Answer:
P+T+t+R=TA
Step-by-step explanation:
this should help
Answer:
17,600
Step-by-step explanation:
16,586 + 1,038 = 17,624 ≈ 17,600
The table below shows the results from a study that compared speed (in miles per hour) and average fuel economy (in miler per gallon) for cars. Find a quadratic model for the data.
0.008
y=13.472x
2
+0.746x−0.008
y
=
25.836
x
+
0.049
y=25.836x+0.049
y
=
−
.
008
x
2
+
0.746
x
+
13.472
y=−.008x
2
+0.746x+13.472
y
=
0.049
x
+
25.836
y=0.049x+25.836
Note that the quadratic model for the data is y = -0.008x² + 0.75x + 13.47.
How is this so ?
Here are the steps on how to find a quadratic model for the data.
Make a scatter plot of the data. The points should form an inverted U-shape. This suggests a quadratic model.Use the quadratic regression feature on your graphing calculator to find an equation of the model.Here is the output of the quadratic regression feature on my graphing calculator
y = -0.008x² + 0.75x + 13.47.
where -
x is the speed in miles per hour
y is the fuel economy in miles per gallon.
Learn more about Quadratic equation at:
https://brainly.com/question/1214333
#SPJ1
the area of a parallelogram shape land is on the square and length of its two adjacent sides are 25 m and 17 M find its diagonal
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Evaluate f-g+(-2) where f = -3.005 and g = 4.7
Answer:
-9.705
Step-by-step explanation:
f-g+(-2)
Let f = -3.005 and g = 4.7
-3.005 -4.7 -2
-9.705
if the cost of 2:dozen copies is Rs 720 , find the cost of 72 copies .
Answer:
Rs 2160
Step-by-step explanation:
1 dozen = 12 copies
2 dozen = 24 copies ( 2*12)
72÷12 = 6 dozen
72 copies = 6 dozen
1 dozen = Rs 720÷2
1 dozen Rs 360
6 dozen = 360*6
6 dozen = 72 copies = Rs 2160
Helpppp and explain pls and ty
Step-by-step explanation:
2 gallons are needed for 10 galloms of lemonade
PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.
Answer:
D
Step-by-step explanation:
2ab*cos(C)=a^2+b^2-c^2
2ab*cos(C)=5^2+4^2-2^2=25+12=37
Answer:
The answer is 37
Step-by-step explanation:
Select the correct answer from the drop-down menu.
Z1 = 4cis (pi/2) and Z2=3cis(3pi/2)
The product of Z1 and Z2 is
Answer:
z₁ × z₂ = 12·cis(2·π)
Step-by-step explanation:
z₁ = 4·cis(π/2), z₂ = 3·cis(3·π/2)
We have;
z₁ = 4·cis(π/2) = 4·(cos(π/2) + i·sin(π/2))
z₂ = 3·cis(3·π/2) = 3·(cos(3·π/2) + i·sin(3·π/2))
According to De Moivre's Theorem,
z₁ × z₂ = 4×3×(cos(π/2 + 3·π/2) + i·sin(π/2 + 3·π/2)) = 12·(cos(2·π) + i·sin(2·π))
∴ z₁ × z₂ = 12·cis(2·π)
Based on the graph of the trigonometric function,
what is the period?
Answer:
[tex]\displaystyle 4[/tex]
Explanation:
[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]
You will need the above information to help you interpret the graph. So, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-5, 0],[/tex] from there to [tex]\displaystyle [-1, 0],[/tex] they are obviously [tex]\displaystyle 4\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 4.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Write these sums as decimals:
2/100 + 3/1,000 =
1/10 + 4/10,000 =
Answer:
1 ) 0.023
2 ) 0.1004
Step-by-step explanation:
2 / 100 + 3 / 1000
= 0.02 + 0.003
= 0.020 + 0.003
= 0.023
1 / 10 + 4 / 10,000
= 0.1 + 0.0004
= 0.1000 + 0.0004
= 0.1004
find the 10 degree value can u help me on it
Solution:-10
As <AGQ and <EQG are corresponding interior angles
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]
[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]
<AGQ=<PQR=60°<BHF=<PRQ=75°[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]
According to angle sum property
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]
[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]
[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]
A rectangular drawing is enlarged by 30%. The original dimensions of this drawing are 16cm x 24cm.
Determine the scale factor, as a fraction that represents this enlargement. What are the new, enlarged
dimensions?
Answer:
Step-by-step explanation: Scale [tex]\frac{130}{100} = \frac{13}{10}[/tex]
New dimensions [tex]16 * 1.3 --- 24*1.3 =20.8 cm * 31.2 cm[/tex]
what is the equation of the line that is parallel to the given line and passes through the point (-3,2)? no links.
Answer:
D) 4x +3y = -6
Step-by-step explanation:
paralell lines so m1 and m2 are equal
m = (3 +1 )/ (0 - 3 )
m = -4/ 3
y -2 = -4/3 (x +3)
y =-4x/3 -2
3y = -4x -6
4x +3y = -6
solve
f(x)=4x5−8x4+8x2−4x
Given:
The function is:
[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]
To find:
The roots of the given equation.
Solution:
We have,
[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]
For roots, [tex]f(x)=0[/tex].
[tex]4x^5-8x^4+8x^2-4x=0[/tex]
[tex]4x(x^4-2x^3+2x-1)=0[/tex]
[tex]4x((x^4-1)+(-2x^3+2x))=0[/tex]
[tex]4x((x^2+1)(x^2-1)-2x(x^2-1))=0[/tex]
On further simplification, we get
[tex]4x(x^2+1-2x)(x^2-1)=0[/tex]
[tex]4x(x-1)^2(x+1)(x-1)=0[/tex]
[tex]4x(x+1)(x-1)^3=0[/tex]
Using zero product property, we get
[tex]4x=0[/tex]
[tex]x=0[/tex]
Similarly,
[tex]x+1=0[/tex]
[tex]x=-1[/tex]
And,
[tex](x-1)^3=0[/tex]
[tex]x=1[/tex]
Therefore, the zeroes of the given function are [tex]-1,0,1[/tex] and the factor form of the given function is [tex]f(x)=4x(x+1)(x-1)^3[/tex].
256x²+² - x²y² + 49y²+²
[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49y^2x^2[/tex]
[tex]\\ \sf\longmapsto 256x^2y^2-x^2y^2+49x^2y^2[/tex]
[tex]\\ \sf\longmapsto (256-1+49)x^2y^2[/tex]
[tex]\\ \sf\longmapsto 304x^2y^2[/tex]
Full working out for this question please.
On Monday Farmer Tom collected 6 times as many eggs as Farmer Jack. On Tuesday, Farmer Tom sold 425 eggs. Farmer Jack then had three times as many eggs as Farmer Tom. How many eggs did farmer Jack have?
a.150
b.175
c.125
d.25
e.75
Answer:
75
Step-by-step explanation:
Let farmar jack collected x eggs, then farmar Tom collect 6x eggs
farmar Tom sold 425 eggs, so he left with 6x-425 eggs, now farmar jack has 3 times of what farmar Tom has, so
3(6x-425)=x
or, x=75
so farmar jack had 75 eggs
Answered by GAUTHMATH
please help meeeeeeeeeeeeee
Answer:
a)-2x(x+4x²)+3(x²+2x)
-2x²-8x³+3x²+6x
-2x²+3x²+6x-8x³
x²-8x³+6x
in descending order
-8x³+x²+6x
b)(4x-3)(4x+3)
4x(4x+3)-3(4x+3)
16x²+12x-12x-9
16x²-9
I hope this helps and sorry if it's wrong
Please answer:
Joanna bakes a cake in the shape of a
cylinder. The cake is 10 inches in
diameter and 4.5 inches tall. She
wants to put frosting on the entire
cake that is not resting on the tray.
How many square inches of frosting
will she need?
The cake has a cylindrical format, and the outside of the cake will be frosted, which means that the total surface area has to be found, and doing this, we find that she will need 298.5 square inches of frosting.
Surface area of a cylinder:
The surface area of a cylinder of radius r and height h is given by:
[tex]S = 2\pi r^2 + 2\pi rh[/tex]
The cake is 10 inches in diameter and 4.5 inches tall.
Radius is half the diameter, so [tex]r = \frac{10}{2} = 5[/tex].
The height is [tex]h = 4.5[/tex].
How many square inches of frosting will she need?
This is the surface area, so:
[tex]S = 2\pi(5)^2 + 2\pi(5)(4.5) = 50\pi + 45\pi = 95\pi = 298.5[/tex]
She will need 298.5 square inches of frosting.
A similar problem can be found at https://brainly.com/question/24332238
Answer:
Step-by-step explanation:
First of all, we need the formula of a cylinder which is: 2[tex]\pi[/tex]rh + 2[tex]\pi[/tex][tex]r^{2}[/tex]
BUT also remember we are solving for one base since we do not count the bottom of the tray. That formula would look like this: 2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex] since we are using 1 base instead of 2.
Now input the missing values into the formula and solve:
2[tex]\pi[/tex]rh + [tex]\pi[/tex][tex]r^{2}[/tex]
2[tex]\pi[/tex](5)(4.5) + [tex]\pi[/tex][tex](5^{2})[/tex]
45[tex]\pi[/tex] + 25[tex]\pi[/tex] = 70[tex]\pi[/tex]
Our Answer is 70[tex]\pi[/tex], or 219.91 [tex]in^{2}[/tex]
hi! can i get some help with this question! :)
Hi there!
[tex]\large\boxed{log_b3b = 1.8397}[/tex]
Keep in mind the following log property:
logₓab = logₓa + logₓb
Thus:
[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]
We know the value of log_b3, and a log with the same values for the base equals 1. Thus:
[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]
If f(1) = 4 and f(n) = f(n − 1) + 5 then find the value of f(5).
Answer:
25
Step-by-step explanation:
f(5)=5(5-1)+5
f(5)=5(4)+5
f(5)=20+5
f(5)=25
Answer:
f(5) = 24
Step-by-step explanation:
f(1) = 4
f(n) = f(n − 1) + 5
Let n = 2
f(2) = f(2 − 1) + 5 = 4+5 = 9
Let n = 3
f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14
Let n = 4
f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19
Let n = 5
f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24
solve for x *show work*
Answer:
x = 14
Step-by-step explanation:
The sum of the interior angles of a six sided figure is 720
10x + 8x-16+12x-8 +7x+2 +9x+4 +6x+10 = 720
Combine like terms
52x-8=720
Add 8 to each side
52x-8+8 = 720+8
52x = 728
Divide by 52
52x/52 = 728/52
x = 14
Step-by-step explanation:
here's the answer for thy question
Simplify for me please
Is student is reading a book about 370 words per minute convert this rate to words per hour
Answer: 22,200 words per hour.
Step-by-step explanation:
You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.
A boy is flying a kite from the terrace of his house. The kite is 175 m above the terrace. If the terrace is 80 m from the ground floor, findthe distance between the kite and the basement which is 8 m below the ground level.
175 m above the terrace + 80 m from terrace to ground + 8m from ground to basement:
175 + 80 + 8 = 263 meters
230% of 99 hours is what?
Answer:
227.7 hours
Step-by-step explanation:
of means multiply and is means equals
230% * 99 = what
Change the percent to decimal form
2.30 * 99 = what
227.7= what
[tex]\\ \sf\longmapsto 230\%\:of\:99[/tex]
[tex]\\ \sf\longmapsto \dfrac{230}{100}\times 99[/tex]
[tex]\\ \sf\longmapsto \dfrac{230(99)}{100}[/tex]
[tex]\\ \sf\longmapsto \dfrac{22777}{100}[/tex]
[tex]\\ \sf\longmapsto 227.7hours[/tex]
find the HCF of the following number by listing the set of factors class 6 questions is 27 and 36
Answer:
The factors of 27 are 1,3,9,27.
The factors of 36 are 1,2,3,4,6,9,12,36.
HCF=1,3,9
Which equation represents a parabola that has a focus of (0,0) and a directix of y = 2?
Answer: D
Step-by-step explanation:
[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]
pls help me asap!!!!!!!!
Answer:
Center: (9,3)
Radius: 9 units
Step-by-step explanation:
[tex]x^{2} -y^{2} -18x-6y+9=0[/tex]
[tex]x^{2} -18x+81+y^{2} -6y+9=-9+81+9[/tex]
[tex](x-9)^{2} +(y-3)^{2} =81[/tex]
Center: (9,3)
[tex]r^{2} =81[/tex] → [tex]r=9[/tex]
Radius : 9 units
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Manish writes the functions g(x) = ^3 sqrt - x - 72 and h(x) = -(x+72)^3
Which pair of expressions could Manish use to show that g(x) and h(x) are inverse functions?
Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.
The correct option is the last one, counting from the top.
∛((x + 72)^3) - 72 and -(∛(-x) - 72 + 72)^3
Two functions f(x) and g(x) are inverses if:
f( g(x) ) = x
g( f(x) ) = x
In this case, we have the functions:
g(x) = ∛(-x) - 72
h(x) = -(x + 72)^3
Then the expressions we need to check are:
g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x
h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x
So we found that the two expressions needed are:
∛((x + 72)^3) - 72 and -(∛(-x) - 72 + 72)^3
Then the correct option is the last one, counting from the top.
If you want to learn more, you can read:
https://brainly.com/question/10300045
Answer:
GUYS ITS C THAT IS THE ANSWER
Make x the subject of the formula
I need help on this one too
E=7x+8f
Thank you so much if you answer!
Answer:
Step-by-step explanation:
To make x the subject, isolate x
7x + 8f = E
Subtract 8f from both sides
7x = E - 8f
Divide both sides by 7
[tex]x =\frac{E-8f}{7}[/tex]
Answer:
x = [tex]\frac{E-8f}{7}[/tex]
Step-by-step explanation:
Given
E = 7x + 8f ( subtract 8f from both sides )
E - 8f = 7x ( isolate x by dividing both sides by 7 )
[tex]\frac{E-8f}{7}[/tex] = x
Verificar que el volumen de ambas figuras es el mismo, para ello lleva a cabo el siguiente procedimiento:
a) Obtén una expresión para el volumen de la primera figura.
b) Transforma la expresión como una multiplicación de polinomios.
c) Identifica en tu resultado el área de la base prisma y su altura para concluir una igualdad.
Answer:
English for fast response