The bullet train was traveling at a speed of 200mi/hr for 2 hours. What
was the total distance traveled? *
O 100mi
O 01mi
O 40mi
O 400mi

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

Solar energy:-

In this way the energy generated through sun light with the help of solar panels and to be used in many works.

Wind energy:-

This is generated by moving turbines with windmills .It is used to create electric energy

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

Answer:

14x6.02x10^23=8.428x10^23 atoms

Answer:

atoms are in 14 moles of cadmium. Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings. We know that 1 mole of Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number

Explanation:

Answer:

I don't understand the question

Explanation:

what is your name

Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

Answer:A

Explanation:

The statement, that describes about nuclear fission and nuclear fusion is "both processes can release huge amounts of energy."

Nuclear fission is the process by which an atom's nucleus breaks into two or more smaller nuclei. Nuclear fusion is the process by which two light atomic nuclei merge to produce a single heavier one, releasing huge quantities of energy in the process.

Fusion and fission are both nuclear reactions that yield significant amounts of energy that can be used to generate power. However, fission is the splitting of atoms, whereas fusion is the joining of them.

To put in another way, while both nuclear reactions that generate energy, the methods are vastly different. They both produce a lot of energy.

Hence the correct answer is B.

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Answer:it’s not B

Explanation:

Answer:

Ionization Energy = 9 eV

Explanation:

If we apply the law of conservation of energy to the given situation, we will get the following equation:

[tex]Energy\ of\ Photon = Ionization\ Energy + Kinetic\ Energy\ of\ Electron\\[/tex]

where,

Energy of Photon = 10 eV

Ionization Energy = ?

Kinetic Energy of Electrons = 1 eV

Therefore,

[tex]10\ eV = Ionization\ Energy + 1\ eV\\Ionization\ Energy = 10\ eV - 1\ eV[/tex]

Ionization Energy = 9 eV

Answer:

solution given:

log k=4-[tex] \frac{200}{t} [/tex]

so,

On comparison

∆S°/R = 4

∆ S° = 4R

mousam brother is correct

hope it helps you have a good day

Answer:

4.90 g

Explanation:

Given that:

volume of t-pentyl alcohol = 5 mL

the standard density of t-pentyl alcohol = 0.805 g/mL

Recall that:

density = mass(in wt) /volume

mass = density × volume

mass = 0.805 g/mL × 5 mL

mass = 4.03 g

Volume of HCl used = 12 mL

The reaction for this equation is shown in the image attached below.

From the reaction,

88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.

4.03 g of t-pentyl alcohol forms,

[tex]= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g}[/tex] of t-pentyl chloride.

Therefore,

Theoretical yield of t-pentyl chloride = 4.90 g

Answer:

C

Explanation:

I got this question right on my test.

The question is incomplete, the complete question is;

A student determines the number of moles of water in a

hydrated metal oxide by weighing a clean, dry crucible

and lid while the crucible is empty, then reweighing the

crucible and lid with a sample of the hydrate, heating the

crucible and lid with a Bunsen burner and then

reweighing the crucible and lid with the sample after

cooling to room temperature. Which error will result in

too high a value for the amount of water of hydration?

(A) The heating is conducted only once instead of the

three times recommended by the procedure.

(B) The lid is left off the crucible when it is weighed

with the hydrated oxide.

(C) The metal oxide reacts partially with oxygen in the

air, forming a compound in a higher oxidation state.

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Answer:

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Explanation:

It is possible to determine the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate. The crucible and lid with the sample are heated, cooled and reweighed.

As this process is going on, suppose some of the heated oxide is spilled from the crucible, then the mass of heated or anhydrous oxide decreases leading to a consequent increase in the number of moles of water in the hydrated metal oxide, hence the answer above.

The too high a value for the amount of water of hydration error is occur due to heating of given hydrated sample.

Hydrated compounds are those compounds in which water molecule is present with the normal compound.

To get the correct value of weight of hydrated compound, first we have to weigh the empty crucible and lid and then with sample of compound in the crucible and lid. After this substract empty weigh of crucible & lid from the sample-crucible-lid weigh. If we substract the weigh from heated sample crucible and lid, then we get the error because the hydrated water molecule may decompose due to heating and moles of water increases.

Hence, error will occur if we heat the sample.

To know more about hydrated compound, visit the below link:

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Answer:

2200 L

Explanation:

There are 22.4 L in 1 mole of neon so if you have 98.2 L, then you have 98.2 mole x (22.4 L/mole) = 2200 L of neon.

Answer: New volume of the solution is 100 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 3 mL,     [tex]M_{1}[/tex] = 200 M

[tex]M_{2}[/tex] = 6 M,     [tex]V_2[/tex] = ?

Formula used to calculate the new volume of solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]

Thus, we can conclude that new volume of the solution is 100 mL.

Answer:

D

Explanation:

D is the answer because 2 is needed to know

Answer:

B) 3 and 7

Explanation:

i just took the test

Answer:

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.

Answer:

600 mL

Explanation:

From the question given above, the following data were obtained:

Initial concentration (C₁) = 6 M

Initial volume (V₁) = 50 mL

Final concentration (C₂) = 0.5 M

Final volume (V₂) =?

Using the dilution formula (i.e C₁V₁ = C₂V₂) we can obtain the final volume as illustrated below:

C₁V₁ = C₂V₂

6 × 50 = 0.5 × V₂

300 = 0.5 × V₂

Divide both side by 0.5

V₂ = 300 / 0.5

V₂ = 600 mL

Thus, the final volume is 600 mL

Answer:

Static energy is an energy between two charges.

Explanation:

a). A van de Graff generator builds up a positive electric charge on the dome by separating the negative static electric charges from the positive static charge using a quickly moving belt. The positive charge collects on the large metal dome of the generator. When the charge builds up is large enough, a lighting like spark can shoot from the dome to a grounded discharge rod.

             Like electric charges always repel each other, and oppositely electric charges will attract each other. When the aluminum pans are being charged by the van de Graff generator, then each of them attain the same positive polarity similar with the dome. Thus,  positive charge starts to accumulate over the surface of each of the pie pan. Each aluminum pan repels the others. These repulsive forces between the pans are so strong that they succeed in overcoming the gravity force and thus the top of the pan is pushed away from the generator's dome.

b). Static electricity is produced by a concentration of negative and positive electric charges. Like charges pushes away each other while unlike charges pulls each other.

            Objects generally have same numbers of positive charges as well as negative charges. And if there is any small imbalance in numbers of the charges on the object, it is charged.

            Negative charges easily torn away from the materials like the fur or hair. Also, the negative charges are held on other materials like the plastics. If we rub a plastic rod with fur, the negative charges will get transferred from fur to rod. The rod gets negatively charged and the fur is positively charged. As a result, the rabbit fur and the plastic rod were attracted to each other.

c). Coulomb's law stated that :

  [tex]$F=\frac{KQ_1Q_2}{d^2}$[/tex]    .............(i)

where, [tex]$Q_1$[/tex]  and [tex]$Q_2$[/tex] are the charges of two objects d is the distance between two objects.

As from the above equation, we can say that force of electrical attraction between two objects depends on the charges and the distance between objects.

1. The electrical force between two charged object is inversely proportional to the distance of separation between two objects.

Decreasing separation distance (d) between the objects will increase its attraction force.

2. And, increasing the charges of two objects(+ve and -ve) increases the force of attraction between two objects.

Answer:

0.5875L

Explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L

Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.

Answer:

This reaction has infinite ways to be balanced

Explanation:

To balance this equation we can use the algebraic method:

N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)

Where we write each molecule as a letter:

A + B → C + D + E

Then, we write the equations according the number of atoms of each molecule. That is:

Oxygen → 4A + B = C + 2D + 2E (1)

Nitrogen → 2A = C + E (2)

Carbon → B = D (3)

Then, we have to give 1 arbitral number for a letter. For example:

B = 1; D = 1

(1) 4A + 1 = C + 2 + 2E

4A = C + 2E + 1

2A = C + E (2) Twice (2):

4A = 2C + 2E

Subtracting (1) in (2)

C + 2E + 1 = 2C + 2E

C + 1 = 2C

1 = C

Si 1 = C:

4A + 1 = 1 + 2 + 2E

4A = 2 + 2E (1)

y:

2A = 1 + E (2)

Twice:

4A = 2 + 2E

As (1) and (2) are the same equation:

For example:

N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)

Answer:

[tex]296.05\ \text{K}[/tex]

Explanation:

[tex]m_w[/tex] = Mass of water = 100 g

[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]

[tex]m_c[/tex] = Mass of copper = 20 g

[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]

[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]

[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]

T = Final temperature of the system

The heat balance of the system is given by

[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]

The final temperature of the water is [tex]296.05\ \text{K}[/tex].

The final temperature of the water when placed in a calorimeter is 296.05K

HOW TO CALCULATE FINAL TEMPERATURE:

Where;

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Answer:

pH = 3.3

Explanation:

Step 1: Given data

Concentration of hydronium ions in the agricultural product ([H₃O⁺]): 4.7 × 10⁻⁴ M

Step 2: Calculate the pH of the agricultural product

We will use the definition of pH.

pH = -log [H₃O⁺]

pH = -log 4.7 × 10⁻⁴

pH = 3.3

Since the pH < 7, the agricultural product is acidic.