Answer:
Crossing over
Explanation:
Prokaryotic cells are cells that do not possess a membrane bound nucleus to house their genetic material e.g bacteria while eukaryotic cells possess a membrane bound nucleus that houses their genetic material e.g plants.
One important characteristics of prokaryotic cells is that they do not undergo any form of sexual reproduction, hence, cannot undergo MEIOSIS, which only occurs in sexual reproducing organisms. Prokaryotes reproduce asexually by binary fission.
Crossing over is a unique process that only occurs during meiosis. Since prokaryotic cells do not undergo meiosis, this means that crossing over is the difference between prokaryotic cells and eukaryotic cells in this question.
A 45-year-old woman named Christine is measured as having the following skinfold thicknesses on the right side of her body: Triceps: 14mm; Thigh: 32mm; Suprailium: 28mm. Estimate her body fat percentage.
Answer:
The skinfold method, the measurement of subcutaneous fat folds, is the most widely adopted field method for the assessment of body fat, especially in children.
It is based on the principle that fat is of a known density and by “summing” measurements of subcutaneous fat thickness across the body, total and regional fat can be estimated.
Skinfold thickness measurements are typically used to rank individuals in terms of relative total “fatness”, or to assess subcutaneous fat at various regions of the body.
Population specific equations are used to derive estimates of percent body fat.
In infancy, it might be the sole tool available for assessing body composition longitudinally as other methods may not be feasible, or may only be suitable for use at body sizes e.g. PEA POD, can only measure infants up to 10kg.
The most generally used field method for determining body fat, particularly in kids, is the skinfold method, which involves measuring subcutaneous fat folds.
What is skinfold method?Skinfold method is defined as a method for determining how much body fat there is. It entails delicately pinching the skin and underlying fat in several locations using a tool called a caliper. To acquire precise findings using this quick and easy body fat estimation technique, a high level of competence is needed.
It is based on the idea that since subcutaneous fat thickness measurements may be "summed" to estimate total and regional fat because subcutaneous fat has a known density. Measures of skinfold thickness are widely used to categorize individuals based on their relative degrees of overall "fatness" or to assess subcutaneous fat in various bodily regions. Estimates of the percent body fat are derived using equations that are specific to a population.
Thus, the most generally used field method for determining body fat, particularly in kids, is the skinfold method, which involves measuring subcutaneous fat folds.
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In female gamete development in humans and other vertebrates, the net result of meiosis is the production of one large egg and three small cells with very little cytoplasm. These three small cells?
In a test cross, a pure-breeding plant is crossed with a plant suspected to be heterozygous (Aa). What is the genotype of the pure-breeding plant?
Answer:
aa
Explanation:
In genetics, a test cross is a cross performed to determine the unknown genotype of a phenotypically dominant organism. The test cross is done by crossing the unknown genotype with a homzygous recessive organism. The result of this cross tell us whether the unknown genotype is heterozygous or homzygous dominant.
According to this question, a test cross was conducted involving a pure breeding plant with a plant suspected to be heterozygous (Aa). Based on the explanation of a test cross above, the genotype of the pure-breeding plant will be "aa". Note; it must be recessive.
i.Name two heart diseases in humans.
ii.State three causes of heart diseases.
Answer:
Arrhythmia
Atherosclerosis
Common causes of heart diseases
Diabetes.
Drug abuse.
Excessive use of alcohol or caffeine.
High blood pressure.
characteristics of Pisces
Answer:
Pisces are known as amazingly imaginative, creative, empathetic, and kind, they can also be overly sentimental, impressionable, and closed off.
Explanation:
Hope this helps!
II. Sequencing Directions: Arrange the procedure/steps to fold a banana table napkin by writing 1 to 8 on the blank before the number.
Repeat the last step with the left side, folding the left tip up to the far corner, creating a diamond shape with a seam running down the center.
Fold the right end up to meet the far corner, ensuring the edge of this new fold lays on the centerline as shown.
Stand it up and tug at it where needed to even it up and out. If your napkins are too limp, then think of starch as a napkin and make them good and stiff round it.
Lay the napkin face down in front of you. Curl the left and right sides of the napkin up so they meet in the middle and tuck one into the other.
Fold the bottom of the napkin up about 2/4's of the way and press this fold down well. Fold the napkin in half diagonally. Orient the napkin so the open ends point away from you.
Fold the smaller triangle down so the point rests on the near edge of the napkin. Press.
Can you please answer it for me
Please if someone know
Explanation:
Lay a square napkin down on a clean work surface so that it's open all the way. Iron if needed.
STEP 2: FOLD IN DIAGONAL HALF
Grab a hold of the right hand corner nearest you and fold it over to meet the opposite upper left corner. Straighten out the edges so that they all meet up.
STEP 3: TURN IT
Turn the triangle so that the longest side is parallel to you and the table's edge.
STEP 4: FOLD IN
Fold the left corner in so that it sits JUST past the midway point of the long side of the triangle, like pictured.
STEP 5: FOLD IN AGAIN
Now repeat for the right hand corner.
STEP 6: FOLD OVER
Take the lower left corner and bring it in to the bottom midpoint of the now 'house' shaped napkin. Press the new left side fold down.
STEP 7: FOLD OVER AGAIN
Repeat on the right side.
STEP 8: FOLD UP
Take both bottom corners and bring them up to rest just below the top right corners. Press down the new folds.
STEP 9: CLOSE THE ENVELOPE
Take the top point of the envelope 'flap' and bring it down (or close it) to complete the envelope.
STEP 10: ADD A PERSONALIZED CARD
Use your envelope napkins to include a personalized 'letter' or card to each guest's plate. Some ideas for what this could be are:
holiday greeting card
menu
place card
family photos from past celebrations
holiday story or poem
coloring cards with pencil crayons for kids
game cards: trivia, scavenger hunt, etc
Can someone help me with this pls
Which of the following results in agglutination?
(1) similar blood types being mixed
(2) the separation of blood cells from plasma
(3) antigens reacting to other antigens
(4) antibodies reacting to foreign antigens (5) the donation of blood to a blood bank
Answer:
your answer is antibodies reacting to foreign antigens.
The protein calcineurin binds to the protein calmodulin with an association rate of 8.9 × 103 M-1s-1 and an overall dissociation constant, Kd, of 10 nM. The dissociation rate kd is:_____. Please explain step by step.
A. 8.9 × 10^3 M-1s-1
B. 8.9 × 10^2 s-1
C. 1.1 × 10-10 s-1
D. 8.9 × 10-5 s-1
Answer:
D
Explanation:
From the information given:
Association rate [tex]K_a[/tex] = [tex]8.9 \times 10^3 M^{-1}s^{-1}[/tex]
dissociation constant [tex]K_D[/tex] = 10 nM
dissociation rate [tex]K_d[/tex] = ???
Using the following relation from equilibrium dissociation constant to determine the dissociation rate, we have:
[tex]K_D =\dfrac{ K_d}{K_a}[/tex]
[tex]K_d = K_D \times K_a[/tex]
[tex]K_d =(10*10^{-9} \ M) \times (8.9*10^3 \ M^{-1}{s^{-1})[/tex]
[tex]\mathbf{K_d =8.9*10^{-5} \ {s^{-1}}}[/tex]
3.Each onion plant begins as a single cell containing 16 chromosomes. How many chromosomes are present in each of the cells that you observed
Answer:
In somatic cells, 16 chromosomes are present whereas in sex cells, there is 8 chromosomes.
Explanation:
In the somatic cells, the replication of chromosomes occur and after the replication is completed, the parent cell is divided into two daughter cells having double number of chromosome by each daughter cell i.e. 16 chromosomes while on the other hand, in sex cells, first the parent cell divides into two daughter cells and after sometime, these daughter cells are again divided having total four daughter cells each receives half number of chromosomes i.e. 8 chromosomes.
we should conserve environment give reason
Answer:
for healthy living and long life
Writing an Equation in Slope-Intercept Form
Q
Check
y
Determine the equation for the given line in
slope-intercept form
4
O y = -5x-1
=-1
2
X
-6
-4
-2
2
LO
O y = x+1
O y = 3x+1
O y=-x-1
-2
-4
Hint
Answer:
need a full picture plzzz
The extinction vortex represents the idea that even if an organism is extant, it may have a gene pool that will not support its long-term survival.A. TrueB. False
Answer:
True.
Explanation:
Extinction vortex is a model used by scientists to understand extinction dynamics within a community. This model allows scientists to assess and understand how a population can become highly vulnerable to elements of its habitat, becoming increasingly apt for extinction. According to this model, any organism is capable of extinction, as all are susceptible to having a gene pool that will not allow its survival, regardless of the environment.
Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these alleles are at Hardy-Weinberg equilibrium, what is the frequency of the disease-causing CFTR alleles in this population
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
How has the natural environment in your area been affected by the human environment?
Answer:
animals are dying :( and people are hunting
Explanation:
The passage suggests that in designing the experiment, Johnson relied on the fact that A) fungal hyphae warn beanstalks of danger if a nearby plant is attacked. B) wasps are harmful to the ongoing existence of broad bean plants. C) broad bean plants release noxious chemicals to ward off infestation. D) aphids are able to withstand the aggressive maneuvers used by wasps.
One true-breeding line of mice is obese and dark and another is lean and light. Dark is dominant to light, but obese and lean exhibit incomplete dominance. What proportion of offspring from a dihybrid cross should be both dark and intermediate between obese and lean
Answer:
6/16 Intermediate and dark ⇒ 2/16 OoDD + 4/16 OoDd
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
lan insect, a mammal,
as shown below.
2
mammal
1 Animal with your legs reptile
Animal with more than your legs in sect 3
2 Animal with scalles on skin
- reptile
Animal with Eur on skin
3 Animal with six legs ingeet P Р
Animal with more than six legs
Q
1 What name is given to a system of putt
organisms , nto groups or Categione
)
a) state the name of The biologicalk
Answer:
.
Explanation:
Further studies of the genes in the region around the MHC locus identified C4 as a likely causative gene. A particular allele of C4 was significantly associated with schizophrenia. In addition, it was found that individuals with high expression of this allele of C4 had elevated risk of developing schizophrenia. Which of the following variants would be most likely to increase risk of schizophrenia from this allele?
a. a variant that decreases binding of an activating transcription factor to the C4 promoter
b. a 5’ UTR variant that destabilizes the C4 mRNA
c. a duplication of the C4 gene
d. a nonsense coding variant
Answer:
c. a duplication of the C4 gene
Explanation:
Schizophrenia is a disease that affects the brain, which is characterized by an imbalance of neurotransmitters and the presence of damaged brain tissues. In humans, the Complement component 4 (C4) protein is found at the neurons (i.e., cell bodies, dendrites and axons), which are the most common brain cells, and neuronal synapses. Moreover, gene duplication can increase gene expression when repressive mechanisms (e.g., DNA methylation at promoter sites) capable of silencing the expression of the duplicated gene are lacking. Recently, it has been discovered that a chromosome rearrangement associated with a tandem duplication of a genomic region that contains a C4 gene may contribute to schizophrenia risk by increasing the expression of this gene. In this example, a, b and d options are associated with a decrease in expression of the C4 gene, either by decreasing its transcription (options a and d) or by posttranscriptional mechanisms (option c).
If a diploid cell has 20 chromosomes, how many sister chromatids will be present
during PROPHASE of MITOSIS?
Answer:
92 chromatids
Explanation:
During phosphate, the nuclear envelope of the cell (which is where the 92 chromatids are contained) begins to break down. The centrioles, which are the only present in animal cells, separate and each moves to an opposite end of the cell
based on the 1:2:1 proportions of carbon, hydrogen and oxygen, it can be determined that a glucose molecule is a
Answer:
Carbohydrate (monosaccharide)
Explanation:
Carbohydrates are one of the four biological molecules in nature. Carbohydrates are structurally composed of carbon, hydrogen and oxygen elements. However, these elements (C,H,O) are present in each carbohydrate in the ratio 1:2:1 respectively.
As stated in this question, glucose is an organic molecule made up of carbon, hydrogen and oxygen in the 1:2:1 proportion, hence, it is a CARBOHYDRATE. Since glucose possess one sugar component, it is classified as a MONOSACCHARIDE with a chemical formula C6H12O6.
How can we get more food for ourselves without damaging other animals' food chains?
Answer:
it's simple We have to crop the vegetables .
choose the letter of the correct answer 1. Which one of the following is NOT an organic compound? a. Methane b. Carbon dioxide d. Lactic acid C. Oil
Answer:
B
Explanation:
What is added to tacos, burritos, and soups that is
high in fiber?
Answer: flax seed whole wheat tortillas.
1⁄2 cup low-fat refried beans.
1⁄4 cup low-fat cheddar cheese.
leaves lettuce.
1⁄ cup salsa.
1⁄4 cup fat free sour cream.
Pinto beans are added to tacos, burritos, and soups that are high in fiber.
What are fibers and their types?The body is unable to digest fiber, which is a form of carbohydrate. While fiber cannot be converted into glucose, the sugar that results from the breakdown of most carbs, fiber travels through the body undigested.
The solubility, viscosity, and fermentability of dietary fibers, which have an impact on how they are metabolized by the body, can be used to classify them in general. Dietary fibers have a wide range of chemical compositions.
Fibre comes in two varieties: soluble and insoluble. Both are crucial for good health, digestion, and illness prevention. Thus, Pinto beans are added to tacos, burritos, and soups that are high in fiber.
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In pea plants, flowers are either white or purple: the purple color is produced by pigments called anthocyanins. The production of anthocyanins is a two-step process: the first step is controlled by the C gene and the second by the P gene. Both genes must produce functional proteins for anthocyanin to be produced. This is an example of:
Answer:
This is an example of gene translation.
Explanation:
Gene translation refers to the genetic process where a set of genes is used to create amino acids that will be responsible for creating a protein needed to perform some function or characteristic of the organism. In the question above, we can see that anthocyanin, responsible for the pigment of flowers, is created through the work of proteins that are created from gebes C and P. This is an example of gene translation, as it presents the formation of proteins regulated by genes.
Individuals with premutation length repeats in FMR1 may have some of the phenotypes of Fragile X but not others, which is _____________; for example, some individuals may have cognitive deficiencies, while others might have late onset ataxia. In addition, some individuals will have no phenotypes of the condition at all, due to ____________.
Answer:
variable expressivity; incomplete penetrance
Explanation:
In genetics, variable expressivity refers to the fact that individuals having the same alleles/genes/genotype associated with a particular genetic condition may exhibit different clinical features of this condition. In general, variable expressivity is due to the combination of both genetic and environmental factors. An example of variable expressivity is the Marfan syndrome, where all individuals with this disorder have a dominant mutation in the FBN1 (fibrillin 1) gene and show different degrees of the same phenotype. Moreover, incomplete penetrance (also known as reduced penetrance) refers to the complete absence of a genetic trait or disease in individuals having alleles/genes/genotype associated with the condition. In consequence, individuals with incomplete penetrance do not develop features of the disease. An example of incomplete penetrance is given by those individuals with mutations in BRCA1/BRCA2 genes (associated with an increased risk of developing breast cancer) that do not develop cancer.
What is the biggest problem of over use of pesticides
Answer:
There have been many issues that have been seen to arise due to the over use of pesticide including:
Explanation:
Overuse has been linked to cancer, Alzheimer's Disease, ADHD, and even birth defects. Along with being reporting to have the potential to harm the nervous system, the reproductive system, and the endocrine system.
Answer:
Pollution.
People applying them are exposed to toxic chemicals. People who live nearby can be exposed too with wind blowing them around.
With rain or just watering of plants, the pesticides 'run off' and end up in water supplies, rivers, lakes, and eventually oceans.
Also, organisms can mutate and make pesticides useless.
Complete these sentences by matching the phrases below.
When light
waves are
emitted by a
moving source,
scientists can
?
the Doppler effect.
measure:
Scientists smash
together tiny bits
of matter using:
?
cosmic microwave
background radiation,
Scientists
extrapolate
backwards in
time to derive:
?
particle accelerators.
The extremely
low temperature
of outer space
can be explained
as:
?
the Big Bang theory
NEED HELP ASAP!
The Doppler Effect talks about the frequency of sound and light as the source and person move. So, When light waves are emitted by a moving source, scientists can measure = the Doppler effect.
Cosmic microwave background radiation has the word "cosmic" in it, so you can assume it has to do with space automatically. There is radiation in space too, so I'm pretty sure that The extremely low temperature of outer space can be explained as = cosmic microwave background radiation.
Particle accelerators are these big machines that usually smash protons/electrons together, so Scientists smash together tiny bits of matter using = particle accelerators.
And now, by process of elimination and because the Big Bang Theory talks about the creation of Earth, we know that Scientists extrapolate backwards in time to derive = the Big Bang Theory.
A biologist thinks the population of chipmunks will be in the range of 2900 to 3100 in the year 2000. Is that a reasonable guess? Why or why not?
Answer:
No
Why not:
The midpoint of range is 3000. Yes, in from 1950-1955 there was a massive increase of the population of chipmunks but from then on it slowly decreased until 1990. In 1995, the population doubled from 1990. If you double 1440, you will get 2880. The biologist said between 2900-3100, using the midpoint of this range (3000) it is too low therefore being a bit unreasonable.
Hoped it is correct and helped you!
7. Shawn plotted the data in a bar graph with two bars: one representing the number of bees per colony in the control cages and the other representing the number of bees per colony in the cages exposed to the fungicide. If the results support the hypothesis that fungicides harm bee development, what would you expect this bar graph to show? Describe the expected pattern in a few sentences.
Answer:
The first bar increases in length as compared to the second bar.
Explanation:
The length of the bar of control cages in graph increases because the number of bees per colony increases while on the other hand, the length of the bar of the cage that is exposed to fungicides decreases because the bees are negatively affected from the application of fungicides. They act abnormal in behaviour and adversely affected the reproduction of bees that greatly affected its population.
Explain how the results from testing Barley High Lysine (BHL) are related to the primary, secondary and tertiary structure of protein?
Answer:
Enhanced derivatives of barley chymotrypsin inhibitor-2 are known as Barley high lysine (BHL) proteins. BHL has tryptophan, threonine, and isoleucine in a folded structure similar as the tertiary structure of protein.
Derivatives of BHL are digestible in gastric juice and other fluid. Denaturation of these proteins shows proteins in gastric fluid minus pepsin which is looks as the secondary structure of protein. It has four soluble protein groups –
a) Albumins
b) globulin fraction in embryo and scutellary proteins
c) Prolamins
d) Glutelin
