we proceed as follows

Regular coffee is :  0.75*968 =   726 pounds of BN

Decaf coffee is :      0.40*430 =   172  pounds of BN

Total quantity of BN = 898 pounds

Regular coffee is :  0.25*968   =  242 pounds of CM

Decaf coffee is :  0.6*430  =  258 pounds of CM

Total quantity of CM =  500 pounds

The cordent plan of the answer is 2

Answer:

The scale factor will just be 2

Step-by-step explanation:

The length of PQ is twice as larger than the length of AB.

so from 12 to 6 or 6 to 12, we multiply 6 by 2 which equals to 12

Answer:

113.1 =VOLUME , 4/3 X 3.14 (3) ^3 = 113.1

Answer:

[tex]x = 77[/tex]

Step-by-step explanation:

Given

[tex]First \to Second[/tex]

[tex]35 \to x[/tex]

[tex]20 \to 44[/tex]

[tex]20 \to 44[/tex]

Required

Find x by SSS

Represent the triangle sides as a ratio

[tex]35 : x = 20 : 44[/tex]

Express as fraction

[tex]\frac{x}{35} = \frac{44}{20}[/tex]

Multiply by 35

[tex]x = \frac{44}{20} * 35[/tex]

[tex]x = \frac{44 * 35}{20}[/tex]

[tex]x = \frac{1540}{20}[/tex]

[tex]x = 77[/tex]

Answer:

ccccccccccccccccccccccccccc

Step-by-step explanation:

Answer:

58.80

Step-by-step explanation:

84 x .7(70%) =58.80

Answer:

The numerical values of the circumference and area of the circle are equal.

Answer:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Step-by-step explanation:

Given

[tex]\triangle ABD \cong \triangle CBD[/tex]

Required

The congruent segments by CPCTC

From the question, we have:

[tex]\angle ADB \cong \angle CDB[/tex] --- given

[tex]\angle DBA \cong \angle DBC[/tex] --- given

Both triangles share a common side (length BD);

So, we have:

[tex]BD = BD[/tex]

Hence, the congruent segments are:

[tex]\angle ADB \cong \angle CDB[/tex]

[tex]\angle DBA \cong \angle DBC[/tex]

[tex]BD = BD[/tex]

Answer:

No, a quadrilateral with the given vertices is not  an isosceles trapezoid.

Step-by-step explanation:

We are given that

A(3,3), B(5,3), C(8,1), D(1,1)

Slope formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]

Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]

Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]

Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]

Slope of AB=Slope of CD

When slopes of two lines are equal then the lines are parallel.

Therefore, AB is parallel to CD.

When one pair of quadrilateral is parallel then the  quadrilateral is trapezoid.

[tex]\implies [/tex]ABCD is a trapezoid.

Distance formula:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]

Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units

Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]

Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]

Length of AD is not equal to length of BC.

Hence, trapezoid is not an isosceles trapezoid.

Answer:

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Step-by-step explanation:

Given

[tex]n = 3[/tex]

[tex]B \to boys[/tex]

[tex]G \to girls[/tex]

[tex]P(G) = P(B) = 0.5[/tex] --- equal probability

See comment for complete question

Required:

[tex]P(At\ least\ one\ girl)[/tex]

To do this, we make use of complement rule:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

The event that there is no girl out of the 3 children is: B B B

And the probability is:

[tex]P(No\ Girl) = P(B) * P(B) * P(B)[/tex]

[tex]P(No\ Girl) = 0.5*0.5*0.5[/tex]

[tex]P(No\ Girl) = 0.125[/tex]

So:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

[tex]P(At\ least\ one\ girl) = 1 - 0.125[/tex]

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Answer:

The answer is 10, hope this helps!

Step-by-step explanation:

Answer:

64in^3

Step-by-step explanation:

6×3 = 18

18×2 = 36

4×7 = 28

36+28 = 64

Hope this helps! :)

Answer:

Add equations A and C to eliminate y and add B and C to eliminate y

Step-by-step explanation:

From the equation given, we can see that the coefficient of y in A and C are alternating values 5 and  -5 which cancels out on adding same for B and C. Hence t eliminate y, we will add B and C and A and C

Therefore the correct answer will be to eliminate add equations A and C to eliminate y and add B and C to eliminate y

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

[tex] {3}^{2} = 9[/tex]

8 is a multiple of 4, and 9 is more than 8.

[tex] {11}^{2} = 121[/tex]

120 is a multiple of 4 and 121 is one more than it.

[tex] {25}^{2} = 625[/tex]

624 is a multiple of 4 and 625 is one more than it.

[tex] {37}^{2} = 1369[/tex]

1368 is a multiple of 4 and 1369 is one more than 1368.

[tex] {131}^{2} = 17161[/tex]

17160 is a multiple of 4.

Answer:  13.2

In fraction form, this is 66/5

=============================================================

Explanation:

The five values are in the ratio 1:2:3:4:5 which scales up to 1x:2x:3x:4x:5x for some positive number x.

Add up the pieces of the second ratio and set that sum equal to 198. Then solve for x.

1x+2x+3x+4x+5x = 198

15x = 198

x = 198/15

x = 66/5

x = 13.2 is the smallest number since 1x = 1*13.2 = 13.2 was the smallest value of the ratio 1x:2x:3x:4x:5x.