The lebgth of a rrctangle is 3 inches more than its width.The perimeter of the rectangle is 34 inches.

Answer:

the answer is 86°

Step-by-step explanation:

look at the photo

Answer:

1st blank=[tex]y_{1}[/tex]

2nd blank=[tex]x_{1}[/tex]

3rd blank= [tex]y_{2}[/tex]

3*27=81

so 1*[tex]y_{1}[/tex]=81

hence [tex]y_{1}[/tex]=81

9* [tex]x_{1}[/tex]= 81

[tex]x_{1}[/tex]=9

27*[tex]y_{2}[/tex]=81

[tex]y_{2}[/tex]=3

Thus solved.

Hope this helps.

Please mark me as brainliest.

Answer:

Step-by-step explanation:

Your equation is weird. The position equation for this situation is

[tex]s(t)=-4.9t^2+15t+7[/tex] and set it equal to 0 to solve for the time it takes to hit the ground. Those times come out to be

t = 3.47 sec and t = -.411 sec. But since time can never be negative, our time is 3.47 seconds

(What is that -52?)

The number of new professors needed to hire to keep the ratio of students and professors the same is 16.66  professors.

Given,

A small college has 1200 students and 80 professors.

The college is planning to increase enrollment to 1450 students next year.

We need to find how many new professors should be hired to keep the

ratio of students to professors the same.

If the two ratios are the same then we called it that they are in proportion.

Example:

4/6 = 10/15

2/3 = 2/3

Find the ratio between the students and professors before the increase in enrollment.

= Number of students / Number of professors

= 1200 / 80

Dividing by 8

= 150 / 10

= 15 / 1

This means one professor for 15 students.

Find the number of students after the increase in enrollment.

= 1450

Find the number of new students enrolled.

= 1450 - 1200

= 250

Since the ratio between the students and professor is 15 students for one professor.

For 250 new students, the number of new professors we need is:

= 250 ÷ 15

= 16.66

This means we need around 16.66 new professors.

Thus the number of new professors needed to hire to keep the ratio of students and professors the same is 16.66 professors.

Learn more about finding the number of students in a college with students and professors relation is given here:

https://brainly.com/question/4773301

#SPJ2

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Answer:

  x = 15

Step-by-step explanation:

In this geometry, x is the geometric mean of the segment lengths of the hypotenuse.

  x = √(9×25)

  x = 15

Answer:

Amount should be reported in investing activities = $173,000

Step-by-step explanation:

Given:

Amount of land costing = $140,000

Sold amount of land = $173,000

Find:

Amount should be reported in investing activities

Computation:

Amount should be reported in investing activities = $173,000

The cash flow statement shows how much money is coming in and going out. The whole amount of cash received, which is 173,000 dollars, will be recorded as proceeds from the sale of land in the investment activity. As a result, the right answer is 173,000.

Answer:

Step-by-step explanation:

[tex]30\% \: \: as \: fraction[/tex]

Answer:

Step-by-step explanation:

- joonie

Answer:

B. -21.012÷ -3.4

its yr correct ans.

hope it helps

Answer:

12 [tex]\pi[/tex] = 37.699 f/s

Actually, the more interesting question

would have been how fast is the ball going in MPH?

25.7 MPH

Step-by-step explanation:

C = 2[tex]\pi r[/tex]

C = 2 [tex]* \pi * 1.2[/tex]

C = 2.4 [tex]\pi feet[/tex]

C (per second) = (5)(2.4 [tex]\pi feet[/tex])

C(per second) = 12 [tex]\pi[/tex] = 37.699 f/s

Answer:

Step-by-step explanation:

Answer:

15*.1=1.5

so either one or two people of the 15 would be left handed

Pentagon has sum of 540°

Answer:

4.4028

Step-by-step explanation:

Probability of game (p) = 0.3669

Number of wins in November (n) = 12

Expected number of wins = p*n

Expected number of wins = 0.3669 * 12

Expected number of wins = 4.4028

So, the expected number of wins for the month of November is 4.4028.

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Answer:

  x = 22, y = 123

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  (2x +13)° +57° +3x° = 180°

  5x +70 = 180 . . . . . . . . . . . . . collect terms, divde by °

  5x = 110 . . . . . . . . . . . subtract 70

  x = 22 . . . . . . . . divide by 5

__

Angles in a linear pair are supplementary.

  y° + 57° = 180°

  y = 123 . . . . . . . . divide by °, subtract 57

Answer:

hope you find it useful and helpful

An equation can be defined as a mathematical statement in which two expressions are set equal to each other. In simple words, equations mean equality i.e. the equal sign. Since equations are all about “equating one quantity with another”,they are simply known as equation

Answer:

In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. ... For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

Answer:

Step-by-step explanation:

From the picture attached,

m∠COB = 90° - m∠BOS

              = 90° - 40°

              = 50°

tan(30°) = [tex]\frac{AC}{OC}[/tex]

[tex]\frac{1}{\sqrt{3}}=\frac{AC}{OC}[/tex]

AC = [tex]\frac{OC}{\sqrt{3}}[/tex]  ------(1)

Similarly, tan(50°) = [tex]\frac{BC}{OC}[/tex]

BC = OC[tan(50°)] -------(2)

Now AC + BC = 30 cm

By substituting the values of AC and BC from equation (1) and (2),

[tex]\frac{OC}{\sqrt{3}}+OC(\text{tan}50)=30[/tex]

(1.769)OC = 30

OC = 16.96

1). cos(30°) = [tex]\frac{OC}{AO}[/tex]

[tex]\frac{\sqrt{3}}{2}= \frac{16.96}{OA}[/tex]

[tex]OA=19.58[/tex] cm

Therefore, distance between the ship and town A is 19.58 cm.

2). cos(50°) = [tex]\frac{OC}{OB}[/tex]

0.6428 = [tex]\frac{16.96}{OB}[/tex]

OB = 26.38 cm

Therefore, distance between the ship and town B is 26.38 cm.

Answer:

if x=0 then they have same value

1 and 2 options are out

for x=-1

g(-1)=1

h(-1)=-1

3 is true

4th

FALSE

for all values except 0, g(x)>h(x)

correct ones are

g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

Step-by-step explanation:

Answer:

107%

Step-by-step explanation:

Round up all possible algorithms

Answer:

7x = x + 9.

Step-by-step explanation:

7 × something = something + 9, right?

So, 7x = x + 9.

Answer:

[tex]\mu =2.16[/tex] --- Mean

[tex]\sigma^2 = 1.4944[/tex] -- Variance

[tex]\sigma = 1.222[/tex] --- Standard deviation

Step-by-step explanation:

Given

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.12} & {0.2} & {0.2} & {0.36} & {0.12} \ \end{array}[/tex]

Solving (a): The population mean

This is calculated as:

[tex]\mu = \sum x * P(x)[/tex]

So, we have:

[tex]\mu =0*0.12 + 1 * 0.2 + 2 * 0.2 + 3 * 0.36 + 4 * 0.12[/tex]

[tex]\mu =2.16[/tex]

Solving (b): The population variance

First, calculate:

[tex]E(x^2)[/tex] using:

[tex]E(x^2) = \sum x^2 * P(x)[/tex]

So, we have:

[tex]E(x^2) = 0^2*0.12 + 1^2 * 0.2 + 2^2 * 0.2 + 3^2 * 0.36 + 4^2 * 0.12[/tex]

[tex]E(x^2) =6.160[/tex]

So, the population variance is:

[tex]\sigma^2 = E(x^2) - \mu^2[/tex]

[tex]\sigma^2 = 6.16 - 2.160^2[/tex]

[tex]\sigma^2 = 6.160 - 4.6656[/tex]

[tex]\sigma^2 = 1.4944[/tex]

Solving (c): The population standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\sigma^2}[/tex]

[tex]\sigma = \sqrt{1.4944}[/tex]

[tex]\sigma = 1.222[/tex]

Answer:

[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]

really?! :|

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Answer:

  -4, 0

Step-by-step explanation:

The denominator is x^2+4x. This is zero when ...

  x^2 +4x = 0

  x(x +4) = 0

The zero product rule tells you the product is zero when the factors are zero.

  x = 0

  x +4 = 0   ⇒   x = -4

The denominator is zero for x=0 and x=-4.

9514 1404 393

Answer:

  6/20, 3:5, 50/100 are all less than 8/10

Step-by-step explanation:

It can help to give all the ratios a common denominator. (We'll use 100, and fudge the last one a bit.)

  8/10 = 80/100 . . . . our reference value

__

  6/20 = 30/100 . . . less than 8/10

  3/5 = 60/100 . . . . less than 8/10

  50/100 . . . . . . . . . less than 8/10

  13/15 ≈ 86.7/100 . . . more than 8/10

Part B is not clear and the clear one is;

P(X ≥ 6)

Answer:

A) 0.238

B) 0.478

C) 0.114

Step-by-step explanation:

To solve this, we will make use of binomial probability formula;

P(X = x) = nCx × p^(x)•(1 - p) ^(n - x)

A) 54% of U.S. adults have very little confidence in newspapers. Thus;

p = 0.54

10 random adults are selected. Thus;

P(X = 5) = 10C5 × 0.54^(5) × (1 - 0.54)^(10 - 5)

P(X = 5) = 0.238

B) P(X ≥ 6) = P(6) + P(7) + P(8) + P(9) + P(10)

From online binomial probability calculator, we have;

P(X ≥ 6) = 0.2331 + 0.1564 + 0.0688 + 0.01796 + 0.0021 = 0.47836 ≈ 0.478

C) P(x<4) = P(3) + P(2) + P(1) + P(0)

Again with online binomial probability calculations, we have;

P(x<4) = 0.1141 ≈ 0.114

Answer:

X o punto Y O punto z

Step-by-step explanation:

Answer:

[tex]{ \tt{2x + 4y = 8 - - - (a)}} \\ { \tt{x = 3y - 6 - - - (b)}} [/tex]

Substitute for x in equation (a) :

[tex]{ \tt{2(3y - 6) + 4y = 8}} \\ { \tt{6y - 12 + 4y = 8}} \\ { \tt{10y = 20}} \\ y = 2[/tex]

Substitute for y in equation (b) :

[tex]{ \tt{x = (3 \times 2) - 6}} \\ x = 0[/tex]

2x+4y =8

x=3y-6 ——> x–3y=–6

x–3y = – 6 ] ×(–2) ——> –2x +6y=12

2x+4y=8

–2x+6y =12

__o_o____

0+10y=20 —> 10y= 20 —> y= 20/10 —> y= 2

2x+4y=8 —> 2x + 4(2) = 8 —> 2x + 8=8 —> 2x = 0 —> x=0

(x,y) —> (0,2)

Answer:

33km

Step-by-step explanation:

Let the distance traveled by bus be x, then distance traveled by train would be 2x

Therefore,

5 + x + 2x = 104

5 + 3x = 104

3x = 104 - 5

3x = 99

x = 33

Answer:

[tex]f(126) \approx 5.01333[/tex]

Step-by-step explanation:

Given

[tex]\sqrt[3]{126}[/tex]

Required

Solve using differentials

In differentiation:

[tex]f(x+\triangle x) \approx f(x) + \triangle x \cdot f'(x)[/tex]

Express 126 as 125 + 1;

i.e.

[tex]x = 125; \triangle x = 1[/tex]

So, we have:

[tex]f(125+1) \approx f(125) + 1 \cdot f'(125)[/tex]

[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]

To calculate f(125), we have:

[tex]f(x) = \sqrt[3]{x}[/tex]

[tex]f(125) = \sqrt[3]{125}[/tex]

[tex]f(125) = 5[/tex]

So:

[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]

[tex]f(126) \approx 5 + 1 \cdot f'(125)[/tex]

[tex]f(126) \approx 5 + f'(125)[/tex]

Also:

[tex]f(x) = \sqrt[3]{x}[/tex]

Rewrite as:

[tex]f(x) = x^\frac{1}{3}[/tex]

Differentiate

[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}\\[/tex]

Using law of indices, we have:

[tex]f'(x) = \frac{x^\frac{1}{3}}{3x}[/tex]

So:

[tex]f'(125) = \frac{125^\frac{1}{3}}{3*125}[/tex]

[tex]f'(125) = \frac{5}{375}[/tex]

[tex]f'(125) = \frac{1}{75}[/tex]

So, we have:

[tex]f(126) \approx 5 + f'(125)[/tex]

[tex]f(126) \approx 5 + \frac{1}{75}[/tex]

[tex]f(126) \approx 5 + 0.01333[/tex]

[tex]f(126) \approx 5.01333[/tex]