The name of an oxyacid has the suffix -ous acid. What is the suffix of the oxyanion?

Answer:

0.456 M

Explanation:

Step 1: Write the balanced neutralization equation

HNO₂ + KOH ⇒ KNO₂ + H₂O

Step 2: Calculate the reacting moles of KOH

9.26 mL of 1.235 M KOH react.

0.00926 L × 1.235 mol/L = 0.0114 mol

Step 3: Calculate the reacting moles of HNO₂

The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.

Step 4: Calculate the initial concentration of HNO₂

0.0114 moles of HNO₂ are in 25.0 mL of solution.

[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M

Answer:

3.50 × 10⁻³ g/L

Explanation:

Step 1: Make an ICE chart for the solution of SrCO₃

"S" represents the molar solubility.

         SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)

I                             0               0

C                           +S              +S

E                             S               S

The solubility product constant (Ksp) is:

Ksp = [Sr²⁺] [CO₃²⁻] = S²

S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M

Step 2: Convert "S" to g/L

The molar mass of SrCO₃ is 147.63 g/mol.

2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L

Answer:

Explanation:

1 mol of anything is 6.02 * 10^23 (in this case molecules)

x mol  has 9.06 * 10^24 molecules of NaNO3

x * 6.02 * 10^23  = 9.06 * 10^24 * 1     Divide by 6.02 * 10^23

x = 9.06 * 10^24/6.02 * 10^23

x = 1.5 * 10

x = 15 mols of NaNO3

1 mol of NaNO3

Na = 23

N = 14

O3 = 48

Total = 85

1 mol of NaNO3 = 85 grams

15 mols = x                              Cross Multiply

x = 15 * 85

x = 1275 grams

Note: these numbers are approximate but they are very close. You have to use your own values from your periodic table to find the mass of NaNO3. Your answer will be very close to 85.

The question is incomplete, the complete question is;

Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.

Answer:

No

Yes

Explanation:

A single replacement reaction occurs when a metal that is higher in the electrochemical series is placed in a solution of the salt of a metal which is lower than it in the electrochemical series.

For instance, when a strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution, a reaction occurs as follows;

Fe(s) + Pb(NO3)2(aq) ---------> Fe(NO3)2(aq) + Pb(s)

However, when a strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution no reaction occurs because lead is lower than iron in the electrochemical series hence it can not displace iron from an aqueous solution of its salt.

Explanation:

If there are 15 protons, 15 nuclear particles of unit positive charge, then

Z

=

15

. Now

Z

≡

the atomic number

, and you look at your copy of the Periodic Table, and you find that for

Z

=

15

, the element phosphorus is specified.

But we are not finished. Along with the 15 defining protons, there are also 16 neutrally charged, massive nuclear particles, 16 neutrons, and the protons and neutrons together determine the atomic mass. The isotope is thus

31

P

, which is almost 100% abundant, and an important nucleus for

NMR spectroscopy.

Explanation:

Answer

Open in answr app

Correct option is

A

Precipitation reaction

B

Double displacement reaction

Balanced equation for the reaction is:

KCl(s)+AgNO3(aq)→AgCl(s)+KNO3(aq)

It is a double displacement reaction as both reactants exchange ions to form new products. Also, it is a precipitation reaction as white precipitates of silver chloride(AgCl) are formed.

Answer:

The mass of the flour required to prepare the cookies is 1.8 kg.

Explanation:

The flour required to prepare the cookies is 3.95 lb.

1 lb = 0.454 kg

So, 3.95 lb = 3.95 x 0.454 kg = 1.8 kg

So, the mass of the flour required to prepare the cookies is 1.8 kg.

Answer:

A. simple

Explanation:

Answer: hello your question is incomplete below is the complete question

Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa​ and the magnitude of the drift velocity of the chloride ions is VCl​.

What is the magnitude of the ammeter reading ?

answer :

| I | = neAVₙₐ  + neAV (Cl-)

Explanation:

Given that there are N sodium ions

Determine the Magnitude of the ammeter reading

| I | = current due to sodium ions + current due to (Cl-) ions

     = neAVₙₐ  + neAV (Cl-)

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

Answer:

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

Explanation:

Answer:

Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature

Explanation:

Answer:

Amides are suitable to synthesize aniline

Explanation:

Amide are basically used to synthesize aniline.

The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2

Amide are solids that can be easily converted to amines.

Answer:

the answer is 3

Explanation:

hope this works

Answer:

1    being or located on the outside; external  

2    further from the middle or central part

Explanation:

Answer:

CH3CH2CH3

Explanation:

Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.

Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.

The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.

We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "

it can be said that

 From the question we are given

CH3CH2CH3

CH3OCH3

CH3CHO

CH3OH

CH3CN

Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.

Therefore,

[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment

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Answer:

Tundra and desert ecosystem are different especially when talking about their climate. Tundra is situated in northern latitude and is very cold having a negative 34 degrees and has a permafrost while desert is often situated closer to equator and thus have hot climate yet they have a similar characteristic when it comes to vegetation or the plants as both experience a water scarcity thus plants are already adapted to live in water-barren environment.

Explanation:

Answer:

The correct answer is "+2.37 V".

Explanation:

Given that,

Concentration of [tex]Mg^{2+}[/tex]

= 1.00 M

[tex]E^0 \ Mg^{2+}/Mg[/tex],

= -2.37 V

[tex]E^0 \ \mu^+/H_2[/tex],

= 0.00V

When S.H.E as well as anode act as cathode, then

⇒ [tex]E^0 cell=E^cathode-E^0 anode[/tex]

By putting the values, we get

⇒            [tex]=0.00V-(-2.37 V)[/tex]

⇒            [tex]=+2.37 \ V[/tex]    

Explanation:  hi go to hell

Answer:

Explanation:

Speed of light = Frequency * Wavelength

Speed of light is 3*10^8 m/s

Wavelength = Speed / Frequency = 3*10^8 / 3.7*10^14

= 8.11*10^(-7) m

= 811 nanometer

The wavelength of light will be

The wavelength of such a periodic wave would be the interval in which the shape of the wave repeats.

Calculation of wavelength of light

It is given that,

frequency = 3.7 x [tex]10^{14}[/tex] Hz

Speed of light = 3 × [tex]10^{8}[/tex] m/s

frequency × wavelength = speed of light.

wavelength =  speed of light / frequency

wavelength =  3 × [tex]10^{8}[/tex] m/s / 3.7 x [tex]10^{14}[/tex] Hz

wavelength = 0.81 × [tex]10^{-7}[/tex] m

wavelength = 8.1 × [tex]10^{-7}[/tex]

Therefore, wavelength of light will be  8.1 × [tex]10^{-7}[/tex].

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Answer:

1178J is the heat of the reaction

Explanation:

Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC

The heat of a reaction follows the equation:

Q = m*S*ΔT

Where Q is the heat of the reaction,

m is the mass:

61.2mL * (1.00g/mL) = 61.2g

S is specific heat = 4.184J/g°C

ΔT = 4.6°C

Replacing:

Q = 61.2g*4.184J/g°C*4.6°C

Q = 1178J is the heat of the reaction

Answer:

If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.

Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.

Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.

A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.

Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.

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Answer: 0.943 M of potassium hydroxide solution is required.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

To calculate the molarity of potassium hydroxide, the equation used is:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]              ........(1)

where,

[tex]n_1, M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid that is [tex]H_2SO_4[/tex]

[tex]n_2, M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the base that is KOH

We are given:

[tex]n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL[/tex]

Putting values in equation 1, we get:

[tex]2\times 0.506\times 23.3=1\times M_2\times 25.0\\\\M_2=\frac{2\times 0.506\times 23.3}{1\times 25.0}\\\\M_2=0.943M[/tex]

Hence, 0.943 M of potassium hydroxide solution is required.

Answer:

-11.13 Degree Celsius

Explanation:

Here

Kf for H20 is 1.86 C/m

Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams

Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol

Mass of water = 100 – 27.1 = 72.9 grams

Molality  = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m

Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C

Melting point of solution = Melting point of water - Melting Point Depression

= 0 – 11.13 = -11.13 Degree Celsius

Answer:

Mass of sample in mg = 15,285 mg

Explanation:

Given:

Volume of urine sample = 15 ml

Density of sample = 1.019 g/ml

FInd:

Mass of sample in mg

Computation:

Mass = density x volume

Mass of sample in mg = Volume of urine sample x Density of sample

Mass of sample in mg = 1.019 x 15

Mass of sample in mg = 15.285 gram

Mass of sample in mg = 15.285 x 1,000

Mass of sample in mg = 15,285 mg

Answer:

both drugs will be equally effective

Explanation:

A racemic mixture is a substance that contains a 50/50 mixture of the (+) and (-) enantiomers of an optically active compound.

It is important to note that even if a drug occurs as a racemic mixture, only the biologically active enantiomer will interact with the substrate on which the drug acts. The other enantiomer present is just irrelevant. Similarly, its presence does not affect the biological activity of the active enantiomer.

Hence, both Prilosec and Nexium are both equally effective.

Answer:

t(9.32% remaining) = 203 yrs (3 sig. figs.)

Explanation:

All radioactive decay follows a 1st order decay profile. This is defined by the expression ...

A =A₀e^-k·t

A = final activity = 9.32%

A₀ = initial activity = 100%

e = base of natural logs

k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹

t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹

 = 203.286637 yrs (calc. ans.)

 ≅ 203 yrs (3 sig. figs.)

Answer:

0.605 M

Explanation:

What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr?

Step 1: Given data

Step 2: Calculate the moles corresponding to 54.0 g of KBr

The molar mass of KBr is 119.00 g/mol.

54.0 g × 1 mol/119.00 g = 0.454 mol

Step 3: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.454 mol / 0.750 L = 0.605 M