The quantity p varies inversely as the square of (q + 2)
p=5 when q = 3
Find p when q = 8​

Answer:

(f+g)(x) = 60x + 400

Step-by-step explanation:

Given :

Amount in account A:

f(x) = 20x + 100

Amount in account B :

g(x) = 40x + 300

Total amount in Account A and B:

f(x) + g(x) = (20x + 100) + (40x + 300)

(f+g)(x) = (20x + 40x) + (100 + 300)

(f+g)(x) = 60x + 400

Step-by-step explanation:

bla bla bla bla123222222333333

Answer:

the product of the 2 numbers is 22

Step-by-step explanation:

x² + y² = 80

(x - y)² = 36

=>

x - y = 6

or y - x = 6

let's start with the first one x-y=6

x = 6 + y

=>

(6+y)² + y² = 80

y² + 6y +6y + 36 + y² = 80

2y² + 12y + 36 = 80

2y² + 12y - 44 = 0

y² + 6y - 22 = 0

the solution of a quadratic equation

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case here we have an squadron in y.

a=1

b=6

c=-22

(-6 ± sqrt(36 + 4×22))/2 = (-6 ± sqrt(36+88))/2 =

= (-6 ± sqrt(124))/2 = (-6 ± sqrt(4×31))/2 =

= (-6 ± 2×sqrt(31))/2 = -3 ± sqrt(31)

y1 = -3 + sqrt(31)

y2 = -3 - sqrt(31)

=>

x1 = 6 + -3 + sqrt(31) = 3 + sqrt(31)

x2 = 3 - sqrt(31)

control :

(-3 + sqrt(31))² + (3 + sqrt(31))² = 80

9 - 3 sqrt(31) - 3 sqrt(31) + 31 + 9 +3 sqrt(31) + 3 sqrt(31) + 31 = 80

9 + 31 + 9 +31 = 80

18 + 62 = 80

80 = 80 correct

solving now for y-x=6

delivers exactly the same calculations, just with x and y trading places.

so, the resulting 2 number pairs are the same.

the product of the 2 numbers :

(3 + sqrt(31))(-3 + sqrt(31)) = -9 - 3 sqrt(31) + 3 sqrt(31) + 31 =

= -9 + 31 = 22

(3 - sqrt(31))(-3 - sqrt(31)) = -9 + 3 sqrt(31) - 3 sqrt(31) + 31 =

= 22

so, the product is the same in both cases.

fig 3 would take 18 triangle

fig 4 would take 30 small triangles

if its wrong i am sorry

Answer:

Answer:

a S(-3) = 2(-3)(-3)+5(-3)-12

=18-15-12

=-9

b 2x2+5x-12=0

2x2+8x-3x-12=0

2x(x-4)-3(x+4)=0

(2x-3)(x+4)=0

2x-3=0

x=3/2

x=-4

sorry I couldn't answer the other question

Answer:

[tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option)

Step-by-step explanation:

The midpoint of a segment connecting two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] can be described by the following formula: [tex]\frac{x_1 + x_2}{2} = x_{mid}[/tex] and [tex]\frac{y_1 + y_2}{2} = y_{mid}[/tex]. As you can see, the formula essentially takes the average of the x- and y-coordinates to find the point in the middle.

With points (u, v) and (s, t), the midpoint becomes [tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option).

Answer:

Answer is B.

Step-by-step explanation:

You can solve this by recognizing the vertex and the y-intercept of the quadratic equation based on the information provided.

The vertex occurs 6 seconds into the jump, when the cord is fully stretched to 72m, before it starts to contract again. This is when the jumper is closest to the ground, 122-72 = 50m above the ground. Notice the jumper never reaches the ground because the cord is only 72m long - it can't make it the full 122m - so there will not be an x-intercept (or t-intercept in this case). Anyway - the vertex is (6,50) using this information.

The y-intercept is the point at which t=0, the beginning of the jump. At the beginning of the jump, the jump is still on top of the cliff, 122m up. So the coordinates of the y-intercept are (0,122).

Now plug these values into the vertex form of the quadratic formula and solve for a:

[tex]f(t) = a(t-h)^2+k\\122=a(0-6)^2+50\\72 = 36a\\a=2[/tex]

This means our general equation (in vertex form) for this scenario is:

[tex]f(t)=2(t-6)^2+50[/tex]

Our answer options are in standard form, so just expand the vertex form of the equation to finish:

[tex]f(t)=2(t-6)^2+50\\f(t)=2(t^2-12t+36)+50\\f(t)=2t^2-24t+72+50\\f(t)=2t^2-24t+122[/tex]

Answer:

1st entry: 41

3rd entry: 17

Step-by-step explanation:

The 1st and 3rd entry are incorrect.

We will use the following for the 1st and 3rd:

[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]

[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]

where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.

Let's do part 1 now)

25+4+2(6)

29+12

41

Let's do part 3 now)

25+4-2(6)

29-12

17

Answer:

55

Angle C is a inscribed angle of the of Arc Ba.

CA is the diameter so that means Arc BA equal 110 becuase

110+70=180.

Angle C is half of Arc BA so Angle C is

[tex]55[/tex]

Answer:

the male weigh than the female

Step-by-step explanation:

[tex]\frac{19}{6}[/tex]=[tex]3\frac{1}{6}[/tex]

Answer:

2x-6

Step-by-step explanation:

( -8ײ +24×) ÷ (-4×) =

2x-6

Answer:

(2w+2)(w+8) ≤ 100

Step-by-step explanation:

A = l x w

we want less than or equal to 100

100 ≥ length (2w +2) x width (w+8)

flip around to look like answer

Answer:

C 8.9

Step-by-step explanation:

all these lines (from the same point of origin, cutting into and through a circle, ending at the far end of the circle they are cutting into) have the same relation of their lengths :

a×(a+b) is the same for all these lines.

with a being the first segment from the point of origin to touching the outside of the circle, and b being the length of the line inside the circle.

so,

4×(4+16) = 8×(8+2) = 80

this is correct for these two lines.

now, the line with the length x is a special case, as it does not really go through a circle, it only touches them.

but the length relation applies also to this line. it is just that the length inside the circle is 0.

so,

x×(x+0) = 80 (the same value as for the other lines)

must be true here too.

=>

x² = 80

x = sqrt(80) ≈ 8.9

Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

Step-by-step explanation:

0.13,1/2,1/8,and 7/8

hope it is helpful to you

a polygon with seven sides is called a heptagon

Answer:

Hyptagon

Step-by-step explanation:

In geometry, a heptagon is a seven-sided polygon or 7-gon.

The heptagon is sometimes referred to as the septagon, using "sept-" (an elision of septua-, a Latin-derived numerical prefix, rather than hepta-, a Greek-derived numerical prefix; both are cognate) together with the Greek suffix "-agon" meaning angle.

Answer:

.79 cents a pound is the lowest unit price for apples

Step-by-step explanation:

Answer:

When you solve for y, you get y = 20.

Step-by-step explanation:

You isolate the variable by dividing each side of the equation by the number with the variable, therefore getting 20.

[tex]\longrightarrow{\green{d.\:y\:=\:20}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

➝[tex]\:56 = 2.8y[/tex]

➝[tex]\:y = \frac{56}{2.8} [/tex]

➝[tex]\:y = 20[/tex]

Therefore, the value of [tex]y[/tex] is 20.

[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]

➝[tex]\:56 = 2.8y[/tex]

➝[tex]\:56 = 2.8 \times 20[/tex]

➝[tex]\:56 = 56[/tex]

➝[tex]\:L.H.S.=R. H. S[/tex]

Hence verified.

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

129° + x = 180°. [Linear pair]

=> x = 180° - 129°

=> x = 51°

Answer:

maybe y - -3x = -11?

Step-by-step explanation:

im rushing so i may have did it wrong sorry

Answer:

The answer for the question is -1.5

Answer:

the answer is the second option

Step-by-step explanation:

it is

Answer:

The two triangles are similar.

What is the value of x?

Enter your answer in the box.

x=

The value of x is 7 units.

Two triangles are said to be comparable if their two sides are in the same ratio as the two sides of another triangle and their two sides' angles inscribed in both triangles are equal.

Given :

AD = 6 units , BD = 8 units, m∠ABC = m∠DBE = 90° and              

∠DEB ≅ ∠ACB

Now, AB = AD + BD

              = 8 + 6 = 14 units

Now, In ΔABC and ΔDBE,

∠DBE = ∠ABC ( Each of 90° )

∠DEB = ∠ACB ( given )

So, By using AA postulate of similarity of triangles , ΔABC ~ ΔDBE

Now, proportion of the corresponding sides will be equal.

AD/ DB= BC/ BE

14/8 = 3x/ 2x-2

4x= 28

x= 7

Hence, the value of x is 7 units.

Learn more about similarity of Triangle here:

https://brainly.com/question/11923416

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Answer:

2/3

Step-by-step explanation:

25=125^k

5^2=5^3k

2=3k

k=2/3

The value of k is k = 2/3.

The number of times a number is multiplied by itself is referred to as an exponent.

Given that, [tex]25 = 125^k[/tex].

Follow the steps to find the value of k:

[tex]25 = 125^k\\\\5^2=(5^3)^k\\\\5^2=5^{3k}[/tex]

Since the base of the exponents is the same, it follows:

2 = 3k

k = 2/3

Hence, the value of k is k = 2/3.

Learn more about exponents here:

https://brainly.com/question/5497425

#SPJ2

Answer:

Step-by-step explanation:

(-5 , 2) here -5 is x coordinate and 2 is y coordinate since x coordinate is negative and y coordinate is positive it lies in II quadrant.

(2 , -5) here 2 is x coordinate whereas -5 is y coordinate and siince x coordiante is positive and y coordinate is negative it lies in IV quadrant.

(x^3 - 2)(x^2 + 11)

to find the degree of polynomial first u need to factor this out

x^3(x^2 + 11) -2(x^2 + 11)

x^3 * x^2 + x^3 * 11 - 2 * x^2 - 2 * 11

x^3+2 + 11x^3 - 2x^2 - 22

x^5 + 11x^3 - 2x^2 - 22

since the highest degree is 5 the degree of the polynomial is also 5.

Step-by-step explanation:

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Given:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex].

To find:

The least common multiple of given expressions.

Solution:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex]. The factor forms of these expressions are:

[tex](x+1)=1\times (x+1)[/tex]

[tex](x-1)=1\times (x-1)[/tex]

[tex](x^2-1)=(x-1)(x+1)[/tex]                 [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

The least common multiple is the product of all distinct factors with its highest degree. So,

[tex]L.C.M.=1\times (x+1)\times (x-1)[/tex]

[tex]L.C.M.=(x+1)(x-1)[/tex]

[tex]L.C.M.=x^2-1^2[/tex]                [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

[tex]L.C.M.=x^2-1[/tex]

Therefore, the least common multiple of given expressions is [tex]x^2-1[/tex].

The answer would be A. 449.1 cm2.

Answer:

904.78

Step-by-step explanation:

I hope this is correct, if it isn't please feel free to let me know and I can fix it. I'm sorry in advance if it is incorrect.

Step By Step Explanation:

Answer:

let's use Pythagoras theorem,

h²=b²+l²

so,

ad²=ac²+dc²

6²=ac²+3²

36-9=ac²=27

√27 can be written as 3√3,

hence ac= 3√3