plz answer please please plz

Answer:

0.58

Explanation:

Sinẞ = opposite ÷ hypotenuse

Sinẞ = 5 ÷ 8.6

Sinẞ = 0.5814

Sinẞ ≈ 0.58

Answer:    0.58

Explanation:

hope this helps

Fun Fact: Peanuts aren’t technically nuts

Answer: As the temperature increases, the flow time increases.

Explanation: i took the test

The relationship between the variables on this graph is that As the temperature increases, the flow time increases, therefore the correct answer is option B.

It is a scale of temperature used to measure the temperature, the kelvin scale of temperature is also known as the absolute scale of temperature.

The Standard International unit of thermodynamic temperature is the kelvin, often known less frequently as the degree Kelvin. The formal definition of one kelvin is 1/273.16  of the thermodynamic temperature of pure water's triple point.

As shown in the graph as the temperature increase across the X axis the flow time is increasing as well, these two variables are directly proportional to each other.

Thus, The graph shows a link between the variables, showing that when the temperature rises, flow time also rises, hence option B is the proper response.

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Answer:

loco

Explanation:

Distance = 2000m

Time = 35 minutes = 35×60 sec = 2100 sec

We know, Speed = Distance/Time

Therefore, Speed

= 2000m/2100s = 20/21 m/s

Answer: 20/21 m/s

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Answer:

and the power to which the number should be raised:

1.50E2 = 1500

4.167E4 = 41,760

4.167E-4 = .0004176

Mass of the earth = 5.98 * 10^24 kg = 5.98E24 kg

Some examples of scientific notation

Answer:

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Answer:

I want to say 10 seconds but im not 1000% sure

Answer:

Average speed= distance traveled/ time taken.

Explanation:

You shouldn't need any formula, just use common sense. You dummy. It goes 20m 10h half a sec. DUH!!!

We have to convert 12.7nm to cm

[tex]\\ \sf\longmapsto 12.7nm[/tex]

[tex]\\ \sf\longmapsto 12.7\times 10^{-9}m[/tex]

[tex]\\ \sf\longmapsto 0.127\times 10^{-7}m[/tex]

[tex]\\ \sf\longmapsto 0.00000127\times 10^{-2}[/tex]

[tex]\\ \sf\longmapsto 0.0000013cm[/tex]

Answer:

The kinematics equations describe the motion of an object undergoing constant acceleration

Explanation:

The kinematics equations describe the motion of an object undergoing constant acceleration. These equations relate the variables of time, position, velocity and acceleration of a moving object, allowing any of these variables to be solved for if the others are known

Answer:

Explanation:

Good relationships with colleagues. Good work-life balance. Good relationships with superiors. Company's financial stability.

Answer:

2,317

Explanation:

on e

Speed varies with Distance travelled w.r.t time

[tex]\boxed{\sf Speed=\dfrac{Distance}{Time}}[/tex]

Whereas velocity varies with displacement w.r.t time.

[tex]\boxed{\sf Velocity=\dfrac{Displacement}{Time}}[/tex]

Answer:

W = F × d

W = 1 × 1

W = 1 Joule

step by step explanation

An apple is having a force of 1 N and it travels to a distance of 1 m then the work done on the apple by the force of gravity will be equal to 1 J.

Work is a physics term used to describe the transfer of energy that occurs when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the strong acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.

Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the pressure is applied at an angle with regard to displacement.

As per the given information in the question,

Force, f = 1 N

Distance, d = 1 m

Then, the work done will be,

W = fd

W = 1 × 1

W = 1 J.

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Answer:

b=t-p(m-n)/s

Explanation:

[tex]\boxed{\sf 1g=1000mg}[/tex]

[tex]\\ \sf\longmapsto 80g[/tex]

[tex]\\ \sf\longmapsto \dfrac{80}{1000}[/tex]

[tex]\\ \sf\longmapsto 0.08g[/tex]

i dont know for real

We have that for the question, Does a cat’s heart rate change while it is napping?

Cats heart rate do not increase while napping.

The range of heart beat of a cat is 140 and 220 bpm

From the Question we are asked

Does a cat’s heart rate change while it is napping.

The answer is NO

Cats heart rate do not increase while napping. Cat have a normal heart beat maximum of 220 beats per minute consistently.The range of heart beat of a cat is 140 and 220 bpm

Therefore

There is something with a cat with heart rate above this number.

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Answer:

The coil spring of a wind-up clock.

An archer's stretched bow.

Explanation:

the answer for 0.429m to mm is 429

Answer:

0.429m=429 mm

Explanation:

Since there are 1,000 millimeters per meter, you need to multiply by 1,000 to convert from meters to millimeters.

Answer:

Explanation:

The total number of protons in the nucleus of an atom gives us the atomic number of that atom. It is represented with the letter ‘Z.’ All the atoms of a particular element have the same number of protons, and hence the same atomic number. Atoms of different elements have different atomic numbers.

Answer:

Accuracy is how close a measured value is to an accepted value. Precision is how close measurements are to one another. To make measurements, you have to evaluate both the accuracy and the precision to get a correct value.

Answer:

Explanation:

Givens

vi = 50 m/s

vf = 0

a = - 9.81

t = ?

Formula

t = (vf - vi)/a

Solution

t = (0 - 50)/-9.81

t = 5.097

Notice that a is made into a minus. It does not mean subtract. It means that the direction of the projectile and gravity must go in opposite directions. You will find that direction is a critically important consideration in physics.

Answer:

It'd take it 5.10 seconds

Explanation:

At the top of the launch, it is maximum height, h

formular derivation :

At maximum height, final velocity, v is zero

From first newtons equation:

[tex]{ \sf{v = u + gt}}[/tex]

v is the final velocity

u is the initial velocity

g is acceleration due to gravity

t is the time taken

but v is zero:

[tex]0 = u + gt \\ gt = u \\ t = \frac{u}{g} [/tex]

since it is vertical motion, u = usin(theta), where angle is 90°

[tex]{ \boxed{t = \frac{u \sin( \theta) }{g} }}[/tex]

t is the time taken to reach the top of the launch:

substitute, taking g to be 9.8 m/s²

[tex]t = \frac{50 \times \sin(90 \degree) }{9.8} = \frac{50}{9.8} \\ \\ { \boxed{ \boxed{time = 5.10 \: seconds}}}[/tex]

Answer:

No.b answer

the ratio of the length of the lever arm where the force is applied divided by the length of the lever are that lifts the load.

No.1 answer

if there is no friction in a simple machine, work output and work input are found to be equal in the machine.

No.3 answer

machine that is 75% efficient means that 75% of the work input is obtained as the useful output and the remaining 25% has been lost in overcoming the friction.

No.4 Answer

A lever is a simple machine made of a rigid beam and a fulcrum. In 3 calss lever is classified.

Simple pulleys change the direction of the force used to lift an object over a distance.

ratio of distance travelled by effort to the distance travelled by load in the machine.

Hope this will help you alot

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keep smiling

Answer:

In atomic physics, the spin quantum number is a quantum number (designated ms) which describes the intrinsic angular momentum (or spin angular momentum, or simply spin) of an electron or other particle.

Answer:

kilogram

Explanation:

Answer:

[tex]300[/tex] cm are equivalent to [tex]3[/tex] m.

Explanation:

[tex]100[/tex] cm are equivalent to [tex]1[/tex] m.

[tex]100 \mathrm{~cm}$=1{~m}$[/tex]

[tex]3 \mathrm{~m}$=3\times100[/tex]

[tex]=$300{~cm}$[/tex]

To convert meters ([tex]\mathrm{~m}$[/tex]) into number of centimeters ([tex]\mathrm{~cm}$[/tex]), multiply that number by [tex]100[/tex].

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Answer:

32,000

Explanation:

There are 1,000 bytes in each kilobyte, so therefore 32,000 bytes are transferred each second.

We have that the gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

[tex]V_2=0.18L[/tex]

From the Question we are told that

Initial Pressure [tex]P_1=720[/tex]

final Volume  [tex]V_1=200mL[/tex]

Initial Pressure [tex]P_2=800[/tex]

final Volume  [tex]V_2=?[/tex]

Generally the equation for Boyle's law  is mathematically given as

[tex]P_1V_1= P_2V_2[/tex]

Therefore

[tex]V_2=\frac{ P_1V_1}{P_2}\\\\V_2=\frac{ 720*200}{800}\\\\V_2=180mL[/tex]

[tex]V_2=0.18L[/tex]

The gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

[tex]V_2=0.18L[/tex]

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