Answer:
A.
Step-by-step explanation:
a strange question, as 2 answer options are actually possible, as they define valid domains for this function.
and if the range of the function would include imaginary numbers ("i"), all 4 would be correct.
the problem statement has to be much more precise. you can tell your teacher that.
but I assume, we base just on real numbers and want the biggest domain range. and that is A.
A. for x=1 we get sqrt(0) + 2, which is absolutely valid.
B. a square root of a negative number is undefined in the works of real numbers. we would need "i", the imaginary numbers, to make this a valid function.
C. is also valid. no bad values and expressions involved. it is just a snake range than A.
D. the same a for B.
The domain of the function [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]
How to determine the domain?The function is given as:
[tex]f(x) = \sqrt{x - 1} + 2[/tex]
Set the radicand greater than or equal to 0
[tex]\sqrt{x - 1} \ge 0[/tex]
Take the square of both sides
[tex]x - 1 \ge 0[/tex]
Add 1 to both sides
[tex]x \ge 1[/tex]
This means the possible values of x starts from 1 till infinity
Hence, the domain of [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]
Read more about domain at:
https://brainly.com/question/1770447
What is the next term of this sequence? -5,5,-6,6,-7,7,-8,..
Answer:
8,-9,9
Step-by-step explanation:
I need help with this
Answer:
Step-by-step explanation:
It was confusing
Without graphing, determine the range of the function f(x) = -5|x-7|+2 over
the interval (-5,10).
A. [2 -62
B. [2, 17]
C. (17, 62]
D. (-7, 2]
Brainliest, 10 Points, & Thanks if answer to these questions!!!!!!!!
Answer:
D
Step-by-step explanation:
+1 and -1 change the x postion
Create an example of a situation where there is a negative cash flow.?
The question is on the picture
answer:
ABCD is not congruent to KLMN
ABCD cannot be mapped onto KLMN
Please help, please no links or websites
Answer:
12
Step-by-step explanation:
Just substitute 3 for n and solve.
Solve the expression [tex]2+(3-1)5\\[/tex]
Use PEMDAS and solve.
(3-1) = 2 so it becomes 2 + (2)5
Then multiply 2 and 5 to get 10.
Then add 2 so you get 12.
[tex]a_{3}[/tex]=12
Determine whether the vectors u and v are parallel, orthogonal, or neither.
u = <2,-4>, v = <6,3> (5 points)
===========================================================
Explanation:
For any two vectors defined as follows
u = <a,b>
v = <c,d>
the dot product is computed by
u dot v = a*c + b*d
If the dot product of the vectors is 0, then the vectors are orthogonal. Meaning they are perpendicular to one another.
-------------------
Let's find the dot product of these two given vectors
u = < 2, -4 >
v = < 6, 3 >
u dot v = 2*6 + (-4)*3
u dot v = 12 - 12
u dot v = 0
Therefore, these two vectors form a right angle and are orthogonal
-------------------
Extra info:
If we can show that u = <a, b> and v = <ka, kb> for some real number k, then we have shown that vectors u and v are parallel.
The dean of a major university claims that the mean number of hours students study at her University (per day) is at most 4.9 hours. If a hypothesis test is performed, how should you interpret a decision that rejects the null hypothesis
Answer:
If the null hypothesis is rejected, the interpreatation is that there is significant evidence at the desired significance level to conclude that the mean time the students study at her university is of more than 4.9 hours.
Step-by-step explanation:
The dean of a major university claims that the mean number of hours students study at her University (per day) is at most 4.9 hours.
At the null hypothesis, we test if the mean is of at most 4.9 hours, that is:
[tex]H_0: \mu \leq 4.9[/tex]
At the alternative hypothesis, we test if the mean is more than 4.9 hours, that is:
[tex]H_1: \mu > 4.9[/tex]
Accepting the null hypothesis:
If the null hypothesis is accepted, the interpretation is that there is not significant evidence to conclude that the mean time the students study at her university is of more than 4.9 hours.
Rejecting the null hypothesis:
As is the case in this question, if the null hypothesis is rejected, the interpreatation is that there is significant evidence at the desired significance level to conclude that the mean time the students study at her university is of more than 4.9 hours.
Find the area of the polygon.
is this right?
ERGENT
Answer:
The answer is in the picture.
15cm²
Don’t save the answer and I really need help
9514 1404 393
Answer:
zero solutions
Step-by-step explanation:
The first inequality has a boundary line with a slope of 3 and a y-intercept of 9. Shading is above the boundary line.
The second inequality has a parallel boundary line with a slope of 3 and a y-intercept somewhat lower, at -1. Shading is below this boundary line.
There is a gap between the shaded areas, so no points will be solutions to both inequalities.
Select the correct answer.
What is the approximate value of the correlation coefficient for the given graph
Answer:
x = -5
Step-by-step explanation:
the answer is -5 sussy baka
This is because all points are on, or nearly on, the same straight line that has a negative slope. We consider this close to or nearly perfect negative linear correlation.
Side note: The r value and slope are both negative, but they aren't equal to one another.
Mary plants roseas in 1/4 of her garden. She also plants some tulips in her garden. She has 1/12 of the garden left to plant more flowers. What fraction of Mary's garden has tulips?
Let x represent the full area if Mary's garden.
Mary plants roses in 1/4 of her garden. This means that the portion of the garden on which she planted roses would be 1/4 × x = x/4
She also plants some tulips in her garden. She has 1/12 of the garden left to plant more flowers. This means that the portion if the garden that she has left to plant more flowers would be 1/12 × x = x/12
The portion of the garden on which she planted tulips would be
x - (x/4 + x/12) = x - (3x + x)/12 = x - 4x/12
x - x/3 = (3x - x)/3 = 2x/3
Therefore, the fraction of Mary's garden that has tulips would be
(2x/3) /x = 2/3
A car that is normally $4200 is on sale for 80% of its original cost.
what is the sale price of the car?
Answer:
$3360
Step-by-step explanation:
4200(.80) = 3360
anything less than 1.00 will be a decreasing amount, so i just took the 80% and put it as a decimal and multiplied to find the current cost of the car
Find f(x) and g(x) so that the function can be described as y = f(g(x)).
y=[tex]\frac{9}{x^2} + 2[/tex]
Hope this help!!!
Have a nice day!!!
Are (2, 5) and (5, 2) the same location? Why or why not?
Answer:
They are not in the same location
Step-by-step explanation:
Well because we have x axis and y axis, x always has to go first. In (2, 5) 2 is first and has to start from the x axis and 5 is the y axis. And the (5,2) is the opposite and the places would be in totally different places on the coordinate plane.
Answer: No
Step-by-step explanation: The order of coordinates for a given point is very important. For example, (2, 5) and (5, 2) represent two very different points on a coordinate system, as shown in the picture below.
A given point, such as (2, 5), is often reffered to as
an ordered pair because the order of coordinates is very important.
45 is what percent of 82
what percent of 5 is 26
Round each answer to the nearest TENTH!
HELP FINALS TODAY :(
Answer:
45 is 54.9 percent of 82.
26 is 520% of 5.
Answer:
45 is 55% of 82 and 520% of 5 is 26.
Step-by-step explanation:
First you want to set up a proportion, using the is over of formula (Is/of= %/100). In the first problem, 45 will be the is, 82 will be the of, for % will be the x, and 100 will go on the bottom (it will look something like this: 45/82=x/100). When you solve it, you get around 55 (45x100/82.) Same thing for the next equation, use the same formula (is/of=%/100) which turns into: 5/26= x/100 and you get 520%.
A sample of 260 students enrolled at a university were asked what they intended to do after graduation. The results are shown below.
Bar Graph of Type of Employment
What percentage of students intend to go into state or local government after graduation?
Hi my name is Fabian and 69% because 69 is a man which is multi colour hair
Find the value of x
Answer:
x = 40
Step-by-step explanation:
Two triangles are similar so we can use similarity ratio to find x
x/16 = 35/14 cross multiply expressions
14x = 560 divide both sides by 14
x = 40
-3 to the 3rd power + 2
Answer:-7
Step-by-step explanation: -3^3+ 2
-9+2= -7
Use this table of values for the rate of rainfall over time.
Rate of Rainfall (mm per hour) Time 6:00 am 20 6.15 am 28 630 am 3.0 645 am 35 7:00 am 3.8 7:15 am 42 7:30 am 4.8 7:45 am 5.6 8:00 am 4.0 8.15 am 3.3 8:30 am 1.8 8:45 am 0.4 9:00 am 1.2.
An approximation of the total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is
a. 9.3 mm.
b. 9.6 mm.
Solution :
Here the subintervals of equal length will be :
[tex][6:00, 6:30], [6:30, 7:00], [7:00, 7:30], [7:30, 8:00], [8:00, 8:30], [8:30, 9:00][/tex]
So thee mid points are
[tex]x_1 = 6:15, \ x_2=6:45, \ x_3=7:15, \ x_4=7:45, \ x_5, 8:15, \ x_6 = 8:45[/tex]
The length of each sub-interval is = [tex]\frac{9-6}{6} = \frac{3}{6} = 0.5[/tex]
So, total amount of rainfall will be :
[tex]$=0.5 \sum^6_{i=1} f(x_i)$[/tex]
[tex]$=0.5\left( f(x_1)+f(x_2)+....+ f(x_6)\right)$[/tex]
= 0.5 (2.8 + 3.5 + 4.2 + 5.6 + 3.3 + 0.4)
= 0.5 (19.8)
= 9.9
The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.
Given that,
The rate of rainfall (mm per hour) over time.
Rate of rainfall;
6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00
Time
2.0 2.8 3.0 3.5 3.8 4.2 4.8 5.6 4.0 3.3 1.8 0.4 1.2
We have to determine,
0.4 9:00 am 1.2.
The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is?
According to the question,
Rate of rainfall;
6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00
Time
2.0 2.8 3.0 3.5 3.8 4.2 4.8 5.6 4.0 3.3 1.8 0.4 1.2
Here, the midpoints sum with 6 equal subintervals are,
[tex]\rm x_1 = 6;15, \ x _2 = 6;45, \ x_3 = 7;15, \ x_4 = 7;45, x_5 = 8;15 , \ x_6 = 8;45[/tex]
Then, the length of each subinterval is,
[tex]= \dfrac{9-6}{6}\\\\= \dfrac{3}{6}\\\\= \dfrac{1}{2}[/tex]
The total amount of rainfall that falls between 6;00 to 9;00 am using the midpoint subinterval is,
[tex]\rm = \dfrac{1}{2} \sum^{6}_{i=0} f(x_i)\\\\= \dfrac{1}{2} \sum^{6}_{i=0} f(x_1)+ f(x_2) + f(x_3) + f(x_4) +f(x_5)+f(x_6)\\\\= \dfrac{1}{2} (2.8+ 3.5+4.2+ 5.6+3.3+0.4}\\\\= \dfrac{1}{2} \times 19.8\\\\= 9.9[/tex]
Hence, The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.
For more details refer to the link given below.
https://brainly.com/question/795909
Express 6x-9≤3x-11 in interval notation
Answer:
(-∞, - 2/3)
Step-by-step explanation:
Given the inequality :
6x-9≤3x-11
Collect like terms :
6x - 3x ≤ - 11 + 9
3x ≤ - 2
Divide both sides by 3
3x/3 ≤ - 2/3
x ≤ - 2/3
(-∞, - 2/3)
HELP PLSSS I WILL GIVE YOU BRAINLYEST
i suck at math this is easy
OPTION C is the correct answer.
the sum of 10 and the product of 12 and s in agebraic expression
Answer and Step-by-step explanation:
10 + 12s would be the algebraic expression.
Because 10 is being added to the product of 12 and s, meaning 12 and s multiply each other.
#teamtrees #PAW (Plant And Water)
PLWASE HELP GEOMETRY
A hot-air balloon is tied to the ground with two taut ropes. One rope is directly under the balloon and makes a right
angle with the ground. The other rope forms an angle of 60° with the ground. Which statements are correct?
Using trigonometry solve for h and d.
H :
Sin(60) = h/120
H = 120 x sin(60)
H = 103.9 = 104 feet
D:
Cos(60) = d/120
D = 120 x cos(60)
D = 60 feet
The correct answers:
A. D = 60 ft.
C. H = 104 ft
simplify x^0 y^-3/x^2y^-1
The answer is 1/x^2y^2
The given expression is [tex] \frac{ {x}^{0} y { - }^{3} }{ {x}^{2}y { - }^{1} } [/tex]
We know that any number raised with zero power equals 1. Thus, [tex] {x}^{0} = 1[/tex]
Hence, the expression becomes
[tex] \frac{y { - }^{3} }{ {x}^{2} y { - }^{1} } [/tex]
Now, apply the quotient rule,[tex] \frac{ {x}^{ \alpha } }{ {x}^{b} } = {x}^{ \alpha - b} [/tex]
Using this rule, we have
[tex] \frac{1}{ {x}^{2} y { - }^{1 - ( - 3)} } [/tex]
[tex] = \frac{1}{ {x}^{2} y { - }^{1 + 3} } [/tex]
[tex]= \frac{1}{ {x}^{2} {y}^{2} } [/tex]Hence, the simplified expression is [tex] \frac{1}{ {x}^{2} {y}^{2} } [/tex]
please help me i’m begging!!
i need to match them
An angle of depression is measured from the horizon downwards and an angle of elevation is measured from the horizon upwards.
When solving for the sides or angles of a right triangle you can use trigonometry. The sine of an angle is found by the ratio of the opposite side and the hypotenuse. The cosine of an angle is found by the ratio of the adjacent side and the hypotenuse. The tangent of an angle is found by the ratio of the opposite side and the adjacent side.
The opposite side is always the leg opposite the angle that you are using. The adjacent side is the leg that forms one of the sides of the angle you are talking about and the hypotenuse is always across from the right angle.
If you know two lengths you can find the third leg length by using the Pythagorean Theorem.
Hi! Could someone check this questions for me and if I have anything wrong tell what I have wrong please? That would be highly appreciated!!
Answer:
Both are correct
I'm only checking the first page
Step-by-step explanation:
Answer:
Step-by-step explanation:
The 3rd page both are wrong the correct answers are 6 degrees C and Ice would form on the top of the lake like it does now.
The 4th page the bottom one is wrong the correct answer is -22.
need help with these table
State if the two triangles are congruent. If they are, prove by using a two column proof!!!
Answer:
Step-by-step explanation:
There are four axioms to prove the triangles are contruent.They are
SSS(side side side axiom)
SAS(side angle side axiom)
AAS(angle angle side axiom)
ASA(angle side angle axiom)
RHS (right angle hypotenuse side axiom)
here two triangles are congruent by RHS axiom