Sara brought a car for 16,586 and paid 1,038 for tax, title, and registration.Which equation shows about how much Sara paid, to the nearest hundred?

Answers

Answer 1

Answer:

P+T+t+R=TA

Step-by-step explanation:

this should help

Answer 2

Answer:

17,600

Step-by-step explanation:

16,586 + 1,038 = 17,624 ≈ 17,600


Related Questions

The table below shows the results from a study that compared speed (in miles per hour) and average fuel economy (in miler per gallon) for cars. Find a quadratic model for the data.

0.008
y=13.472x
2
+0.746x−0.008

y
=
25.836
x
+
0.049
y=25.836x+0.049

y
=

.
008
x
2
+
0.746
x
+
13.472
y=−.008x
2
+0.746x+13.472

y
=
0.049
x
+
25.836
y=0.049x+25.836

Answers

Note that the  quadratic model for the data is  y = -0.008x² + 0.75x + 13.47.

How is this so  ?

Here are the steps on how to  find a quadratic model for the data.

Make a   scatter plot of the data. The points should form an inverted U-shape. This suggests a quadratic model.Use the quadratic regression feature on your graphing calculator to find an equation of the model.

Here is the output of the quadratic regression feature on my graphing calculator

y = -0.008x² + 0.75x + 13.47.

where  -

x is the speed in miles per hour

y is the fuel economy in miles per gallon.

Learn more about Quadratic equation at:

https://brainly.com/question/1214333

#SPJ1

the area of a parallelogram shape land is on the square and length of its two adjacent sides are 25 m and 17 M find its diagonal​

Answers

Step-by-step explanation:

Draw diagonal AC

The triangle ABC has sides 17 and 25

Say AB is 17, BC is 25

Draw altitude on side BC from A , say h

h = 17 sin B

Area = 25*17 sin B = 408

sin B = 24/25

In ∆ ABC

Cos B = +- 7/25

= 625 + 289 — b^2 / 2*25*17

b^2 = 914 — 14*17 = 676

b = 26

h = 17*24/25 = 408/25 = 16.32

Draw the second diagonal BD

In ∆ BCD, draw altitude from D, say DE =h

BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2

BD^2 = 16.32^2 + (25 + 4.76)^2

= 885.6576 + 266.3424

BD = √ 1152 = 33.94 m

Evaluate f-g+(-2) where f = -3.005 and g = 4.7

Answers

Answer:

-9.705

Step-by-step explanation:

f-g+(-2)

Let  f = -3.005 and g = 4.7

-3.005 -4.7 -2

-9.705

if the cost of 2:dozen copies is Rs 720 , find the cost of 72 copies .

Answers

Answer:

Rs 2160

Step-by-step explanation:

1 dozen = 12 copies

2 dozen = 24 copies ( 2*12)

72÷12 = 6 dozen

72 copies = 6 dozen

1 dozen = Rs 720÷2

1 dozen Rs 360

6 dozen = 360*6

6 dozen = 72 copies = Rs 2160

Helpppp and explain pls and ty

Answers

Step-by-step explanation:

2 gallons are needed for 10 galloms of lemonade

PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.

Answers

Answer:

D

Step-by-step explanation:

2ab*cos(C)=a^2+b^2-c^2

2ab*cos(C)=5^2+4^2-2^2=25+12=37

Answer:

The answer is 37

Step-by-step explanation:

Select the correct answer from the drop-down menu.
Z1 = 4cis (pi/2) and Z2=3cis(3pi/2)
The product of Z1 and Z2 is

Answers

Answer:

z₁ × z₂ = 12·cis(2·π)

Step-by-step explanation:

z₁ = 4·cis(π/2), z₂ = 3·cis(3·π/2)

We have;

z₁ = 4·cis(π/2) = 4·(cos(π/2) + i·sin(π/2))

z₂ = 3·cis(3·π/2) = 3·(cos(3·π/2) + i·sin(3·π/2))

According to De Moivre's Theorem,

z₁ × z₂ = 4×3×(cos(π/2 + 3·π/2) + i·sin(π/2 + 3·π/2)) = 12·(cos(2·π) + i·sin(2·π))

∴ z₁ × z₂ = 12·cis(2·π)

Based on the graph of the trigonometric function,
what is the period?

Answers

Answer:

[tex]\displaystyle 4[/tex]

Explanation:

[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

You will need the above information to help you interpret the graph. So, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-5, 0],[/tex] from there to [tex]\displaystyle [-1, 0],[/tex] they are obviously [tex]\displaystyle 4\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 4.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Write these sums as decimals:

2/100 + 3/1,000 =

1/10 + 4/10,000 =

Answers

Answer:

1 ) 0.023

2 ) 0.1004

Step-by-step explanation:

2 / 100 + 3 / 1000

= 0.02 + 0.003

= 0.020 + 0.003

= 0.023

1 / 10 + 4 / 10,000

= 0.1 + 0.0004

= 0.1000 + 0.0004

= 0.1004

find the 10 degree value can u help me on it ​

Answers

Solution:-10

As <AGQ and <EQG are corresponding interior angles

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]

<AGQ=<PQR=60°<BHF=<PRQ=75°

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]

According to angle sum property

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]

A rectangular drawing is enlarged by 30%. The original dimensions of this drawing are 16cm x 24cm.
Determine the scale factor, as a fraction that represents this enlargement. What are the new, enlarged
dimensions?

Answers

Answer:

Step-by-step explanation: Scale [tex]\frac{130}{100} = \frac{13}{10}[/tex]

New dimensions [tex]16 * 1.3 --- 24*1.3 =20.8 cm * 31.2 cm[/tex]

what is the equation of the line that is parallel to the given line and passes through the point (-3,2)? no links.

Answers

Answer:

D) 4x +3y = -6

Step-by-step explanation:

paralell lines so m1 and m2 are equal

m = (3 +1 )/ (0 - 3 )

m = -4/ 3

y -2 = -4/3 (x +3)

y =-4x/3 -2

3y = -4x -6

4x +3y = -6

solve
f(x)=4x5−8x4+8x2−4x

Answers

Given:

The function is:

[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]

To find:

The roots of the given equation.

Solution:

We have,

[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]

For roots, [tex]f(x)=0[/tex].

[tex]4x^5-8x^4+8x^2-4x=0[/tex]

[tex]4x(x^4-2x^3+2x-1)=0[/tex]

[tex]4x((x^4-1)+(-2x^3+2x))=0[/tex]

[tex]4x((x^2+1)(x^2-1)-2x(x^2-1))=0[/tex]

On further simplification, we get

[tex]4x(x^2+1-2x)(x^2-1)=0[/tex]

[tex]4x(x-1)^2(x+1)(x-1)=0[/tex]

[tex]4x(x+1)(x-1)^3=0[/tex]

Using zero product property, we get

[tex]4x=0[/tex]

[tex]x=0[/tex]

Similarly,

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

And,

[tex](x-1)^3=0[/tex]

[tex]x=1[/tex]

Therefore, the zeroes of the given function are [tex]-1,0,1[/tex] and the factor form of the given function is [tex]f(x)=4x(x+1)(x-1)^3[/tex].

256x²+² - x²y² + 49y²+²

Answers

[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49y^2x^2[/tex]

[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49x^2y^2[/tex]

[tex]\\ \sf\longmapsto (256-1+49)x^2y^2[/tex]

[tex]\\ \sf\longmapsto 304x^2y^2[/tex]

Full working out for this question please.

On Monday Farmer Tom collected 6 times as many eggs as Farmer Jack. On Tuesday, Farmer Tom sold 425 eggs. Farmer Jack then had three times as many eggs as Farmer Tom. How many eggs did farmer Jack have?

a.150
b.175
c.125
d.25
e.75

Answers

Answer:

75

Step-by-step explanation:

Let farmar jack collected x eggs, then farmar Tom collect 6x eggs

farmar Tom sold 425 eggs, so he left with 6x-425 eggs, now farmar jack has 3 times of what farmar Tom has, so

3(6x-425)=x

or, x=75

so farmar jack had 75 eggs

Answered by GAUTHMATH

please help meeeeeeeeeeeeee

Answers

Answer:

a)-2x(x+4x²)+3(x²+2x)

-2x²-8x³+3x²+6x

-2x²+3x²+6x-8x³

x²-8x³+6x

in descending order

-8x³+x²+6x

b)(4x-3)(4x+3)

4x(4x+3)-3(4x+3)

16x²+12x-12x-9

16x²-9

I hope this helps and sorry if it's wrong

Please answer:
Joanna bakes a cake in the shape of a
cylinder. The cake is 10 inches in
diameter and 4.5 inches tall. She
wants to put frosting on the entire
cake that is not resting on the tray.
How many square inches of frosting
will she need?

Answers

The cake has a cylindrical format, and the outside of the cake will be frosted, which means that the total surface area has to be found, and doing this, we find that she will need 298.5 square inches of frosting.

Surface area of a cylinder:  

The surface area of a cylinder of radius r and height h is given by:

[tex]S = 2\pi r^2 + 2\pi rh[/tex]

The cake is 10 inches in  diameter and 4.5 inches tall.

Radius is half the diameter, so [tex]r = \frac{10}{2} = 5[/tex].

The height is [tex]h = 4.5[/tex].

How many square inches of frosting  will she need?

This is the surface area, so:

[tex]S = 2\pi(5)^2 + 2\pi(5)(4.5) = 50\pi + 45\pi = 95\pi = 298.5[/tex]

She will need 298.5 square inches of frosting.

A similar problem can be found at https://brainly.com/question/24332238

Answer:

Step-by-step explanation:

First of all, we need the formula of a cylinder which is: 2[tex]\pi[/tex]rh + 2[tex]\pi[/tex][tex]r^{2}[/tex]

BUT also remember we are solving for one base since we do not count the bottom of the tray. That formula would look like this: 2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex] since we are using 1 base instead of 2.

Now input the missing values into the formula and solve:

2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex]

2[tex]\pi[/tex](5)(4.5) + [tex]\pi[/tex][tex](5^{2})[/tex]

45[tex]\pi[/tex] + 25[tex]\pi[/tex] = 70[tex]\pi[/tex]

Our Answer is 70[tex]\pi[/tex], or 219.91 [tex]in^{2}[/tex]

hi! can i get some help with this question! :)

Answers

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]

If f(1) = 4 and f(n) = f(n − 1) + 5 then find the value of f(5).

Answers

Answer:

25

Step-by-step explanation:

f(5)=5(5-1)+5

f(5)=5(4)+5

f(5)=20+5

f(5)=25

Answer:

f(5) = 24

Step-by-step explanation:

f(1) = 4

f(n) = f(n − 1) + 5

Let n = 2

f(2) = f(2 − 1) + 5 = 4+5 = 9

Let n = 3

f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14

Let n = 4

f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19

Let n = 5

f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24

solve for x *show work*​

Answers

Answer:

x = 14

Step-by-step explanation:

The sum of the interior angles of a six sided figure is 720

10x + 8x-16+12x-8 +7x+2 +9x+4 +6x+10 = 720

Combine like terms

52x-8=720

Add 8 to each side

52x-8+8 = 720+8

52x = 728

Divide by 52

52x/52 = 728/52

x = 14

Step-by-step explanation:

here's the answer for thy question

Simplify for me please

Answers

6^21

it would equal about 2.19^10 just as the original equation

hope this helps:))

Is student is reading a book about 370 words per minute convert this rate to words per hour

Answers

answer:
22,200 words per hour
step-by-step explanation:
60 minutes per hour
370 words per minute
370(60)
22,200

Answer: 22,200 words per hour.

Step-by-step explanation:

You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.

A boy is flying a kite from the terrace of his house. The kite is 175 m above the terrace. If the terrace is 80 m from the ground floor, findthe distance between the kite and the basement which is 8 m below the ground level.

Answers

175 m above the terrace + 80 m from terrace to ground + 8m from ground to basement:

175 + 80 + 8 = 263 meters

230% of 99 hours is what?

Answers

Answer:

227.7 hours

Step-by-step explanation:

of means multiply and is means equals

230% * 99 = what

Change the percent to decimal form

2.30 * 99 = what

227.7= what

[tex]\\ \sf\longmapsto 230\%\:of\:99[/tex]

[tex]\\ \sf\longmapsto \dfrac{230}{100}\times 99[/tex]

[tex]\\ \sf\longmapsto \dfrac{230(99)}{100}[/tex]

[tex]\\ \sf\longmapsto \dfrac{22777}{100}[/tex]

[tex]\\ \sf\longmapsto 227.7hours[/tex]

find the HCF of the following number by listing the set of factors class 6 questions is 27 and 36​

Answers

Answer:

The factors of 27 are 1,3,9,27.

The factors of 36 are 1,2,3,4,6,9,12,36.

HCF=1,3,9

Which equation represents a parabola that has a focus of (0,0) and a directix of y = 2?​

Answers

Answer: D

Step-by-step explanation:

[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]

pls help me asap!!!!!!!!

Answers

Answer:

Center: (9,3)

Radius: 9 units

Step-by-step explanation:

[tex]x^{2} -y^{2} -18x-6y+9=0[/tex]

[tex]x^{2} -18x+81+y^{2} -6y+9=-9+81+9[/tex]

[tex](x-9)^{2} +(y-3)^{2} =81[/tex]

Center: (9,3)

[tex]r^{2} =81[/tex] → [tex]r=9[/tex]

Radius : 9 units

-----------------------

OAmalOHopeO

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Manish writes the functions g(x) = ^3 sqrt - x - 72 and h(x) = -(x+72)^3

Which pair of expressions could Manish use to show that g(x) and h(x) are inverse functions?

Answers

Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.

The correct option is the last one, counting from the top.

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Two functions f(x) and g(x) are inverses if:

f( g(x) ) = x

g( f(x) ) = x

In this case, we have the functions:

g(x) = ∛(-x) - 72

h(x) =  -(x + 72)^3

Then the expressions we need to check are:

g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x

h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x

So we found that the two expressions needed are:

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Then the correct option is the last one, counting from the top.

If you want to learn more, you can read:

https://brainly.com/question/10300045

Answer:

GUYS ITS C THAT IS THE ANSWER

Make x the subject of the formula

I need help on this one too
E=7x+8f

Thank you so much if you answer!​

Answers

Answer:

Step-by-step explanation:

To make x the subject, isolate x

7x + 8f = E

Subtract 8f from both sides

7x = E - 8f

Divide both sides by 7

[tex]x =\frac{E-8f}{7}[/tex]

Answer:

x = [tex]\frac{E-8f}{7}[/tex]

Step-by-step explanation:

Given

E = 7x + 8f ( subtract 8f from both sides )

E - 8f = 7x ( isolate x by dividing both sides by 7 )

[tex]\frac{E-8f}{7}[/tex] = x

Verificar que el volumen de ambas figuras es el mismo, para ello lleva a cabo el siguiente procedimiento:
a) Obtén una expresión para el volumen de la primera figura.
b) Transforma la expresión como una multiplicación de polinomios.
c) Identifica en tu resultado el área de la base prisma y su altura para concluir una igualdad. ​

Answers

Answer:

English for fast response

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